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NCERT exemplar Class 9 Maths solutions chapter 12 details Heron’s formula and related questions. The Heron's formula helps in finding the areas of triangles if side lengths are given. The NCERT exemplar Class 9 Maths chapter 12 solutions are highly accurate and elaborate in nature (prepared by experienced subject experts at Careers 360) and provides an outstanding approach to study NCERT Class 9 Maths. These NCERT exemplar Class 9 Maths chapter 10 solutions build a strong foundation of Heron’s Formula, also these NCERT exemplar Class 9 Maths solutions chapter 12 follow the syllabus recommended by the CBSE.
Also, read - NCERT Solutions for Class 9 Maths
Question:1
An isosceles right triangle has area . The length of its hypotenuse is
(A)
(B)
(C)
(D)
Answer:
An isosceles right triangle is given.Question:2
The perimeter of an equilateral triangle is 60 m. The area is
(A)
(B)
(C)
(D)
Answer:
[D]Question:3
The sides of a triangle are 56 cm, 60 cm and 52 cm long. Then the area of the triangle is
(A) 1322 cm^{2}
(B) 1311 cm^{2}
(C) 1344 cm^{2}
(D) 1392 cm^{2}
Answer:
[C]Question:4
The area of an equilateral triangle with side 2 cm is
(A) 5.196 cm^{2}
(B) 0.866 cm^{2}
(C) 3.496 cm^{2}
(D) 1.732 cm^{2}
Answer:
[A] Given side of equilateral triangleQuestion:5
The length of each side of an equilateral triangle having an area of is
(A) 8 cm
(B) 36 cm
(C) 4 cm
(D) 6 cm
Answer:
[D]Question:6
If the area of an equilateral triangle is , then the perimeter of the triangle is:
(A) 48 cm
(B) 24 cm
(C) 12 cm
(D) 36 cm
Answer:
[B]Question:7
The sides of a triangle are 35 cm, 54 cm and 61 cm, respectively. The length of its longest altitude
(A)
(B)
(C)
(D) 28
Answer:
Question:8
The area of an isosceles triangle having base 2 cm and the length of one of the equal sides 4 cm, is
(A)
(B)
(C)
(D)
Answer:
^{[A]}
^{}
^{}
^{}
^{}
^{}
^{Using Heron’s formula area of ABC }
^{}
^{}
^{}
^{Hence, area of given triangle is .}
Question:9
The edges of a triangular board are 6 cm, 8 cm and 10 cm. The cost of painting it at the rate of 9 paise per is
(A) Rs 2.00
(B) Rs 2.16
(C) Rs 2.48
(D) Rs 3.00
Answer:
[B]Question:1
Write True or False and justify your answer:
The area of a triangle with base 4 cm and height 6 cm is 24
Answer:
[False]Question:2
Write True or False and justify your answer:
The area of ABC is 8 in which AB = AC = 4 cm and A =
Answer:
[True]Question:3
Write True or False and justify your answer:
The area of the isosceles triangle is , if the perimeter is 11 cm and the base is 5 cm.
Answer:
[True]Question:4
Answer:
[False]Question:5
Write True or False and justify your answer:
If the side of a rhombus is 10 cm and one diagonal is 16 cm, the area of the rhombus is 96 .
Answer:
[True]Question:6
Answer:
[False]Question:7
Answer:
[False]Question:8
Answer:
[True]Question:9
Answer:
TrueQuestion:1
Find the cost of laying grass in a triangular field of sides 50 m, 65 m and 65 m at the rate of Rs
Answer:
Question:2
Answer:
Question:3
Answer:
Question:4
Answer:
Question:5
Answer:
Question:6
Answer:
Question:7
Answer:
Question:8
Answer:
Question:9
Answer:
[Rs. 960]Question:10
Find the area of the trapezium PQRS with height PQ given in Figure.
Answer:
Question:1
Answer:
Question:2
Answer:
Question:3
Answer:
Question:4
Answer:
Question:5
Answer:
Question:6
Answer:
AB = 7.5 cm, AC = 6.5 cm, BC = 7 cm
Let a = 7.5 cm, b = 6.5 cm, c = 7 cm
According to question,
Question:7
Answer:
Question:8
Answer:
Key topics covered in NCERT exemplar Class 9 Maths solutions chapter 12 are:
These Class 9 Maths NCERT exemplar chapter 12 solutions provide a basic knowledge of how Heron’s formula can be used to find out the area of a triangle without calculating any angle or any other distance except the length of sides. The proof of this formula can be obtained in a book named Metrica. This formula can be proved by the use of trigonometry in modern mathematics. The practice problems provided in the exemplar are explained in a highly elaborate way through Class 9 Maths NCERT exemplar solutions chapter 12 Heron’s formula and prove to be adequate for solving other books such as NCERT Class 9 Maths, RD Sharma Class 9 Maths, Mathematics Pearson Class 9, RS Aggarwal Class 9 Maths etcetera.
NCERT exemplar Class 9 Maths solutions chapter 12 pdf download allows the users to use the pdf version of these solutions and can be used while attempting NCERT exemplar Class 9 Maths chapter 12 in an offline environment. The web page can be downloaded using any existing options to download the web page.
Chapter No. | Chapter Name |
Chapter 1 | |
Chapter 2 | |
Chapter 3 | |
Chapter 4 | |
Chapter 5 | |
Chapter 6 | |
Chapter 7 | |
Chapter 8 | |
Chapter 9 | |
Chapter 10 | |
Chapter 11 | |
Chapter 12 | |
Chapter 13 | |
Chapter 14 | |
Chapter 15 |
Yes, we can find out the area of any triangle if three sides of a triangle are known by using the heron’s formula.
No, we can use heron’s formula to find out the area of any triangle if sides are given.
In an equilateral triangle, all sides have equal length, therefore if we know the perimeter of triangle, we know each side length. Now by using hero formula we can find out area of this equilateral triangle.
We can find out area of triangle by two methods. If we know the base length and height of triangle then half of their product will give the area of triangle. If we know three sides of the triangle, we can use hero formula to find out area of triangle
This chapter concludes to around 5-7% marks of the final paper. Generally, the type of questions that can be expected from this chapter is MCQs and short answer-type questions. NCERT exemplar Class 9 Maths solutions chapter 12 is adequate to practice, understand and score well in the examinations.
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