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NCERT Solutions for Exercise 6.6 Class 10 Maths Chapter 6 Triangles are discussed here. These NCERT solutions are created by subject matter expert at Careers360 considering the latest syllabus and pattern of CBSE 2023-24. Class 10 maths ex 6.6 help us to understand how to apply all the concepts till now we have learned through all the exercises in the chapter. The notion of triangle similarity, criteria for triangle similarity, areas of similar triangles, and Pythagoras Theorem are covered in this exercise.
10th class Maths exercise 6.6 answers are designed as per the students demand covering comprehensive, step by step solutions of every problem. Practice these questions and answers to command the concepts, boost confidence and in depth understanding of concepts. Students can find all exercise together using the link provided below.
Triangles Class 10 Chapter 6 Exercise: 6.6
Q1 In Fig. 6.56, PS is the bisector of
Answer:
A line RT is drawn parallel to SP which intersect QP produced at T.
Given: PS is the bisector of
By construction,
From the above equations, we get
By construction, PS||TR
In
Hence proved.
Answer:
Join BD
Given : D is a point on hypotenuse AC of D ABC, such that BD
In
In
From equation 1 and 2, we get
From equation 1 and 3, we get
In
Hence proved
Q2 (2) In Fig. 6.57, D is a point on hypotenuse AC of D ABC, such that BD
Answer:
In
In
BD
From equation 1 and 3, we get
From equation 2 and 3, we get
In
Hence proved.
Q3 In Fig. 6.58, ABC is a triangle in which
Answer:
In
In
Q4 In Fig. 6.59, ABC is a triangle in which
Answer:
In
In
Q5 (1) In Fig. 6.60, AD is a median of a triangle ABC and AM
Answer:
Given: AD is a median of a triangle ABC and AM
In
In
Q5 (2) In Fig. 6.60, AD is a median of a triangle ABC and AM
Answer:
In
Q5 (3) In Fig. 6.60, AD is a median of a triangle ABC and AM
Answer:
In
In
Adding equation 1 and 2,
Answer:
In parallelogram ABCD, AF and DE are altitudes drawn on DC and produced BA.
In
In
In
In
Since ABCD is a parallelogram.
SO, AB=CD and BC=AD
In
AD=AD (common)
Adding 2 and, we get
Q7 (1) In Fig. 6.61, two chords AB and CD intersect each other at point P. Prove that :
Answer:
Join BC
In
Q7 (2) In Fig. 6.61, two chords AB and CD intersect each other at point P. Prove that :
Answer:
Join BC
In
Answer:
In
So,
Answer:
In
So,
24440
Q9 In Fig. 6.63, D is a point on side BC of D ABC such that
Answer:
Produce BA to P, such that AP=AC and join P to C.
Using converse of Thales theorem,
AD||PC
By construction,
AP=AC
From equation 1,2,3, we get
Thus, AD bisects angle BAC.
Answer:
Let AB = 1.8 m
BC is a horizontal distance between fly to the tip of the rod.
Then, the length of the string is AC.
In
Hence, the length of the string which is out is 3m.
If she pulls in the string at the rate of 5cm/s, then the distance travelled by fly in 12 seconds.
=
Let D be the position of fly after 12 seconds.
Hence, AD is the length of the string that is out after 12 seconds.
Length of string pulled in by nazim=AD=AC-12
=3-0.6=2.4 m
In
Horizontal distance travelled by fly = BD+1.2 m
=1.587+1.2=2.787 m
= 2.79 m
Class 10 Maths chapter 6 exercise 6: The questions in exercise 6.6 Class 10 Maths consist of many types of questions covering different types of theorems and formulas. Firstly we have a question in which we have to prove the left-hand side argument and right-hand side argument NCERT solutions for Class 10 Maths exercise 6.6 also have questions. Exercise 6.6 Class 10 Maths covers all types of questions that can be formed on the similarity of triangles. Students can also access Triangles Class 10 Notes here and use them for quickly revision of the concepts related to Triangles.
Also, See:
As per latest 2024 syllabus. Maths formulas, equations, & theorems of class 11 & 12th chapters
similarity of triangle
Criteria for Similarity of Triangles
Areas of Similar Triangles
Pythagoras Theorem
If the respective angles are congruent and the corresponding sides are proportional, two triangles are said to be similar.
NCERT solutions for Class 10 Maths exercise 6.6 is different from other exercises as all other exercises are based on a single concept and theorem they are base building exercises but Class 10 Maths chapter 6 exercise 6.6 is based on all the concepts.
Yes Class 10 Maths chapter 6 exercise 6.6 because it have questions which have mix concepts
There are 13 main theorems are there which we require to solve NCERT solutions for Class 10 Maths 1 exercise 6.6
There are ten questions in exercise 6.6 Class 10 Maths question
There are two types of questions in exercise 6.6 Class 10 Maths question one type is there in which we have to proof LHS and RHS these contains uses of theorem and other is real life application of triangle
Admit Card Date:03 February,2025 - 18 March,2025
Admit Card Date:03 February,2025 - 04 April,2025
Hello
Since you are a domicile of Karnataka and have studied under the Karnataka State Board for 11th and 12th , you are eligible for Karnataka State Quota for admission to various colleges in the state.
1. KCET (Karnataka Common Entrance Test): You must appear for the KCET exam, which is required for admission to undergraduate professional courses like engineering, medical, and other streams. Your exam score and rank will determine your eligibility for counseling.
2. Minority Income under 5 Lakh : If you are from a minority community and your family's income is below 5 lakh, you may be eligible for fee concessions or other benefits depending on the specific institution. Some colleges offer reservations or other advantages for students in this category.
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After the KCET exam, you will need to participate in online counseling.
You need to select your preferred colleges and courses.
Seat allocation will be based on your rank , the availability of seats in your chosen colleges and your preferences.
4. Required Documents :
Domicile Certificate (proof that you are a resident of Karnataka).
Income Certificate (for minority category benefits).
Marksheets (11th and 12th from the Karnataka State Board).
KCET Admit Card and Scorecard.
This process will allow you to secure a seat based on your KCET performance and your category .
check link for more details
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Hello Aspirant, Hope your doing great, your question was incomplete and regarding what exam your asking.
Yes, scoring above 80% in ICSE Class 10 exams typically meets the requirements to get into the Commerce stream in Class 11th under the CBSE board . Admission criteria can vary between schools, so it is advisable to check the specific requirements of the intended CBSE school. Generally, a good academic record with a score above 80% in ICSE 10th result is considered strong for such transitions.
hello Zaid,
Yes, you can apply for 12th grade as a private candidate .You will need to follow the registration process and fulfill the eligibility criteria set by CBSE for private candidates.If you haven't given the 11th grade exam ,you would be able to appear for the 12th exam directly without having passed 11th grade. you will need to give certain tests in the school you are getting addmission to prove your eligibilty.
best of luck!
According to cbse norms candidates who have completed class 10th, class 11th, have a gap year or have failed class 12th can appear for admission in 12th class.for admission in cbse board you need to clear your 11th class first and you must have studied from CBSE board or any other recognized and equivalent board/school.
You are not eligible for cbse board but you can still do 12th from nios which allow candidates to take admission in 12th class as a private student without completing 11th.
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