NCERT Solutions for Class 10 Science Chapter 10 - The Human Eye and The Colorful World

Edited By Vishal kumar | Updated on Mar 21, 2025 05:43 PM IST | #CBSE Class 10th

Have you ever thought about why the sky is blue during the day but turns reddish-orange at sunset and sunrise, or why stars are only visible at night? Class 10 Science Chapter 10, The Human Eye and the Colorful World, provides explanations for these queries. Important phenomena including how our eyes function and common vision problems, how light bends (refraction), how light disperses into multiple colours (dispersion), why stars sparkle, how light scatters, and the Tyndall effect are all explained in this chapter of NCERT solutions. Students may better grasp these concepts, get any misunderstandings about the natural occurrences around them cleared up, and get ready for the exam with the help of the NCERT solutions for Class 10 Science Chapter 10.

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This Story also Contains

NCERT Solutions for Class 10 Science Chapter 10: Download Solution PDF
NCERT Class 10 Science Chapter 10: Intext Solutions
The Human Eye and The Colorful World Exercise Solutions
NCERT Solutions for Class 10 Science Chapter 10: Important Diagrams
NCERT Solutions for Class 10 Science Chapter 10 The Human Eye and The Colorful World: Important Topics
Human Eye and Colourful World Class 10: Types of Questions Asked
NCERT Class 10 Science Solutions Chapter 10: Weightage in Board Exams
NCERT Solutions for Class 10 Science Chapter 10: Important Highlights
Class 10 Science Chapter 10 NCERT Solutions: Summary
NCERT Solutions for Class 10 Science: Chapter Wise

NCERT Solutions for Class 10 Science Chapter 10 - The Human Eye and The Colorful World

NCERT Solutions for Class 10 Science Chapter 10: Download Solution PDF

Click on the link given below to download the solution PDF of Human Eye and Colourful World which contains complete exercise questions with answers along with intext questions.

Download Solution PDF

NCERT Class 10 Science Chapter 10: Intext Solutions

Solutions to CBSE Class 10 questions are given below so, that students can understand the topic well and it is advised to solve the intext question which covers numerous topics like the introduction of vision and ways to correct the Vision.

Topic 10.2 - Defects of vision and their correction

Q. 1. What is meant by the power of accommodation of the eye?

Answer:

The power of accommodation is the ability of an eye to focus near and far objects clearly and make the image on the retina by adjusting its focal length. However, the focal length of the eye lens cannot be decreased below a certain minimum limit.

Q.2. A person with a myopic eye cannot see objects beyond 1.2 m distinctly. What should be the type the corrective lens used to restore proper vision?

Answer:

The correction for a myopic eye should be the concave lens (negative power) to restore proper vision.

Q.3. What is the far point and near point of the human eye with normal vision?

Answer:

The far point of the human eye with normal vision is at infinity and the near point is 25cm distance from the eye.

Q.4. A student has difficulty reading the blackboard while sitting in the last row. What could be the defect the child is suffering from? How can it be corrected?

Answer:

Since the student has difficulty reading the blackboard while sitting in the last row, he is most likely to suffer from the disease of myopia (short-sightedness) i.e., he can see the closer objects clearly but is unable to see the far objects properly.

Hence it can be corrected by placing the spectacles with concave lenses of appropriate power.

The Human Eye and The Colorful World Exercise Solutions

Q.1. The human eye can focus on objects at different distances by adjusting the focal length of the eye lens. This is due to

(a) presbyopia
(b) Accommodation
(c) near-sightedness
(d) far-sightedness

Answer:

It is due to the accommodation of the eye. The human eye can adjust its focal length according to the different distances. Therefore, the option (b) is correct.

