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NCERT Solutions for Class 7 Maths Chapter 12 Algebraic Expressions - Download PDF

NCERT Solutions for Class 7 Maths Chapter 12 Algebraic Expressions - Download PDF

Edited By Ravindra Pindel | Updated on Feb 07, 2024 06:13 PM IST

NCERT Solutions for algebraic expressions class 7: An algebraic expression contains variables, numbers, and operations. In this article, you will get NCERT solutions for class 7 maths chapter 12 Algebraic Expressions. All the algebraic expressions are explained in NCERT. In solutions of NCERT for Class 7 Maths chapter 12 Algebraic Expressions, you will get questions related to solving all three types of algebraic expressions. Also, you will learn the addition and subtraction of algebraic expression. There are many problems in the CBSE NCERT solutions for Class 7 Maths chapter 12 Algebraic Expressions which will give more clarity of the concepts. You can also refer to the NCERT syllabus of Class 7 Maths for better understanding. Check NCERT Solutions from Classes 6 to 12 for Science and Math by clicking on the above link. Here you will get NCERT Solutions for Class 7 for Maths Chapter 12 .

This Story also Contains
  1. NCERT Solutions for Class 7 Maths Chapter 12 Algebraic Expressions - Important Formulae
  2. NCERT Solutions for Maths Chapter 12 Algebraic Expressions Class 7 - Important Points
  3. NCERT Solutions for Maths Chapter 12 Algebraic Expressions Class 7
  4. NCERT Solutions for Maths Chapter 12 Algebraic Expressions Class 7th Topic 12.2
  5. NCERT Solutions for Class 7 Maths Chapter 12 Algebraic Expressions Topic 12.3
  6. NCERT Solutions for Maths Chapter 12 Algebraic Expressions Class 7th Topic 12.4
  7. NCERT Solutions for Class 7th Math Chapter 12 Algebraic Expressions Topic 12.5 Monomials, Binomials, Trinomials and Polynomials
  8. NCERT Solutions for Class 7th Math Chapter 12 Algebraic Expression Exercise 12.1
  9. NCERT Solutions for Class 7th Math Chapter 12 Algebraic Expressions Topic 12.6
  10. NCERT Solutions for Chapter 12 Maths Class 7 Algebraic Expression Exercise: 12.2
  11. NCERT Solutions for Chapter 12 Maths Class 7th Algebraic Expression Exercise 12.3
  12. NCERT Solutions for Class 7 Maths Chapter 12 Algebraic Expression Exercise 12.4
  13. Algebraic Expressions Class 7 Chapter 12-Topics

This chapter is important for our coming classes. We must practice questions of this chapter and must be able to solve problems very fastly.

NCERT Solutions for Class 7 Maths Chapter 12 Algebraic Expressions - Important Formulae

Perimeter of Equilateral triangle = 3a, where, a = side length of triangle

Perimeter of a square = 4a, where, a = side length of square

Perimeter of regular pentagon = 5a, where, a = side length of pentagon

Area of square = a2, where, a = side length of square

Area of rectangle = l × b where, l = length and b = breadth

Area of a Triangle = (1/2) ( b) (h), where b = base and h = height

NCERT Solutions for Maths Chapter 12 Algebraic Expressions Class 7 - Important Points

Variable: A symbol denoted by letters (such as x, y, z, p, q, r, etc.) that can vary, representing an unknown quantity or value.

How Are Expressions Formed:

Algebraic expressions are formed by combining variables and constants using mathematical operations (Addition, Subtraction, Multiplication, Division).

Terms and Factors of An Expression:

Terms are components of expressions formed by combining variables and constants.

The term includes the sign, so we say "added" without specifying addition or subtraction.

In the diagram, factors are shown with dotted lines and terms with continuous lines.

1692070816523

Coefficient: The coefficient is the numerical factor of a term in an expression.

Free download NCERT Solutions for Class 7 Maths Chapter 12 Algebraic Expressions PDF for CBSE Exam.

NCERT Solutions for Maths Chapter 12 Algebraic Expressions Class 7

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NCERT Solutions for Class 7 Maths Chapter 12 Questions and Exercise

NCERT Solutions for Maths Chapter 12 Algebraic Expressions Class 7th Topic 12.2

Question: Describe how the following expressions are obtained:

7xy+5, x^{2} y,4x^{2}-5x

Answer: 7xy+5

the above expression is obtained by adding 7xy with 5. Here 7xy is obtained by multiplying 7,x and y

4 x^2-5x

the above expression is obtained by subtracting the product of 5 and x from the product of 4,x and x

NCERT Solutions for Class 7 Maths Chapter 12 Algebraic Expressions Topic 12.3

Question:1 What are the terms in the following expressions? Show how the terms are formed. Draw a tree diagram for each expression:

8y+3x^{2},7mn-4,2x^{2}y.

Answer: 8y+3x^{2} The terms in the expression are

8y\ and\ 3x^{2}

8y+3x^{2} is obtained by adding the product of 8 and y with the product of 3 x and x

the tree diagram for the expression is given below

1643021027441

7mn-4 has two terms 7mn and 4 and the expression is obtained by subtracting 4 from the product of 7,m and n. The tree diagram is shown below.

2x^2y has only one term, that is the expression itself.

The expression is formed by multiplying 4 terms 2, x, x and y. The tree diagrams are shown below

1643021048526

Question:2 Write three expressions each having 4 terms.

Answer: We can write as many expressions we need with 4 terms. Following are a few examples of expression with 4 terms

\\ a+b+c+d\\ab+bc+cd+ad\\abc+bcd+acd+abcd

Question: Identify the coefficients of the terms of following expressions:

4x-3y,a+b+5,2y+5,2xy

Answer: i) 4x-3y has two terms 4x and -3y

the coefficient of x is 4 and the coefficient of y is -3

ii) a+b+5 has 3 terms a,b and a constant that is 5.

the coefficient of a is 1 and b is also 1. Constant terms have no coefficient

iii) 2y+5 has two terms 2y and 5 which is constant.

