Browse by Stream
My Companion New
Search Colleges, Exams, Schools & more

NCERT Solutions for Class 7 Maths Chapter 7 Congruence of Triangles

Updated on Jul 28, 2020 - 12:39 p.m. IST by Ravindra Pindel

NCERT solutions for class 7 maths chapter 7 Congruence of Triangles- Congruence of triangles is one of the important topics of the geometry. In this chapter, there are two exercises and topic wise practice questions. The solutions of NCERT class 7 chapter 7 congruence of triangles give detailed explanations to all these questions. Students can do their homework easily if they have a tool like NCERT solutions for class 7 in hand. In geometry, two objects or two figures are congruent if they have the same dimension and same shape, or in other words, we can say that two objects or figures are congruent if both are exact copies of one another. The relation of two objects or two figures being congruent is called congruence. NCERT class 7 maths chapter 7 congruence of triangles deal with plane figures or 2D only, although congruence is a general concept applicable to 3D figures also. Congruence of plane figures, congruence among line segments, congruence of angles, congruence of triangles, some criteria for congruence of triangles like SSS congruence of two triangles, SAS congruence of two triangles, ASA congruence of two triangles, RHS congruence of two right-angled triangles are the concepts which are covered in this chapter. Questions on all these concepts are discussed in the NCERT solutions for class 7 maths chapter 7 congruence of triangles. The NCERT solutions are prepared in such a manner that students are able to understand the concepts easily and prepare themselves very well for CBSE final exams to score higher marks. Here you will get solutions to two exercises in NCERT .

Latest :  Trouble with homework? Post your queries of Maths and Science with step-by-step solutions instantly. Ask Mr AL

Topics of NCERT Grade 7 Maths Chapter 7 Congruence of Triangles

7.1 Introduction

7.2 Congruence of Plane Figures

7.3 Congruence among Line Segments

7.4 Congruence of Angles

7.5 Congruence of Triangles

7.6 Criteria for Congruence of Triangles

7.7 Congruence among Right-Angled Triangles

NCERT solutions for class 7 maths chapter 7 congruence of triangles topic 7.5

1. When two triangles, say ABC and PQR are given, there are, in all, six possible matchings or correspondences. Two of them are:

(i) ABC\leftrightarrow PQR and (ii) ABC\leftrightarrow QRP

Find the other four correspondences by using two cutouts of triangles. Will all these correspondences lead to congruence? Think about it.

Answer:

the other four correspondences by using two cutouts of triangles are :

(i) ABC\leftrightarrow RPQ

(ii) BCA\leftrightarrow PQR

(iii) CAB\leftrightarrow PQR

(iv) CBA \leftrightarrow PQR

NCERT solutions for class 7 chapter 7 congruence of triangles topic 7.6

1. In Fig 7.14, lengths of the sides of the triangles are indicated. By applying the SSS congruence rule, state which pairs of triangles are congruent. In case of congruent triangles, write the result in symbolic form:

Answer:

i) Since

AB = PQ

BC = QR

CA = PR

So, by SSS congruency rule both triangles are congruent to each other.

\Delta ABC \cong\Delta PQR


ii) Since,

ED = MN

DF = NL

FE = LM

So, by SSS congruency rule both triangles are congruent to each other.

\Delta EDF\cong\Delta MNL .

iii) Since

AC = PR

BC = QR But

AB\neq QR

So the given triangles are not congruent.

iv) Since,

AD = AD

AB = AC

BD = CD

So, By SSS Congruency rule, they both are congruent to each other.

\Delta ADB\cong\Delta ADC .

2. In Fig 7.15, AB=AC and D is the mid-point of \overline{BC}. .

(i) State the three pairs of equal parts in \Delta ADB and \Delta ADC.
(ii) Is \Delta ADB\cong \Delta ADC ? Give reasons.
(iii) Is \angle B = \angle C ? Why?

Answer:

Here in \Delta ADB and \Delta ADC.

i) Three pair of equal parts are:

AD = AD ( common side )

BD = CD ( as d is the mid point of BC)

AB = AC (given in the question)

ii) Now,

by SSS Congruency rule,

\Delta ADB\cong \Delta ADC

iii) As both triangles are congruent to each other we can compare them and say

\angle B = \angle C .

