NCERT Solutions for Class 6 Maths Chapter 11 Algebra
NCERT Solutions for Class 6 Maths Chapter 11 Algebra: This is a very important branch of mathematics comprising 5 exercises and 27 questions. You will get NCERT Class 6 Maths Solutions of Chapter 11 for these all questions. In this NCERT Solutions for Class 6 maths chapter 11, you will study about algebraic expressions. This chapter of NCERT will give you some basics of algebra. These CBSE NCERT solutions for class 6 maths chapter 11 algebra are very useful in solving many reallife problems using variables. There are many questions in solutions of NCERT for class 6 maths chapter 11 algebra where you will learn to form an equation and solve them. Apart from that, there are some practice questions given at the end of every topic for conceptual clarity. NCERT solutions for class 6 are prepared by expert faculty to clear doubts which will aid you to understand the concepts given in NCERT 6th class maths syllabus. Scroll down to access NCERT solutions for Claas 6 Maths chapter 11.
Also, Check NCERT solutions to get class 6 to 12 solutions for science and maths.
Latest : Trouble with homework? Post your queries of Maths and Science with stepbystep solutions instantly. Ask Mr AL
The main topics of NCERT Solutions for Class 6 Maths Chapter 11 Algebra are
 11.1 Introduction
 11.2 Matchstick Patterns
 11.3 The Idea of a Variable
 11.4 More Matchstick Patterns
 11.5 More Examples of Variables
 11.6 Use of Variables in Common Rules
 11.7 Expressions with Variables
 11.8 Using Expressions Practically
 11.9 What is an Equation?
 11.10 Solution of an Equation
Understanding the concept of variables and equations are mandatory for our higher studies. So solving all the NCERT questions are mandatory. Solve as many questions as possible from this chapter.
NCERT Solutions for Class 6 Maths Chapter 11 exercise 11.1
(a) A pattern of letter T as .
(b) A pattern of letter Z as .
(c) A pattern of letter U as .
(d) A pattern of letter V as .
(e) A pattern of letter E as .
(f) A pattern of letter S as .
(g) A pattern of letter A as .
Answer:
(a) A pattern of letter T as ( because 2 matchsticks are used )
(b) A pattern of letter Z as ( because 3 matchsticks are used )
(c) A pattern of letter U as ( because 3 matchsticks are used )
(d) A pattern of letter V as ( because 2 matchsticks are used )
(e) A pattern of letter E as ( because 5 matchsticks are used )
(f) A pattern of letter S as ( because 5 matchsticks are used )
(g) A pattern of letter A as ( because 6 matchsticks are used )
Answer: Letter "T" and "v" has pattern 2n because 2 matchsticks are used in these two letters.
Answer: Cadets in a row = 5
number of rows = n
Thus, the total number of cadets = 5n
Answer: Mangoes in a box = 50
Number of boxes = b
Thus, the total number of mangoes = 50b
Answer: pencils per student = 5
number of students = s
Thus, the total pencils needed = 5s
Answer: Time taken by bird = t minutes
Speed of bird = 1 km per minute
Thus, distance covered by bird
Answer: Number of rows = r
Number of dots in each row = 9 dots
Thus, the total number of dots = 9r
When the number of rows is 8, then the total number of dots are dots.
When the number of rows is 10, then the total number of dots are dots.
Answer: Radha's age = x years
Thus, age of Leela = (x4) years
Answer: Number of laddus given = l
Number of laddus remaining = 5
Thus,tota number of laddus = (l+5)
Answer: Number of oranges in one box = x
Number of box = 2
So, the total number of oranges = 2x
Remaining number of oranges = 10
Thus, the number of oranges = 2x+10
Answer:
(a) 4 matchsticks
(b) 7 matchsticks
(c) 10 matchsticks
(d) 13 matchsticks
If we remove 1 matchstick from each then it forms a table of 3 i.e.,3,6,9,12,.....
So, required equation = 3x+1 , x= number of squares
Answer:
(a) 3 matchsticks
(b) 5 matchsticks
(c) 7 matchsticks
(d) 9 matchsticks
If we remove 1 matchstick from each then it forms a table of 2 i.e., 2,4,6,8............
So, required equation = 2x+1 , x= number of triangles
NCERT Solutions for Class 6 Maths Chapter 11 exercise 11.2
Question: 1 The side of an equilateral triangle is shown by . Express the perimeter of the equilateral triangle using
Answer: The side of an equilateral triangle is .
Therefore, the perimeter of the equilateral triangle
Answer: The side of a hexagon is l.
Therefore, the perimeter of the hexagon
Answer: Length of one edge of cube = l
Number of edges in a cube = 12
So, total length =
Answer: Length of diameter is double the length of the radius.
Thus,d = 2r
Question: 5 To find sum of three numbers and we can have two ways:
(a) We may first add and to get and then add to it to get the total sum or
(b) We may add and to get and then add to get the sum Thus,
Answer: According to the given condition,
NCERT Solutions for Class 6 Maths Chapter 11 exercise 11.3
Answer: The other expressions are :
(i)
Question: 4(i) Give expressions for the following cases.
Answer:
(a) added to
(b) subtracted from
(c) multiplied by
(d) divided by
(e) subtracted from
(f) multiplied by
(g) divided by
(h) multiplied by
Question: 4(ii) Give expressions for the following cases.
Answer:
(e) subtracted from =
(f) multiplied by
