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NCERT Solutions for Class 9 Maths Chapter 5 Introduction to Euclids Geometry

NCERT Solutions for Class 9 Maths Chapter 5 Introduction to Euclids Geometry

Edited By Ramraj Saini | Updated on Sep 27, 2023 10:27 PM IST

NCERT Solutions for Class 9 Maths Chapter 5 Introduction to Euclids Geometry

Introduction to Euclids Geometry Class 9 Questions And Answers are provided here. These NCERT solutions are designed by expert team considering latest CBSE syllabus 2023-24 and to provide comprehensive coverage of concepts to students which ultimately help in the exam. This class 9 NCERT syllabus chapter will discuss Euclid’s approach to geometry and its real-life applications. Here you will get NCERT solutions for class 9 maths also.

This Introduction to euclids geometry class 9 solutions includes two exercises with 9 questions. NCERT solutions for class 9 maths chapter 5 Introduction to Euclid’s Geometry consist of detailed explanations for all the 9 questions. This chapter talks about the basic observation of geometry which is generally ignored by the students. Introduction to Euclids geometry class 9 NCERT solutions is covering each and every single step to answer the practice exercise questions. In this chapter, you will study definitions like a point, a line, and a plane which are defined by Euclid’s and Euclid’s five postulates.

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Introduction to Euclids Geometry Class 9 Questions And Answers PDF Free Download

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Introduction to Euclids Geometry Class 9 Solutions - Important Points

>> Axioms:

  • Equality Axiom: If two things are equal to the same thing, they are equal to each other.

  • Addition Axiom: If equals are added to equals, the wholes are equal.

  • Subtraction Axiom: If equals are subtracted from equals, the remainder are equal.

  • Coincidence Axiom: Things which coincide with one another are equal to one another.

  • Whole-Part Axiom: The whole is greater than the part.

>> Postulates (Euclid's five postulates):

  • Postulate of Straight Lines: A straight line can be drawn from any one point to any other point.

  • Postulate of Line Extension: A terminated line can be produced indefinitely.

  • Postulate of Circle Drawing: A circle can be drawn with any centre and any radius.

  • Postulate of Right Angles: All right angles are equal to one another.

  • Postulate of Parallel Lines: If a straight line falling on two straight lines makes the interior angles on the same side of it taken together less than two right angles, then the two straight lines, if produced indefinitely, meet on that side on which the angles are less than two right angles.

Free download NCERT Solutions for Class 9 Maths Chapter 5 Introduction to Euclids Geometry for CBSE Exam.

Introduction to Euclids Geometry Class 9 NCERT Solutions (Intext Questions and Exercise)

Class 9 maths chapter 5 question answer Excercise: 5.1

Q1 Which of the following statements are true and which are false? Give reasons for your answers.

(i) Only one line can pass through a single point.

(ii) There are an infinite number of lines which pass through two distinct points.

(iii) A terminated line can be produced indefinitely on both the sides.

(iv) If two circles are equal, then their radii are equal.

(v) In Fig. 5.9, if AB = PQ and PQ = XY, then AB = XY.

1640082731275

Answer:

i) FALSE
Because there is the infinite number of lines that can be passed through a single point. As shown in the diagram below
1640082806946 ii) FALSE
Because only one line can pass through two distinct points. As shown in the diagram below
1640082824490 iii) TRUE
Because a terminated line can be produced indefinitely on both sides. As shown in the diagram below
1640082837386 iv) TRUE
Because if two circles are equal, then their centre and circumference will coincide and hence, the radii will also be equal.

v) TRUE
By Euclid’s first axiom things which are equal to the same thing, are equal to one another

Q2 (i) Give a definition for each of the following terms. Are there other terms that need to be defined first? What are they, and how might you define them?
(i) parallel lines

Answer:

Yes, there are other terms that are needed to be defined first which are:

Plane: A plane is a flat surface on which geometric figures are drawn.

Point: A point is a dimensionless dot which is drawn on a plane surface.

Line: A line is the collection of n number of points which can extend in both the directions and has only one dimension.
i) Parallel line:-
If the perpendicular distance between two lines is always constant and they never intersect with each other in a plane. Then, two lines are called parallel lines.