Q.2. The human eye forms the image of an object at its

(a) cornea

(b) iris

(d) retina

Answer:

The human eye forms the image of an object at its retina. Therefore, the correct option is (d) Retina

Q.3. The least distance of distinct vision for a young adult with normal vision is about

(a) 25 m

(b) 2.5 cm

(d) 2.5 m

Answer:

The least distance of distinct vision for a young adult with normal vision is about (c) 25 cm

Q.4. The change in focal length of an eye lens is caused by the action of the

(a) pupil

(b) retina

(d) iris

Answer:

The change in focal length of an eye-lens is caused by the action of the :(c) ciliary muscles

Q.5. A person needs a lens of power –5.5 dioptres for correcting his distant vision. For correcting his near vision he needs a lens of power +1.5 dioptre. What is the focal length of the lens required for correcting (i) distant vision, and (ii) near vision?

Answer:

For the distant vision:

The power of the lens, given $P = - 5.5 D$

$Power (in D) = \frac{1}{f (m)}$

Hence the focal length will be:

$f = \frac{100}{- 5.5} = - 18.2 cm$

Therefore, the focal length of the lens required for correcting distant vision will be: -18.2 cm (Here, the negative sign of focal length tells us that it is a concave lens).

For near vision:
The power of the lens, given $P = + 1.5 D$

$Power (in D) = \frac{1}{f (m)}$

Hence the focal length will be:

$f = \frac{100}{+ 1.5} = 66.66 cm$

Therefore, the focal length of the lens required for correcting near vision will be: +66.7 cm (Here, the positive sign of focal length tells us that it is a convex lens).

Q.6. The far point of a myopic person is 80 cm in front of the eye. What is the nature and power of the lens required to correct the problem?

Answer:

The myopic person is suffering from near-sightedness which can be corrected by putting the concave lens in spectacles.

Given the far point up to which a myopic person can see is 80cm in front of the eye.

Here, this person can see the distant object (kept at infinity) clearly if the image of this distant object is formed at his far point.

So, we have

The object distance, $u = \infty$ (in finity $)$
The image distance, $v = - 80 cm$ (far point, in front of the lens) and the focal length, $f =$ to find.

Hence substituting the values in the lens formula: we obtain

$\begin{aligned} \frac{1}{v} - \frac{1}{u} = \frac{1}{f} \\ \Rightarrow \frac{1}{- 80} - \frac{1}{\infty} = \frac{1}{f} \\ \Rightarrow \frac{1}{f} = \frac{1}{- 80} \end{aligned}$

$\Rightarrow f = - 80 cm$
Therefore, the focal length of the required concave lens will be 80 cm
Now, Power,

$Power = \frac{1}{f (m)} = \frac{1}{- 0.8} = - 1.25 D$

Hence the power of the concave lens required is -1.25 D

Q.7. Make a diagram to show how hypermetropia is corrected. The near point of a hypermetropic eye is 1 m. What is the power of the lens required to correct this defect? Assume that the near point of the normal eye is 25 cm.

Answer:

1644209753983

Given the near point for the hypermetropic eye is 1m.

Assume the near point of the normal eye is 25 cm.

So,

The object distance will be, $u = - 25 cm$ (Normal near the point)
The image distance, $v = - 1 m$ (Near the point of this defective eye) or -100 cm
Then the focal length can be found from the lens formula:

$\frac{1}{v} - \frac{1}{u} = \frac{1}{f}$

Substituting the values in the equation, we obtain

$\begin{aligned} \Rightarrow \frac{1}{- 100} - \frac{1}{- 25} = \frac{1}{f} \\ \Rightarrow \frac{- 1 + 4}{100} = \frac{1}{f} \\ \Rightarrow \frac{3}{100} = \frac{1}{f} \\ \Rightarrow f = \frac{100}{3} = 33.3 cm or 0.333 m \end{aligned}$

Hence the power of the lens will be:

$P = \frac{1}{f (m)} = \frac{1}{+ 0.333 m} = + 3.0 D$

Thus, the power of the convex lens required will be +0.3 D

Q.8. Why is a normal eye not able to see clearly the objects placed closer than 25 cm?

Answer:

A normal eye is not able to see clearly the objects placed closer than 25 cm because the ciliary muscles have a limit of contraction and relaxation, to see closer objects, ciliary muscles, must decrease the focal length of the eye lens. However, the focal length of the eye lens cannot be decreased below a certain minimum limit. Due to this, our eyes are not able to see objects clearly when placed closer than 25cm.

