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NCERT Solutions for Class 6 Science Chapter 9 - Methods of Separation in Everyday Life

NCERT Solutions for Class 6 Science Chapter 9 - Methods of Separation in Everyday Life

Edited By Shivani Poonia | Updated on Apr 29, 2025 03:28 PM IST

Ever noticed your elders separating tiny stones or unwanted substances from wheat or rice, separating tea leaves from tea, purifying sandy water, etc. In our daily life, we come across mixtures of various substances and separation becomes essential to remove unwanted substances from useful substances and make them useful. Various techniques are used to separate unwanted substances from useful substances depending upon the types of substances and impurities present in them. Like handpicking is used to separate small stones from rice, winnowing is used to separate lighter impurities like husk from heavier grains, decantation is used to purify a liquid by settling down impurities at the bottom, filtration is used to separate insoluble solid compounds from the liquid.

This Story also Contains
  1. NCERT Solutions for Class 6 Science Chapter 9 - Methods of Separation in Everyday Life (Exercise Question)
  2. NCERT Solutions for Class 6 Science Chapter-wise
  3. NCERT Solutions of Class 6 Science Chapter 9 Methods of Sepration in Everyday Life summary
  4. NCERT Solutions class 6 Subject Wise -Links

NCERT Class 6 Science Chapter 9 ‘Methods of separation in everyday life’ is all about different methods of separating impurities from useful substances, and how different methods are selected to separate impurities substances based on the type of substance and impurities present in them. Methods of separation in everyday life help students to develop analytical and problem-solving skills. This chapter not only just helps them to score good marks in exams but also forms the basis of some advanced chapters and topics that students are going to study in higher classes.

Class 6 NCERT Science Chapter 9 explains the methods of separation used to separate impurities from substances. At the end of this chapter text questions are provided and our subject experts make the detailed solutions of each question in a very comprehensive and systematic way. NCERT Solutions designed by subject experts provide easy-to-understand and comprehensive explanations of every question. These solutions help students to develop analytical and problem-solving abilities. To get the detailed solution of the question scroll down.

NCERT Solutions for Class 6 Science Chapter 9 - Methods of Separation in Everyday Life (Exercise Question)

Q1. What purpose does handpicking serve in the process of separation?

(i) Filtration

(ii) Sorting

(iii) Evaporation

(iv) Decantation

Ans. (ii). Sorting is correct answer

Because handpicking is used to sort or remove unwanted substances.

Q2. Which of the following substances are commonly separated using the churning method?

(i) Oil from water

(ii) Sand from water

(iii) Cream from milk

(iv) Oxygen from air

Ans. (iii). Cream from milk is correct answer

Because when milk is churned the lighter cream is separated from milk

Q3. Which factor is usually essential for the filtration?

(i) Apparatus size

(ii) Presence of air

(iii) Pore size

(iv) Temperature of the mixture

Ans. (iii). Pore size is the correct answer

Because Filtration is used to separate solid from liquid using filter and pore size of the filter paper is most important factor

Q4. State with reason(s) whether the following statements are True [T] or False [F]. Also, correct the False statement(s).

(i) Salt can be separated from salt solution by keeping it under the Sun.

(ii) Handpicking should be used only when the quantity of one component is less.

(iii) A mixture of puffed rice and rice grains can be separated by threshing.

(iv) A mixture of mustard oil and lemon water can be separated by decantation.

(v) Sieving is used to separate a mixture of rice flour and water.

Ans. (i). True

Reason: Salt will left behind after evaporation of water

Ans. (ii). True

Reason: When impurities are less in quantity and can be easily identified then only handpicking is used

Ans. (iii). False

Reason: Threshing is used to separate harvested stalk from grain. Not to separate two types of grains.

Correct statement : A mixture of puffed rice and rice grains can be separated by winnowing.

Ans. (iv). True

Reason : Mustard oil and lemon water do not mix, so they can be separated by decantation

Ans. (v). False

Reason: Because sieving is used to separate solids of different kinds

Correct statement: Filtration is used to separate a mixture of rice flour and water

Q5. Match the mixtures in Column I with their method of separation in Column II.

