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Edited By Vishal kumar | Updated on Oct 17, 2023 09:16 AM IST

NCERT Solutions for Class 9 Maths Exercise 13.6 deals with the concept of the volume of the right circular cylinder. A right circular cylinder is a cylinder with a closed circular surface, two parallel bases on both ends and elements that are perpendicular to the base. The volume of the right circular cylinder is the capacity of the cylinder in exercise 13.6 Class 9 Maths, which estimates the amount of material that it can carry. The volume of the right circular cylinder can be calculated by using the dimensions such as the radius and height of the right circular cylinder.

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- NCERT Solutions for Class 9 Maths Exercise 13.6 Chapter 13 Surface Areas and Volumes- Download Free PDF
- Download the PDF of NCERT Solutions for Class 9 Maths Chapter 13 Surface Areas and Volumes Exercise 13.6
- Access Surface Area and Volumes Class 9 Maths Chapter 13 Exercise: 13.6
- Q1 The circumference of the base of a cylindrical vessel is 132 cm and its height is 25 cm. How many litres of water can it hold? ( )
- Q8 A patient in a hospital is given soup daily in a cylindrical bowl of diameter 7 cm. If the bowl is filled with soup to a height of 4 cm, how much soup the hospital has to prepare daily to serve 250 patients? Answer: Given, Height = The radius of the cylindrical bowl = The volume of soup in a bowl for a single person = The volume of soup given for 250 patients = Therefore, the amount of soup the hospital has to prepare daily to serve 250 patients is
- More About NCERT Solutions for Class 9 Maths Exercise 13.6
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- Key Features of 9th Class Maths Exercise 13.6 Answers
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The product of the area of the base and the height of the right circular cylinder gives the volume of the right circular cylinder. That is V=πr^{2}h where r is the radius of the cylinder's round base. The NCERT solutions for Class 9 Maths exercise 13.6 also focused on the volume of the hollow cylinder. A cylinder that is empty from the inside and has some difference between the internal and external radius is known as a hollow cylinder. NCERT Solutions for Class 9 Maths chapter 13 exercise 13.6 consists of 8 questions regarding the volume of the right circular cylinder. The concepts related to the volume of the right circular cylinder and hollow cylinder are well explained in this NCERT syllabus Class 9 Maths chapter 13 exercise 13.6. Along with NCERT book exercise 13.6 class 9 maths solution, the following exercises are also present.

- Surface Area and Volumes Exercise 13.1
- Surface Area and Volumes Exercise 13.2
- Surface Area and Volumes Exercise 13.3
- Surface Area and Volumes Exercise 13.4
- Surface Area and Volumes Exercise 13.5
- Surface Area and Volumes Exercise 13.7
- Surface Area and Volumes Exercise 13.8
- Surface Area and Volumes Exercise 13.9

****This chapter has been renumbered as Chapter 11 according to the CBSE Syllabus 2023-24.**

** Answer: **

Given,

Circumference of the base of a cylindrical vessel =

Height =

Let the radius of the base of the cylinder be

Now, Circumference of the circular base of the cylinder =

The volume of the cylinder =

Also,

Therefore, the cylindrical vessel can hold of water.

** Answer: **

Given, A hollow cylinder made of wood.

The inner diameter of the cylindrical wooden pipe =

Outer diameter =

Length of the pipe =

The volume of the wooden cylinder =

Mass of wood =

Mass of wood =

Therefore, the mass of the wooden hollow cylindrical pipe is

** Answer: **

Given,

(i) The dimension of the rectangular base of the tin can =

Height of the can =

The volume of the tin can =

(ii) The radius of the circular base of the plastic cylinder =

Height of the cylinder =

The volume of the plastic cylinder =

Clearly, the plastic cylinder has more capacity than the rectangular tin can.

The difference in capacity =

** Q4 (i) ** If the lateral surface of a cylinder is and its height is 5 cm, then find radius of its base (Use )

** Answer: **

Given,

The lateral surface area of the cylinder =

Height of the cylinder =

(i) Let the radius of the base be

We know,

The lateral surface area of a cylinder =

Therefore, the radius of the base is

** Q4 (ii) ** If the lateral surface of a cylinder is and its height is 5 cm, then find it's volume. (Use )

** Answer: **

Given,

The lateral surface area of the cylinder =

Height of the cylinder =

The radius of the base is

(ii) We know,

The volume of a cylinder =

Therefore, the volume of the cylinder is .

** Answer: **

(i) Given,

Rs 20 is the cost of painting area of the inner curved surface of the cylinder.

Rs 2200 is the cost of painting area of the inner curved surface of the cylinder.

