NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers

NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers

Edited By Ramraj Saini | Updated on Nov 29, 2023 12:44 PM IST

NCERT solutions for class 6 maths chapter 2 Whole Numbers provided here that are created by expert team at careers360. These solutions are developed considering the latest syllabus of CBSE. Students looking for NCERT Class 6 solution for Maths chapter 2 pdf can access the solutions for all topics in this article. The Whole Number chapter is a part of the number system unit. Referring to NCERT 6 Maths solution chapter 2 aid to clear doubts and prepare well. CBSE NCERT solutions for whole numbers class 6 are covering the solutions for the questions from every concept of NCERT. Representation and properties of whole numbers are important topics.

Class 6 NCERT Maths solutions of chapter 2 are prepared as per questions available in NCERT Class 6 Syllabus. There are 3 exercises in this chapter containing 38 questions. NCERT Class 6 maths solution chapter 2 contains the answer to all the 38 problems. CBSE NCERT solutions for Class 6 Maths chapter 2 Whole Numbers are answering every problem related to the whole numbers. Along with all these, you can click on the link given to get NCERT Solutions for other classes and subjects.

NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers - Important Formula

  1. Whole numbers: 0, 1, 2, 3, and so on.

  2. A factor of a number is a number that divides the other number without leaving a remainder.

  3. A multiple of a number is a number that is exactly divisible by the given number.

  4. The number 1 is a factor of every number and has only one factor.

  5. Even numbers are those that are divisible by 2, while odd numbers are not divisible by 2.

  6. Divisibility rules:

    • A number is divisible by 2 if its unit digit is 0, 2, 4, 6, or 8.

    • A number is divisible by 3 if the sum of its digits is divisible by 3.

    • A number is divisible by 4 if the digits in its tens and units place are divisible by 4.

    • A number is divisible by 5 if its unit digit is 0 or 5.

    • A number is divisible by 6 if it satisfies the divisibility rules for both 2 and 3.

    • A number is divisible by 8 if the number formed by its hundreds, tens, and units placed is divisible by 8.

    • A number is divisible by 9 if the sum of its digits is divisible by 9.

    • A number is divisible by 10 if its units place digit is 0.

    • A number is divisible by 11 if the difference between the sum of its digits in odd places and the sum of its digits in even places is either 0 or divisible by 11.

  7. The LCM (Least Common Multiple) of two numbers, a and b, is the smallest positive integer that is divisible by both a and b.

  8. The HCF (Highest Common Factor) of two numbers, a and b, is the largest positive integer that divides both a and b.

  9. LCM(A, B) HCF(A, B) = AB

  10. Properties of whole numbers:

  • Closure Property of Addition: a + b is a whole number

  • Closure Property of Multiplication: a × b is a whole number

  • Associativity of Addition:
    (a + b) + c = a + (b + c)

  • Associativity of Multiplication:
    a × (b × c) = (a × b) × c

  • Distributive Property of Multiplication over Addition:
    a × (b + c) = a × b + a × c

  • Distributive Property of Multiplication over Subtraction:
    a × (b - c) = a × b - a × c.

  • Existence of Multiplicative Identity:
    a + 0 = a = 0 + a

  • Existence of Multiplicative Identity:
    a × 0 = 0 = 0 × a

  • Unit Multiplication:
    a × 1 = a = 1 × a

NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers - Important Topics

Natural Numbers: The numbers 1, 2, 3,... which we use for counting are known as natural numbers. Natural numbers represent the set of positive integers starting from 1 and extending infinitely. They are the most basic numbers used for counting and ordering objects.

Successor and Predecessor: If you add 1 to a natural number, we get its successor. If you subtract 1 from a natural number, you get its predecessor. Successor and predecessor are terms used to denote the number that comes after or before a given number in the natural number sequence.

