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Suppose a person has a cuboid and you want to paint this cuboid from the outer, and you want to know how much is required to paint this cuboid. For this, the total area of the outer layer should be calculated, and this area is called the surface area of any object. Therefore, surface area is the total outer space of any three-dimensional object. After painting this cuboid, if a person wants to fill this cuboid with water, then how much water is needed to fill this cuboid? To determine the answer to this question person should know the amount of space within this cuboid, and this amount of space is called the volume of the cuboid. Therefore, the amount of space within any three-dimensional object is called the volume.
In the NCERT Books exercise 12.1, Class 10 Maths, we have to find the surface area of the combined solids. Some of these solids are cylinders with both sides hemispheres, and cones with a hemisphere on top. Surface area can be categorised into two types of surface areas: the curved surface area and the total surface area. 10th class Maths exercise 12.1 answers are designed as per the students' demand, covering comprehensive, step-by-step solutions of every problem. Practice these questions and answers to command the concepts, boost confidence and in-depth understanding of concepts. These NCERT solutions Class 10 Maths ex 12.1 present us with the surface area of a combination of Solids. Some solids, such as the cuboid, cone, cylinder, and sphere, are recognisable to you from Class IX. You've also learned how to calculate their volumes and surface areas. In our daily lives, we come across a variety of solids that are made up of two or more of the fundamental solids.
Q1. 2 cubes, each of volume 64 cm3 are joined end to end. Find the surface area of the resulting cuboid.
Answer:
We are given that volume of the cube
Also, the volume of a cube is given by
Thus:
Now, according to the question, we have combined the two cubes so that the edge lengths of the formed cuboid are 4 cm, 4 cm, and 8 cm.
The surface area of a cuboid is :
or
or
or
Thus, the area of the formed cuboid is 160 cm².
Answer:
Since the vessel consists of a hemisphere and a cylinder, its area is given by :
Area of vessel = Inner area of the cylinder(curved) + Inner area of the hemisphere
The inner surface area of the hemisphere is :
or
or
And the surface area of the cylinder is :
or
or
Thus, the inner surface area of the vessel is
Answer:
The required surface area of the toy is given by :
Area of toy = Surface area of hemisphere + Surface area of the cone
Firstly, consider the hemisphere:
The surface area of a hemisphere is
or
or
Now, for the cone we have:
The surface area of a cone
Thus, we need to calculate the slant of the cone.
We know that:
or
or
or
Thus surface area of a cone
or
or
Hence, the total surface area of toy =
Answer:
It is given that the hemisphere is mounted on the cuboid, thus, the hemisphere can take on complete as its diameter (which is maximum).
Thus, the greatest diameter of the hemisphere is 7 cm.
Now, the total surface area of the solid = Surface area of the cube + Surface area of the hemisphere - Area of the base of the hemisphere (as this is counted on one side of the cube)
The surface area of the cube is :
Now the area of a hemisphere is
And the area of the base of a hemisphere is
Hence, the surface area of the solid is
Answer:
It is given that the diameter of the hemisphere is equal to the edge length of the cube.
The total surface area of the solid is given by :
The surface area of a solid = Surface area of the cube + Surface area of the hemisphere - Area of the base of the hemisphere
The surface area of the cube
And the surface area of the hemisphere:
Area of the base of the hemisphere:
Thus, the area of the solid is:
Answer:
It is clear from the figure that the capsule has a hemisphere and cylinder structure.
The surface area of the capsule = 2 (Area of the hemisphere) + Area of the cylindrical part
Area of hemisphere
or
or
And the area of the cylinder
or
or
Thus, the area of the solid is :
Answer:
The canvas will cover the cylindrical part as well as the conical part.
So, the area of canvas = Area of cylindrical part (curved) + Area of the conical part
Now, the area of the cylindrical part is
or
or
And the area of the cone is
or
or
Thus, the area of the canvas
or
Further, it is given that the rate of canvas per m 2 is = Rs. 500.