Q.9. What happens to the image distance in the eye when we increase the distance of an object from the eye?

Answer:

There is no change to the image distance in the eye when we increase the distance of an object from the eye. The image is always formed in the retina of our eye.

Q.10. Why do stars twinkle?

Answer:

Stars twinkle because of turbulence in the atmosphere of the Earth.

The light from the star is refracted in different directions because of the variable refractive index. This seems to us like the position of stars to be changed slightly and also brightness and position, Hence, the twinkling of stars happens.

Q.11. Explain why the planets do not twinkle.

Answer:

Planets do not twinkle the way stars do, the reason is that stars are so far away that they appear to be a point source of light on the sky, while planets have finite size and the size of a planet "averages out" the turbulent effects of the atmosphere.

Therefore, we see a relatively stable image of the eye. Hence, twinkling is not observed on planets.

Q.12. Why does the Sun appear reddish early in the morning?

Answer:

At sunrise and sunset, the sun is closer to the horizon. The sunlight near the horizon passes through denser layers of the air and covers a larger distance before reaching our eyes. Most of the blue light gets scattered. The light that reaches our eyes is of longer wavelengths, mainly orange and red. That is why the sun appears red at sunrise and at sunset.

Q.13. Why does the sky appear dark instead of blue to an astronaut?

Answer:

The dark colour is nothing but the absence of light.

The sky appears dark instead of blue to an astronaut because there is no atmosphere in outer space that can scatter the sunlight. As the sunlight is not scattered, no scattered light reaches the eyes of the astronauts the sky appears black to them.

NCERT Solutions for Class 10 Science Chapter 10: Important Diagrams

Learning formulas and diagrams is just as crucial to getting good scores on the Class 10 Science exam as understanding the theory. Key formulas and diagrams are explained in detail in the Human Eye and Colourful World NCERT solutions, which are included below.

Human Eye

Human eye

The human eye is a complex and sensitive organ that allows us to see the world around us. It consists of several key parts:

Cornea: The transparent, curved outer layer that helps focus light onto the retina.
Pupil: The dark circular opening in the centre of the iris, which controls the amount of light entering the eye.
Iris: The coloured part of the eye that regulates the size of the pupil and controls how much light enters.
Lens: A flexible, transparent structure that further focuses light onto the retina.
Retina: The light-sensitive layer at the back of the eye that captures visual information and sends it to the brain via the optic nerve.
Optic Nerve: Transmits visual information from the retina to the brain for processing.

Dispersion of White Light in A Prism

When white light passes through a glass prism, it undergoes dispersion, which means the light splits into its component colours. This happens because different colours of light travel at different speeds through the prism, with each colour bending by a different amount.

Rainbow Formation

A rainbow is formed when sunlight interacts with water droplets in the atmosphere. The process of refraction, internal reflection, and dispersion causes the light to break into a spectrum of colours, creating a rainbow.

Rainbow Formation

The NCERT Class 10 Science Chapter 10 Solutions include essential formulas for solving problems, helpful diagrams to make the concepts clearer, and key points at the end of each chapter for quick reference. By using these resources, students can gain a deeper understanding of the topic, which will lead to improved performance in their exams. The PDF link provided below is also a great tool for quick revision when exam time approaches.

Download - NCERT Class 10 Science: Chapterwise Important Formulas, Diagrams, And Points

NCERT Solutions for Class 10 Science Chapter 10 The Human Eye and The Colorful World: Important Topics

Here are the key topics from the Human Eye and Colourful World class 10 questions and answers that will help you quickly revise the chapter and be well-prepared for class tests, exams, and other assessments:

Structure and functions of the human eye
How we see: the process of vision
Common vision defects and their correction methods
Refraction of light through a prism
Dispersion of white light using a glass prism
Atmospheric refraction and its effects
Scattering of light
The Tyndall effect

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Human Eye and Colourful World Class 10: Types of Questions Asked

Before moving to the exam, students must familiarize themselves with the types of questions that may be asked from class 10 science chapter 10 question answers. The following question types are generally asked in the exams

Very short answer type
Short answer type
Long answer type
Practical based questions

Also, check - NCERT Solutions for Class 10 Maths

NCERT Class 10 Science Solutions Chapter 10: Weightage in Board Exams

The Human Eye and the Colourful World in NCERT is a vital chapter, carrying considerable importance in the board exams. To achieve full marks, students should concentrate on the chapter’s solutions and NCERT Class 10 Science notes, which will help them grasp the concepts thoroughly and perform excellently in the exams.