The coefficient of y is 2. Constant terms have no coefficient

iv) 2xy has only one term which is 2xy and the coefficient of xy is 2

NCERT Solutions for Maths Chapter 12 Algebraic Expressions Class 7th Topic 12.4

Question:1(i) Group the like terms together from the following:

12x , 12 , -25x , -25 , -25y , 1 , x , 12y , y

Answer: The like terms are grouped below

Group 1: 12x , -25x , x

Group 2: -25y , 12y , y

Group 3: 12 , -25 , 1

NCERT Solutions for Class 7th Math Chapter 12 Algebraic Expressions Topic 12.5 Monomials, Binomials, Trinomials and Polynomials

Question: Classify the following expressions as a monomial, a binomial or a trinomial:

a,a+b.ab+a+b,ab+a+b-5,xy,xy+5,5x^{2}-x+2,4pq-3q+5p,7,4m-7n+10,4mn+7.

Answer: Monomial: a, xy, 7

binomial: a+b, xy+5, 4mn+7

Trinomial: ab+a+b, 5x 2 -x+2, 4pq-3q+5p, 4m-7n+10

Polynomial with 4 terms: ab+a+b-5

NCERT Solutions for Class 7th Math Chapter 12 Algebraic Expression Exercise 12.1

Question: 1(i) Get the algebraic expressions in the following cases using variables, constants and arithmetic operations.

Subtraction of z from y .

Answer: Subtraction of z from y: y-z

Question: 1(ii) Get the algebraic expressions in the following cases using variables, constants and arithmetic operation.

One-half of the sum of numbers x and y .

Answer: Sum of numbers x and y = x + y

One half of the sum of numbers x and y

=\frac{x+y}{2}

Question: 1(iii) Get the algebraic expressions in the following cases using variables, constants and arithmetic operations.

The number z multiplied by itself.

Answer:

The number z multiplied by itself =z\times z=z^{2}

Question: 1(iv) Get the algebraic expressions in the following cases using variables, constants and arithmetic operations.

One-fourth of the product of numbers p and q .

Answer: Product of the numbers p and q = p \times q=pq

One-fourth of the product of numbers p and q

=\frac{pq}{4}

Question: 1(v) Get the algebraic expressions in the following cases using variables, constants and arithmetic operations.

Numbers x and y both squared and added.

Answer: Number x squared = x^{2}

Number y squared = y^{2}

Numbers x and y both squared and added = x^{2}+ y^{2}

Question:1(vi) Get the algebraic expressions in the following cases using variables, constants and arithmetic operation.

Number 5 added to three times the product of numbers m and n .

Answer: Product of numbers m and n =m\times n=mn

Number 5 added to three times the product of numbers m and n = =3\times mn+5=3mn+5

Question:1(vii) Get the algebraic expressions in the following cases using variables, constants and arithmetic operations.

Product of numbers y and z subtracted from 10 .

Answer: Product of numbers y and z =y\times z=yz

Product of numbers y and z subtracted from 10 =10-yz

Question: 1(viii) Get the algebraic expressions in the following cases using variables, constants and arithmetic operations.

Sum of numbers a and b subtracted from their product.

Answer: Sum of numbers a and b = a + b

Product of the numbers a and b =a\times b=ab

Sum of numbers a and b subtracted from their product = ab - (a+b) = ab - a - b .

Question:2(i) Identify the terms and their factors in the following expressions

Show the terms and factors by tree diagrams. (a) x-3

Answer: Expression : x - 3

Terms in the above expression: x and -3

Tree diagram for the given expression

1643021082718


Question: 2 (i) Identify the terms and their factors in the following expressions

Show the terms and factors by tree diagrams (b) 1+x+x^{2}

Answer: Expression: 1 + x + x^2

Tems in the above expression: 1, x \and\ x^2

Factors of x 2 : x and x

Tree diagram for the given expression

1643021117870

Question:2(i) Identify the terms and their factors in the following expressions

Show the terms and factors by tree diagrams (c) y-y^{3}

Answer: Expression: y - y 3

Terms in the above expression: y and -y 3

Factors of -y 3 : -1, y, y and y

Tree diagram for the given expression

1643021160195

Question: 2 (i) Identify the terms and their factors in the following expressions

Show the terms and factors by tree diagrams. (d) 5xy^{2}+7x^{2}y

Answer: Expression: 5xy 2 + 7x 2 y

Terms in the above expression: 5xy 2 and 7x 2 y

Factors of 5xy 2 : 5, x, y and y

Factors of 7x 2 y: 7, x, x and y

Tree diagram for the given expression

1643021192704

Question: 2 (i) Identify the terms and their factors in the following expressions

Show the terms and factors by tree diagrams (e) -ab+2ab^{2}-3a^{2}

Answer:

Expression: -ab + 2ab 2 - 3a 2

Terms in the above expression: -ab, 2ab 2 and -3a 2

Factors of -ab: -1, a and b

Factors of 2ab 2 : 2, a, b and b

Factors of -3a 2 : -1, 3, a and a

Tree diagram for the given expression

1643021223439

Question: 2 (ii) Identify terms and factors in the expressions given below:

(a) -4x+5

Answer: Expression: -4x + 5

Terms in the above expression: -4x and 5

Factors of -4x: -1, 4 and x

Factors of 5: 5

Question: 2 (ii) Identify terms and factors in the expressions given below:

(b) -4x+5y

Answer: Expression: -4x + 5y

Terms in the above expression: -4x and 5y

Factors of -4x: -1, 4 and x

Factors of 5y: 5 and y

Question: 2 (ii) Identify terms and factors in the expressions given below:

(c) 5y+3y^{2}

Answer: Expression: 5y + 3y 2

Terms in the above expression: 5y and 3y 2

Factors of 5y: 5 and y

Factors of 3y 2 : 3, y and y

Question: 2 (ii) Identify terms and factors in the expressions given below:

(d) xy+2x^{2}y^{2}

Answer: Expression: xy + 2x 2 y 2

Terms in the above expression: xy and 2x 2 y 2

Factors of xy: x and y

Factors of 2x 2 y 2 : 2, x, x, y and y

Question: 2 (ii) Identify terms and factors in the expressions given below:

