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NCERT Solutions for Class 6 Maths Chapter 8 Decimals are discussed here. Subject matter at Careers360 has created detailed solutions considering the latest syllabus of CBSE 2023. Students can check detailed NCERT Class 6 Maths solutions for chapter 8 in this article. There are many questions in the Class 6 solutions of NCERT Maths chapter 8 which will give more clarity to the concepts. In this NCERT 6 Maths solutions chapter 8 students will study about addition and subtraction of decimal numbers and other concepts.
There are 38 questions in 6 exercises of this chapter of NCERT. You will get detailed explanations of these questions in the CBSE NCERT solutions for Class 6 Maths chapter 8. Referring to NCERT Class 6 Maths solutions of chapter 8 helps to understand the chapters of NCERT Class 6 Syllabus in a more easy way. Topic-wise and exercise-wise solved questions are available below in the NCERT solutions for Class 6 Maths chapter 8 Decimals. You can also access NCERT Solutions for all Classes.
Tenths = 1/10
Hundredths = 1/100
The decimal point is moved to the left by the number of zeros in the denominator
For example 150/100 = 1.5 (shifting decimal point by 2 points to left)
For more, Download Ebook - NCERT Class 6 Maths: Chapterwise Important Formulas And Points
Every decimal can be written as a fraction: Decimals can be expressed as fractions, where the decimal part is written as the numerator and the place value of the decimal determines the denominator. For example, 0.5 can be written as 5/10 or 1/2.
Comparing decimal numbers: Decimal numbers can be compared by starting with the whole part. If the whole parts are equal, then the tenth parts can be compared, followed by the hundredth parts, and so on. By comparing the place values, you can determine which decimal number is greater or smaller.
Use of decimals: Decimals are used in various real-life situations, including money transactions, measurements, scores in sports, and scientific calculations. They provide a more precise representation of values compared to whole numbers.
Free download NCERT Solutions for Class 6 Maths Chapter 8 Decimals for CBSE Exam
Hundreds (100) | Tens (10) | Ones (1) | Tenths
|
5 | 3 | 8 | 1 |
2 | 7 | 3 | 4 |
3 | 5 | 4 | 6 |
Answer: Yes, we can write to them in Decimal form. The Numbers in the decimal forms are:
Question: 1 Write in decimal notation.
Answer: The number in decimal forms are:
Question: 1 Write the following as numbers in the given table.
Answer: Observing from the figure, we get
Hundreds (100) | Tens (10) | Ones (1) | Tenths
|
a) 0 | 3 | 1 | 2 |
b) 1 | 1 | 0 | 4 |
Question: 2 Write the following decimals in the place value table.
(a) (b) (c) (d)
Answer: The Value table of the numbers are:
Number | Hundreds | Tens | Ones | Tenths |
19.3 | 0 | 1 | 9 | 3 |
0.3 | 0 | 0 | 0 | 3 |
10.6 | 0 | 1 | 0 | 6 |
205.9 | 2 | 0 | 5 | 9 |
Question: 3 Write each of the following as decimals :
(a) Seven-tenths (b) Two tens and nine-tenths
(c) Fourteen point six (d) One hundred and two ones
(e) Six hundred point eight
Answer:
Question: 4 Write each of the following as decimals:
(a) (b) (c) (d)
(e) (f) (g) (h) (i) (j) (k)
Answer: As we know when we divide a number by 10, the result is that number with a decimal after one digit,(we count the digit from right to left). So Keeping that in mind,
Question: 5 Write the following decimals as fractions. Reduce the fractions to lowest form.
(a) (b) (c) (d) (e) (f) (g)
Answer: Converting Decimals into Fractions. we get
Question: 6 Express the following as cm using decimals.
(a) 2 mm (b) 30 mm (c) 116 mm (d) 4 cm 2 mm (e) 162 mm (f) 83 mm
Answer: As we know
1 cm = 10 mm
1 mm = 0.1 cm
So,
(a) 2 mm
(b) 30 mm
(c) 116 mm
(d) 4 cm 2 mm
(e) 162 mm
(f) 83 mm
(a) (b) (c) (d) (e) (f)
Answer:
Question: 8 Show the following numbers on the number line.
(a) (b) (c) (d)
Answer: The numbers on the number line are:
(a) (b) (c) (d)
Question: 9 Write the decimal number represented by the points A, B, C, D on the given number line.
Answer: As we can see the points lies in the number line,
Question: 10 (a) The length of Ramesh’s notebook is 9 cm 5 mm. What will be its length in cm?
Answer: length of Ramesh’s notebook = 9 cm 5 mm
As we know,
So Length in the unit of cm :
Hence the Length of Ramesh's notebook is 9.5 cm.
