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NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers are discussed here in detailed. These NCERT solutions are created as per the latest syllabus and pattern of the CBSE considering the need of the students. Numbers are very important for real life as well as for Mathematics. In NCERT textbook for Class 6 chapter 1, students can learn Indian arrangement of numeration, the universal arrangement of numeration, learn large numbers up to 1 crore (10000000), estimation of large numbers and roman numerals. CBSE NCERT Solutions for Class 6 Maths are covering the solutions for the problems from all the concepts. In NCERT Solutions for Class 6 Math chapter 1, there is a total of 19 questions in 3 exercises.
NCERT 6th Class solutions are covering all the answers or solutions in a very comprehensive manner. CBSE NCERT solutions for Class 6 Maths chapter 1 also provides assistance in solving the practice problems. Along with NCERT Class 6 Maths solutions, students can check the NCERT solutions for other subjects prepared based on NCERT syllabus.
Natural numbers: 1, 2, 3, 4, and so forth.
Sum of first n natural numbers = n(n+1)/2
A number is formed by combining digits, which can only be 0, 1, 2, 3, 4, 5, 6, 7, 8, or 9.
Place Value of a digit in a number = Face Value × Position Value
When comparing two numbers, the one with more digits is always greater. If two numbers have the same digit, the comparison starts from the leftmost digit.
To create the smallest number, begin with 1 in the leftmost position and add zeroes. For instance, the smallest four-digit number is 1000.
To create the largest number, start with 9 in the leftmost position. For example, the largest four-digit number is 9999.
There are specific quantity weights for conversions, such as:
1 kilometre (km) = 1000 metres (m)
1 metre (m) = 100 centimetres (cm)
1 centimetre (cm) = 10 millimetres (mm)
1 kilogram (kg) = 1000 grams (gm)
1 litre (l) = 1000 millilitres (ml)
Roman numerals are another system of representation, where each symbol corresponds to a specific value:
I – 1
II – 2
V – 5
X – 10
L – 50
C – 100
D – 500
K – 1000
In Roman numerals, you can perform subtraction or addition by placing the desired quantity to the left or right. For example, 21 can be written as XXI, and 49 can be written as ILIX.
Place Value: Place value refers to the value of a digit based on its position in a number. It helps understand the significance of each digit and determines the overall value of a number.
Comparing Numbers: Comparing numbers involves determining the relationship between two or more numbers, whether they are equal, greater than, or less than each other. It helps in understanding the order and magnitude of numbers.
Estimation: Estimation is the process of making approximate calculations or predictions based on available information. It helps in getting a quick idea of the magnitude or value of a number or quantity without performing precise calculations.
Rounding Off: Rounding off involves approximating a number to a specified place value. It simplifies numbers and makes them easier to work with by reducing the number of digits while retaining a reasonable degree of accuracy.
Brackets: Brackets are symbols used in mathematical expressions to indicate grouping or prioritizing operations. They help in clarifying the order of operations and ensure correct calculation.
Roman Numerals: Roman numerals are a numeral system used in ancient Rome. They use specific symbols to represent different values, such as I, V, X, L, C, D, and M. Understanding Roman numerals helps in interpreting historical dates, numbering lists, and understanding some traditional numeral systems.
Free download NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers PDF for CBSE Exam.
Knowing Our Numbers Class 6 NCERT Topic-Comparing Numbers
Q1 Can you instantly find the greatest and the smallest numbers in each row?
2. 1473, 89423, 100, 5000, 310
3. 1834, 75284, 111, 2333, 450
4. 2853, 7691, 9999, 12002, 124
Answer: By Observing the number of digits and digit in the leftmost place can straight away tell us about the greatest and smallest number
(2) 1473, 89423, 100, 5000, 310
89423 is the greatest while 100 is the smallest
(3) 1834, 75284, 111, 2333, 450
75284 is the greatest 111 while is the smallest
(4) 2853, 7691, 9999, 12002, 124
12002 is the greatest while 124 is the smallest
Answer:
(a) 4536, 4892, 4370, 4452
4892 is the greatest while 4370 is the smallest
(b) 15623, 15073, 15189, 15800
15800 is the greatest while 15073 is the smallest
(c) 25286, 25245, 25270, 25210
25286 is the greatest while 25245 is the smallest
(d) 6895, 23787, 24569, 24659
24659 is the greatest while 6895 is the smallest
Knowing Our Numbers Class 6 NCERT Topic: Number Formation
Answer:
(a) 2, 8, 7, 4
8742 is the greatest while 2478 is the smallest
(b) 9, 7, 4, 1
9741 is the greatest 1479 while is the smallest
(c) 4, 7, 5, 0
4750 is the greatest while 4057 is the smallest
(d) 1, 7, 6, 2
7621 is the greatest while 1267 is the smallest
(e) 5, 4, 0, 3
5430 is the greatest while 3045 is the smallest
Answer:
(a) 3, 8, 7
8873 is the greatest while 3387 is the smallest
(b) 9, 0, 5
9950 is the greatest while 5009 is the smallest
(c) 0, 4, 9
9940 is the greatest while 4009 is the smallest
(d) 8, 5, 1
8851 is the greatest while 1158 is the smallest
Q3 Make the greatest and the smallest 4-digit numbers using any four different digits with conditions as given.
