The world contains numerous three-dimensional objects, which include boxes together with cans and balls, as well as pipes. The objects possess two features: areas to measure and inner space to fill. This chapter offers methods to determine the exterior surface area and internal volume measurement of cubic shapes, including cuboids, cubes, and cylinders solve practical issues, such as wall painting requirements and tank water capacity determination. The information provides valuable tools for examinations and serves important functions in everyday life and architectural engineering design professions. Students should use the excellent NCERT class 9th maths notes to establish foundational mathematical concepts and efficiently review key concepts of the various subjects, cones, spheres and also the hemispherical geometry.
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The chapter provides basic formulas which solve practical issues that include wall painting requirements and tank water capacity determination. The information provides valuable tools for examinations and serves important functions across everyday life situations and architectural engineering design professions. Students should use the excellent NCERT class 9th maths notes to establish foundational mathematical concepts. And, efficiently utilise the NCERT Notes to review key concepts of the various subjects.
Surface Area: The entire space which the external surface of an object takes up is known as the surface area of that object.
(Measured in square units, e.g., cm², m²)
Volume: The measurement of the space occupied by an object is referred to as volume.
(Measured in cubic units, e.g., cm³, m³)
A cube is a cuboid with the same length, width, and height. Six surfaces, twelve edges, eight corners, and four diagonals make up a cube. Example: a dice.
Total Surface Area: 6 × (side)²
Lateral Surface Area: 4 × (side)²
Volume: (side)³
Example:
If side = 3 cm, then Volume = (side)³ = 3³ = 27 cm³
A cuboid is a figure that is surrounded by six rectangular surfaces, with opposite surfaces equal and parallel. In a Cuboid, 12 edges and 8 corners are there. The vertex of a cuboid is each of its four corners. The diagonal of a cuboid is the line segment connecting the opposite vertices. In a cuboid, there are four diagonals. Example: a brick or a matchbox.
L = Length, B = Breadth and H = Height
Total Surface Area: 2 × (lb + bh + hl)
Lateral Surface Area: 2 × (l + b) × h
Volume: l × b × h
Example:
If l = 5 cm, b = 4 cm, h = 3 cm, then Volume = l × b × h = 5 × 4 × 3 = 60 cm³
A solid generated by the revolution of a rectangle around one of its sides is known as a right circular cylinder. It is a three-dimensional shape having two congruent and parallel sides. Thus, two circular and one lateral face, when combined, form a cylinder as shown in the figure. Example: a cold drink can or a water tank.
R = Radius and H = Height
Total Surface Area: 2πr(h + r)
Curved Surface Area: 2πrh
Volume: πr²h
Example:
If r = 7 cm, h = 14 cm, π = $\frac{22}{7}$, then Curved surface area = 2πrh = 2 × $\frac{22}{7}$ × 7 × 14 = 616 cm²
A right circular cone is a solid formed when a right triangle is rotated around one of its sides (other than the hypotenuse). Thus, it contains a circular base and a curved surface that gradually decreases to a single point called the vertex. Example: an ice cream cone.
R = Radius, L = Slant Height and H = Height
Total Surface Area: Curved surface area + Base area
⇒ πrl + πr²
Curved Surface Area: πrl
Volume: $\frac{1}{3}$ × πr²h
Example:
If r = 7 cm, h = 12 cm, π = $\frac{22}{7}$,
then Volume = $\frac{1}{3}$ × πr²h
= $\frac{1}{3}$ × $\frac{22}{7}$ × 7 × 7 × 12 = 616 cm³
A sphere is the spatial area of a solid that touches a curved surface by which every point maintains an equal distance to its fixed centre. The centre point of the sphere serves as its fixed position. A sphere possesses a radius that represents the straight distance from its centre point to the surface. Example: ball
R = Radius
Surface Area: 4πr²
Volume: $\frac{4}{3}$ × πr³
Example:
If r = 21 cm, π = $\frac{22}{7}$,
then Volume = $\frac{4}{3}$ × πr³
= $\frac{4}{3}$ × $\frac{22}{7}$ × 21 × 21 × 21 = 38808 cm³
A plane which passes through the sphere's centre produces equal halves which correspond to each other as two separate hemispheres. Each divided part of the sphere is named a hemisphere. Example: a dome
R = Radius
Total Surface Area: 3πr²
Curved Surface Area (CSA) = 2πr²
Volume: $\frac{2}{3}$ × πr³
Example:
If r = 21 cm, π = $\frac{22}{7}$,
then Volume = $\frac{2}{3}$ × πr³
= $\frac{2}{3}$ × $\frac{22}{7}$ × 21 × 21 × 21 = 19404 cm³
Students must download the notes below for each chapter to ace the topics.
NCERT Notes Class 9 Maths Chapter 4 - Linear Equation in Two Variables |
NCERT Notes Class 9 Maths Chapter 5 - Introduction To Euclid’s Geometry |
NCERT Notes Class 9 Maths Chapter 11 - Surface Areas and Volumes |
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