(g) divided by
(h) multiplied by
Question:5(i) Give expressions in the following cases.
(d) times y from which is subtracted
Answer:
(a) added to
(b) subtracted from
c) times y to which is added
(d) times y from which is subtracted
(e) is multiplied by
Question: 5(ii) Give expressions in the following cases.
(f) is multiplied by and then is added to the result
(g) is multiplied by and the result is subtracted from
(h) is multiplied by and the result is added to
Answer:
(f) is multiplied by and then is added to the result=
(g) is multiplied by and the result is subtracted from
(h) is multiplied by and the result is added to
Question: 6 (a) Form expressions using and Use not more than one number operation. Every expression must have in it.
Answer: According to given condition,
Question: 6 (b) Form expressions using and . Every expression must have in it. Use only two number operations. These should be different.
Answer: According to the given condition,
NCERT Solutions for Class 6 Maths Chapter 11 exercise 11.4
Question:1 Answer the following:
(a) Take Sarita’s present age to be years
(i) What will be her age years from now?
(ii) What was her age years back?
(iii) Sarita’s grandfather is times her age. What is the age of her grandfather?
(iv) Grandmother is years younger than grandfather. What is grandmother's age?
(v) Sarita’s father’s age is years more than times Sarita’s age. What is her father's age?
Answer: According to the given condition,
(a) (i)
(ii)
(iii) 6y
(iv)
(v)
Question: 1 (b) The length of a rectangular hall is meters less than times the breadth of the hall. What is the length, if the breadth is meters?
Answer: Breadth = b
And length = (3b4) meters
Answer: Height of box = h cm
Length of box = 5 times height = 5h cm
Breadth of box = 10 cm less than length = (5h10) cm
Question: 1 (d) Meena, Beena and Leena are climbing the steps to the hill top. Meena is at step s, Beena is 8 steps ahead and Leena steps behind. Where are Beena and Meena? The total number of steps to the hilltop is less than times what Meena has reached. Express the total number of steps using
Answer: Meena's position = s
Beena's position = 8 steps ahead = s+8
Leena's position =7 steps behind = s7
Total steps =
Answer: Speed of bus = v km\h
Distance travelled in 5 hours = 5v km
Remaining distance = 20 km
Totsl distance =
(a) A notebook costs ` .A book costs
(b) Tony puts marbles on the table. He has marbles in his box.
(c) Our class has students. The school has students.
(d) Jaggu is years old. His uncle is years old and his aunt is years old.
(e) In an arrangement of dots there are rows. Each row contains dots.
Answer:
(a) A book cost 3 times the cost of a notebook.
(b) The number of marbles in the box is 8 times marbles on the table.
(c) The total number of students in school is 20 times that in our class.
(d) Jaggu's uncle's age is 4 times the age of Jaggu. Jaggu's aunt is 3 years younger than his uncle.
(e) The total number of dots is 5 times the number of rows.
Question: 3 (a) Given Munnu’s age to be years, can you guess what may show? (Hint : Think of Munnu’s younger brother.)
Can you guess what may show? What may show?
Answer:
(a) Munnu's age = x years
Munnu’s younger brother is 2years younger than him = years
Munnu’s elder brother is 4years older than him = years
His father is 7 years more than thrice of his age =
Question: 3 (b) Given Sara’s age today to be y years. Think of her age in the future or in the past. What will the following expression indicate?
Answer:
Her age in past =
Her age in future =
Question: 3 (c) Given students in the class like football, what may show? What may show? (Hint : Think of games other than football).
Answer:
Number of students like hockey is twice the students like football, i.e.,2n
Number of students like tennis is half the students like football, i.e.,
NCERT Solutions for Class 6 Maths Chapter 11 exercise 11.5
Answer: (a) It is an equation of variable as both sides are equal. The variable is x.
Answer: (b) It is not an equation as LHS is greater than RHS.
Answer: (c) It is an equation with no variable. We may call this a numerical equation
Answer: (d) It is an equation with no variable. It is a numerical equation.
Question: 1(e) State which of the following are equations (with a variable). Give reason for your answer. Identify the variable from the equations with a variable.
Answer: (e) It is an equation of variable as both sides are equal. The variable is x.
Answer: (f) It is an equation of variable x.
Answer: (g) It is not an equation because LHS is less than RHS.
Answer: (h) It is an equation of variable as both sides are equal. The variable is n.
Answer: (i) It is an equation with no variable as both sides are equal.
Answer: (j) It is equation of variable p.
Answer: (k) It is an equation of varaible y.
Answer: (l) It is not an equation as LHS is less than RHS.
Answer: (m) It is not an equation as LHS is greater than RHS.
Answer: (n) It is an equation with no variable.
Answer: (o) It is an equation of variable x.
Question: 2 Complete the entries in the third column of the table.
Answer:
S. no.  Equation  Value of variable  Equ.satisfied Yes/No  Sol. of LHS 
(a)  10 y =80  y = 10  No 