(e) pq+q

Answer: Expression: pq + q

Tems in the above expression: pq and q

Factors of pq: p and q

Factors of q: q

Question: 2 (ii) Identify terms and factors in the expressions given below:

(f) 1.2 \; ab-2.4\; b+3.6\; a

Answer: Expression: 1.2ab - 2.4b + 3.6a

Tems in the above expression: 1.2ab, -2.4b and 3.6a

Factors of 1.2ab: 1.2, a and b

Factors of -2.4b: -1, 2.4 and b

Factors of 3.6a: 3.6 and a

Question: 2( ii) Identify terms and factors in the expressions given below:

(g) \frac{3}{4}x+\frac{1}{4}

Answer: Expression: \frac{3}{4}x+\frac{1}{4}

Terms in the above expression: \frac{3}{4}x and \frac{1}{4}

Factors of \frac{3}{4}x : \frac{3}{4} and x

Factors of \frac{1}{4} : \frac{1}{4}

Question: 2 (ii) Identify terms and factors in the expressions given below:

(h) 0.1\; p^{2}+0.2\; q^{2}

Answer: Expression: 0.1p 2 + 0.2q 2

Tems in the above expression:0.1p 2 and 0.2q 2

Factors of 0.1p 2 : 0.1, p and p

Factors of 0.2q 2 : 0.2, q and q

Question:3(i) Identify the numerical coefficients of terms (other than constants) in the following expressions:

5-3t^{2}

Answer: Expression: 5 - 3t 2

Tems in the above expression: 5 and -3t 2

Coefficient of -3t 2 : -3

Question:3(ii) Identify the numerical coefficients of terms (other than constants) in the following expressions:

1+t+t^{2}+t^{3}

Answer: Expression: 1 + t + t 2 + t 3

Terms in the above expression: 1, t, t 2 and t 3

Coefficient of t is 1

Coefficient of t 2 is 1

Coefficient of t 3 : is 1

Question: 3(iii) Identify the numerical coefficients of terms (other than constants) in the following expressions:

x+2xy+3y

Answer: Expression: x + 2xy + 3y

Terms in the above expression: x, 2xy and 3y

Coefficient of x: 1

Coefficient of 2xy: 2

Coefficient of 3y: 3

Question: 3(iv) Identify the numerical coefficients of terms (other than constants) in the following expressions:

100m+1000n

Answer: Expression: 100m + 1000n

Terms in the above expression: 100m and 1000n

Coefficient of 100m: 100

Coefficient of 1000n: 1000

Question: 3(v) Identify the numerical coefficients of terms (other than constants) in the following expressions:

-p^{2}q^{2}+7pq

Answer: Expression: -p 2 q 2 + 7pq

Tems in the above expression: -p 2 q 2 and 7pq

Coefficient of -p 2 q 2 : -1

Coefficient of 7pq: 7

Question:3(vi) Identify the numerical coefficients of terms (other than constants) in the following expressions:

1.2\; a+0.8\; b

Answer: Expression: 1.2a + 0.8b

Terms in the above expression: 1.2a and 0.8b

Coefficient of 1.2a: 1.2

Coefficient of 0.8b: 0.8

Question:3(vii) Identify the numerical coefficients of terms (other than constants) in the following expressions:

3.14\; r^{2}

Answer: Expression: 3.14r 2

Terms in the above expression: 3.14r 2

Coefficient of 3.14r 2 is 3.1

Question: 3(viii) Identify the numerical coefficients of terms (other than constants) in the following expressions:

2(l+b)

Answer: Expression: 2(l + b) = 2l + 2b

Tems in the above expression: 2l and 2b

Coefficient of 2l: 2

Coefficient of 2b: 2

Question: 3(ix) Identify the numerical coefficients of terms (other than constants) in the following expressions:

0.1\; y+0.01\; y^{2}

Answer: Expression: 0.1y + 0.01y 2

Tems in the above expression: 0.1y and 0.01y 2

Coefficient of 0.1y is 0.1

Coefficient of 0.01y 2 is 0.01

Question: 4 (a) Identify terms which contain x and give the coefficient of x.

(i) y^{2}x+y

Answer: Expression: y 2 x + y

Terms with x: y 2 x

Coefficient of x in y 2 x: y 2

Question:4(a) Identify terms which contain x and give the coefficient of x.

(ii) 13y^{2}-8yx

Answer: Expression: 13y 2 - 8yx

Terms with x: -8yx

Coefficient of x in -8yx: -8y

Question: 4 (a) Identify terms which contain x and give the coefficient of x.

(iii) x+y+2

Answer: Expression: x + y + 2

Terms with x: x

Coefficient of x in x: 1

Question: 4 (a) Identify terms which contain x and give the coefficient of x.

(iv) 5+z+zx

Answer: Expression: 5 + z + zx

Terms with x: zx

Coefficient of x in zx: z

Question: 4 (a) Identify terms which contain x and give the coefficient of x .

(v) 1+x+xy

Answer: Expression: 1 + x + xy

Terms with x: x and xy

Coefficient of x in x: 1

Coefficient of x in xy: y

Question:4(a) Identify terms which contain x and give the coefficient of x.

(vi) 12xy^{2}+25

Answer: Expression: 12xy 2 + 5

Terms with x: 12xy 2

Coefficient of x in 12xy 2 : 12y 2

Question:4(a) Identify terms which contain x and give the coefficient of x.

(vii) 7x+xy^{2}

Answer: Expression: 7x + xy 2

Terms with x: 7x and xy 2

Coefficient of x in 7x: 7

Coefficient of x in xy 2 : y 2

Question: 4 (b) Identify terms which contain y^{2} and give the coefficient of y^{2} .

(i) 8-xy^{2}

Answer: Expression: 8 - xy 2

Terms with y 2 : -xy 2

Coefficient of y 2 in -xy 2 : -x

Question: 4 (b) Identify terms which contain y^{2} and give the coefficient of y^{2} .