(a) Digit 7 is always at one's place
Greatest - 9 8 6 7
Smallest - 1 0 2 7
(Note, the number cannot begin with the digit 0. Why?)
(b) Digit 4 is always at tens place
Greatest - _ _ 4 _
Smallest - _ _ 4 _
(c) Digit 9 is always at hundreds place
Greatest - _ 9 _ _
Smallest - _ 9 _ _
(d) Digit 1 is always at thousands place
Greatest- 1 _ _ _
Smallest - 1 _ _ _
Answer:
(b) Digit 4 is always at tens place
Greatest - 98 47
Smallest - 10 42
(c) Digit 9 is always at hundreds place
Greatest - 8 976
Smallest - 1 902
(d) Digit 1 is always at thousands place
Greatest- 1987
Smallest - 1023
Answer:
Greatest number - 3322
Smallest number - 2233
Different numbers are
2222, 2232, 2233, 2322, 2333, 2332, 2323, 2223, 3222, 3223, 3232, 3233, 3322, 3333, 3332, 3323
There are 16 in total
Solutions For Knowing Our Numbers Class 6 NCERT Topic: Arrangement of Numbers
Answer:
(a) 847, 8320, 8320, 571
571 < 847 < 8320 < 8320
(b) 9801, 25751, 25751, 38802
9801 < 25751 < 25751 < 38802
Answer:
(a) 5000, 7500, 85400, 7861
85400 > 7861 > 5000 > 75000
(b) 1971, 45321, 88715
88715 > 45321 > 1971
Solutions For Knowing Our Numbers Class 6 NCERT Topic-Revisiting Place Value
Q1 Read and expand the numbers wherever there are blanks.
5. 29485________________________________________
6. 29085________________________________________
Answer:
1. 50000-Fifty thousand
2. 41000-forty one thousand
3. 47300- forty-seven thousand and three hundred
4. 57630- fifty-seven thousand six hundred
5. 29485- twenty-nine thousand and four hundred eighty-five
6. 29085- twenty-Nine Thousand and Eighty-Five
Q2 Read and expand the numbers wherever there are blanks.
4,57,928 _______________ _______________
4,07,928 _______________ _______________
4,00,829 _______________ _______________
4,00,029 _______________ _______________
Answer:
4,57,928 Four Lakhs Fifty Seven Thousand and Nine Hundred Twenty Eight
4,07,928 Four Lakhs Seven Thousand and Nine Hundred Twenty-Eight
4,00,829 Four Lakhs Eight Hundred Twenty-Nine
4,00,029 Four Lakhs and Twenty-Nine
Q3 You have the following digits 4, 5, 6, 0, 7 and 8.
Using them, make five numbers each with 6 digits.
(a) Put commas for easy reading.
(b) Arrange them in ascending and descending order.
Answer:
Given, digits :
Five 6-digit numbers are:
(a) 1 lakh = _______ ten thousand.
(b) 1 million = _______ hundred thousand.
(c) 1 crore = _______ ten lakh.
(d) 1 crore = _______ million.
Answer:
Let us take this as a physical world problem:
You went to a shop and you bought a toy of Rs. 100. You checked your pocket and found many notes but of only Rs.10
How many Rs.10 notes will you give to shopkeeper:
Well, it’s simple.
You will pay 10 notes.
How?