Q2 (ii) Give a definition for each of the following terms. Are there other terms that need to be defined first? What are they, and how might you define them? (ii) perpendicular lines

Answer:

Yes, there are other terms that are needed to be defined first which are:

Plane: A plane is a flat surface on which geometric figures are drawn.

Point: A point is a dimensionless dot which is drawn on a plane surface.

Line: A line is the collection of n number of points which can extend in both the directions and has only one dimension.
ii) perpendicular line:-
If two lines intersect with each other and make a right angle at the point of intersection. Then, two lines are called perpendicular lines.

Q2 (iii) Give a definition for each of the following terms. Are there other terms that need to be defined first? What are they, and how might you define them? iii) line segment

Answer:

Yes, there are other terms that are needed to be defined first which are:

Plane: A plane is a flat surface on which geometric figures are drawn.

Point: A point is a dimensionless dot which is drawn on a plane surface.

Line: A line is collection of n number of points which can extend in both the directions and has only one dimension.
iii) line segment : -
A straight line with two end points that cannot be extended further and has a definite length is called line segment

Q2 (iv) Give a definition for each of the following terms. Are there other terms that need to be defined first? What are they, and how might you define them? iv) radius of circle

Answer:

iv) Radius of the circle : -
The distance between the centre of the circle and any point on the circumference of the circle is called the radius of a circle.

Q2 (v) Give a definition for each of the following terms. Are there other terms that need to be defined first? What are they, and how might you define them? v) square

Answer:

v) Square:-
A square is a quadrilateral in which all the four sides are equal and each internal angle is a right angle.

To define the square, we must know about quadrilateral.

Q3 Consider two ‘postulates’ given below:

(i) Given any two distinct points A and B, there exists a third point C which is in between A and B.

(ii) There exist at least three points that are not on the same line.

Do these postulates contain any undefined terms? Are these postulates consistent?

Do they follow from Euclid’s postulates? Explain.

Answer:

There are various undefined terms in the given postulates.:

1) There is no information given about the plane whether the points are in the same plane or not.

2) There is the infinite number of points lie in a plane. But here the position of the point C has not specified whether it lies on the line segment joining AB or not.

Yes, these postulates are consistent when we deal with these two situations:

(i) Point C is lying in between and on the line segment joining A and B.

(ii) Point C does not lie on the line segment joining A and B.

No, they don’t follow from Euclid’s postulates. They follow the axioms.

Q4 If a point C lies between two points A and B such that AC = BC, then prove that AC = 1/2 AB. Explain by drawing the figure.

Answer:

It is given that
AC = BC
Now,
1640082867954 In the figure given above, AB coincides with AC + BC.
Also, Euclid’s Axiom (4) says that things which coincide with one another are equal to one another. So, it can be deduced that AC + BC = AB
Now,
2AC = AB (\because AC = BC )
Therefore,
AC = \frac{1}{2}AB
Hence proved.

Q5 In Question 4, point C is called a mid-point of line segment AB. Prove that every line segment has one and only one mid-point.

Answer:

1640082899454 Let's assume that there are two midpoints C and D
Now,
If C is the midpoint then, AC = BC
And
In the figure given above, AB coincides with AC + BC.
Also, Euclid’s Axiom (4) says that things which coincide with one another are equal to one another. So, it can be deduced that AC + BC = AB
From this, we can say that
2AC = AB -(i)

Similarly,
If D is the midpoint then, AD = BD
And
In the figure given above, AB coincides with AD + BD.
Also, Euclid’s Axiom (4) says that things which coincide with one another are equal to one another. So, it can be deduced that AD + BD = AB
From this, we can say that
2AD = AB -(ii)
Now,
From equation (i) and (ii) we will get
AD = AC
and this is only possible when C and D are the same points
Hence, our assumption is wrong and there is only one midpoint of line segment AB.

Q6 In Fig. 5.10, if AC = BD, then prove that AB = CD.

1640082935536

Answer:

From the figure given in the problem,
We can say that
AC = AB + BC and BD = BC + CD
Now,
It is given that AC = BD
Therefore,
AB + BC = BC + CD
Now, According to Euclid's axiom, when equals are subtracted from equals, the remainders are also equal. Subtracting BC from both sides.
We will get
AB + BC - BC = BC + CD - BC
AB = CD
Hence proved

Q7 Why is Axiom 5, in the list of Euclid’s axioms, considered a ‘universal truth’? (Note that the question is not about the fifth postulate.)