Thus, the required money is
Answer:
Firstly, we need to calculate the slant height of the cone :
or
or
or
Now, the total surface area of the solid can be calculated as :
The surface area of a solid = Surface area of cylinder + Surface area of cone + Area of base of the cylinder
The surface area of the cylinder is
or
or
Now, the surface area of a cone
or
or
And the area of the base of the cylinder is
or
or
Thus required area of the solid = 10. 56 + 5.50 + 1.54 = 17.60 cm2 .
Thus total surface area of the remaining solid to the nearest cm2 is 18 cm2.
Answer:
The required surface area is given by :
The surface area of the article = Surface area of the cylindrical part + 2 (Surface area of the hemisphere)
Now, the area of the cylinder
or
or
And the surface area of the hemisphere:
or
or
Thus, the required area
Also Read
Also See:
As per latest 2024 syllabus. Maths formulas, equations, & theorems of class 11 & 12th chapters
Students must check the NCERT solutions for class 10 of the Mathematics and Science Subjects.
Students must check the NCERT Exemplar solutions for class 10 of the Mathematics and Science Subjects.
Curved surface area of hemisphere used is =2πr²
Curved surface area of hemisphere used in 2πrl
The most commonly used value of pi used in exercise 12.1 Class 10 Maths is
We can use surface area in many places in our daily life, for example identifying the amount of paint require to paint object , determining the cost of things like clothes , covers and canvas tents
The total number of examples that have been solved before the class 10 Maths chapter 12 exercise 12.1 is four
The total number of questions in the NCERT solutions for Class 10 Maths chapter 12 exercise is nine.
There are many basic question in which we have to find the total surface of combination of solid or real life objects such as tents , capsules toys etc but some are direct that only ask about the solid
Hello
Since you are a domicile of Karnataka and have studied under the Karnataka State Board for 11th and 12th , you are eligible for Karnataka State Quota for admission to various colleges in the state.
1. KCET (Karnataka Common Entrance Test): You must appear for the KCET exam, which is required for admission to undergraduate professional courses like engineering, medical, and other streams. Your exam score and rank will determine your eligibility for counseling.
2. Minority Income under 5 Lakh : If you are from a minority community and your family's income is below 5 lakh, you may be eligible for fee concessions or other benefits depending on the specific institution. Some colleges offer reservations or other advantages for students in this category.
3. Counseling and Seat Allocation:
After the KCET exam, you will need to participate in online counseling.
You need to select your preferred colleges and courses.
Seat allocation will be based on your rank , the availability of seats in your chosen colleges and your preferences.
4. Required Documents :
Domicile Certificate (proof that you are a resident of Karnataka).
Income Certificate (for minority category benefits).
Marksheets (11th and 12th from the Karnataka State Board).
KCET Admit Card and Scorecard.
This process will allow you to secure a seat based on your KCET performance and your category .
check link for more details
https://medicine.careers360.com/neet-college-predictor
Hope this helps you .
Hello Aspirant, Hope your doing great, your question was incomplete and regarding what exam your asking.
Yes, scoring above 80% in ICSE Class 10 exams typically meets the requirements to get into the Commerce stream in Class 11th under the CBSE board . Admission criteria can vary between schools, so it is advisable to check the specific requirements of the intended CBSE school. Generally, a good academic record with a score above 80% in ICSE 10th result is considered strong for such transitions.
hello Zaid,
Yes, you can apply for 12th grade as a private candidate .You will need to follow the registration process and fulfill the eligibility criteria set by CBSE for private candidates.If you haven't given the 11th grade exam ,you would be able to appear for the 12th exam directly without having passed 11th grade. you will need to give certain tests in the school you are getting addmission to prove your eligibilty.
best of luck!
According to cbse norms candidates who have completed class 10th, class 11th, have a gap year or have failed class 12th can appear for admission in 12th class.for admission in cbse board you need to clear your 11th class first and you must have studied from CBSE board or any other recognized and equivalent board/school.
You are not eligible for cbse board but you can still do 12th from nios which allow candidates to take admission in 12th class as a private student without completing 11th.
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As per latest 2024 syllabus. Physics formulas, equations, & laws of class 11 & 12th chapters
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