NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry

NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry - Download PDF

Edited By Ravindra Pindel | Updated on Feb 07, 2024 06:08 PM IST

NCERT Practical Geometry class 7 - The word geometry comprises of two greek words geo and metron. Geo means earth and metron means measurements. Geometry is applied in everyday life from designing simple things like your furniture, doors and windows, the wall clock to the design of complex structures like the designing of a new house. To design all the above structures you need to know about geometry. In CBSE NCERT solutions for Class 7 Maths chapter 10 Practical Geometry, you will get questions related to applications of geometry in real life. You will study a few rulers and compass constructions in this chapter. You will learn how to draw a parallel line to a given line through a point outside the line, how to construct triangles if three sides of triangle are given (SSS), how to construct a triangle if measure of two sides and the angle between them are given (SAS), how to draw a triangle if value of two angles and the length of side included between them are given (ASA), how to draw a triangle if length of hypotenuse and the measure of one leg of a right-angled triangle are given (RHS). There are practice questions given on all the above topics in the NCERT .

Latest: NCERT Class 7 Maths: Chapterwise Important Formulas with Examples and Points

This Story also Contains

NCERT Solutions for Maths Chapter 10 Practical Geometry Class 7th- Important Formulae
NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry - Important Points
NCERT Solutions for Maths Chapter 10 Practical Geometry Class 7th
NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry (Intext Questions and Exercise)
NCERT Solutions for Maths Chapter 10 Practical Geometry Class 7th Exercise 10.1
NCERT Solutions for Maths Chapter 10 Practical Geometry Class 7th Exercise 10.2
NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Exercise 10.3
NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Exercise 10.4
NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Exercise 10.5
Practical Geometry Class 7 Maths Chapter 10-Topics
Some applications of geometry

You should try to solve all these questions by yourself. You can take help from NCERT Solutions for Class 7 . While solving the problems learn the steps and draw the figures. Just only going through the steps of drawings may not help in the exams. If you have tried to draw all the figures mentioned in the solutions of NCERT for Class 7 Maths chapter 10 Practical Geometry it will be easy for you solve all the questions in the exam related to this chapter. You can get NCERT Solutions from Classes 6 to 12 for Science and Maths by clicking on the above link. Here you will get solutions to five exercises of this chapter.

NCERT Solutions for Maths Chapter 10 Practical Geometry Class 7th- Important Formulae

Criteria for Congruence of Triangles:

SSS Congruence: For triangles ABC and DEF, If AB = DE, BC = EF, and AC = DF, Then △ABC ≅ △DEF.
SAS Congruence: For triangles ABC and DEF, If AB = DE, ∠BAC = ∠EDF, and BC = EF, Then △ABC ≅ △DEF.
ASA Congruence: For triangles ABC and DEF, If ∠BAC = ∠EDF, ∠ABC = ∠DEF, and AC = DF, Then △ABC ≅ △DEF.
AAS Congruence: For triangles ABC and DEF, If ∠BAC = ∠EDF, ∠ACB = ∠EFD, and BC = EF, Then △ABC ≅ △DEF.
RHS Congruence: For right-angled triangles ABC and DEF, If ∠CAB = ∠FDE, AC = DF, and BC = EF, Then △ABC ≅ △DEF.

For more, Download Ebook - NCERT Class 7 Maths: Chapterwise Important Formulas And Points

NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry - Important Points

Five Measurements Determine a Quadrilateral:

A quadrilateral can be uniquely determined when five measurements related to its sides and angles are known.

Construction with Four Sides and a Diagonal:

If the lengths of all four sides and one diagonal of a quadrilateral are given, the quadrilateral can be constructed uniquely.

Construction with Diagonals and Three Sides:

When the lengths of both diagonals and three sides of a quadrilateral are known, the quadrilateral can be constructed uniquely.

Construction with Adjacent Sides and Angles:

If the lengths of two adjacent sides and the measures of three angles of a quadrilateral are provided, the quadrilateral can be constructed uniquely.