Question: 10 (b) The length of a young gram plant is 65 mm. Express its length in cm.
Answer: length of a young gram plant is 65 mm
As we know,
So,
So Length of young gram plant is 6.5 cm.
Question:1 Complete the table with the help of these boxes and use decimals to write the number.
Ones | Tenths | Hundredsths | Number | |
(a) | ||||
(b) | ||||
(c) |
Answer:
Ones | Tenths | Hundredths | Number | |
(a) | 0 | 2 | 6 | 0.26 |
(b) | 1 | 3 | 8 | 1.38 |
(c) | 1 | 2 | 8 | 1.28 |
Question:2 Write the numbers given in the following place value table in decimal form.
Hundreds 100 | Tens 10 | Ones 1 | Tenths | Hundredths | Thousands | |
(a) (b) (c) (d) (e) | 0 1 0 2 0 | 0 0 3 1 1 | 3 2 0 1 2 | 2 6 0 9 2 | 5 3 2 0 4 | 0 0 5 2 1 |
Answer: As we can see from the table, the numbers are:
(a)
(b)
(c)
(d)
(e)
Question: 3 Write the following decimals in the place value table.
(a) (b) (c) (d) (e)
Answer:
(a)
(b)
(c)
(d)
(e)
So, the table becomes:
Hundreds | Tens | Ones | Tenths | Hundredths | Thousands |
0 | 0 | 0 | 2 | 9 | 0 |
0 | 0 | 2 | 0 | 8 | 0 |
0 | 1 | 9 | 6 | 0 | 0 |
1 | 4 | 8 | 3 | 2 | 0 |
2 | 0 | 0 | 8 | 1 | 2 |
Question: 4 Write each of the following as decimals.
(a) (b) (c)
(d) (e)
Answer:
Writing the number in a decimal form:
(a)
(b)
(c)
(d)
(e)
Question: 5 Write each of the following decimals in words.
(a) (b) (c) (d) (e) (f)
Answer: As we know After decimal, we call one digit at a time.
Question:6 Between which two numbers in tenths place on the number line does each of the given number lies?
(a) (b) (c) (d) (e) (f)
Answer: Here, we have a zoomed version of the number line in which the interval between two number is 0.1 instead of 1 which we use normally. So,
Question:7 Write as fractions in lowest terms.
(a) (b) (c) (d) (e) (f) (g)
Answer: The Numbers in the lowest form of the fraction are:
(a)
(b)
(c)
(d)
(e)
(f)
(g)
Question: 1 Which is greater? (a) or (b) or (c) or (d) or (e) or (f) or
(g) or (h) or (i) or (j) or
Answer: We compare Decimals just like the way we compare normal numbers. First, we see the leftmost digit of the numbers and if they are same then we move toward the right digits. So,
(a) or
0.4 is greater as while number part (the number before the decimal) is the same.
(b) or
0.07 is greater
(c) or
3 is greater as the whole part of the numbers are 3 and 0.so obviously 3 is greater than 0.
(d) or
0.5 is greater
(e) or
1.23 is greater
(f) or
0.19 is greater
(g) or
As we know that after the decimal, we can add as many zeros as we want in the rightmost to the numbers just like we can add zeroes to the left side of any whole number. this we can do because those zeroes do not carry any value so they don't affect the numbers.
So. They both are the same number.
(h) or
1.490 is greater
(i) or
As we know in decimal the RIGHTMOST zeros don't carry any value.so,
They both are the same number
(j) or
5.64 is greater.
Question:2 Make five more examples and find the greater number from them.
Answer: we can take any two number from the number line and compare them. For example,
1) 9.9 > 3.3
2) 6.6 < 9.9
3) 3.6 > 3.3
4) 9.6 < 9.9
5) 6.9 > 3.9
Question:(i) Write 2 rupees 5 paise and 2 rupees 50 paise in decimals.
Answer: As we know that
1 rupee = 100 paise
So
2 rupees 5 paise :
and 2 rupees 50 paise:
Question:(ii) Write 20 rupees 7 paise and 21 rupees 75 paise in decimals?
Answer: As we know that
1 rupee = 100 paise
So
20 rupees 7 paise:
and 21 rupees 75 paise:
Question:1 Can you write 4 mm in ‘cm’ using decimals?
Answer: As we know,
1 cm = 10 mm
So,
.
Question:2 How will you write 7cm 5 mm in ‘cm’ using decimals?
Answer: As we know,
1 cm = 10 mm
So,
7cm 5 mm :
.
Answer: As we know,
1 km = 1000 m
So,
52 m in km :
340 m in km :
2008 m in km :
Question:1 Can you now write 456 g as ‘kg’ using decimals?