The inner curved surface area of the cylindrical vessel =

** Answer: **

The inner curved surface area of the cylindrical vessel =

Height of the cylinder =

Let the radius of the circular base be

The inner curved surface area of the cylindrical vessel =

Therefore, the radius of the base of the vessel is

** Answer: **

(iii) Height of the cylinder =

Radius of the base of the vessel =

Volume of the cylindrical vessel =

Therefore, the capacity of the cylindrical vessel is

** Answer: **

(Using capacity(volume), we will find the radius and then find the surface area)

The capacity of the vessel = Volume of the vessel = litres

Height of the cylindrical vessel =

Let the radius of the circular base be

The volume of the cylindrical vessel =

Therefore, the total surface area of the vessel =

Therefore, square metres of metal sheet needed to make it is

** Answer: **

Given,

Length of the cylindrical pencil =

The radius of the graphite (Inner solid cylinder) =

Radius of the pencil (Inner solid graphite cylinder + Hollow wooden cylinder) =

=

We know, Volume of a cylinder=

The volume of graphite =

And, Volume of wood =

Therefore, the volume of wood is and the volume of graphite is

** Answer: **

Given,

Height =

The radius of the cylindrical bowl =

The volume of soup in a bowl for a single person =

The volume of soup given for 250 patients =

Therefore, the amount of soup the hospital has to prepare daily to serve 250 patients is

The NCERT solutions for Class 9 Maths exercise 13.6 is also focused on elaborating the process to find the volume of the cylinder and hollow cylinder. In order to find the volume of the right circular cylinder, first, we need to check the dimensions such as the radius of the circular base and the height of the given cylinder. Then we must determine whether or not all of the dimensions, such as radius and height, are in the same units, or convert them to the same ones. After we've made all of the measurements units the same, we'll need to calculate the area of the circular base. Then we need to multiply the area of the circular base and height together. Thus the obtained value is the volume of the right circular cylinder which should be written in cubic units.

**Also Read| **Surface Areas And Volumes Class 9 Notes

• NCERT solutions for Class 9 Maths exercise 13.6 give us a general notion of several figures that are always comparable to one another, regardless of their size. Example: The shapes of a sphere, a cuboid, and a cone.

• Solving the NCERT solution for Class 9 Maths chapter 13 exercise 13.6 teaches us how to solve problems quickly and easily, as well as how to analyse situations and correctly apply formulas. It also improves our efficiency and speed in solving problems.

• Class 9 Maths Exercise 13.6 assists us in determining the volume of the cylinder as well as the radius and height of the cylinder using the volume formula.

**Extensive Coverage:**This exercise comprehensively covers topics related to surface areas and volumes of various geometrical solids, including spheres, hemispheres, and more.**Practical Applications:**Class 9 ex 13.6 solutions provide practical insights, helping students understand the real-life relevance of these geometric concepts.**Expert-Crafted Solutions:**The ex 13.6 class 9 solutions are expertly crafted to offer clear explanations and step-by-step problem-solving techniques.**CBSE 2023-24 Syllabus Alignment:**The class 9 maths ex 13.6 aligns with the CBSE 2023-24 syllabus, ensuring that students are well-prepared for their examinations.**Homework and Assignment Support:**These solutions are invaluable for completing homework and assignments with confidence.**Quick Reference Guide:**Students can use these 9th class maths exercise 13.6 answers as a quick reference guide to reinforce their understanding of geometry, 3D shapes, and surface area calculations.

**Also See:**

NCERT Solutions for Class 9 Maths Chapter 13 – Surface Area and Volumes

NCERT Exemplar Solutions Class 9 Maths Chapter 13 – Surface Area and Volumes

1. Volume of the right circular cylinder is _________

Volume of the right circular cylinder is r2h.

2. Volume of the hollow cylinder is __________

Volume of the hollow cylinder is πhr12–r22

3. Define hollow cylinder.

A cylinder that is empty from the inside and has some difference between the internal and external radius is known as a hollow cylinder.

4. A pencil is ______ a)Cone b)Cylinder c)Sphere

A pencil is cylinder

5. The volume of the right circular cylinder can be calculated by using ________

The volume of the right circular cylinder can be calculated by using the dimensions.

6. What are the dimensions of the right circular cylinder ?

The dimensions of the right circular cylinder are radius and height.

7. Define a right circular cylinder, according to NCERT solutions for Class 9 maths chapter 13 exercise 13.6 .

A cylinder with a closed circular surface, two parallel bases on both ends, and elements that are perpendicular to its base is known as a right circular cylinder, according to NCERT solutions for Class 9 maths chapter 13 exercise 13.6.

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