Answer:

Axiom 5 states that the whole is greater than the part.
Lets take A = x + y + z
where A , x , y , z all are positive numbers
Now, we can clearly see that A > x , A > y , A > z
Hence, by this we can say that the whole (A) is greater than the parts. (x , y , z)

Class 9 maths chapter 5 NCERT solutions Excercise: 5.2

Q1 How would you rewrite Euclid’s fifth postulate so that it would be easier to understand?

Answer:

Euclid's postulate 5: If a straight line falling on two straight lines makes the interior angles on the same side of it taken together less than two right angles, then the two straight lines, if produced indefinitely, meet on that side on which the sum of angles is less than two right angles.

1640082956556 Now, in an easy way
Let the line PQ in falls on lines AB and CD such that the sum of the interior angles 1 and 2 is less than 180° on the left side of PQ. Therefore, the lines AB and CD will eventually intersect on the left side of PQ.

Q2 Does Euclid’s fifth postulate imply the existence of parallel lines? Explain.

Answer: 1640082975160 According to Euclid's 5 postulates, the line PQ falls on lines AB and CD such that the sum of the interior angles 1 and 2 is less than 180° on the left side of PQ. Therefore, the lines AB and CD will eventually intersect on the left side of the PQ
Now,
If \angle 1+\angle 2 = 180\degree then, the line never intersects with each other.
Therefore, we can say that lines AB and CD are parallel to each other


NCERT Solutions For Class 9 chapter 5 - Topics

5.1 Introduction to Euclid’s Geometry

5.2 Euclid’s Definitions, Axioms, and Postulates

5.3 Equivalent Versions of Euclid’s Fifth Postulate

Interested students can study class 9 maths ch 5 question answer using the exercise solution links given below.

Key Features of Class 9 Introduction To Euclids Geometry NCERT Solutions

Comprehensive Coverage: NCERT solutions for maths chapter 5 class 9 typically provide in-depth coverage of the chapter's topics, ensuring that all key concepts and subtopics are addressed.

Clear and Concise Explanations: The solutions for ch 5 maths class 9 offer clear and concise explanations for complex scientific concepts, making it easier for students to understand.

Step-by-Step Solutions: Problems and exercises are accompanied by step-by-step solutions, aiding students in understanding the problem-solving process.

NCERT Solutions For Class 9 - Chapter Wise

Chapter No.
Chapter Name
Chapter 1
Chapter 2
Chapter 3
Chapter 4
Chapter 5
Introduction to Euclid's Geometry
Chapter 6
Chapter 7
Chapter 8
Chapter 9
Chapter 10
Chapter 11
Chapter 12
Chapter 13
Chapter 14
Chapter 15

NCERT Solutions For Class 9 - Subject Wise

How To Use NCERT Solutions For Class 9 Maths Chapter 5

  • Go through each and every theorem and property have given at the start of the chapter.
  • Have a glance through some examples given using those theorem and properties.
  • Now, you can jump to the practice exercises to implement the acquired knowledge.
  • During the practice, if you stuck anywhere then you can take the help of NCERT solutions for class 9 maths chapter 5 Introduction to Euclid's Geometry.
  • Once you complete the above three points, then you can do some more practice using past papers.

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Frequently Asked Questions (FAQs)

1. Do NCERT class 9 maths chapter 5 solutions align well with the CBSE curriculum for students?

NCERT Solutions have long been recommended as a comprehensive learning resource for CBSE students to enhance their analytical skills. They have become an indispensable tool for comprehending the syllabus and building the confidence necessary to approach exams. The NCERT Solutions for Class 9 Maths Chapter 5 provide a precise explanation of the steps involved in solving a problem, covering all crucial aspects without skipping any essential details.