(ii) 5y^{2}+7x

Answer: Expression: 5y 2 + 7x

Terms with y 2 : 5y 2

Coefficient of y 2 in 5y 2 : 5

Question: 4 (b) Identify terms which contain y^{2} and give the coefficient of y^{2} .

(iii) 2x^{2}y-15xy^{2}+7y^{2}

Answer: Expression: 2x 2 y -15xy 2 + 7y 2

Terms with y 2 : -15xy 2 and 7y 2

Coefficient of y 2 in -15xy 2 : -15x

Coefficient of y 2 in 7y 2 : 7

Question:5 Classify into monomials, binomials and trinomials.

(i) 4y – 7z

(ii) y 2

(iii) x + y – xy

(iv) 100

(v) ab – a – b

(vi) 5 – 3t

(vii) 4p 2 q – 4pq 2

(viii) 7mn

(ix) z 2 – 3z + 8

(x) a 2 + b 2

(xi) z 2 + z

(xii) 1 + x + x 2

Answer: (i) 4y – 7z

Binomial

(ii) y 2

Monomial

(iii) x + y – xy

Trinomial

(iv) 100

Monomial

(v) ab – a – b

Trinomial

(vi) 5 – 3t

Binomial

(vii) 4p 2 q – 4pq 2

Binomial

(viii) 7mn

Monomial

(ix) z 2 – 3z + 8

Trinomial

(x) a 2 + b 2

Binomial

(xi) z 2 + z

Binomial

(xii) 1 + x + x 2

Trinomial

Question:6(i) State whether a given pair of terms is of like or unlike terms.

1,100

Answer: (i) 1,100 are Like terms.

Question:6(ii) State whether a given pair of terms is of like or unlike terms.

-7x,\frac{5}{2}x

Answer: (ii) -7x,\frac{5}{2}x are Like terms

Question:6(iii) State whether a given pair of terms is of like or unlike terms.

-29x, -29y

Answer: Unlike since y and x are unlike terms

Question: 6(iv) State whether a given pair of terms is of like or unlike terms.

14xy,42yx

Answer: Like terms, since both the terms contain xy and only the coefficient is different

Question: 6(v) State whether a given pair of terms is of like or unlike terms.

4m^{2}p,4mp^{2}

Answer: Unlike since m^2p \ and \ mp^2 are different

Question: 6(vi) State whether a given pair of terms is of like or unlike terms.

12xz,12x^{2}z^{2}

Answer: Unlike since xz \ and\ x^2z are unlike terms

Question:7(a) Identify like terms in the following:

-xy^{2},-4yx^{2},8x^{2},2xy^{2},7y,-11x^{2},-100x,-11yx,20x^{2}y,-6x^{2},y,2xy,3x

Answer: Like terms are

(i) -xy 2 and 2xy 2

(ii) -4x 2 y and 20x 2 y

(iii) 8x 2 , -11x 2 and -6x 2

(iv) 7y and y

(v) -100x and 3x

(vi) -11yx and 2xy

Question:7(b) Identify like terms in the following:

10pq,7p,8q,-p^{2}q^{2},-7qp,-100q,-23,12q^{2}p^{2},-5p^{2},41,2405p,78qp,13p^{2}q,qp^{2},701p^{2}

Answer: Like terms are

(i) 10pq, -7qp and 78qp

(ii) 7p and 2405p

(iii) 8q and -100q

(iv) -p 2 q 2 and 12q 2 p 2

(vii) -23 and 41

(viii) -5p 2 and 701p 2

(ix) 13p 2 q and qp 2

NCERT Solutions for Class 7th Math Chapter 12 Algebraic Expressions Topic 12.6

Question:(i) Add and subtract

m-n,m+n

Answer: Adding

m-n,m+n

Will give the result as follows

m-n+m+n=2m

Subtracting

m-n,m+n

Will give the result as follows

m-n-(m+n)=m-n-m-n=-2n

Question:(ii) Add and subtract

mn+5-2,mn+3

Answer: Adding the following terms

mn+5-2,mn+3

we will get

mn+5-2+mn+3=2mn+6

Subtracting

mn+5-2,mn+3

We will get

mn+5-2-(mn+3)=mn+5-2-mn-3=0

NCERT Solutions for Chapter 12 Maths Class 7 Algebraic Expression Exercise: 12.2

Question: 1(i) Simplify combining like terms:

21b-32+7b-20b

Answer: 21b - 32 + 7b -20b

= (21 + 7 - 20)b -32

= 8b - 32

The simplified expression is 8b - 32.

Question:1(ii) Simplify combining like terms:

-z^{2}+13z^{2}-5z+7z^{3}-15z

Answer: -z^{2}+13z^{2}-5z+7z^{3}-15z

-z 2 + 13z 2 - 5z + 7z 3 - 15z

= (-1 + 13)z 2 + (-5 - 15)z +7z 3

=12z 2 - 20z + 7z 3

The simplified expression is 12z 2 - 20z + 7z 3

Question:1(iii) Simplify combining like terms:

p-(p-q)-q-(q-p)

Answer: p - (p - q) - q - (q - p)

= p - p + q - q - q + p

= p - p + p + q - q -q

= p - q

The simplified expression is p - q.

Question: 1(iv) Simplify combining like terms:

3a-2b-ab-(a-b+ab)+3ab+b-a

Answer: 3a - 2b - ab - (a - b + ab) + 3ab + b - a

= 3a - 2b - ab - a + b - ab + 3ab + b - a

= (3 - 1 - 1)a + (-2 + 1 +1)b + (-1 - 1 + 3)ab

= a + ab

The simplified expression is a + ab.