Answer: As we know,
1 kg = 1000 g
So,
456 g in kg:
Question:2 How will you write 2 kg 9 g in ‘kg’ using decimals?
Answer: As we know,
1 kg = 1000 g
So,
2 kg 9 g in kg:
Question:1 Express as rupees using decimals.
(a) 5 paise (b) 75 paise (c) 20 paise (d) 50 rupees 90 paise (e) 725 paise
Answer: As we know,
1 rupee = 100 paise
So
(a) 5 paise
(b) 75 paise
(c) 20 paise
(d) 50 rupees 90 paise
(e) 725 paise
Question:2 Express as meters using decimals.
(a) 15 cm (b) 6 cm (c) 2 m 45 cm (d) 9 m 7 cm (e) 419 cm
Answer: As we know,
1 m = 100 cm
Which means
.
So,
(a) 15 cm
(b) 6 cm
(c) 2 m 45 cm
(d) 9 m 7 cm
(e) 419 cm
Question:3 Express as cm using decimals.
(a) 5 mm (b) 60 mm (c) 164 mm (d) 9 cm 8 mm (e) 93 mm
Answer: As we know,
1 cm = 10 mm
which means
So,
(a) 5 mm :
(b) 60 mm
(c) 164 mm
(d) 9 cm 8 mm
(e) 93 mm
Question:4 Express as km using decimals.
(a) 8 m (b) 88 m (c) 8888 m (d) 70 km 5 m
Answer: As we know,
1 km = 1000 m
which means
So,
(a) 8 m
(b) 88 m
(c) 8888 m
(d) 70 km 5 m
Question:5 Express as kg using decimals.
(a) 2 g (b) 100 g (c) 3750 g
(d) 5 kg 8 g (e) 26 kg 50 g
Answer: As we know,
1 kg = 1000 g
which means
So,
(a) 2 g
(b) 100 g
(c) 3750 g
(d) 5 kg 8 g
(e) 26 kg 50 g
Question:(i) Find
Answer: As we know that the decimal addition is exactly like normal addition and we don't change the position of decimal in the number.
So,
Hence
Question:(ii) Find
Answer: As we know that the decimal addition is exactly like normal addition and we don't change the position of decimal in the number.
So,
Hence,
Question:(iii) Find
Answer: As we know that the decimal addition is exactly like normal addition and we don't change the position of decimal in the number.
So,
.
Question:(iv) Find
Answer: As we know that decimal addition is exactly like normal addition and we don't change the position of decimal in the number.
So,
(a)
(b)
(c)
(d)
(e)
(f)
Answer: As we know that the decimal addition is exactly like normal addition and we don't change the position of decimal in the number.
So,
(a)
(b)
(c)
(d)
(e)
(f)
Question: 2 Rashid spent Rs for Maths book and Rs for Science book. Find the total amount spent by Rashid.
Answer:
Amount spend on maths book = Rs
Amount spend on science book = Rs
Total amount spend = Rs Rs
= Rs
Hence the total amount spends by Rashid is Rs 68.35.
Answer:
The amount Radhika got from mother = Rs
The amount Radhika got from father = Rs
Total amount Radhika have = Rs Rs
= Rs
Hence the total amount of money Radhika got from her parents is Rs 26.30.
Answer:
Length of cloth for shirt = 3 m 20 cm
Length of cloth for trouser = 2 m 5 cm
As we know.
For adding two numbers their unit must be the same.
So making length in meter:
and
Now,
Total Length of the cloth = 3.2 m + 2.05 m
= 5.25 m
Hence Nasreen bought clothe with a length of 5.25 m.
Answer:
The distance covered in the morning = 2 km 35 m
The distance covered in the evening = 1 km 7 m
As we know.
For adding two numbers their unit must be the same.
So Lengths in the Kilometer :
And
Now,
Total Distance covered by Naresh = 2.035 km + 1.007 km
= 3.042 km
Hence the distance covered by Naresh is 3.042 km.
Answer:
The distance travelled by bus = 15 km 268 m
The distance travelled by car = 7 km 7 m
The distance travelled by foot = 500 m
As we know.
For adding two numbers their unit must be the same.
So,
Also
And,
So,
The total distance Sunita traveled = 15.268 km + 7.007 km + 0.5 km
= 22.775 km
Hence the distance between Sunita's residence and school is 22.775 km.
Answer:
amount of rice purchased by Ravi = 5 kg 400 g.
amount of sugar purchased by Ravi = 2 kg 20 g.
amount of flour purchased by Ravi = 10 kg 850 g.
As we know.
For adding two numbers their unit must be the same.
So,
Also,
And,
So,
The total weight of the grain Ravi purchased = 5.4 kg + 2.002 kg + 10.85 kg
= 18.270 kg
Hence Ravi purchased total grain having the weight of 18.270 kg.