Existence of Successor and Predecessor: Every natural number has a successor, meaning that we can always find the next number in the sequence by adding 1. Every natural number except 1 has a predecessor, which is the number that comes before it in the sequence.

Whole Numbers: If we add the number zero to the collection of natural numbers, we get the collection of whole numbers. Whole numbers include 0 along with the set of natural numbers. Thus, the numbers 0, 1, 2, 3,... form the collection of whole numbers.

Successor and Predecessor of Whole Numbers: Every whole number has a successor, meaning there is always a next number in the sequence. Every whole number except zero has a predecessor, which is the number that comes before it in the sequence.

Relationship between Natural Numbers and Whole Numbers: All natural numbers are whole numbers because they are included in the set of whole numbers. However, all whole numbers are not natural numbers since zero is a whole number but not a natural number.

Number Line Representation: A number line is a line marked with points at equal intervals, starting from 0 and extending in both positive and negative directions. It provides a visual representation of numbers. Natural and whole numbers can be represented on a number line, allowing for easy visualization and operations such as addition, subtraction, and multiplication.

Operations on Number Line: Addition on a number line corresponds to moving to the right, whereas subtraction corresponds to moving to the left. Multiplication corresponds to making jumps of equal distance starting from zero. Number lines aid in understanding and performing these operations.

Closure Property: Adding two whole numbers always gives a whole number. Similarly, multiplying two whole numbers always gives a whole number. This property is known as closure, which means that a particular operation performed on two whole numbers results in another whole number. However, whole numbers are not closed under subtraction and division.

Division by Zero: Division by zero is not defined. It is considered undefined because it leads to contradictory or nonsensical results. Dividing any number by zero is not permissible in mathematics.

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NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers

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NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers (Intext Questions and Exercise)

NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers Topic: Predecessor and Successor

Q1 Write the predecessor and successor of 19; 1997; 12000; 49; 100000.

Answer: The predecessor and successor of:

  • 19:
    • Predecessor : 18
    • Successor : 20
  • 1997:
    • Predecessor : 1996
    • Successor : 1998
  • 12000
    • Predecessor : 11999
    • Successor : 12001
  • 49:
    • Predecessor : 48
    • Successor : 50
  • 100000:
    • Predecessor : 99999
    • Successor : 100001

Q2 Is there any natural number that has no predecessor?

Answer: Every natural number has a predecessor. Although, it is interesting to know that the predecessor of 1 is not a natural number.

Q3 Is there any natural number which has no successor? Is there a last natural number?

Answer: Every natural number has a successor. There is no last natural number. There are infinite natural numbers.

NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers Topic: Whole Numbers

Q1 Are all natural numbers also whole numbers?

Answer: Yes, all the natural numbers are whole numbers. But, all whole numbers are not natural numbers.
Natural numbers = 1, 2, 3, 4, ....

Whole numbers= 1, 2, 3, 4, ....

Q2 Are all whole numbers also natural numbers?

Answer: No, all whole numbers are not natural numbers. 0 is a whole number, but it is not a natural number.

Q3 Which is the greatest whole number?

Answer: There are infinite whole numbers. Hence, there is no greatest whole number. Every whole number you can think of has a successor, which is greater than than the number.

NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers Exercise: 2.1

Q1 Write the next three natural numbers after 10999.

Answer: Given, 10999
The next three natural numbers are:
10999 + 1 = 11000
10999 + 2 = 11001
10999 + 3 = 11002

Q2 Write the three whole numbers occurring just before 10001.

Answer: Given, 10001
Three whole numbers occurring just before are:
11001 - 1 = 10000
11001 - 2 = 9999
11001 - 3 = 9998

Q3 Which is the smallest whole number?

Answer: The smallest whole number is 0. It has no whole number predecessor.

Q4 How many whole numbers are there between 32 and 53?