3. In Fig 7.16, AC=BD and AD=BC. . Which of the following statements is meaningfully written?

(i) \Delta ABC\cong \Delta ABD (ii) \Delta ABC\cong \Delta BAD

Answer:

Given,

AC=BD and

AD=BC. .

AB = AB ( common side )

So By SSS congruency rule,

\Delta ABC\cong \Delta BAD .

So this statement is meaningfully written as all given criterions are satisfied in this.

1. ABC is an isosceles triangle with AB=AC (Fig 7.17). Take a trace-copy of \Delta ABC and also name it as \Delta ABC
(i) State the three pairs of equal parts in \Delta ABC \; and \: \Delta ACB .
(ii) Is \Delta ABC \cong \Delta ACB ? Why or why not?
(iii) Is \angle B = \angle C ? Why or why not?

Answer:

Here, in \Delta ABC \; and \: \Delta ACB .

i)the three pairs of equal parts in \Delta ABC \; and \: \Delta ACB are

AB = AC

BC = CB

AC = AB

ii)

Hence By SSS Congruency rule, they both are congruent.

\Delta ABC \cong \Delta ACB

iii) Yes, \angle B = \angle C because \Delta ABC \; and \: \Delta ACB are congruent and by equating the corresponding parts of the triangles we get,

\angle B = \angle C .

1. Which angle is included between the sides \overline{DE} and \overline{EF} of \bigtriangleup DEF ?

Answer:

Since both the sides \overline{DE} and \overline{EF} intersects at E,

\angle E is included between the sides \overline{DE} and \overline{EF} of \bigtriangleup DEF .

2. By applying SAS congruence rule, you want to establish that \bigtriangleup PQR\cong \bigtriangleup FED . It is given that PQ= FE and RP= DF . What additional information is needed to establish the congruence?

Answer:

To prove congruency by SAS rule, we need to equate two corresponding sides and one corresponding angle,

so in proving \bigtriangleup PQR\cong \bigtriangleup FED we need,

PQ= FE

RP= DF

And

\angle P = \angle F .

Hence the extra information we need is \angle P = \angle F .

3. In Fig 7.24, measures of some parts of the triangles are indicated. By applying SAS congruence rule, state the pairs of congruent triangles, if any, in each case. In case of congruent triangles, write them in symbolic form.

Answer:

i) in \Delta ABC and \Delta DEF

AB = DE

AC = DF

\angle A \neq \angle D

Hence, they are not congruent.


ii) In \Delta ACB and \Delta RPQ

AC = RP = 2.5 cm

CB = PQ = 3 cm

\angle C = \angle P = 35^0

Hence by SAS congruency rule, they are congruent.

\Delta ACB \cong\Delta RPQ .


iii) In \Delta DFE and \Delta PQR

DF= PQ = 3.5 cm

FE= QR = 3 cm

\angle F = \angle Q

Hence, by SAS congruency rule, they are congruent.

\Delta DFE\cong\Delta PQR


iv) In \Delta QPR and \Delta SRP

QP = SR = 3.5 cm

PR = RP (Common side)

\angle QPR = \angle SRP

Hence, by SAS congruency rule, they are congruent.

\Delta QPR\cong\Delta SRP .

1. What is the side included between the angles M and N of \bigtriangleup M\! N\! P ?

Answer:

The side MN is the side which is included between the angles M and N of \bigtriangleup M\! N\! P .

2. You want to establish \bigtriangleup DEF\cong \bigtriangleup MNP , using the ASA congruence rule. You are given that \angle D= \angle M and \angle F= \angle P . What information is needed to establish the congruence? (Draw a rough figure and then try!)

Answer:

As we know, in ASA congruency two angles and one side is equated to their corresponding parts. So

To Prove \bigtriangleup DEF\cong \bigtriangleup MNP

\angle D= \angle M

\angle F= \angle P

And The side joining these angles is

\overline {DF}= \overline {MP} .

So the information that is needed in order to prove congruency is \overline {DF}= \overline {MP} .

4. In Fig 7.25, \overline{AB} and \overline{CD} bisect each other at O .

(i) State the three pairs of equal parts in two triangles AOC and BOD .

(ii) Which of the following statements are true?