(b)  10 y = 80  y = 8  Yes 

(c)  10 y = 80  y = 5  No 

(d)  4l = 20  l = 20  No 

(e)  4l = 20  l = 80  No 

(f)  4l = 20  l =5  Yes 

(g)  b + 5 =9  b = 5  No 

(h)  b + 5=9  b = 9  Yes 

(i)  b+5=9  b = 4  Yes 

(j)  h 8 =5  h =13  Yes 

(k)  h 8 =5  h = 8  No 

(l)  h 8 =5  h = 0  No 

(m)  p+3=1  p = 3  No 

(n)  p+3=1  p = 1  No 

(o)  p+3=1  p = 0  No 

(p)  p+3=1  p = 1  Yes 

(q)  p+3=1  p = 2 
Answer:
(a)
Putting given values in LHS.
m = 10 is not a solution. m = 12 is a solution.
m = 5 is not a solution. m = 15 is not a solution.
(b)
Putting given values in LHS.
n = 12 is not a solution. n = 20 is not a solution.
n = 8 is a solution. n =0 is not a solution.
(c)
Putting given values in LHS.
p =0 is not a solution. p = 10 is a solution.
p = 5 is not a solution. p = 5 is not a solution
(d)
Putting given values in LHS.
q =7 is not a solution. q = 2 is not a solution.
q = 10 is not a solution. q = 14 is a solution.
(e)
Putting given values in LHS.
r =4 is a solution. r = 4 is not a solution.
r = 8 is not a solution. r = 0 is not a solution
(f)
Putting given values in LHS.
x = 2 is a solution. x = 0 is a solution.
x = 2 is not a solution. x = 4 is not a solution
Question: 4 (a) Complete the table and by inspection of the table find the solution to the equation
Answer: (a)
m  1  2  3  4  5  6  7  8  9  10  11  12  13 
m+10  11  12  13  14  15  16  17  18  19  20  21  22  23 
At m = 6, m+10=16
Thus, m =6 is a solution.
Question: 4 (b) Complete the table and by inspection of the table, find the solution to the equation
Answer: (b)
t  3  4  5  6  7  8  9  10  11  12  13  14  15  16 
5t  15  20  25  30  35  40  45  50  55  60  65  70  75  80 
At t=7, 5t = 35
Thus, t = 7 is the solution.
Question: 4 (c) Complete the table and find the solution of the equation using the table.
Answer: (c)
z  8  9  10  11  12  13  14  15  16  17  18  19  20 

