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NCERT Solutions for Class 9 Maths Chapter 7 Triangles Exercise 7.2- Welcome to NCERT Solutions for Class 9 Maths, Chapter 7 - Triangles, Exercise 7.2. This exercise delves deeper into the subject, helping you master the intricacies of triangle geometry. In 9th class maths exercise 7.2 answers, we encounter a range of thought-provoking problems that challenge your understanding and problem-solving skills. Our expert-crafted solutions offer clear explanations and step-by-step guidance to assist you in tackling these challenges. Furthermore, you can easily download the PDF version of these class 9 maths chapter 7 exercise 7.2 for free, ensuring accessibility wherever and whenever you need them.
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Along with NCERT book Class 9 Maths, chapter 9 exercise 7.2 the following exercises are also present.
Answer:
In the triangle ABC,
Since AB = AC, thus
or
or (Angles bisectors are equal)
Thus as sides opposite to equal are angles are also equal.
Answer:
Consider and ,
(i) (Given)
(ii) (Common in both the triangles)
(iii) (Proved in previous part)
Thus by SSS congruence rule, we can conclude that :
Now, by c.p.c.t.,
Hence AO bisects .
Q2 In , AD is the perpendicular bisector of BC (see Fig). Show that is an isosceles triangle in which .
Answer:
Consider ABD and ADC,
(i) (Common in both the triangles)
(ii) (Right angle)
(iii) <BD=<CD
Answer:
Consider and ,
(i) is common in both the triangles.
(ii) (Right angles)
(iii) (Given)
Thus by AAS congruence axiom, we can conclude that :
Now, by c.p.c.t. we can say :
Hence these altitudes are equal.
Q4 (i) ABC is a triangle in which altitudes BE and CF to sides AC and AB are equal (see Fig). Show that
Answer:
Consider and ,
(i) is common in both the triangles.
(ii) (Right angles)
(iii) (Given)
Thus by AAS congruence, we can say that :
Answer:
From the prevoius part of the question we found out that :
Now, by c.p.c.t. we can say that :
Hence is an isosceles triangle.
Q5 ABC and DBC are two isosceles triangles on the same base BC (see Fig.). Show that .
Answer:
Consider and ,
(i) (Common in both the triangles)
(ii) (Sides of isosceles triangle)
(iii) (Sides of isosceles triangle)
Thus by SSS congruency, we can conclude that :
Answer:
Consider ABC,
It is given that AB = AC
So, (Since angles opposite to the equal sides are equal.)
Similarly in ACD,
We have AD = AB
and
So,
or ...........................(i)
And in ADC,
..............................(ii)
Adding (i) and (ii), we get :
or
and
Q7 ABC is a right angled triangle in which and . Find and .
Answer:
In the triangle ABC, sides AB and AC are equal.
We know that angles opposite to equal sides are also equal.
Thus,
Also, the sum of the interior angles of a triangle is .
So, we have :
or
or
Hence
Q8 Show that the angles of an equilateral triangle are each.
Answer:
Consider a triangle ABC which has all sides equal.
We know that angles opposite to equal sides are equal.
Thus we can write :
Also, the sum of the interior angles of a triangle is .
Hence,
or
or
So, all the angles of the equilateral triangle are equal ( ).
In NCERT Solutions for exercise 7.2 class 9 maths, we will begin by understanding the definitions and important terms related to triangles. It's essential to revise the basics before diving into any topic. A triangle is a closed figure formed by three intersecting lines (the prefix "tri" signifies "three"). A triangle consists of three sides, three angles, and three vertices.
Triangle Congruence: Two triangles are considered congruent if the sides and angles of one triangle are equal to the corresponding sides and angles of the other. When PQR and ABC are congruent, we denote it as PQR = ABC.
The NCERT syllabus for Class 9 Maths Exercise 7.2 covers different criteria for establishing the congruence of triangles, which include: Side-Angle-Side, Angle-Side-Angle, Side-Side-Side, and Right-angle-Hypotenuse-Side.
Theorem 1: In an isosceles triangle, the angles opposite the equal sides are equal.
Theorem 2: In a triangle, the sides opposite equal angles are equal.
Also Read| Triangles Class 9 Notes
Exercise 7.2 Class 9 Maths, is related to triangles.
From Class 9 Maths chapter 7 exercise 7.2 introduces us to theorems related to isosceles triangles.
Understanding the principles from Class 9 Maths Chapter 7 Exercise 7.2 will assist us in understanding the notions of congruency and isosceles triangle characteristics.
Comprehensive Coverage: The 9th class maths exercise 7.2 answers covers various aspects of triangles, including congruence criteria and theorems related to triangle properties.
Clear Explanations: The class 9 maths ex 7.2 solutions provide clear and concise explanations, making it easier for students to understand and apply the concepts.
Step-by-Step Approach: Each ex 7.2 class 9 problem is solved step by step, allowing students to follow the thought process and replicate it in similar problems.
Variety of Problems: The class 9 ex 7.2 includes a range of problems based on different congruence criteria, ensuring that students get a well-rounded practice.
Application of Theorems: The exercise 7.2 class 9 maths helps students apply theorems related to triangles, enhancing their problem-solving skills.
Conceptual Clarity: By solving these problems, students gain a deeper understanding of the properties and congruence criteria of triangles.
Aligned with Curriculum: The content aligns with the Class 9 mathematics curriculum, preparing students for examinations and future topics in geometry.
Free Resource: These solutions are available to students at no cost, making quality math resources accessible to all.
Also, See
An isosceles triangle is one with two equal sides. It has two equal angles as well.
An isosceles triangle has two sides and two angles equal to each other.
Yes, every equilateral triangle is an isosceles triangle, but every isosceles triangle is not an equilateral triangle.
Yes, every equilateral triangle is an isosceles triangle, but every isosceles triangle is not an equilateral triangle.
The angle bisector of the vertex angle divides the base into 1:1 ratio which means into two equal parts i.e., it passes through the midpoint of the base.
The angle bisector of the vertex angle divides the base into 1:1 ratio which means into two equal parts i.e., it passes through the midpoint of the base.
The angle bisector of the vertex angle divides the base into 1:1 ratio which means into two equal parts i.e., it passes through the midpoint of the base.
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