100/10 =10
The similar easy approach can be done in all the blanks,
Hint: Always remember to keep your eyes on a number of zeros
(a)1 lakh= 100000
1thousand= 1000
Ten thousand= 10*1000 = 10000
Therefore,
1 lakh/ 10 thousand =100000/10000 =10
So, 1lakh= 10 ten thousand
(b) 1 million= 1000000
1thousand= 1000
Hundred thousand= 100*1000 = 100000
Therefore,
1 million/ hundred thousand =1000000/100000 =10
So, 1milion= 10 hundred thousand
(c) 1 crore= 10000000 (7 zeros)
1lakh= 100000 (5 zeros)
Ten lakh= 10*1000 = 1000000( 6 zeros)
Therefore,
1 crore/ Ten lakh=10000000/1000000 =10
So, 1 crore= 10 Ten lakh
(d)1 crore= 10000000 (7 zeros)
1million= 100000 (6 zeros)
Therefore,
1 crore/ 1million=10000000/1000000 =10
So, 1 crore= 10 million
(e) 1 million= 1000000
1lakh= 100000
Therefore,
1million/ 10 lakh = 1000000/100000 =10
So, 1 million= 10 lakhs
See, all answers came out to be 10 but not everytime
Q2 Place commas correctly and write the numerals:
(a) Seventy three lakh seventy five thousand three hundred seven.
(b) Nine crore five lakh forty one.
(c) Seven crore fifty two lakh twenty one thousand three hundred two.
(d) Fifty eight million four hundred twenty three thousand two hundred two.
(e) Twenty three lakh thirty thousand ten.
Answer:
(a) Seventy three lakh seventy five thousand three hundred seven.
(b) Nine crore five lakh forty one.
(c) Seven crore fifty two lakh twenty one thousand three hundred two.
(d) Fifty eight million four hundred twenty three thousand two hundred two.
(e) Twenty three lakh thirty thousand ten.
Q3 Insert commas suitably and write the names according to Indian System of Numeration :
(a) 87595762 (b) 8546283 (c) 99900046 (d) 98432701
Answer:
(a) : Eight crores seventy five lakhs ninety five thousand seven hundred sixty two
(b) : Eighty five lakhs forty six thousand two hundred eighty three.
(c) : Nine crores ninety nine lakhs and forty six.
(d) : Nine crores eighty four lakhs thirty two thousand seven hundred and one.
NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers: Large Numbers in Practise
Number of medicine tablets =
Weight of each medicine tablet =
Therefore, total weight =
(i) Total distance from A to D = AB + BC + CD
(ii) Total distance between D to G = DE + EF + FG
(iii) Required distance = AD + DG + GA
(iv) The difference of distances from C to D and D to E
Answer: Given,
Total number of tickets sold =
Answer:
The number of runs scored by Shekhar so far = 6980
The number of runs Shekhar wishes to score = 10,000
The number of runs required =
Therefore, Shekhar requires .
Answer: Given,
Number of votes registered by the successful candidate = 5, 77,500 votes
Number of votes registered by the rival candidate = 3, 48,700 votes
The margin
Therefore, the successful candidate won the election by a margin of votes.
Answer: Given,
Worth of books sold in the first week =
Worth of books sold in the second week =
Total sale in the two weeks =
Clearly, sales in the second week is greater than the first year by
Answer:
Given, digits: 6, 2, 7, 4 and 3
Since, the digits have to be used only once, arrange them in ascending and descending order to get the minimum and maximum number.
Greatest number =
Smallest number =
The difference between the greatest and the least number
Answer:
Given,
Screws produced by machine in one day =
We know, there are 31 days in January
Screws produced in 31 days =
Therefore, screws produced in January 2006 =
Answer:
Total money merchant has =
Cost of one radio set =
Cost of 40 radio sets =
Money left with the merchant =
Therefore, money left with her after purchase =
Answer: Given,
The student multiplied instead of .
Wrong answer =
Correct answer =
The difference in the answers =
Hence, his answer was greater than the correct answer by
Answer: We know,
Given,
Length of cloth required to stitch a shirt =
Also,
Now, the cloth required for one shirt =
Number of shirts that can be stitched out =
Therefore, 18 shirts can be made from the given cloth.
And, cloth will remain unused.
Answer- We know,
Weight of each medicine box=
Weight limit of the van =
The number of boxes that can be loaded in the van =
Hence, 177 boxes can be loaded in the van.
Answer: We know,
Given, - Distance between the school and her house =
The distance she covers each day =
Therefore, she will cover in six days.
Answer:
We know,
Given, Capacity of vessel =
The capacity of a single glass =
Number of glasses required to fill the vessel =
Hence, 180 glasses are needed to fill the vessel completely.
NCERT Solutions for Class 6 Maths Chapter 1 - Estimating to the Nearest Thousand Rounding Off
Ques- 1 Round off the given numbers to the nearest tens, hundreds and thousands.
Answer:
Given Number | Approximate to Nearest | Rounded Form |
75847 | Tens | |
75847 | Hundreds | |
75847 | Thousands | |
75847 | Ten thousands |
Answer:
(a)
By rounding off to hundreds,
730 rounds off to 700,
998 rounds off to 1000.