Construction with Three Sides and Included Angles:

If the lengths of three sides and the measures of two angles included between those sides are given, the quadrilateral can be constructed uniquely.

Free download NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry PDF for CBSE Exam.

NCERT Solutions for Maths Chapter 10 Practical Geometry Class 7th

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NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry (Intext Questions and Exercise)

NCERT Solutions for Maths Chapter 10 Practical Geometry Class 7th Exercise 10.1

Question:1 Draw a line, say AB, take a point C outside it. Through C, draw a line parallel to AB using ruler and compasses only.

Answer:

1. Draw the line AB

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2. Mark any point C outside AB and a point D on AB

3. Join CD

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4. Draw an arc with convenient radius with D as centre cutting AB at E and DC at F

5. With the same radius as in step 4 draw an arc IGH with C as a centre and cutting line AC at G.

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6 Place one tip of the compass on E and adjust the opening so that pencil tip touches at F.

7. With the same opening in step 6 and G as centre cut an arc at J on IGH.

8. Join CJ and extend the line. This line will be parallel to AB

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Question:2 Draw a line $l$ . Draw a perpendicular to $l$ at any point on $l$ . On this perpendicular choose a point X, 4 cm away from l. Through X, draw a line m parallel to $l$ .

Answer:

1. Draw a line l. Mark a point P on the line

2. With p as a centre and with any radius draw an arc which touches the line at A and B

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3. Take a length more than AP with A as centre draw an arc. with the same length on compass and B as centre draw an arc to cut the previous arc at Q.

4. Join PQ. PQ is perpendicular to the line l

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5. Take 4 cm on the compass and with P as centre cut an arc on line PQ at C. The length PC=4 cm

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6. with P as a centre and any radius, draw an arc to cut line l at D and PQ at E.

7. with the same radius as in step 6 draw an arc GF with centre C so that it cuts the line PQ at G.

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8. Take the length DE on the compass and with G as centre draw an arc to cut FG at J

9. Join CJ and extend the line to name it as line m. Now the line l is parallel to line m

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Question:3 Let $l$ be a line and P be a point not on $l$ . Through P, draw a line m parallel to $l$ . Now join P to any point Q on $l$ . Choose any other point R on m. Through R, draw a line parallel to PQ. Let this meet $l$ at S. What shape do the two sets of parallel lines enclose?

Answer:

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1. Draw the line PQ parallel to l using the steps to draw parallel lines

2. Draw the line RS parallel to PQ using the steps to draw parallel lines

the two parallel lines make the shape of a parallelogram PQRS.

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NCERT Solutions for Maths Chapter 10 Practical Geometry Class 7th Exercise 10.2

Question:1 Construct $\Delta XYZ$ in which XY= 4.5 cm, YZ = 5 cm and ZX = 6 cm.

Answer:

$\Delta XYZ$ in which XY= 4.5 cm, YZ = 5 cm and ZX = 6 cm :

1. Draw a line XY = 4.5 cm

2. with x as centre and length= 6cm draw an arc

3. with y as centre and length = 5cm draw another arc to cut the arc drawn in step 2 at Z

4. Join XZ and YZ. XYZ is the required triangle

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Question:2 Construct an equilateral triangle of side 5.5 cm.

Answer:

an equilateral triangle of side 5.5 cm :

1. Draw a line AB = 5.5 cm

2. with A as centre and length= 5.5cm draw an arc

3. with B as centre and length = 5.5cm draw another arc to cut the arc drawn in step 2 at C

4. Join AC and BC.ABC is the required triangle

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Question:3 Draw ?PQR with PQ = 4 cm, QR = 3.5 cm and PR = 4 cm. What type of triangle is this?

Answer:

PQR with PQ = 4 cm, QR = 3.5 cm and PR = 4 cm:

1.Draw a line QR = 3.5 cm

2. With Q as centre and length = 4 cm draw an arc

3. With R as centre and length = 4cm draw another arc to cut the previous arc at P

4. Join QP and QR. Then PQR is the required triangle

1643174049602 1643174083055

As we can see two sides of the triangle are same so The triangle is an isosceles triangle.