NCERT Solutions for Class 10 Science Chapter 10: Important Highlights

The goal of the NCERT solutions for Chapter 10, The Human Eye and the Colourful World is to give students a thorough grasp of the optical principles pertaining to light, the human eye, and how these relate to various materials. The following pointer explains why the solutions are crucial:

Clear and Simple Explanations: Students can better understand challenging concepts because of the straightforward and intelligible writing style of the solutions.
Exam-Focused Preparation: All necessary topics are covered in the question-answer format, which is designed to assist students in efficiently preparing for the CBSE exams.
Extensive Answers: Every question has a detailed, sequential explanation that helps students grasp the subject topic better.
Accurate and Detailed Answers: Students can prepare more effectively because of the accurate solutions, which guarantee accuracy and clarity.
Full Coverage of NCERT Questions: The solutions contain all of the NCERT textbook's questions, providing students with all the information they need to study and perform well on their exams.

Also, check

Class 10 Science Chapter 10 NCERT Solutions: Summary

The human eye has the ability to adjust and focus on objects both near and far, a process called accommodation.
For a person with normal vision, the closest point at which they can see objects clearly without any strain is 25 cm.
There are three common vision problems: myopia (also known as nearsightedness), hypermetropia (farsightedness), and presbyopia (age-related difficulty in focusing).
As people age, the eye's ability to adjust and focus, known as accommodation, gradually weakens.
Dispersion occurs when white light passes through a medium like a prism, breaking it down into its individual colors, and creating a spectrum.
The phenomenon of scattering of light is what causes the sky to appear blue and the sun to take on a reddish hue, particularly during sunrise and sunset.

NCERT Solutions for Class 10 Science: Chapter Wise

NCERT Solutions for Class 10 Science Chapter 1 – Chemical Reactions and Equations

NCERT Solutions for Class 10 Science Chapter 2 – Acids, Bases, and Salts

NCERT Solutions for Class 10 Science Chapter 3 – Metals and Non-Metals

NCERT Solutions for Class 10 Science Chapter 4 – Carbon and its Compounds

NCERT Solutions for Class 10 Science Chapter 5 – Life Processes

NCERT Solutions for Class 10 Science Chapter 6 – Control and Coordination

NCERT Solutions for Class 10 Science Chapter 7 – How do Organisms Reproduce?

NCERT Solutions for Class 10 Science Chapter 8 – Heredity

NCERT Solutions for Class 10 Science Chapter 9 – Light: Reflection and Refraction

NCERT Solutions for Class 10 Science Chapter 10 – The Human Eye and the Colourful World

NCERT Solutions for Class 10 Science Chapter 11 – Electricity

NCERT Solutions for Class 10 Science Chapter 12 – Magnetic Effects of Electric Current

NCERT Solutions for Class 10 Science Chapter 13 – Our Environment

Frequently Asked Questions (FAQs)

1. What are the important topics of NCERT Class 10 Science solutions chapter 10?

Here is the list of some important topics:

Functioning of a Lens in Human Eye
Applications of Spherical Mirrors & Lenses
Refraction of Light through a Prism
Dispersion & Scattering of Light
Power of Accommodation
Defects of Vision and Their Corrections

2. What benefits can be gained from studying chapter 10 class 10 science, specifically the topics on the human eye and the colourful world?

By studying the human eye and the colourful world solutions you will gain a comprehensive understanding of the following topics:

The anatomy and function of the human eye, including its ability to accommodate or focus on both near and distant objects.
The common vision defects such as myopia, hypermetropia, and presbyopia, and how they can be corrected.
The near point of clear vision and how it varies with age.
The principle of dispersion and how it splits white light into its component colours.