Question:1(v) Simplify combining like terms:

5x^{2}y-5x^{2}+3yx^{2}-3y^{2}+x^{2}-y^{2}+8xy^{2}-3y^{2}

Answer: 5x 2 y - 5x 2 + 3yx 2 - 3y 2 + x 2 - y 2 + 8xy 2 - 3y 2

= (5 + 3 )x 2 y + (-5 + 1)x 2 + (-3 - 1 - 3)y 2 + 8xy 2

= 8x 2 y - 4x 2 - 7y 2 + 8xy 2

The simplified expression is 8x 2 y - 4x 2 - 7y 2 + 8xy 2

Question:1(vi) Simplify combining like terms:

(3y^{2}+5y-4)-(8y-y^{2}-4)

Answer: (3y 2 + 5y - 4) - (8y - y 2 - 4)

= 3y 2 + 5y - 4 - 8y + y 2 + 4

= (3 + 1)y 2 + (5 - 8)y - 4 + 4

= 4y 2 - 3y

The simplified expression is 4y 2 - 3y

Question:2 Add:

(i) 3mn,-5mn,8mn,-4mn

(ii) t-8tz,3tz-z,z-t

(iii) -7mn+5,12mn+2,9mn-8,-2mn-3

(iv) a+b-3,b-a+3,a-b+3

(v) 14x+10y-12xy-13,18-7x-10y+8xy,4xy

(vi) 5m-7n,3n-4m+2,2m-3mn-5

(vii) 4x^{2}y,-3xy^{2},-5xy^{2},5x^{2}y

(viii) 3p^{2}q^{2}-4pq+5,-10 p^{2}q^{2},15+9pq+7p^{2}q^{2}

(ix) ab-4a,4b-ab,4a-4b

(x) x^{2}-y^{2}-1,y^{2}-1-x^{2},1-x^{2}-y^{2}

Answer: The given terms are added as follows

\\(i) 3mn + (-5mn) + 8mn + (-4mn)\\ = (3 - 5 + 8 - 4)mn\\ = 2mn

\\(ii) t - 8tz + (3tz - z) + (z - t)\\ = t - 8tz + 3tz - z + z - t\\ = (1 - 1)t + (-8 + 3)tz + (-1 + 1)z\\ = -5tz

\\(iii) -7mn + 5 + (12mn + 2) + (9mn - 8) + (-2mn - 3)\\ = -7mn + 5 + 12mn + 2 + 9mn - 8 - 2mn - 3 \\= (-7 + 12 + 9 - 2)mn + 5 + 2 - 8 - 3 \\= 12mn - 4

\\(iv) a + b - 3 + (b - a + 3) + (a - b + 3)\\ \\= a + b - 3 + b - a + 3 + a - b + 3 \\= (1 - 1 + 1)a + (1 + 1 -1)b - 3 + 3 + 3 \\= a + b + 3

\\(v) 14x + 10y - 12xy - 13 + (18 - 7x - 10y + 8xy) + 4xy\\ = 14x + 10y - 12xy - 13 + 18 - 7x - 10y + 8xy + 4xy \\= (14 -7)x + (10 - 10)y + (-12 + 8 + 4)xy - 13 + 18 \\= 7x + 5

\\(vi) 5m - 7n + (3n - 4m + 2) + (2m - 3mn - 5) \\= 5m - 7n + 3n - 4m + 2 + 2m - 3mn - 5 \\= (5 - 4 + 2)m + (-7 + 3)n + 2 - 5 - 3mn \\= 3m - 4n - 3mn - 3

\\(vii) 4x^2y - 3xy^2 - 5xy^2 + 5x^2y\\ \\= (4 + 5)x^2y + (-3 - 5)xy^2 \\= 9x^2y - 8xy^2

\\(viii) 3p^2q^2 - 4pq + 5 + (-10p^2q^2) + (15 + 9pq + 7p^2q^2) \\= 3p^2q^2 - 4pq + 5 - 10p^2q^2 + 15 + 9pq + 7p^2q^2 \\= (3 - 10 + 7)p^2q^2 + (-4 + 9)pq + 5 + 15 \\= 5pq + 20

\\(ix) ab - 4a + (4b - ab) + (4a - 4b) \\= ab - 4a + 4b - ab + 4a - 4b \\= (1 - 1)ab + (-4 + 4)a + (4 - 4)b \\=0

\\(x)\ x^2 - y^2 - 1 + (y^2 - 1 - x^2) + (1 - x^2 - y^2) \\= (1 - 1 - 1)x^2 + (-1 + 1 - 1)y^2 - 1 - 1 + 1 \\= -x^2 - y^2 - 1

Question:3 Subtract:

(i) -5y^{2} from y^{2}

(ii) 6xy from -12xy

(iii) (a-b) from (a+b)

(iv) a(b-5) from b(5-a)

(v) -m^{2}+5mn from 4m^{2}-3mn+8

(vi) -x^{2}+10x-5 from 5x-10

(vii) 5a^{2}-7ab+5b^{2} from 3ab-2a^{2}-2b^{2}

(viii) 4pq-5q^{2}-3p^{2} from 5p^{2}+3q^{2}-pq

Answer: The given terms are subtracted as follows

(i)

\\ y^2 - (-5y^2) \\= y^2 + 5y^2 \\= 6y^2

(ii)

\\ -12xy - 6xy\\ = -18xy

(iii)

\\(a+b)-(a-b)\\ =a+b-a+b =2b

(iv)

\\ b(5 - a) - a(b - 5) \\= 5b - ab - (ab - 5a) \\= 5b - ab - ab + 5a \\= 5b - 2ab + 5a

(v)

\\4m^2 - 3mn + 8 - (-m^2 + 5mn) \\= 4m^2 - 3mn + 8 + m^2 - 5mn \\= (4 + 1)m^2 + (-3 - 5)mn + 8 \\= 5m^2 - 8mn + 8


(vi)

\\ 5x - 10 - (-x^2 + 10x - 5) \\= 5x - 10 + x^2 - 10x + 5 \\= x^2 + (5 - 10)x - 10 + 5 \\= x^2 - 5x - 5

(vii)

\\ 3ab - 2a^2 - 2b^2 - (5a^2 - 7ab + 5b^2) \\= 3ab - 2a^2 - 2b^2 - 5a^2 + 7ab - 5b^2 \\= (3 + 7)ab + (-2 -5)a^2 + (-2 - 5)b^2 \\= 10ab - 7a^2 - 7b^2
(viii)

\\ 5p^2 + 3q^2 - pq - (4pq - 5q^2 - 3p^2) \\= 5p^2 + 3q^2 - pq - 4pq + 5q^2 + 3p^2 \\= (5 + 3) p^2 + (3 + 5)q^2 + (-1 - 4)pq \\= 8p^2 + 8q^2 - 5pq

Question: 4 (a) What should be added to x^{2}+xy+y^{2} to obtain

2x^{2}+3xy?