Question:4 Construct $\Delta ABC$ such that AB = 2.5 cm, BC = 6 cm and AC = 6.5 cm. Measure $\angle B$ .

Answer:

$\Delta ABC$ such that AB = 2.5 cm, BC = 6 cm and AC = 6.5 cm. Measure $\angle B$ :

1. Draw a line AB = 2.5 cm

2. with A as centre and length= 6.5cm draw an arc

3. with B as centre and length = 6cm draw another arc to cut the arc drawn in step 2 at C

4. Join AC and BC. ABC is the required triangle

1643174148746 1643174176580

On measuring angle B comes out to be 90 degrees.

NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Exercise 10.3

Question:1 Construct $\Delta DEF$ such that DE = 5 cm, DF = 3 cm and $m\angle EDF=90^{\circ}$ .

Answer:

$\Delta DEF$ such that DE = 5 cm, DF = 3 cm and $m\angle EDF=90^{\circ}$ :

1. Draw a line DE = 5cm

2. Draw a line DX making 90 degrees with DE.

3. cut the length DF =3cm using the compass on the line DX

4. Join E and F

DEF is the required triangle

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Question:2 Construct an isosceles triangle in which the lengths of each of its equal sides is 6.5 cm and the angle between them is $110^{\circ}$ .

Answer:

1. Draw a line DE = 6.5 cm

2. Draw a line DX making 110 degrees with DE.

3. cut the length DF =6.5 cm using the compass on the line DX

4. Join E and F

DEF is the required triangle

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Question:3 Construct $\Delta ABC$ with BC = 7.5 cm, AC = 5 cm and $m\angle C=60^{\circ}$ .

Answer:

$\Delta ABC$ with BC = 7.5 cm, AC = 5 cm and $m\angle C=60^{\circ}$ :

1. Draw a line AC = 5 cm

2. Draw a line CX making 60 degrees with AC from C.

3. cut the length BC =7.5 cm using the compass on line CX

4. Join A and B

ABC is the required triangle

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NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Exercise 10.4

Question:1 Construct $\Delta ABC$ , given $m\angle A=60^{\circ}$ , $m\angle B=30^{\circ}$ and AB = 5.8 cm.

Answer:

$\Delta ABC$ , given $m\angle A=60^{\circ}$ , $m\angle B=30^{\circ}$ and AB = 5.8 cm :

1. Draw the line AB=5.8 cm

2. At A making an angle 60 degrees with AB draw a line AX

3. At B making an angle 30 degrees with AB draw a line BY

4. The lines AX and BY intersect at C ( in case the drawn line AX or BY is small extend it to intersect each other)

ABC is the requires triangle

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Question:2 Construct $\Delta PQR$ if PQ = 5 cm, $m\angle PQR = 105^{\circ}$ and $m\angle QRP = 40^{\circ}$ .

Answer:

$\Delta PQR$ if PQ = 5 cm, $m\angle PQR = 105^{\circ}$ and $m\angle QRP = 40^{\circ}$ :

the sum of angles of a triangle is 180 degrees. Given angles PQR and QRP, so the angle QPR= 180-(105+40)=35 degrees

1. Draw the line PQ=5 cm

2. At Q making an angle 105 degrees with PQ draw a line QY

3. At P making an angle 35 degrees with PQ draw a line PX

4. The lines PX and QY intersect at R ( in case the drawn line PX or QY is small extend it to intersect each other)

PQR is the required triangle

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Question:3 Examine whether you can construct $\Delta DEF$ such that EF = 7.2 cm, $m\angle E = 110^{\circ}$ and $m\angle F = 80^{\circ}$ . Justify your answer.

Answer:

No, we cannot construct such that EF = 7.2 cm, $m\angle E = 110^{\circ}$ and $m\angle F = 80^{\circ}$ . This is because of the property of the triangle of having a sum of internal angles equal to 180 degrees. if we have $m\angle E = 110^{\circ}$ , then we cannot have $m\angle F = 80^{\circ}$ because then the sum would exceed 180 degree which is impossible.

NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Exercise 10.5

Question:1 Construct the right angled $\Delta PQR$ , where $\angle Q=90^{\circ}$ , QR = 8cm and PR = 10 cm.

Answer:

the right-angled $\Delta PQR$ , where $\angle Q=90^{\circ}$ , QR = 8cm and PR = 10 cm:

1. Draw QR = 8 cm

2. Draw a perpendicular QX to QR at Q

3. From R and with length = 10 cm cut an arc on QX. The arc meet QX at P

4. Join PR

PQR is the required triangle

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Question:2 Construct a right-angled triangle whose hypotenuse is 6 cm long and one of the legs is 4 cm long.

Answer:

a right-angled triangle whose hypotenuse is 6 cm long and one of the legs is 4 cm long:

1. Draw QR = 4 cm

2. Draw a perpendicular QX to QR at Q

3. From R and with length = 6 cm cut an arc on QX. The arc meet QX at P

4. Join PR

Triangle PQR is the required triangle

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Question:3 Construct an isosceles right-angled triangle ABC, where $m\angle ACB=90^{\circ}$ and AC = 6 cm.

Answer:

1. Draw CA = 6 cm

2. Draw a perpendicular CX to CA at C

3. From C and with length = 6 cm cut an arc on CX. The arc meet CX at B

4. Join BA

Triangle ABC is the required triangle

Practical Geometry Class 7 Maths Chapter 10-Topics

Construction Of A Line Parallel To A Given Line, Through A Point Not On The Line
Construction Of Triangles
Constructing A Triangle When The Lengths Of Its Three Sides Are Known (Sss Criterion)
Constructing A Triangle When The Lengths Of Two Sides And The Measure Of The Angle Between Them Are Known. (Sas Criterion)
Constructing A Triangle When The Measures Of Two Of Its Angles And The Length Of The Side Included Between Them Is Given. (Asa Criterion)
Constructing A Right-angled Triangle When The Length Of One Leg And Its Hypotenuse Are Given (Rhs Criterion )

NCERT Solutions for Class 7 Maths Chapter Wise

Chapter No.	Chapter Name
Chapter 1	Integers
Chapter 2	Fractions and Decimals
Chapter 3	Data Handling
Chapter 4	Simple Equations
Chapter 5	Lines and Angles
Chapter 6	The Triangle and its Properties
Chapter 7	Congruence of Triangles
Chapter 8	Comparing quantities
Chapter 9	Rational Numbers
Chapter 10	Practical Geometry
Chapter 11	Perimeter and Area
Chapter 12	Algebraic Expressions
Chapter 13	Exponents and Powers
Chapter 14	Symmetry
Chapter 15	Visualising Solid Shapes

NCERT Solutions for Class 7 Subject Wise

NCERT Solutions for Class 7 Maths

NCERT Solutions for Class 7 Science

Some applications of geometry

Construction works:- For the construction of houses, bridges, buildings, roads, tanks, dams, etc you need to have knowledge of geometry otherwise you cant do these things with better accuracy. In NCERT solutions for class 7 maths chapter 10 practical geometry, you have learnt some basics of geometry which will help you in higher study.
Games:- In all the computer games or mobile games, you will see particular patterns, maps, 2D and 3D images etc. To designing all these thing you need to have knowledge of geometry.
Art:- Artist uses the geometry to organise the arrangement of space in a picture.
Architecture:- Architect use knowledge of geometry to transform the build the material of architectural design.
Sports:- From designing the pitch, the boundary in cricket to draw the lines in tennis court you need to have knowledge of geometry.

In CBSE NCERT solutions for Class 7 Maths chapter 10 Practical Geometry, you have learnt some fundamental of geometry for simple mathematical geometry. There are many other applications of geometry in the field of designing, civil engineering, CAD(computer-aided design), mapping, GPS and many more which you will learn in higher classes.

Happy Reading!!!

Also Check NCERT Books and NCERT Syllabus here:

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NCERT Solutions for Class 7 Science Chapter 13 Motion and Time

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