Column I

Column II

(i). Gram flour mixed with black gram

(a). Handpicking

(ii). Chalk powder mixed with water

(b). Magnetic separation

(iii). Corn mixed with potatoes

( c). Decantation

(iv). Iron powder mixed with sawdust

(d). Sieving

(v). Oil mixed with water

(e). Filtration

Ans.

(i) - (d)

(ii) - (e)

(iii) - (a)

(iv) - (b)

(v) - ( c)

Q6. In what situations would you use decantation instead of fIltration to separate solids from liquids?

Ans. Decantation is used to separate impurities from liquid, meaning when impurities are heavy in solution then after some time these heavy impurities settle down leaving pure liquid and that liquid can be easily separated. Example sand settled down at the bottom of a glass of water.

Q7. Can you relate the presence of nasal hair to any separation process?

Ans. Nasal hairs are like a natural filter that prevents dust particles or other impurities entering into our body through the nose. This process is similar to filtration method, in filtration method filter paper separates solid from liquid.

Q8. During the COVID-19 pandemic, all of us wore masks. Generally, what material are they made of? What is the role of these masks?

Ans. Masks are made up of non-woven fabrics, cotton and polyester. Masks act as protective shields that filter air, pollen and germs entering our body. The role of these masks is to filter air particles, pollens, etc.

Q9. A mixture containing potatoes, salt and sawdust has been given to you. Outline a stepwise procedure for separating each component from this mixture.

Ans. The following steps are given to separate potatoes, salt, and saws and :

  • 1). Handpicking of potatoes
  • 2). To dissolve salt we have to add water as salt is soluble in water and sawdust is not
  • 3). Filter solution to separate sawdust from solution
  • 4). To obtain salt evaporate water

Q10. Read the following story titled ‘Intelligent Leela’ and tick the most appropriate options. Provide a suitable title of your choice for the paragraph.

Leela was working in the farm with her father when she realised that they left their drinking water at home. Before her father felt thirsty/hungry, she went to the nearby pond to fetch some water/grains. After obtaining some water in the container, she noticed that the water was muddy and fit/unfit for drinking. To purify the water, she kept it for some time and then she filtered/ churned the muddy water using a piece of paper/muslin cloth. Leela, then, cooled/boiled the water for about 10 minutes in a covered pan. After cooling/boiling, she filtered/churned it again and made it fit/unfit for drinking. She served this water to her father while having food, who blessed her and appreciated her efforts

Ans.

  1. Thirsty
  2. Water
  3. Unfit
  4. Filtered
  5. Muslin cloth
  6. Boiled
  7. Cooling
  8. Filtered
  9. Fit

NCERT Solutions for Class 6 Science Chapter-wise



NCERT Solutions of Class 6 Science Chapter 9 Methods of Sepration in Everyday Life summary

‘Methods of separation in everyday life’ is all about the methods used to separate different substances. Class 6 Science Chapter 9 Methods of separation in everyday life teach us about how to separate unwanted substances from mixtures to make them usable using different techniques like handpicking, winnowing, filtration, decantation, sewing, evaporation, and the use of magnets. All these techniques are not only just used in the kitchen or classroom but they also form the basis of higher classes like metallurgy in higher classes.

NCERT Solutions class 6 Subject Wise -Links

Also check NCERT book and NCERT Syllabus here :


Frequently Asked Questions (FAQs)

1. What does 'separation of substances' mean? Why is it important?

Separation of substances is the process of isolating individual components from a mixture. It's important because:

  • To remove undesirable or harmful substances.
  • To obtain useful substances in pure form.
  • To study the individual components of a mixture.
  • For various industrial and laboratory applications.
2. What is the difference between a mixture and a pure substance?

pure substance is made up of only one kind of particle (atoms or molecules) and has a fixed composition and properties. Examples: pure water, gold, oxygen. A mixture is made up of two or more different substances that are physically combined, but not chemically bonded. The composition and properties of a mixture can vary. Examples: air, soil, seawater.