Answer: Let the term be a which must be added to x 2 + xy + y 2 to obtain 2x 2 + 3xy

\\a + x^2 + xy + y^2 = 2x^2 + 3xy \\a = 2x^2 + 3xy - (x^2 + xy + y^2) \\a = (2-1)x^2 + (3 - 1)xy -y^2 \\a = x^2 + 2xy - y^2

x 2 + 2xy - y 2 should be added to x 2 + xy + y 2 to obtain 2x 2 + 3xy

Question: 4 (b) What should be subtracted from 2a+8b+10 to get

-3a+7b+16 ?

Answer: Let the term be c which must be subtracted from 2a + 8b + 10 to get -3a + 7b + 16

\\2a + 8b + 10 - c = -3a + 7b + 16 \\c = 2a + 8b + 10 - (-3a + 7b + 16) \\c = 2a + 8b + 10 + 3a - 7b - 16 \\c = (2 + 3)a + (8 - 7)b + 10 - 16 \\c = 5a + b - 6

5a + b - 6 must be subtracted from 2a + 8b + 10 to get -3a + 7b + 16

Question: 5 What should be taken away from 3x^{2}-4y^{2}+5xy+20 to obtain

-x^{2}-y^{2}+6xy+20 ?

Answer: Let the term be a which must be taken away from 3x 2 - 4y 2 + 5xy + 20 to obtain -x 2 - y 2 + 6xy + 20

\\3x^2 - 4y^2 + 5xy + 20 - a = -x^2 - y^2 + 6xy + 20 \\a = 3x^2 - 4y^2 + 5xy + 20 - ( -x^2 - y^2 + 6xy + 20 ) \\a = 3x^2 - 4y^2 + 5xy + 20 + x^2 + y^2 - 6xy - 20 \\a = ( 3 + 1 )x^2 + ( -4 + 1 )y^2 + ( 5 - 6 )xy + 20 - 20 \\a = 4x^2 - 3y^2 - xy

4x 2 - 3y 2 - xy must be taken away from 3x 2 - 4y 2 + 5xy + 20 to obtain -x 2 - y 2 + 6xy + 20

Question:6(a) From the sum of 3x-y+11 and -y-11 , subtract 3x-y-11.

Answer:

\\( 3x - y + 11 + ( - y - 11 ) ) - ( 3x - y - 11 ) \\= 3x - y + 11 - y - 11 - 3x + y + 11 \\= ( 3 - 3 )x + ( -1 - 1 + 1)y + 11 - 11 + 11 \\= -y + 11

On subtracting 3x - y - 11 from the sum of 3x - y + 11 and -y - 11 we get -y + 11

Question: 6 (b) From the sum of 4+3x and 5-4x+2x^{2}, subtract the sum of 3x^{2}-5x and -x^{2}+2x+5 .

Answer:

\\( 4 + 3x + ( 5 - 4x + 2x^2) ) - ( 3x^2 - 5x + ( -x^2 + 2x + 5) \\= (4 + 3x + 5 - 4x + 2x^2 ) - ( 3x^2 - 5x -x2 + 2x + 5) \\= 4 + 3x + 5 - 4x + 2x^2 - 3x^2 + 5x + x^2 - 2x - 5 \\=4 + 5 - 5 + ( 3 - 4 + 5 - 2 )x + ( 2 - 3 + 1 )x^2 \\=4 + 2x

On subtracting the sum of 3x^{2}-5x and -x^{2}+2x+5 from the sum of 4+3x and 5-4x+2x^{2} we get 4+2x

NCERT Solutions for Chapter 12 Maths Class 7th Algebraic Expression Exercise 12.3

Question:1(i) If m=2, find the value of:

m-2

Answer: (i) m - 2

= 2 - 2

= 0

If m = 2 the value of m - 2 = 0

Question:1(ii) If m=2, find the value of:

3m-5

Answer:

\\3m - 5 \\= 3 \times 2 - 5 \\= 6 - 5 \\= 1

If m = 2 the value of 3m - 5 = 1

Question:1(iii) If m=2, find the value of:

9-5m

Answer:

\\9 - 5m \\= 9 - 5 \times 2 \\= 9 - 10 \\= -1

If m = 2 the value of 9 - 5m = -1

Question: 1(iv) If m=2, find the value of:

3m^{2}-2m-7

Answer:

\\3m^2 - 2m - 7 \\= 3 \times 2^2 - 2 \times 2 - 7 \\= 12 - 4 - 7 \\= 1

If m = 2 the value of 3m 2 - 2m - 7 = 1

Question: 1(v) If find the value of: (v) If m=2, find the value of:

\frac{5m}{2}-4

Answer:

\frac{5m}{2}-4

=\frac{5\times 2}{2}-4

= 5 - 4

= 1

If m = 2 the value of \frac{5m}{2}-4 = 1

Question:2(i) If p=-2, find the value of:

4p+7

Answer:

\\4p + 7 \\= 4 \times ( -2 ) + 7 \\= -8 + 7 \\= -1

If p = -2 the value of 4p + 7 = -1

Question: 2(ii) If p=-2, find the value of:

-3p^{2}+4p+7

Answer:

\\-3p^2 + 4p + 7 \\= -3 x ( -2 )^2 + 4 x ( -2 ) + 7 \\= -12 - 8 + 7 \\= -13

If p = -2 the value of -3p 2 + 4p + 7 = -13

Question: 2(iii) If p=-2 , find the value of:

-2p^{3}-3p^{2}+4p+7

Answer:

\\-2p3 - 3p2 + 4p + 7 \\= - 2 \times ( -2)^3 - 3 \times ( -2 )^2 + 4 \times ( -2 ) + 7 \\= 16 - 12 - 8 + 7 \\= 3