(a) \bigtriangleup AOC\cong \bigtriangleup DOB
(b) \bigtriangleup AOC\cong \bigtriangleup BOD

Answer:

i) The three pairs of equal parts in two triangles AOC and BOD are:

CO = DO (given)

OA = OB (given )

\angle COA = \angle DOB ( As opposite angles are equal when two lines intersect.)

ii) So by SAS congruency rule,

\Delta COA \cong\Delta DOB

that is

\bigtriangleup AOC\cong \bigtriangleup BOD

Hence, option B is correct.

3. In Fig 7.27, measures of some parts are indicated. By applying ASA congruence rule, state which pairs triangles are congruent. In case of congruence, write the result in symoblic form.

Answer:

i) in \Delta ABC and \Delta FED

AB = FE = 3.5 cm

\angle A = \angle F = 40 ^0

\angle B = \angle E = 60^0

So by ASA congruency rule, both triangles are congruent.i.e.

\Delta ABC \cong \Delta FED

ii) in \Delta PQR and \Delta FDE

\angle Q= \angle D= 90 ^0

\angle R= \angle E = 50^0

But,

\overline {EF}\neq\overline {RP}

So, given triangles are not congruent.

iii) in \Delta RPQ and \Delta LMN

RQ = LN = 6 cm

\angle R = \angle L = 60 ^0

\angle Q= \angle N= 30^0

So by ASA congruency rule, both triangles are congruent.i.e.

\Delta RPQ\cong \Delta LMN .

iv) in \Delta ADB and \Delta BCA

AB = BA (common side)

\angle CAB = \angle DBA= 30 ^0

\angle D= \angle C=180^0-30^0-30^0-45^0=75^0

So by ASA congruency rule, both triangles are congruent.i.e.

\Delta ADB \cong \Delta BCA

4. Given below are measurements of some parts of two triangles. Examine whether the two triangles are congruent or not, by ASA congruence rule. In the case of congruence, write it in symbolic form.

\bigtriangleup DEF \bigtriangleup PQR

(i)\angle D= 60^{o},\angle F= 80^{o},DF= 5cm \angle Q= 60^{o},\angle R= 80^{o},QR= 5cm
(ii)\angle D= 60^{o},\angle F= 80^{o},DF= 6cm \angle Q= 60^{o},\angle R= 80^{o},QP= 6cm
(iii)\angle D= 80^{o},\angle F= 30^{o},EF= 5cm \angle P= 80^{o},PQ= 5 cm,\angle R= 30^{o}


Answer:

i)

Given in \bigtriangleup DEF and \bigtriangleup PQR .

\\\angle D=\angle Q= 60^{o}\\\angle F=\angle R= 80^{o}\\DF=QR= 5cm

So, by ASA congruency criterion, they are congruent to each other.i.e.

\bigtriangleup DEF\cong\Delta QPR .

ii)

Given in \bigtriangleup DEF and \bigtriangleup PQR .

\\\angle D=\angle Q= 60^{o}\\\angle F=\angle R= 80^{o}\\DF=QP= 6cm

For congruency by ASA criterion, we need to be sure of equity of the side which is joining the two angles which are equal to their corresponding parts. Here the side QR is not given which is why we cannot conclude the congruency of both the triangles.

iii)

Given in \bigtriangleup DEF and \bigtriangleup PQR .

\\\angle D=\angle Q= 60^{o}\\\angle F=\angle R= 80^{o}\\DF=QP= 6cm

For congruency by ASA criterion, we need to be sure of equity of the side which is joining the two angles which are equal to their corresponding parts. Here the side QR is not given which is why we cannot conclude the congruency of both the triangles.

5. In Fig 7.28, ray AZ bisects \angle DAB as well as \angle DCB .

(i) State the three pairs of equal parts in triangles BAC and DAC .
(ii) Is \Delta BAC\cong \Delta DAC ? Give reasons.
(iii) Is AB = AD ? Justify your answer.
(iv) Is CD = CB \; ? Give reasons.


Answer:

i)

Given in triangles BAC and DAC

\angle DAC=\angle BAC

\angle DCA=\angle BCA

\overline {AC}=\overline {AC} ( common side)

ii)

So, By ASA congruency criterion,triangles BAC and DAC are congruent.