Answer: Given numbers are: 32 and 53

Number of whole numbers between 32 and 53 = (53-32) - 1 = 21 - 1 = 20

There are 20 whole numbers between 32 and 53

Q5 Write the successor of :
(a) 2440701 (b) 100199 (c) 1099999 (d) 2345670

Answer: The successor of following numbers are:

  • (a) 2440701
    • 2440701+1 = 2440702
  • (b) 100199
    • 100199 +1 = 100200
  • (c) 1099999
    • 1099999+1 = 1100000
  • (d) 2345670
    • 2345670+1 = 2345671

Q6 Write the predecessor of :
(a) 94 (b) 10000 (c) 208090 (d) 7654321

Answer: The predecessor of the following numbers are:

  • (a) 94
    • 94-1=93
  • (b) 10000
    • 10000 -1=9999
  • (c) 208090
    • 208090 -1=208089
  • (d) 7654321
    • 7654321-1=7654320

Q7 In each of the following pairs of numbers, state which whole number is on the left of the other number on the number line. Also write them with the appropriate sign (>, <) between them.
(a) 530, 503 (b) 370, 307 (c) 98765, 56789 (d) 9830415, 10023001

Answer: The number on the left on the number line is smaller than the number that is on the right on the number line.

  • (a) 530, 503
    • 503 is on the left.
    • \therefore 530 > 503
  • (b) 370, 307
    • 307 is on the left.
    • \therefore 370> 307
  • (c) 98765, 56789
    • 56789 is on the left.
    • \therefore 98765> 56789
  • (d) 9830415, 10023001
    • 9830415 is on the left.
    • \therefore 9830415< 10023001

Q8 Which of the following statements are true (T) and which are false (F)?
(a) Zero is the smallest natural number.
(b) 400 is the predecessor of 399.
(c) Zero is the smallest whole number.
(d) 600 is the successor of 599.
(e) All natural numbers are whole numbers.
(f) All whole numbers are natural numbers.
(g) The predecessor of a two-digit number is never a single-digit number.
(h) 1 is the smallest whole number.
(i) The natural number 1 has no predecessor.
(j) The whole number 1 has no predecessor.
(k) The whole number 13 lies between 11 and 12.
(l) The whole number 0 has no predecessor.
(m) The successor of a two-digit number is always a two-digit number

Answer:

(a) Zero is the smallest natural number. - False. 0 is not a natural number.
(b) 400 is the predecessor of 399. - False. 400 is the successor of 399.
(c) Zero is the smallest whole number. - True.
(d) 600 is the successor of 599. - True
(e) All natural numbers are the whole numbers.- True.
(f) All whole numbers are natural numbers.- False. 0 is a whole number but not a natural number.
(g) The predecessor of a two-digit number is never a single-digit number.- False. The predecessor of 10 is 9.
(h) 1 is the smallest whole number. - False. 0 is the smallest whole number.
(i) The natural number 1 has no predecessor. - True.
(j) The whole number 1 has no predecessor. - False. The whole number 1 has 0 as its predecessor.
(k) The whole number 13 lies between 11 and 12.- False. The whole number 13 lies on the right side of 12 on the number line.
(l) The whole number 0 has no predecessor.- True.
(m) The successor of a two-digit number is always a two-digit number- False. The successor of 99 is 100.

NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers Topic: Properties of Whole Numbers

Q Find : 7 + 18 + 13; 16 + 12 + 4.

Answer: 7 + 18 + 13; 16 + 12 + 4

NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers Exercise: 2.2

Q1 Find the sum by suitable rearrangement:
(a) 837 + 208 + 363 (b) 1962 + 453 + 1538 + 647

Answer: Sum by suitable rearrangement:

  • (a) 837 + 208 + 363
    837 + 208 + 363 =837 + 363+ 208
    = (837 + 363)+ 208
    = 1200 + 208
    = 1408
  • (b) 1962 + 453 + 1538 + 647
    1962 + 453 + 1538 + 647 = 1962+ 1538 + 453 + 647
    = (1962+ 1538) + (453 + 647)
    = 3500 + 1100
    = 4600