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Here NCERT solutions for class 9 maths students can find these solutions. Also, Careers360 website offers NCERT Solutions for Class 9 Maths Chapter 5, which are considered a crucial study material for Class 9 students. The solutions available on Careers360 are formulated meticulously, with every step explained in detail to provide clarity to the students. Our subject experts have prepared the solutions for Class 9 Maths NCERT to aid students in their board exam preparation. It is imperative for students to become well-versed in these solutions to obtain a good score in the Class 9 examination.

3. What is the meaning of Euclidean geometry according to NCERT Solutions for introduction to euclids geometry class 9?

The study of geometrical shapes and figures based on various axioms and theorems is known as Euclidean geometry. This type of geometry is primarily developed for two-dimensional, flat surfaces and is well-suited for explaining the shapes of geometrical figures and planes. Referring to NCERT Solutions for Class 9 Maths Chapter 5 can aid students in achieving a good score in their exams.

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A block of mass 0.50 kg is moving with a speed of 2.00 ms-1 on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is

Option 1)

0.34\; J

Option 2)

0.16\; J

Option 3)

1.00\; J

Option 4)

0.67\; J

A person trying to lose weight by burning fat lifts a mass of 10 kg upto a height of 1 m 1000 times.  Assume that the potential energy lost each time he lowers the mass is dissipated.  How much fat will he use up considering the work done only when the weight is lifted up ?  Fat supplies 3.8×107 J of energy per kg which is converted to mechanical energy with a 20% efficiency rate.  Take g = 9.8 ms−2 :

Option 1)

2.45×10−3 kg

Option 2)

 6.45×10−3 kg

Option 3)

 9.89×10−3 kg

Option 4)

12.89×10−3 kg

 

An athlete in the olympic games covers a distance of 100 m in 10 s. His kinetic energy can be estimated to be in the range

Option 1)

2,000 \; J - 5,000\; J

Option 2)

200 \, \, J - 500 \, \, J

Option 3)

2\times 10^{5}J-3\times 10^{5}J

Option 4)

20,000 \, \, J - 50,000 \, \, J

A particle is projected at 600   to the horizontal with a kinetic energy K. The kinetic energy at the highest point

Option 1)

K/2\,

Option 2)

\; K\;

Option 3)

zero\;

Option 4)

K/4

In the reaction,

2Al_{(s)}+6HCL_{(aq)}\rightarrow 2Al^{3+}\, _{(aq)}+6Cl^{-}\, _{(aq)}+3H_{2(g)}

Option 1)

11.2\, L\, H_{2(g)}  at STP  is produced for every mole HCL_{(aq)}  consumed

Option 2)

6L\, HCl_{(aq)}  is consumed for ever 3L\, H_{2(g)}      produced

Option 3)

33.6 L\, H_{2(g)} is produced regardless of temperature and pressure for every mole Al that reacts

Option 4)

67.2\, L\, H_{2(g)} at STP is produced for every mole Al that reacts .

How many moles of magnesium phosphate, Mg_{3}(PO_{4})_{2} will contain 0.25 mole of oxygen atoms?

Option 1)

0.02

Option 2)

3.125 × 10-2

Option 3)

1.25 × 10-2

Option 4)

2.5 × 10-2

If we consider that 1/6, in place of 1/12, mass of carbon atom is taken to be the relative atomic mass unit, the mass of one mole of a substance will

Option 1)

decrease twice

Option 2)

increase two fold

Option 3)

remain unchanged

Option 4)

be a function of the molecular mass of the substance.

With increase of temperature, which of these changes?

Option 1)

Molality

Option 2)

Weight fraction of solute

Option 3)

Fraction of solute present in water

Option 4)

Mole fraction.

Number of atoms in 558.5 gram Fe (at. wt.of Fe = 55.85 g mol-1) is

Option 1)

twice that in 60 g carbon

Option 2)

6.023 × 1022

Option 3)

half that in 8 g He

Option 4)

558.5 × 6.023 × 1023

A pulley of radius 2 m is rotated about its axis by a force F = (20t - 5t2) newton (where t is measured in seconds) applied tangentially. If the moment of inertia of the pulley about its axis of rotation is 10 kg m2 , the number of rotations made by the pulley before its direction of motion if reversed, is

Option 1)

less than 3

Option 2)

more than 3 but less than 6

Option 3)

more than 6 but less than 9

Option 4)

more than 9

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