3. How can I download NCERT solutions for class 10 Science chapter 10 pdf?

Through NCERT solutions Class 10 science chapter 10 pdf download facility download this solution as a webpage to access offline. To get more problems on The Human Eye and The Colourful World refer to NCERT exemplar.

4. What is atmospheric refraction according to class 10 chapter 10 science?

Atmospheric refraction is the bending of light as it travels through the Earth's atmosphere due to variations in temperature and density. This bending of light causes objects to appear displaced or distorted from their true position, leading to phenomena such as elevated sun or star positions and mirages.

5. How human eye class 10 solutions is important for the board exam?

The NCERT Solutions for Class 10 Science's "The Human Eye and the Colorful World" chapter is important for board exams as it covers a key aspect of the Science syllabus. The solutions provide a comprehensive explanation of the concepts, helping students to score well in the subject and prepare for internal assessments and tests. It is a valuable resource for students preparing for board exams.

6. What is the chapter number of human eye and colourful world class 10?

As per the revised CBSE Syllabus, Chapter 11 "The Human Eye and The Colourful World" has been renumbered as Chapter 10.

7. What causes the formation of a rainbow?

The combination of sunlight and water droplets in the air creates rainbows through light refraction and reflection that results in spectrum color dispersal.

8. What is the function of the retina in the human eye?

The major function of the retina is to converts light into electrical signals, it is light-sensitive layer of tissue.

9. Why do stars twinkle but planets do not?

When we look from the naked eye planets appear as disks but stars appear to twinkle because stars are farther away and appear as points while planets are closer.

10. How does the refraction of light cause a mirage in deserts?

Mirage occur as light passes through layers of air with varying temperature due to which the sky appears as a pool of water. This phenomenon is due to the refraction of light.

11. How does atmospheric refraction affect sunrise and sunset timing

Atmospheric refraction is the bending of light through the earth's atmosphere. It causes the sunrise to appear 2 minutes earlier and the sunset to appear 2 minutes later.

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Questions related to CBSE Class 10th

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i studied 1 to 10th CBSE board abroad and 11th 12th in karnataka state board . i am a domicile of karnataka and comes under minority, income under 5 lakhs. how neet councillng will allocate my seat

Hello

Since you are a domicile of Karnataka and have studied under the Karnataka State Board for 11th and 12th , you are eligible for Karnataka State Quota for admission to various colleges in the state.

1. KCET (Karnataka Common Entrance Test): You must appear for the KCET exam, which is required for admission to undergraduate professional courses like engineering, medical, and other streams. Your exam score and rank will determine your eligibility for counseling.

2. Minority Income under 5 Lakh : If you are from a minority community and your family's income is below 5 lakh, you may be eligible for fee concessions or other benefits depending on the specific institution. Some colleges offer reservations or other advantages for students in this category.

3. Counseling and Seat Allocation:

After the KCET exam, you will need to participate in online counseling.

You need to select your preferred colleges and courses.

Seat allocation will be based on your rank , the availability of seats in your chosen colleges and your preferences.

4. Required Documents :

Domicile Certificate (proof that you are a resident of Karnataka).

Income Certificate (for minority category benefits).

Marksheets (11th and 12th from the Karnataka State Board).

KCET Admit Card and Scorecard.

This process will allow you to secure a seat based on your KCET performance and your category .

check link for more details

https://medicine.careers360.com/neet-college-predictor

Hope this helps you .

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Mitali Sharma 30 January,2025

show the previous year exams ?

Hello Aspirant, Hope your doing great, your question was incomplete and regarding what exam your asking.

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SWETCHCHA MISKA 10 July,2024

as an icse student in class 10 is above 80 percent good enough to get into commerce in 11th cbse

Yes, scoring above 80% in ICSE Class 10 exams typically meets the requirements to get into the Commerce stream in Class 11th under the CBSE board . Admission criteria can vary between schools, so it is advisable to check the specific requirements of the intended CBSE school. Generally, a good academic record with a score above 80% in ICSE 10th result is considered strong for such transitions.