Answer: As we know, subtraction in decimal works exactly like normal subtraction, we just have to maintain the place of decimal.
So
Question:2 Subtract from
Answer: As we know, subtraction in decimal works exactly like normal subtraction, we just have to maintain the place of decimal.
So
Question:3 Subtract from
Answer: As we know, subtraction in decimal works exactly like normal subtraction, we just have to maintain the place of decimal.
So
Question: 4 Subtract from
Answer: As we know, subtraction in decimal works exactly like normal subtraction, we just have to maintain the place of decimal.
So
Question: 1 Subtract :
(a) Rs from Rs
(b) m from 250 m
(c) Rs from Rs
(d) km from km
(e) kg from kg
Answer: As we know, subtraction in decimal works exactly like normal subtraction, we just have to maintain the place of decimal.
So
(a) Rs from Rs
Rs
(b) m from 250 m\
m
(c)Rs from Rs
Rs
(d ) km from km
km
(e) kg from kg
kg
Question: 2 Find the value of :
(a)
(b)
(c)
(d)
Answer: As we know, subtraction in decimal works exactly like normal subtraction, we just have to maintain the place of decimal.
So
(a)
(b)
(c)
(d)
Answer: Total money Raju gave to shopkeeper = Rs 50
The price of the book = Rs 35.65
Money shopkeeper will return Raju = Rs 50.00 - Rs 35.65
= Rs 14.35
Hence Raju got 14.35 Rs from the shopkeeper.
Question: 4 Rani had Rs . She bought one ice-cream for Rs . How much money does she have now?
Answer: Total Money Rani had = Rs 18.50
The money she spent on ice-cream = 11.75
The Remaining money Rani have = Rs 18.50 - Rs 11.75
= Rs 6.75
Hence Rani has 6.75 Rs now.
Answer: Length of cloth initially = 20 m 5 cm = 20.05 m
Length of cloth Tina cuts = 4 m 50 cm = 4.50 m
The length of remaining cloth = 20.05 m - 4.50 m
= 15.55 m
= 15 m 55 cm
Hence the length of remaining cloth Tina have is 15 m 55 cm.
Answer: Total distance travelled by Namita = 20 km 50 m = 20.05 km
The distance travelled by bus = 10 km 200 m = 10.20 km
The remaining distance which is traveled by auto = 20.05 km - 10.20 km
= 9.850 km.
Hence the distance travelled by Namita in auto is 9.850 km.
Answer: Total weight of the vegetables = 10 kg
weight of onion = 3 kg 500 g = 3.5 kg
weight of tomato = 2 kg 75 g = 2.075 kg
Total weight of onion and potato = 3.5 kg + 2.075 kg
= 5.575 kg
So, The rest weight of potato = 10 kg - 5.575 kg
= 4.425 kg
Hence, the weight of the potato is 4.425 kg.
Chapters No. | Chapters Name |
Chapter - 1 | |
Chapter - 2 | |
Chapter - 3 | |
Chapter - 4 | |
Chapter - 5 | |
Chapter - 6 | |
Chapter - 7 | |
Chapter - 8 | Decimals |
Chapter - 9 | |
Chapter -10 | |
Chapter -11 | |
Chapter -12 | |
Chapter -13 | |
Chapter -14 |
Some important findings from the NCERT solutions for Class 6 Maths chapter 8 Decimals which will be useful in real life too are listed below.
Converting a quantity from one unit to another-
.
Tip- You don't have to remember these units conversion. If you know the value of the quantity in one unit and other units, you can convert it very easily. In CBSE NCERT solutions for class 6 maths chapter 8 decimals, you will find many unit conversion questions that will further strengthen your fundamentals.
Happy Reading !!!
Also Check NCERT Books and NCERT Syllabus here:
The Topics are covered In NCERT given below
Decimal numbers are used to represent numbers smaller than 1. The decimal point or period separates the whole number part from the fractional part in a decimal number. Each digit in a decimal number has a place value, which represents its value based on its position in the number. These concepts are important for exams, and you can find detailed explanations in the NCERT Class 6 Maths Solutions available in PDF format.
Yes, the NCERT Solutions for class 6 chapter 8 maths will indeed help students understand important concepts from an exam perspective. The solutions provide step-by-step explanations and examples that can assist students in grasping the expansion procedure and solving problems effectively. By practicing with the solutions PDF, students can become proficient in solving equations and achieve better scores in exams.
In decimals, a terminating decimal has a finite number of digits after the decimal point, and its value comes to an end. On the other hand, a recurring decimal keeps repeating the same sequence of digits infinitely after the decimal point. These concepts may appear in the question paper during the annual exam, and to solve them easily, students can refer to the NCERT Solutions and aim for good marks.
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