\Delta BAC\cong\Delta DAC

iii)

Since \Delta BAC\cong\Delta DAC , all corresponding parts will be equal. So

AB = AD .

iv)

Since \Delta BAC\cong\Delta DAC , all corresponding parts will be equal. So

CD = CB \;

NCERT solutions for class 7 maths chapter 7 congruence of triangles topic 7.7

1. In Fig 7.32, measures of some parts of triangles are given.By applying RHS congruence rule, state which pairs of triangles are congruent. In case of congruent triangles, write the result in symbolic form.

Answer:

i) In \Delta PQR and \Delta DEF

\angle Q = \angle E

PR = DF=6cm

PQ\neq DE

Hence they are not congruent.

ii)

In \Delta ACB and \Delta BDA

\angle D = \angle C

DB= AC=2cm

AB=BA ( same side )

So, by RHS congruency rule,

\Delta ACB\cong\Delta BDA

iii)

In \Delta ABC and \Delta ADC

\angle B = \angle D

AB= AD=3.6cm

AC=AC ( same side )

So, by RHS congruency rule,

\Delta ABC\cong\Delta ADC

iv)

In \Delta PSQ and \Delta PSR

\angle PSQ = \angle PSR

PQ= PR=3cm

PS=PS ( same side )

So, by RHS congruency rule,

\Delta PSQ\cong\Delta PSR


2. It is to be established by RHS congruence rule that \bigtriangleup ABC\cong \bigtriangleup RPQ . What additional information is needed, if it is given that

\angle B= \angle P= 90^{\underline{0}} and AB= RP?

Answer:

To prove congruency by RHS (Right angle, Hypotenuse, Side ) rule, we need hypotenuse and side equal to the corresponding hypotenuse and side of different angle.

So Given

\angle B= \angle P= 90^0 ( Right angle )

AB= RP. ( Side )

So the third information we need is the equality of Hypotenuse of both triangles. i.e.

AC= RQ

Hence, if this information is given then we can say,

\bigtriangleup ABC\cong \bigtriangleup RPQ .

3. In Fig 7.33, BD and CE are altitudes of \bigtriangleup ABC such that BD= CE .

(i) State the three pairs of equal parts in \bigtriangleup CBD and \bigtriangleup BCE .
(ii) Is \bigtriangleup CBD\cong \bigtriangleup BCE ? Why or why not?
(iii) Is \angle DCB= \angle EBC ? Why or why not?

Answer:

i) Given, in \bigtriangleup CBD and \bigtriangleup BCE .

BD= CE

\angle CEB=\angle BDC=90^o

\overline{ BC} = \overline{ CB}


ii) So, By RHS Rule of congruency, we conclude:

\bigtriangleup CBD\cong \bigtriangleup BCE


iii) Since both the triangle are congruent, all parts of one triangle are equal to their corresponding part from another triangle.

So.

\bigtriangleup CBD\cong \bigtriangleup BCE .

4. ABC is an isosceles triangle with AB= AC and AD is one of its altitudes (Fig 7.34).

(i) State the three pairs of equal parts in \bigtriangleup AD\! B and \bigtriangleup ADC .
(ii) Is \bigtriangleup ADB\cong \bigtriangleup ADC ? Why or why not?
(iii) Is \angle B= \angle C ? Why or why not?
(iv) Is BD= CD ? Why or why not?

Answer:

i) Given in \bigtriangleup AD\! B and \bigtriangleup ADC .

AB= AC

\angle ADB = \angle ADC=90^0

AD = AD ( Common side)


ii) So, by RHS Rule of congruency, we conclude

\bigtriangleup ADB\cong \bigtriangleup ADC


iii) Since both triangles are congruent all the corresponding parts will be equal.

So,

\angle B= \angle C


iv) Since both triangles are congruent all the corresponding parts will be equal.

So,

BD= CD .


NCERT solutions for class 7 maths chapter 7 congruence of triangles exercise 7.1

1. Complete the following statements:

(a) Two line segments are congruent if ___________.
(b) Among two congruent angles, one has a measure of 70^{o} ; the measure of the other angle is ___________.
(c) When we write \angle A = \angle B , we actually mean ___________.

Answer:

a) Two line segments are congruent if they are identical in shape and size and which is the case when the length of two line segments are equal.

b) 70^0 As the congruent things are a photocopy of each other.

c) When we write \angle A = \angle B , We mean that both the angles(A & B) are equal.