If p = -2 the value of -2p 3 - 3p 2 + 4p + 7 = 3

Question: 3(i) Find the value of the following expressions, when x=-1 :

2x-7

Answer:

\\2x - 7 \\= 2 \times ( -1 ) - 7 \\= -2 - 7 \\= -9

If x = -1 the value of 2x - 7 = -9

Question: 3(ii) Find the value of the following expressions, when

x=-1:

-x+2

Answer:

-x + 2

= -( -1 ) + 2

= 1 + 2

= 3

If x = -1 the value of -x + 2 = 3

Question:3(iii) Find the value of the following expressions, when x=-1 :

x^{2}+2x+1

Answer:

\\x^2 + 2x + 1 \\= ( -1 )^2 + 2 \times ( -1 ) + 1 \\= 1 - 2 + 2 \\= 0

If x = -1 the value of x 2 + 2x + 1 = 0

Question:3(iv) Find the value of the following expressions, when x=-1 :

2x^{2}-x-2

Answer:

\\2x^2 - x - 2 \\= 2\times ( -1 )^2 - ( -1 ) - 2 \\ = 2 + 1 - 2 \\= 1

So the value at x=-1 is 1

Question: 4(i) If a=2,b=-2, find the value of:

a^{2}+b^{2}

Answer:

a 2 + b 2

= ( 2 ) 2 + ( -2 ) 2

= 4 + 4

= 8

If a = 2 and b = -2 the value of a 2 + b 2 = 8

Question: 4(ii) If a=2,b=-2, find the value of:

a^{2}+ab+b^{2}

Answer:

\\a^2 + ab + b^2 \\= 2^2 + 2 \times ( -2 ) + ( -2 )^2 \\= 4 - 4 + 4 \\= 4

If a = 2 and b = -2 the value of a 2 + ab + b 2 = 4

Question:4(iii) If a=2,b=-2, find the value of

a^{2}-b^{2}

Answer:

a 2 - b 2

= 2 2 - ( -2 ) 2

= 4 - 4

= 0

If a = 2 and b = -2 the value of a 2 - b 2 = 0

Question: 5(i) When a=0,b=-1, find the value of the given expressions:

2a+2b

Answer:

\\2a + 2b \\= 2 \times 0 + 2 \times ( -1 ) \\= 0 - 2 \\= -2

When a = 0 and b = -1 the value of the given expression 2a + 2b = -2

Question: 5(ii) When a=0,b=-1, find the value of the given expressions:

2a^{2}+b^{2}+1

Answer:

\\2a^2 + b^2 + 1 \\= 2 \times 0^2 + ( -1 )2 + 1 \\= 0 + 1 + 1 \\= 2

When a = 0 and b = -1 the value of the given expression 2a 2 + b 2 + 1 = 2

Question: 5(iii) When a=0,b=-1 , find the value of the given expressions:

2a^{2}b+2ab^{2}+ab

Answer:

\\2a^2b + 2ab^2 + ab \\= 2 \times 0^2 \times ( -1 ) + 2 \times 0 \times ( -1 )^2 + 0 \times ( -1 )\\ = 0 + 0 + 0 \\= 0

When a = 0 and b = -1 the value of the given expression 2a 2 b + 2ab 2 + ab = 0

Question:5(iv) When a=0,b=-1, find the value of the given expressions:

a^{2}+ab+2

Answer:

\\a^2 + ab + 2 \\= 0^2 + 0 \times ( -1 ) + 2 \\= 0 + 0 + 2 \\= 2

When a = 0 and b = -1 the value of the given expression a 2 + ab + 2 = 2

Question: 6(i) Simplify the expressions and find the value if x is equal to 2

x+7+4(x-5)

Answer:

\\x + 7 + 4( x - 5 ) \\= x + 7 + 4x - 20 \\= 5x - 13 \\= 5 \times 2 - 13 \\= 10 - 13 \\= -3

If x is equal to 2 the value of x + 7 + 4( x - 5 ) = -3

Question: 6(ii) Simplify the expressions and find the value if x is equal to 2

3(x+2)+5x-7

Answer:

\\3( x + 2 ) + 5x - 7 \\= 3x + 6 + 5x - 7 \\= 8x - 1 \\= 8 \times (2) - 1 \\= 16 - 1 \\= 15

If x is equal to 2 the value of 3( x + 2 ) + 5x - 7 = 15

Question: 6(iii) Simplify the expressions and find the value if x is equal to 2

6x+5(x-2)

Answer:

\\6x + 5( x - 2 ) \\= 6x + 5x - 10 \\= 11x - 10 \\= 11 \times 2 - 10 \\= 22 - 10 \\= 12

If x is equal to 2 the value of 6x + 5( x - 2 ) = 12

Question: 6(iv) Simplify the expressions and find the value if x is equal to 2

4(2x-1)+3x+11

Answer:

\\4( 2x - 1 ) + 3x + 11 \\= 8x - 4 + 3x + 11 \\= 11x + 7 \\= 11 \times 2 + 7 \\= 22 + 7 \\= 29

If x is equal to 2 the value of 4( 2x - 1 ) + 3x + 11 = 29

Question: 7 Simplify these expressions and find their values if

x=3,a=-1,b=-2.