Q3 Find the value of the following:
(a) 297 × 17 + 297 × 3 (b) 54279 × 92 + 8 × 54279
(c) 81265 × 169 – 81265 × 69 (d) 3845 × 5 × 782 + 769 × 25 × 218

Answer:

  • (a) 297 \times 17 + 297 \times 3
    Using Distributive law.
    \\ = 297 \times (17 +3) \\ = 297 \times 20 \\ = 5940
  • (b) 54279 \times 92 + 8 \times 54279
    Using Commutative under multiplication
    54279 \times 92 + 54279 \times 8
    Using Distributive law.
    \\ = 54279 \times( 92 +8) \\ = 54279 \times 100 \\ = 5427900
  • (c) 81265 \times 169 - 81265 \times 69
    Using Distributive law.
    \\ = 81265 \times (169 - 69) \\ = 81265 \times 100 \\ = 8126500
  • (d) 3845 \times 5 \times 782 + 769 \times 25 \times 218
    \\ = (3845 \times 5) \times 782 + (769 \times 25) \times 218 \\ = 19225 \times 782 + 19225\times 218
    Using distributive law.
    \\ = 19225 \times( 782 + 218) \\ = 19225 \times1000 \\ = 19225000

Q4 Find the product using suitable properties.
(a) 738 × 103 (b) 854 × 102
(c) 258 × 1008 (d) 1005 × 168

Answer: The product of the folllowing using suitable properties are:

  • (a) 738 \times 103
    \\ = 738 \times (100+3)
    Using distributive law.
    \\ = 738 \times 100+738 \times3 \\ = 73800+2214 \\ = 76014
  • (b) 854 \times 102
    \\ = 854 \times (100+2)
    Using distributive law.
    \\ = 854 \times 100+854 \times 2 \\ = 85400+1708 \\ = 87108
  • (c) 258 \times 1008
    \\ = 258 \times (1000+8)
    Using Distributive law.
    \\ = 258 \times 1000+258 \times8 \\ = 258000+2064 \\ = 260064
  • (d) 1005 \times 168
    \\ = (1000+5) \times 168
    Using Distributive law.
    \\ = 1000\times 168+5 \times 168 \\ = 168000+840 \\ = 168840

Q5 A taxidriver filled his car petrol tank with 40 litres of petrol on Monday. The next day, he filled the tank with 50 litres of petrol. If the petrol costs rupees 44 per litre, how much did he spend in all on petrol?

Answer: Amount of petrol filled on Monday = 40\ litres
Amount of petrol filled on Tuesday = 40\ litres
\therefore Total amount of petrol = (40+40)\ litres = 80\ litres
Cost of 1 litre of petrol = Rs.\ 44
\therefore Cost of 80\ litres of petrol = Rs.\ (44\times80)
= Rs.\ 3520

Q6 A vendor supplies 32 litres of milk to a hotel in the morning and 68 litres of milk in the evening. If the milk costs rupees 45 per litre, how much money is due to the vendor per day?

Answer: Amount of milk supplied in the morning = 32\ litres
Amount of milk supplied in the evening = 68\ litres
\therefore Total amount of petrol = (32+68)\ litres = 100\ litres
Cost of 1 litre of milk = Rs.\ 45
\therefore Cost of 100\ litres of milk = Rs.\ (45\times100)
= Rs.\ 4500

NCERT solutions for class 6 maths chapter 2 Whole Numbers Topic: Patterns in Whole Numbers

Q1 Which numbers can be shown only as a line?

Answer: 1,5,7,11,13 can be shown only as a line. They cannot be shown as a rectangle or square or triangle.

Q2 Which can be shown as squares?

Answer: 4 and 9 can be shown as squares.
4: 2 rows and 2 columns.
9: 3 rows and 3 columns

Q3 Which can be shown as rectangles?