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Manasvini Gupta 23 July,2024

i had cleared 10th from cbse in 2022 2 years ago now i wish to apply for 12th as private candidate in 2025. can i do so?

hello Zaid,

Yes, you can apply for 12th grade as a private candidate .You will need to follow the registration process and fulfill the eligibility criteria set by CBSE for private candidates.If you haven't given the 11th grade exam ,you would be able to appear for the 12th exam directly without having passed 11th grade. you will need to give certain tests in the school you are getting addmission to prove your eligibilty.

best of luck!

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Ashvadha 03 July,2024

i had cleared 10th in 2022 from cbse can i apply for 12th as private candidate this year?

According to cbse norms candidates who have completed class 10th, class 11th, have a gap year or have failed class 12th can appear for admission in 12th class.for admission in cbse board you need to clear your 11th class first and you must have studied from CBSE board or any other recognized and equivalent board/school.

You are not eligible for cbse board but you can still do 12th from nios which allow candidates to take admission in 12th class as a private student without completing 11th.

Read Complete Answer

sadafreen356 03 July,2024

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Central Board of Secondary Education Class 10th Examination

Applications Open

Option 1) $0.34\; J$	Option 2) $0.16\; J$
Option 3) $1.00\; J$	Option 4) $0.67\; J$

Option 1) $2,000 \; J - 5,000\; J$	Option 2) $200 \, \, J - 500 \, \, J$
Option 3) $2\times 10^{5}J-3\times 10^{5}J$	Option 4) $20,000 \, \, J - 50,000 \, \, J$

Option 1) $K/2\,$	Option 2) $\; K\;$
Option 3) $zero\;$	Option 4) $K/4$

Option 1) $11.2\, L\, H_{2(g)}$ at STP is produced for every mole $HCL_{(aq)}$ consumed	Option 2) $6L\, HCl_{(aq)}$ is consumed for ever $3L\, H_{2(g)}$ produced
Option 3) $33.6 L\, H_{2(g)}$ is produced regardless of temperature and pressure for every mole Al that reacts	Option 4) $67.2\, L\, H_{2(g)}$ at STP is produced for every mole Al that reacts .

Option 1) 0.02	Option 2) 3.125 × 10^-2
Option 3) 1.25 × 10^-2	Option 4) 2.5 × 10^-2

Option 1) decrease twice	Option 2) increase two fold
Option 3) remain unchanged	Option 4) be a function of the molecular mass of the substance.

Option 1) Molality	Option 2) Weight fraction of solute
Option 3) Fraction of solute present in water	Option 4) Mole fraction.

Option 1) twice that in 60 g carbon	Option 2) 6.023 × 10²²
Option 3) half that in 8 g He	Option 4) 558.5 × 6.023 × 10²³

Option 1) less than 3	Option 2) more than 3 but less than 6
Option 3) more than 6 but less than 9	Option 4) more than 9

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NCERT Solutions for Class 10 Science Chapter 10 - The Human Eye and The Colorful World

NCERT Solutions for Class 10 Science Chapter 10: Download Solution PDF

NCERT Class 10 Science Chapter 10: Intext Solutions

Topic 10.2 - Defects of vision and their correction

The Human Eye and The Colorful World Exercise Solutions

NCERT Solutions for Class 10 Science Chapter 10: Important Diagrams

Human Eye

Dispersion of White Light in A Prism

Rainbow Formation

NCERT Solutions for Class 10 Science Chapter 10 The Human Eye and The Colorful World: Important Topics

NEET/JEE Coaching Scholarship

JEE Main Important Mathematics Formulas

Human Eye and Colourful World Class 10: Types of Questions Asked

NCERT Class 10 Science Solutions Chapter 10: Weightage in Board Exams

NCERT Solutions for Class 10 Science Chapter 10: Important Highlights

Class 10 Science Chapter 10 NCERT Solutions: Summary

NCERT Solutions for Class 10 Science: Chapter Wise

Frequently Asked Questions (FAQs)