(i) 3x-5-x+9

(ii) 2-8x+4x+4

(iii) 3a+5-8a+1

(iv) 10-3b-4-5b

(v) 2a-2b-4-5+a

Answer:

The expression is simplified as follows and also obtained their values

(i)

\\ 3x - 5 - x + 9 \\= 2x + 4 \\= 2 \times 3 + 4 \\= 10

(ii)

\\ 2 - 8x + 4x + 4 \\= 6 - 4x \\= 6 - 4 \times 3 \\= -6

(iii)

\\3a + 5 - 8a + 1 \\= -5a + 6 \\= -5 \times ( -1 ) + 6 \\= 5 + 6 \\=11

(iv)

\\10 - 3b - 4 - 5b \\= 6 - 8b \\= 6 - 8 \times ( -2 ) \\= 6 + 16 \\= 22

(v)

\\2a - 2b - 4 - 5 + a \\= 3a - 2b - 9 \\= 3 \times ( -1 ) - 2 \times ( -2 ) - 9 \\= -3 + 4 - 9 \\= -8

Question: 8 (i) If z=10, find the value of

z^{3}-3(z-10)

Answer:

\\z^3 - 3( z - 10 ) \\= z^3 - 3z + 30 \\= 10^3 - 3 \times 10 + 30 \\= 1000 - 30 + 30 \\= 1000

If z = 10 the value of z 3 - 3( z - 10 ) = 1000

Question: 8 (ii) If p=-10, find the value of

p^{2}-2p-100

Answer:

\\p^2 - 2p - 100 \\= ( -10 )^2 - 2 \times ( -10 ) - 100 \\= 100 + 20 - 100 \\= 20

If p = -10 the value of p 2 - 2p - 100 = 20

Question: 9 What should be the value of a if the value of 2x^{2}+x-a equals to 5 , when

x=0?

Answer:

\\2x^2 + x - a = 5 \\2 \times 0^2 + 0 - a = 5 \\-a = 5 \\a = -5

Therefore for a = -5 when the value of x=0

Question: 10 Simplify the expression and find its value when a=5 and

b=-3\; .2(a^{2}+ab)+3-ab

Answer:

\\2( a^2 + ab ) + 3 - ab \\= 2a^2 + 2ab + 3 - ab \\= 2a^2 + ab + 3 \\= 2 \times 5^2 + 5 \times ( -3 ) + 3 \\= 50 - 15 + 3 \\= 38

When a = 5 and b = -3 the value 2( a 2 + ab ) + 3 - ab = 38

NCERT Solutions for Class 7 Maths Chapter 12 Algebraic Expression Exercise 12.4

Question:1 Observe the patterns of digits made from line segments of equal length. You will find such segmented digits on the display of electronic watches or calculators.

1643021315624

1643021328650

1643021389568

Answer:

1643021404783

The number of segments required to form n of each digits shown above are 5n + 1, 3n + 1 and 5n + 2

When n = 5

\\5n + 1 = 5 \times 5 + 1 = 26 \\3n + 1 = 3 \times 5 + 1 = 16 \\5n + 2 = 5 \times 5 + 2 = 27

When n = 10

\\5n + 1 = 5 \times 10 + 1 = 51 \\3n + 1 = 3 \times 10+ 1 = 31 \\5n + 2 = 5 \times 10 + 2 = 52

When n = 100

\\5n + 1 = 5 \times 100 + 1 = 501 \\3n + 1 = 3 \times 100+ 1 = 301 \\5n + 2 = 5 \times 100 + 2 = 502

Question: 2 Use the given algebraic expression to complete the table of number patterns.

1643021436757

Answer: Below you can find the table of number patterns:

1643021453229

Algebraic Expressions Class 7 Chapter 12-Topics

  • How Are Expressions Formed?
  • Terms Of An Expression
  • Like And Unlike Terms
  • Monomials, Binomials, Trinomials And Polynomials
  • Addition And Subtraction Of Algebraic Expressions
  • Finding The Value Of An Expression
  • Using Algebraic Expressions – Formulas And Rules

NCERT Solutions for Class 7 Maths Chapter Wise

Chapter No.

Chapter Name

Chapter 1

Integers

Chapter 2

Fractions and Decimals

Chapter 3

Data Handling

Chapter 4

Simple Equations

Chapter 5

Lines and Angles

Chapter 6

The Triangle and its Properties

Chapter 7

Congruence of Triangles

Chapter 8Comparing quantities

Chapter 9

Rational Numbers

Chapter 10

Practical Geometry

Chapter 11

Perimeter and Area

Chapter 12

Algebraic Expressions

Chapter 13

Exponents and Powers

Chapter 14

Symmetry

Chapter 15Visualising Solid Shapes

NCERT Solutions for Class 7 Subject Wise

NCERT Solutions for Class 7 Maths

NCERT Solutions for Class 7 Science

Benefits of NCERT Solutions for Class 7 Maths Chapter 12 Algebraic Expressions

  • You will learn to simplify and solve algebraic expressions in this chapter.
  • You will also learn the addition and subtraction of algebraic expressions which is helpful in making the expression simpler.
  • It will help you in your homework as all the NCERT questions including practice questions given below every topic are covered in this article.
  • There are many questions given below every topic to give you conceptual clarity. In NCERT solutions for Class 7 Maths chapter 12 Algebraic Expressions, you will get solutions to these practice questions also.
  • You should practice all the NCERT questions including examples. If you facing difficulties in doing so, you can take help from these solutions.

Happy learning!!!

Also Check NCERT Books and NCERT Syllabus here:

Frequently Asked Questions (FAQs)

1. How many terms are there in the expression 2y+5?

There are 2 terms in this expression. To know what are terms and other concepts students can download algebraic expressions class 7 pdf and study both online and offline mode. After practicing these concepts you have confidence that will help you during the exam and lead to score well. 

2. How many exercises in NCERT Class 7 Maths Chapter 12?

There are 4 exercises in NCERT Class 7 Mathematics Chapter 12

NCERT Maths Chapter 12 Algebraic Expression Class 7 Exercise 12.1 - 7 questions

NCERT Maths Chapter 12 Algebraic Expression Class 7 Exercise 12.2 - 6 questions

Class 7 Maths Chapter 12 Algebraic Expression Exercise 12.3 - 10 questions

Class 7 Maths Chapter 12 Algebraic Expression Exercise 12.4 - 2 questions

3. What are the topics covered in NCERT Class 7 Chapter 12?

Here are the topics covered in NCERT Maths Class 7 Chapter 12

  •  How Are Expressions Formed?   
  •   Terms Of An Expression   
  •    Like And Unlike Terms   
  •    Monomials, Binomials, Trinomials And Polynomials   
  •    Addition And Subtraction Of Algebraic Expressions   
  •    Finding The Value Of An Expression   
  •    Using Algebraic Expressions – Formulas And Rules  

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