2. Give any two real-life examples for congruent shapes.

Answer:

Any two things that have identical shape and size are congruent like all the same kind of pens are congruent to one another. every same kind of bench in class are congruent to one another.all the similar football is congruent to one another.

3. If \Delta ABC\cong \Delta FED under the correspondence ABC\leftrightarrow FED, write all the corresponding congruent parts of the triangles.

Answer:

Corresponding parts of the two congruent triangles ABC\leftrightarrow FED, are :

Sides:

\overline {AB}\:\:and \:\:\overline {FE},

\overline {BC}\:\:and\:\:\overline {ED},

\overline {AC}\:\:and\:\:\overline {FD}.

Angles:

\angle {ABC}=\angle FED

\angle {BCA}=\angle EDF

\angle {CAB}=\angle DFE

4. If \Delta DEF \cong \Delta BCA, write the part(s) of \Delta BCA that correspond to

(i)\; \angle E (ii) \; \overline{EF} (iii) \; \angle F (iv) \; \overline{DF}

Answer:

Given,

\Delta DEF \cong \Delta BCA,

The part of \Delta BCA that correspond to

(i)\; \angle E=\angle C

(ii) \; \overline{EF}=\overline{CA}

(iii) \; \angle F=\angle A

(iv) \; \overline{DF}=\overline{BA}


NCERT solutions for class 7 maths chapter 7 congruence of triangles exercise 7.2

1.(a) Which congruence criterion do you use in the following?

\\(a)\: Given\; AC=DF

AB = DE

BC = EF

So,\; \; \Delta ABC \cong \Delta DEF

Answer:

Since we are comparing all the sides of two triangles, The SSS (side, side, side) Congruent criterion is used.

1.(b) Which congruence criterion do you use in the following?

(b)\; Given:ZX=RP

RQ = ZY

\angle PRQ =\angle XZY

So, \Delta PQR\cong \Delta XYZ

Answer:

Since we are comparing two sides and one angle of the two triangles, the SAS (sie, angle, side) congruent criterion is used to prove them congruent.

1.(c) Which congruence criterion do you use in the following?

(c)\; Given:\angle MLN=\angle FGH

\angle NML=\angle GFH

ML = FG

So,\; \Delta LMN\cong \Delta GFH

Answer:

Since we are comparing two angles and one side, ASA(Angle, Side, Angle) congruency criterion is used to prove the congruency.


1.(d) Which congruence criterion do you use in the following?

(d) Given:\; EB = DB

AE = BC

\angle A = \angle C = 90^{o}

So, \Delta ABE\cong \Delta CDB


Answer:

Since we are comparing two sides and one angle of the two triangles, the SSA (Side, Side, Angle) congruent criterion is used to prove the congruency.

2.(a) You want to show that \Delta ART\cong \Delta PEN,

(a) If you have to use SSS criterion, then you need to show

(i)AR= (ii)RT= (iii)AT=


Answer:

As we know that in the criterion of proving congruent, all three corresponding sides are equal to another. So to prove the congruency, we kneed to know the following things:

(i)AR=PE

(ii)RT= EN

(iii)AT= PN

2.(b) You want to show that \Delta ART\cong \Delta PEN,

(b) If it is given that \angle T=\angle N and you are to use SAS criterion, you need to have

(i)RT = \; \; \; \; \; \; \; \; \; \; \; \; \; and \; \; \; \; \; \; \; \; \; \; \; \; \; (ii)PN=


Answer:

As we know in SAS criterion the two sides and one angle are identical to their corresponding parts of another triangle. So to prove congruency we need to prove that,

\\(i)RT = EN\; \; \; \; \; \;\; \; \; and \; \; \; \; \; \; \; \; \; \; \; \; \; \\(ii)PN= AT

2.(c) You want to show that \Delta ART\cong \Delta PEN,

(c) If it is given that AT=PN and you are to use ASA criterion, you need to have

(i)?\; \; \; \; \; \; \; \; \; \; \; \; \; \; \;\; \; \; \; \; (ii)?

Answer:

Given, \Delta ART\cong \Delta PEN,

also, AT=PN

Now, As we know in the ASA criterion of proving congruency, the one and side two angles are equal to their corresponding parts. So,

(i)\:\angle{RAT}=\angle{EPN}

(ii)\:\angle{RTA}=\angle{ENP}



3. You have to show that \bigtriangleup AMP\cong \bigtriangleup AMQ . In the following proof, supply the missing reasons.