3. What determines which method of separation is best to use?

The best method depends on:

  • The nature of the substances in the mixture (solid, liquid, gas).
  • The size of the particles involved.
  • The properties of the substances (e.g., solubility, density, volatility, magnetic properties).
  • The purpose of the separation (e.g., simply removing impurities or isolating a specific compound).

Articles

A block of mass 0.50 kg is moving with a speed of 2.00 ms-1 on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is

Option 1)

0.34\; J

Option 2)

0.16\; J

Option 3)

1.00\; J

Option 4)

0.67\; J

A person trying to lose weight by burning fat lifts a mass of 10 kg upto a height of 1 m 1000 times.  Assume that the potential energy lost each time he lowers the mass is dissipated.  How much fat will he use up considering the work done only when the weight is lifted up ?  Fat supplies 3.8×107 J of energy per kg which is converted to mechanical energy with a 20% efficiency rate.  Take g = 9.8 ms−2 :

Option 1)

2.45×10−3 kg

Option 2)

 6.45×10−3 kg

Option 3)

 9.89×10−3 kg

Option 4)

12.89×10−3 kg

 

An athlete in the olympic games covers a distance of 100 m in 10 s. His kinetic energy can be estimated to be in the range

Option 1)

2,000 \; J - 5,000\; J

Option 2)

200 \, \, J - 500 \, \, J

Option 3)

2\times 10^{5}J-3\times 10^{5}J

Option 4)

20,000 \, \, J - 50,000 \, \, J

A particle is projected at 600   to the horizontal with a kinetic energy K. The kinetic energy at the highest point

Option 1)

K/2\,

Option 2)

\; K\;

Option 3)

zero\;

Option 4)

K/4

In the reaction,

2Al_{(s)}+6HCL_{(aq)}\rightarrow 2Al^{3+}\, _{(aq)}+6Cl^{-}\, _{(aq)}+3H_{2(g)}

Option 1)

11.2\, L\, H_{2(g)}  at STP  is produced for every mole HCL_{(aq)}  consumed

Option 2)

6L\, HCl_{(aq)}  is consumed for ever 3L\, H_{2(g)}      produced

Option 3)

33.6 L\, H_{2(g)} is produced regardless of temperature and pressure for every mole Al that reacts

Option 4)

67.2\, L\, H_{2(g)} at STP is produced for every mole Al that reacts .

How many moles of magnesium phosphate, Mg_{3}(PO_{4})_{2} will contain 0.25 mole of oxygen atoms?

Option 1)

0.02

Option 2)

3.125 × 10-2

Option 3)

1.25 × 10-2

Option 4)

2.5 × 10-2

If we consider that 1/6, in place of 1/12, mass of carbon atom is taken to be the relative atomic mass unit, the mass of one mole of a substance will

Option 1)

decrease twice

Option 2)

increase two fold

Option 3)

remain unchanged

Option 4)

be a function of the molecular mass of the substance.

With increase of temperature, which of these changes?

Option 1)

Molality

Option 2)

Weight fraction of solute

Option 3)

Fraction of solute present in water

Option 4)

Mole fraction.

Number of atoms in 558.5 gram Fe (at. wt.of Fe = 55.85 g mol-1) is

Option 1)

twice that in 60 g carbon

Option 2)

6.023 × 1022

Option 3)

half that in 8 g He

Option 4)

558.5 × 6.023 × 1023

A pulley of radius 2 m is rotated about its axis by a force F = (20t - 5t2) newton (where t is measured in seconds) applied tangentially. If the moment of inertia of the pulley about its axis of rotation is 10 kg m2 , the number of rotations made by the pulley before its direction of motion if reversed, is

Option 1)

less than 3

Option 2)

more than 3 but less than 6

Option 3)

more than 6 but less than 9

Option 4)

more than 9

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