Required sum =
(b)
By rounding off to hundreds,
796 rounds off to 800,
314 rounds off to 300.
Required difference =
(c)
By rounding off to thousands,
2904 rounds off to 13000,
2822 rounds off to 3000.
Required sum =
(d)
By rounding off to nearest thousands,
28,296 rounds off to 28000,
21,496 rounds off to 21,000
Required difference =
Answer:
(a)
Rounding off to nearest hundreds,
439 rounds off to 400
334 rounds off to 300
4317 rounds off to 4300,
Required sum =
Again, by rounding off to nearest tens,
439 rounds off to 440
334 rounds off to 330
4317 rounds off to 4320,
Required sum =
(b)
Rounding off to nearest hundreds,
rounds off to
rounds off to
Required difference =
Also, rounding off to nearest tens,
rounds off to
rounds off to
Required difference =
(c)
Rounding off to nearest hundreds,
8325 rounds off to 8300
491 rounds off to 500
Required difference =
Also, rounding off to nearest tens,
8325 rounds off to 8330
491 rounds off to 490
Required difference =
(d)
Rounding off to nearest hundreds,
rounds off to
rounds off to
Required difference =
Also, rounding off to nearest tens,
rounds off to
rounds off to
Required difference =
Answer:
(a)
Rounding off by general rule,
578 rounds off to 600
161 rounds off to 200,
Required product =
(b)
Rounding off by the general rule,
5281 rounds off to 5000
3491 rounds off to 3500
Required product =
(c)
Rounding off by general rule,
1291 rounds off to 1300
592 rounds off to 600
Required product =
(d)
Rounding off by general rule,
9250 rounds off to 10000
29 rounds off to 30Required product =
NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers- Topic Using Brackets
Answer:
(a) Four multiplied by the sum of nine and two.
(b) Divide the difference of eighteen and six by four.
(c) Forty-five divided by three times the sum of three and two.
1.1 Introduction
1.2 Comparing Numbers
1.2.1 How many numbers can you make?
1.2.2 Shifting of numbers.
1.2.3 Introducing 10,000.
1.2.4 Revisiting place value.
1.2.5 Introducing 1,00,000.
1.2.6 Larger numbers.
1.2.7 An aid in reading and writing large numbers.
1.3 Large Numbers in Practice
1.3.1 Estimation
1.3.2 Estimating to the nearest tens by rounding off.
1.3.3 Estimating to the nearest hundreds by rounding off.
1.3.4 Estimating to the nearest thousands by rounding off.
1.3.5 Estimating outcomes of number situations.
1.3.6 To estimate sum or difference.
1.3.7 To estimate products.
1.4 Using Brackets
1.5 Roman Numerals
Chapters No. | Chapters Name |
Chapter - 1 | Knowing Our Numbers |
Chapter - 2 | |
Chapter - 3 | |
Chapter - 4 | |
Chapter - 5 | |
Chapter - 6 | |
Chapter - 7 | |
Chapter - 8 | |
Chapter - 9 | |
Chapter -10 | |
Chapter -11 | |
Chapter -12 | |
Chapter -13 | |
Chapter -14 |
Expertly Crafted Solutions: The NCERT Solutions for Chapter 1 are carefully developed to provide clear and accurate explanations to all the problems and concepts discussed in the chapter.
Conceptual Clarity: The NCERT maths book class 6 chapter 1 solutions aim to enhance the conceptual understanding of students by breaking down complex topics into simpler and more understandable explanations.
Comprehensive Coverage: The maths class 6 chapter 1 cover all the important topics and subtopics of Chapter 1, ensuring that students have a complete understanding of the chapter.
Exam-Focused Approach: The ncert class 6 maths chapter 1 are designed with an exam-focused approach, providing students with the necessary tools and techniques to tackle questions effectively and score well in exams.
Also Check -
NCERT Books and NCERT Syllabus
NCERT Solutions for Class 6 Maths Chapter 1 - Knowing Our Numbers provide a comprehensive and student-friendly approach to learning mathematics, helping students build a strong foundation in the subject. There are 3 exercise including exercise 1 which has 4 questions, exercise 2 that has 12 questions and exercise 3 that has 3 questions. Students can practice these exercise to command the concepts.
Knowing Our Numbers is an important chapter from NCERT syllabus of Class 6. Students can download Knowing Our Numbers solutions to use it offline. they can study knowing our numbers class 6 pdf after download. On clicking the download button the complete page will be downloaded and can be used for offline preparation.
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