Steps Reasons
(i)PM= QM (i).......
(ii)\angle PMA = \angle QMA (ii).......
(iii)AM= AM (iii).......
(iv)\bigtriangleup AMP\cong \bigtriangleup AMQ (iv).......







Answer

Steps Reasons
(i)PM= QM Given in the question
(ii)\angle PMA = \angle QMA Given in the question.
(iii)AM= AM the side which is common in both triangle
(iv)\bigtriangleup AMP\cong \bigtriangleup AMQ By SAS Congruence Rule





4. In \bigtriangleup ABC , \angle A= 30^{o} , \angle B= 40^{o} and \angle C= 110^{o} .

In \bigtriangleup PQR , \angle P=30^{o} , \angle Q=40^{o} and \angle R=110^{o} . A student says that \bigtriangleup ABC\cong \bigtriangleup PQR by AAA congruence criterion. Is he justified? Why or why not?

Answer:

No, because it is not necessary that two triangles will be congruent if their all three corresponding angles are equal. in this case, the triangles might be zoomed copy of one another.

5. In the figure, the two triangles are congruent. The corresponding parts are marked. We can write \Delta RAT\cong ?


Answer:

Comparing from the figure.

R\leftrightarrow W,A\leftrightarrow O,\:and\:\:T\leftrightarrow N

By SAS Congruency criterion, we can say that

\Delta RAT\cong \Delta WON ]

6. Complete the congruence statement:

Answer:

Comparing from the figure, we get,

B\leftrightarrow B,A\leftrightarrow A,\:\:and\:\:C\leftrightarrow T

So By SSS Congruency Rule,

\Delta BCA\cong \Delta BTA

Also,

Comparing from the figure, we get,

P\leftrightarrow R,T\leftrightarrow Q,\:\:and\:\:Q\leftrightarrow S

So By SSS Congruency Rule,

\Delta QRS\cong \Delta TPQ .

7. In a squared sheet, draw two triangles of equal areas such that
(i) the triangles are congruent.
(ii) the triangles are not congruent.

What can you say about their perimeters?

Answer:

When two triangles are congruent, the corresponding parts are exactly identical so they have the same area and perimeter.

While the triangles are not congruent but have the same area, then the perimeter of both triangles are not equal.

8. Draw a rough sketch of two triangles such that they have five pairs of congruent parts but still the triangles are not congruent.

Answer:

Five pairs of congruent parts can be three pairs of sides and two pairs of angles. In that case, the SAS or ASA criterion would prove them to be congruent. Hence, such a figure is not possible.


9. If \Delta ABC and \Delta PQR are to be congruent, name one additional pair of corresponding parts. What criterion did you use?

Answer:

Given \Delta ABC \cong \Delta PQR

One additional pair which is not given in the figure is \overline {BC}=\overline {QR}

We used the ASA Criterion as the two corresponding angles are given and we figured out the side by congruency.

10. Explain, why \Delta ABC\cong \Delta FED

Answer:

Comparing both triangles, we have,

\angle A = \angle F

\angle B = \angle E=90^0

\overline {BC} = \overline {ED}

So By RHS congruency criterion,

\Delta ABC\cong \Delta FED .

NCERT Solutions for Class 7 Maths Chapter wise

Chapter No.