Answer: 4, 6, 8,10, 12 can be shown as rectangles. (Note: We are not counting squares as rectangles here)

Q5 Some numbers can be shown by two rectangles, for example


Give at least five other such examples.

Answer: We can represent a number by two rectangles. for example 12 = 3 x 4 or 2 x 6

five other such examples are :

  • 24 = 12 x 2 or 24 = 6 x 4
  • 18 = 9 x 2 or 18 = 3 x 6
  • 15 = 15 x 1 or 15 = 3 x 5
  • 30 = 10 x 3 or 30 = 5 x 6
  • 40 = 10 x 4 or 40 = 5 x 8.

NCERT solutions for class 6 maths chapter 2 Whole Numbers Exercise: 2.3

Q1 Which of the following will not represent zero:
(a) 1 + 0 (b) 0 × 0 (c) 0/ 2 (d) (10-10)/2

Answer:

  • (a) 1 + 0
    It does not represent zero.
  • (b) 0 × 0
    It represents zero.
  • (c) \frac{0}{2}=0
    It represents zero.
  • (d) \frac{10-10}{2}=0
    It represents zero.

Q2 If the product of two whole numbers is zero, can we say that one or both of them will be zero? Justify through examples.

Answer: If the product of 2 whole numbers is zero, then one of them is definitely zero.
For example, 0 x 2 = 0 and 17 x 0 = 0
If the product of 2 whole numbers is zero, then both of them may be zero.
0 x 0 = 0
However, 2 x 3 = 6 (Since numbers to be multiplied are not equal to zero, the result of the product will also be non-zero.)

Q3 If the product of two whole numbers is 1, can we say that one or both of them will be 1? Justify through examples.

Answer: If the product of 2 numbers is 1, then both the numbers have to equal to 1.
For example, 1 x 1 = 1
However, 1 x 6 = 6
Clearly, the product of two whole numbers will be 1 in the situation when both numbers to be multiplied are 1.

Q4 Find using distributive property :
(a) 728 \times 101 (b) 5437 \times 1001 (c) 824 \times 25 (d) 4275 \times 125 (e) 504 \times 35

Answer:

  • (a) 728 \times 101= 728 \times (100 + 1)
    • = 728 \times 100 + 728 \times 1
    • = 72800 + 728
    • = 73528
  • (b) 5437 \times 1001 = 5437 \times (1000 + 1)
    • = 5437 \times 1000 + 5437 \times 1
    • = 5437000 + 5437
    • = 5442437
  • (c) 824 \times 25 (800 + 24) \times 25 = (800 + 25 - 1) 25
    • =800 \times 25+25 x 25-1 \times 25
    • = 20000 + 625 - 25
    • = 20000 + 600
    • = 20600
  • (d) 4275 \times 125 = (4000 + 200 + 100 - 25) \times 125
    • = 4000 \times 125 + 200 \times 125 + 100 \times 125 - 25 \times 125
    • = 500000 + 25000 + 12500 - 3125
    • = 534375
  • (e) 504 \times 35 = (500 + 4) \times 35
    • = 500 x 35 +4 \times 35
    • = 17500 + 140
    • = 17640

Q5 Study the pattern :
1 \times 8 + 1 = 9 1234 \times 8 + 4 = 9876
12 \times 8 + 2 = 98 12345 \times 8 + 5 = 98765
123 \times 8 + 3 = 987
Write the next two steps. Can you say how the pattern works?
(Hint: 12345 = 11111 + 1111 + 111 + 11 + 1).