 3 

 4 

 5 

 6 


At z = 12 ,
Thus, z= 12 is a solution.
Question: 4 (d) Complete the table and find the solution to the equation
Answer: (d)
m  5  6  7  8  9  10  11  12  13  14  15 
m  7  2  1  0  1  2  3  4  5  6  7  8 
At m=10, m7 = 3
Thus, m=10 is the solution
Question:5 Solve the following riddles, you may yourself construct such riddles.
Answer:
(i) Square has 4 sides.
Counting every corner Thrice and no more!
Implies we go around square thrice,i.e. 12 times.
Add the count to me To get exactly thirty  four!
Let us assume the number as y, we get 34.
12+y=34
So, 22 is the number .
(ii) If 23 is number for Sunday.
Then counting up, Saturday is 22, Friday is 21, Thursday is 20.
Wednesday is 19, Tuesday is 18, Monday is 17 and Sunday is 16.
Therefore, the number considered is 16.
(iii) Let the number be x.
If we take away 6 from x, we get a cricket team.
x  6 = 11
Special number is 17.
(iv) Let the number be x.
22  x = x
22 = 2x
The number is 11.
NCERT Solutions for Class 6 Mathematics Chapter wise
Chapters No.  Chapters Name 
Chapter  1  NCERT Solutions for class 6 maths chapter 1 Knowing Our Numbers 
Chapter  2  
Chapter  3  NCERT solutions for class 6 maths chapter 3 Playing with Numbers 
Chapter  4  NCERT Solutions for class 6 maths chapter 4 Basic Geometrical Ideas 
Chapter  5  NCERT solutions for class 6 maths chapter 5 Understanding Elementary Shapes 
Chapter  6  
Chapter  7  
Chapter  8  
Chapter  9  
Chapter 10  
Chapter 11  NCERT Solutions for class 6 maths chapter 11 Algebra 
Chapter 12  NCERT solutions for class 6 maths chapter 12 Ratio and Proportion 
Chapter 13  
Chapter 14  NCERT Solutions for class 6 maths chapter 14 Practical Geometry 
NCERT Solutions for Class 6  Subject wise
Benefits of NCERT solutions for class 6 maths chapter 11 algebra
 You will learn NCERT class 6 Maths solutions chapter 11 very easily.
 You can develop an algebraic expression of some reallife problems and solve them which you have learnt in this chapter.
 It is going to help you with your homework as you can get detailed explanations of practice questions given at the end of every topic in the CBSE NCERT solutions for class 6 maths chapter 11 algebra.
 You will get some short tricks and tips to solve some specific problems.
 Tip Mathematics required more practice to get conceptual clarity. So, you should solve all the NCERT questions including examples and practice questions on your own.
Happy learning!!!
Latest Articles
IEO Result 20202021  Check SOF IEO Level 1 & 2 Merit List Here
IEO Result 20202021  Science Olympiad Foundation will releas...
Kendriya Vidyalaya Bangalore Admission 2021  Apply Here
Kendriya Vidyalaya Bangalore Admission 2021  Know the admissi...
iOM Result 202021  Check Silverzone iOM Level 1 & 2 Result ...
iOM Result 202021  Silverzone International Olympiad of Mat...
IOEL Result 202021  Check SilverZone IOEL Result Here
IOEL Result 202021  SilverZone Foundation will release the r...
NCO Sample Papers 202021
NCO Sample Papers 202021  The sample papers of National Cybe...
Kendriya Vidyalaya Pune Admission 2021  Check Eligibility, Re...
Kendriya Vidyalaya Pune Admission 2021  Check the admission p...
JAC 9th Syllabus 20202021  Download Jharkhand Board Class 9t...
JAC Cass 9th Syllabus 20202021  Students can download Jharkh...
JAC 11th Syllabus 20202021  Check Jharkhand Board Class 11 S...
JAC 11th Syllabus 20202021  The syllabus of Class 11 JAC for...
Rashtriya Military School Result 2021 Date  Check RMS Result ...
Rashtriya Military School Result 2021  Rashtriya Military Sch...
IOS Result 202021 for Level 1  Check Silverzone iOS Results ...
IOS Result 202021  Silverzone Foundation will release Scienc...