Chapter Name

Chapter 1

NCERT solutions for class 7 maths chapter 1 Integers

Chapter 2

NCERT solutions for class 7 maths chapter 2 Fractions and Decimals

Chapter 3

NCERT solutions for class 7 maths chapter 3 Data Handling

Chapter 4

NCERT solutions for class 7 maths chapter 4 Simple Equations

Chapter 5

NCERT solutions for class 7 maths chapter 5 Lines and Angles

Chapter 6

NCERT solutions for class 7 maths chapter 6 The Triangle and its Properties

Chapter 7

NCERT solutions for class 7 maths chapter 7 Congruence of Triangles

Chapter 8 NCERT solutions for class 7 maths chapter 8 comparing quantities

Chapter 9

NCERT solutions for class 7 maths chapter 9 Rational Numbers

Chapter 10

NCERT solutions for class 7 maths chapter 10 Practical Geometry

Chapter 11

NCERT solutions for class 7 maths chapter 11 Perimeter and Area

Chapter 12

NCERT solutions for class 7 maths chapter 12 Algebraic Expressions

Chapter 13

NCERT solutions for class 7 maths chapter 13 Exponents and Powers

Chapter 14

NCERT solutions for class 7 maths chapter 14 Symmetry

Chapter 15
NCERT solutions for class 7 maths chapter 15 Visualising Solid Shapes

NCERT Solutions for Class 7 Subject wise

NCERT solutions for class 7 maths

NCERT solutions for class 7 science

Important points of NCERT Class 7 Maths Chapter 7 Congruence of Triangles

Questions discussed in the NCERT solutions for class 7 maths chapter 7 congruence of triangles are based on the following congruence criteria.

  • SSS Congruence of two triangles- Under a given correspondence, two triangles are congruent if the three sides of the one triangle are equal in measure to the three corresponding sides of the other triangle.
  • SAS Congruence of two triangles- Under a given correspondence, two triangles are congruent if two sides and the angle included between them in one of the triangles are equal in measures to the corresponding sides and the angle included between them of the other triangle.
  • ASA Congruence of two triangles- Under a given correspondence, two triangles are congruent if two angles and the side included between them in one of the triangles are equal in measures to the corresponding angles and the side included between them of the other triangle.
  • RHS Congruence of two right-angled triangles- Under a given correspondence, two right-angled triangles are congruent if the hypotenuse and a leg of one of the triangles are equal to the hypotenuse and the corresponding leg of the other triangle.

Same questions described in the NCERT solutions for class 7 maths chapter 7 congruence of triangles can be expected for exams.

Solutions

Frequently Asked Question (FAQs) - NCERT Solutions for Class 7 Maths Chapter 7 Congruence of Triangles

Question: Whether the class 7 maths chapter Congruence of Triangles is useful in higher studies

Answer:

Yes, the chapter is important for higher studies in the field of maths and science and also in class 8, 9 and 10 maths also

Latest Articles

Jharkhand Scholarship 2020-21 (E-Kalyan Portal) - Apply Here

Jharkhand Scholarship 2020-21 - Students can check important d...

1 day ago
Read More
CBSE Class 9 Hindi Syllabus 2021 Reduced - Download Hindi A & ...

CBSE Class 9 Hindi Syllabus 2021 is available here to download...

37 minutes ago
Read More
CBSE Class 9 Social Science Syllabus 2021 reduced - Download P...

CBSE Class 9 Social Science Syllabus 2021 - CBSE prescribes th...

38 minutes ago
Read More
CBSE Class 9 Science Syllabus 2021 Reduced - Download Pdf Here

CBSE Class 9 Science Syllabus 2021 - Students can download CBS...

39 minutes ago
Read More
CBSE class 11 Chemistry syllabus 2021 (Theory & Practica) l - ...

CBSE class 11 Chemistry syllabus 2021 - Students can download ...

46 minutes ago
Read More
CBSE Class 11 English Syllabus 2021 - Download PDF

CBSE Class 11 English Syllabus 2021 - CBSE prescribes the Clas...

47 minutes ago
Read More
TN 11th Time Table 2021 - Check Tamil Nadu 11th Exam Time Tabl...

TN 11th Time Table 2021 - Directorate of Government Examinatio...

2 days ago
Read More
IEO Result 2020-2021 - Check SOF IEO Level 1 & 2 Merit List Here

IEO Result 2020-2021 -Science Olympiad Foundation will release...

2 days ago
Read More
NSO Result 2020-21 - Check SOF NSO Result for Level 1 Here

NSO Result 2020-21 - SOF will declare the result for level in ...

2 days ago
Read More
CBSE Class 11 syllabus 2021 for All subjects - Check Revised S...

CBSE Class 11 syllabus 2021 - CBSE Board has released the redu...