Answer: 123456 \times 8 + 6 = 987648 + 6 = 987654
1234567 \times 8 + 7 = 9876536 + 7 = 9876543
Yes, the pattern works.
As 123456 = 111111 + 11111 + 1111 + 111 + 11 + 1,
123456 \times 8 = (111111 + 11111 + 1111 + 111 + 11 + 1) \times 8
= 111111 \times 8 + 11111 \times 8 + 1111 \times 8 + 111 \times 8 + 11 \times 8 + 1 \times 8
= 888888 + 88888 + 8888 + 888 + 88 + 8
= 987648
And,
123456 \times 8 + 6 = 987648 + 6 = 987648

NCERT Solutions for Class 6 Subject wise

NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers - Topics

2.1 Identities and Special Properties of Whole Numbers.

2.2 Introduction to Whole Numbers.

2.3 Patterns in Whole Numbers.

2.4 Properties of Whole Numbers.

NCERT Solutions for Class 6 Mathematics Chapter wise

Chapters No.

Chapters Name

Chapter - 1

Knowing Our Numbers

Chapter - 2

Whole Numbers

Chapter - 3

Playing with Numbers

Chapter - 4

Basic Geometrical Ideas

Chapter - 5

Understanding Elementary Shapes

Chapter - 6

Integers

Chapter - 7

Fractions

Chapter - 8

Decimals

Chapter - 9

Data Handling

Chapter -10

Mensuration

Chapter -11

Algebra

Chapter -12

Ratio and Proportion

Chapter -13

Symmetry

Chapter -14

Practical Geometry

Key Features Of NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers

Comprehensive Coverage: The class 6 chapter 2 provides comprehensive coverage of the topic of whole numbers, ensuring that all important concepts and subtopics are included. It covers the definition of whole numbers, their properties, representation on a number line, and operations such as addition, subtraction, and multiplication.

Conceptual Clarity: The chapter focuses on providing conceptual clarity to students. It explains the fundamental concepts of whole numbers in a clear and concise manner, enabling students to grasp the underlying principles and theories effectively.

Problem-solving Approach: The chapter adopts a problem-solving approach, offering numerous examples and practice exercises to reinforce understanding. It encourages students to apply the concepts learned to solve real-life problems and mathematical problems related to whole numbers.

Step-by-step Solutions: The chapter provides step-by-step solutions to exercises and examples, guiding students in the correct approach to solving problems. This systematic approach assists students in understanding the process of solving mathematical problems related to whole numbers.

Practice Exercises: The chapter includes a variety of practice exercises, ranging from basic to challenging, to reinforce the understanding of whole numbers. These exercises allow students to practice and apply their knowledge, enabling them to develop proficiency in working with whole numbers.

Also Check -

NCERT Books and NCERT Syllabus

Keep Working hard and happy learning!

Frequently Asked Questions (FAQs)

1. What are the topic covered in NCERT Class 6 Maths Chapter 2

The following topics are covered in the NCERT syllabus Class 6 Maths chapter 2

  • Whole Numbers
  • The Number Line
  • Properties Of Whole Numbers
  • Patterns in Whole Numbers

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Option 1)

0.34\; J

Option 2)

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Option 3)

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Option 4)

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2.45×10−3 kg

Option 2)

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12.89×10−3 kg

 

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2,000 \; J - 5,000\; J

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Option 3)

2\times 10^{5}J-3\times 10^{5}J

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K/2\,

Option 2)

\; K\;

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zero\;

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2Al_{(s)}+6HCL_{(aq)}\rightarrow 2Al^{3+}\, _{(aq)}+6Cl^{-}\, _{(aq)}+3H_{2(g)}

Option 1)

11.2\, L\, H_{2(g)}  at STP  is produced for every mole HCL_{(aq)}  consumed

Option 2)

6L\, HCl_{(aq)}  is consumed for ever 3L\, H_{2(g)}      produced

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Option 1)

0.02

Option 2)

3.125 × 10-2

Option 3)

1.25 × 10-2

Option 4)

2.5 × 10-2

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decrease twice

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increase two fold

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Option 1)

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twice that in 60 g carbon

Option 2)

6.023 × 1022

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less than 3

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more than 3 but less than 6

Option 3)

more than 6 but less than 9

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more than 9

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