2 days ago
Read More
View All Latest Articles

Explore Popular Degree, Branches and Courses

Browse by Degrees

B.Tech (Bachelor of Technology)
MBBS (Bachelor of Medicine, Bachelor of Surgery)
B.A (Bachelor of Arts) - Course, Eligibility, Admission, Syllabus, Scope & Career Growth
BBA (Bachelor of Business Administration) - Full Form, Course Eligibility, Syllabus, Subject, Scope & Career
BAMS (Bachelor of Ayurvedic Medicine and Surgery)

Browse by Branches/Majors

B. Tech in Biotechnology - Admission, Eligibility, Top Colleges, Career Scope
B.Tech in Computer Science: Course, Eligibility, Syllabus, Scope, Fees
B.A. in Political Science
B.Tech in Electronics and Communication Engineering: Course, Syllabus, Career, Scope
B.Tech in Civil Engineering: Course, Admission, Syllabus, Scope and Salary

Browse by Courses

Computer Science Engineering
Mechanical Engineering
Information Technology
Radiology
Electrical Engineering
View All Courses

Popular Questions around NCERT

(a) Differentiate between meristematic and permanent tissues in plants (b) Define the process of differentiation (c) Name any two simple and two complex permanent tissues in plants.
In the gold foil experiment of Geiger and Marsden, that paved the way for Rutherford’s model of an atom, \sim1.00% of the a-particles were found to deflect at angles > 50°.
Why are xylem and phloem called complex tissues? How are they different from one other?
List the characteristics of cork. How are they formed? Mention their role.
Show diagrammatically the electron distributions in a sodium atom and a sodium ion and also give their atomic number.
Give reasons for a Meristematic cells have a prominent nucleus and dense cytoplasm but they lack vacuole b Intercellular spaces are absent in sclerenchymatous tissues c We get a crunchy and granular feeling, when we chew pear fruit.d Branches of a tree
What are the postulates of Bohr's model of an atom?
Draw well labelled diagrams of various types of muscles found in human body.
Describe the structure and function of different types of epithelial tissues. Draw diagram of each type of epithelial tissue.
Differentiate between sclerenchyma and parenchyma tissues. Draw well labelled diagram.
View All Questions

Trending Articles

SOF Results 2020-21 - Check Science Olympiad Foundation Results @ sofworld.org

5 days ago

IGKO Result 2020-21 - Check SOF IGKO 2020 Result & Answer Key Here

14 Jan 2021

IMO Result 2020-21 (Class 1 to 12) - Check SOF IMO Level 1 Results Here

2 days ago

National Scholarship Portal 2020-21 - NSP 2.0 Last Date, Online Form, Scholarships

16 Dec 2020

10th Time Table 2021- Download All Boards 10th Class Date Sheet Here

3 days ago

IMO Answer Key 2020-21 (Level 1) - Download Class 1 to 12 Set A, B C & D Answer Key

5 days ago

IEO Answer Key 2020-21 (Set B, C) - Download Class 1 to 12 IEO Level 1 Answer Key

6 days ago

Kendriya Vidyalaya Admission 2021 for Class 1 - Know Admission Details Here

07 Dec 2020

PSEB 8th Date Sheet 2021 Released- Check Punjab Board 8th Exam Dates @ pseb.ac.in

15 Jan 2021

ICSE Class 9 Syllabus 2020-21 for Maths, Biology, Physics, Chemistry, English

3 days ago

Most Viewed Careers Options

Indian Airforce Airman
Indian Foreign Service Officer
Health Inspector
Operation Theatre Technician
Forester
Food Inspector
Pharmacist
Civil Engineer
Credit Manager
Engineer
Never miss exam and college updates
Login
Back to top
The question have been saved in answer later, you can access it from your profile anytime. Access now

Explore Schools in Other Popular Locations

Schools in Karnataka Schools in Maharashtra Schools in Uttar Pradesh Schools in Delhi Schools in Haryana Schools in New Delhi Schools in Pune Schools in Mumbai Schools in Chennai Schools in Bangalore CISCE Schools in India Karnataka Board PUE Schools in India MSBSHSE Schools in India CAIE Schools in India CBSE Schools in India Boys Schools in India Girls Schools in India Co-ed Schools in India Day Schools in India Boarding Schools in India Day-cum-Boarding Schools in India Marathi Medium Schools in India Telugu Medium Schools in India English Medium Schools in India Gujarati Medium Schools in India Hindi Medium Schools in India Government Schools in India Private Aided Schools in India Private Unaided Schools in India Central Government Schools in India State Government Schools in India

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

Careers360 App
  • 150M+ Students
  • 24,000+ Colleges
  • 500+ Exams
  • 1500+ E-books
  • Economic Times
  • Financial Express
  • Firstpost
  • Livemint