Aakash Repeater Courses
Take Aakash iACST and get instant scholarship on coaching programs.
NCERT Solutions for Class 10 Maths exercise 15.2 – We will come across some terminologies like Experiment, Outcome, Event, etc. Any situation or phenomenon, such as tossing a coin, playing cards, rolling dice, and so on, can be used as an experiment.
This Story also Contains
Outcome: The outcome of an experiment, such as the number that appears on the dice after rolling, the side of the coin after flipping, and a card drawn from a pack of well-shuffled cards, and so on.
Event: The shuffling of all possible outcomes of an experiment, such as finding a king in an all-around rearranged deck of cards, getting heads or tails on a flipped coin, settling the score or odd numbers on dice, etc.
Sample space is the arrangement of every conceivable outcome or result, for example, getting heads or tails while flipping a coin.
NCERT solutions Class 10 Maths exercise 15.2- An elementary event is one that has only one outcome. The sum of the probabilities of all of an experiment's elementary events is one.
The probability (likelihood) of an occasion goes from 0 to 1, inclusive of 0 and 1. i.e.,
Complementary events are the main two potential results of a solitary occasion (a single event). This is closely resembling flipping a coin and checking whether it lands on heads or tails.
where E is representing event and is representing not E or complementary of the event E.
Along with Class 10 Maths chapter 15 exercise 15.2 the following exercises are also present.
Answer:
Total possible ways Shyam and Ekta can visit the shop = $5\times5 = 25$
(1) A case that both will visit the same day.
Shyam can go on any day between Tuesday to Saturday in 5 ways.
For any day that Shyam goes, Ekta will go on the same day in 1 way.
Total ways that they both go in the same day = $5\times1 = 5$
$\therefore P(both\ go\ on\ same\ day) = \frac{5}{25} = \frac{1}{5}$
Answer:
Total possible ways Shyam and Ekta can visit the shop = $5\times5 = 25$
(2) The case that both will visit the shop on consecutive days.
Shyam can go on any day between Tuesday to Friday in 4 ways.
For any day that Shyam goes, Ekta will go on the next day in 1 way
Similarly, Ekta can go on any day between Tuesday to Friday in 4 ways.
And Shyam will go on the next day in 1 way.
(Note: None of the cases repeats since they are in a different order!)
Total ways that they both go in the same day = $4\times1+4\times1 =8$
$\therefore P(they\ go\ on\ consecutive\ days) = \frac{8}{25}$
Answer:
Total possible ways Shyam and Ekta can visit the shop = $5\times5 = 25$
(1) A case that both will visit the same day.
Shyam can go on any day between Tuesday to Saturday in 5 ways.
For any day that Shyam goes, Ekta will go on a different day in $(5-1) = 4$ ways.
Total ways that they both go in the same day = $5\times4 = 20$
$\therefore P(both\ go\ on\ different\ days) = \frac{20}{25} = \frac{4}{5}$
What is the probability that the total score is (i) even?
Answer:
+ | 1 | 2 | 2 | 3 | 3 | 6 |
1 | 2 | 3 | 3 | 4 | 4 | 7 |
2 | 3 | 4 | 4 | 5 | 5 | 8 |
2 | 3 | 4 | 4 | 5 | 5 | 8 |
3 | 4 | 5 | 5 | 6 | 6 | 9 |
3 | 4 | 5 | 5 | 6 | 6 | 9 |
6 | 7 | 8 | 8 | 9 | 9 | 12 |
Total possible outcomes when two dice are thrown = $6\times6=36$
(1) Number of times when the sum is even = 18
$\therefore P(sum\ is\ even) = \frac{18}{36} = \frac{1}{2}$
What is the probability that the total score is (ii) 6?
Answer:
+ | 1 | 2 | 2 | 3 | 3 | 6 |
1 | 2 | 3 | 3 | 4 | 4 | 7 |
2 | 3 | 4 | 4 | 5 | 5 | 8 |
2 | 3 | 4 | 4 | 5 | 5 | 8 |
3 | 4 | 5 | 5 | 6 | 6 | 9 |
3 | 4 | 5 | 5 | 6 | 6 | 9 |
6 | 7 | 8 | 8 | 9 | 9 | 12 |
Total possible outcomes when two dice are thrown = $6\times6=36$
Number of times when the sum is 6 = 4
$\therefore P(sum\ is\ 6) = \frac{4}{36} = \frac{1}{9}$
What is the probability that the total score is (iii) at least 6?
Answer:
+ | 1 | 2 | 2 | 3 | 3 | 6 |
1 | 2 | 3 | 3 | 4 | 4 | 7 |
2 | 3 | 4 | 4 | 5 | 5 | 8 |
2 | 3 | 4 | 4 | 5 | 5 | 8 |
3 | 4 | 5 | 5 | 6 | 6 | 9 |
3 | 4 | 5 | 5 | 6 | 6 | 9 |
6 | 7 | 8 | 8 | 9 | 9 | 12 |
Total possible outcomes when two dice are thrown = $6\times6=36$
Number of times when the sum is at least 6, which means sum is greater than 5 = 15
$\therefore P(sum\ is\ atleast\ 6) = \frac{15}{36} = \frac{5}{12}$
Answer:
Let there be the number of blue balls in the bag.
Number of red balls = 5
Thus, the total number of balls = total possible outcomes = $5+x$
$P(getting\ a\ red\ ball) = \frac{5}{5+x}$
And, $P(getting\ a\ blue\ ball) = \frac{x}{5+x}$
According to question,
$P(getting\ a\ blue\ ball) = P(getting\ a\ red\ ball)$
$\\ \frac{x}{5+x} = 2.\left (\frac{5}{5+x} \right )$
$\implies x = 2.5 = 10$
Therefore, there are 10 blue balls in the bag.
Answer:
Total number of balls in the bag = 12
Number of black balls in the bag = $x$
$\therefore P(getting\ a\ black\ ball) = \frac{x}{12}$
According to the question,
6 more black balls are added to the bag.
$\therefore$ Total number of balls = $12 + 6 = 18$
And, the new number of black balls = $x+ 6$
$\therefore P'(getting\ a\ black\ ball) = \frac{x+6}{18}$
Also, $P' = 2\times P$
$\implies \frac{x+6}{18} = 2\left (\frac{x}{12} \right )$
$\\ \implies \frac{x+6}{18} = \frac{x}{6} \\ \implies x+6 = 3x \\ \implies 2x = 6$
$\implies x =3$
The required value of $x$ is 3
Answer:
Let $x$ be the number of blue marbles in the jar.
$\therefore$ Number of green marbles in the jar = $24-x$
According to question,
$P(getting\ a\ green\ marble) = \frac{24-x}{24} = \frac{2}{3}$
$\\ \implies 24-x = 2\times8 \\ \implies x = 24-16 = 8$
$\therefore$ Number of blue marbles in the jar is 8
Also Read| Probability Class 10 Notes
Exercise 15.2 Class 10 Maths, depends on PROBABILITY and higher ramifications of the likelihood of an event.
NCERT book Class 10 Maths chapter 15 exercise 15.2 assists us with testing our essential idea of probability by addressing a portion of the hard and extensive inquiries identified with it.
NCERT syllabus Class 10 Maths chapter 15 exercise 15.2 sets us up for the new sorts of problems that are to come in our higher classes related to probability.
Also, See:
Take Aakash iACST and get instant scholarship on coaching programs.
Frequently Asked Questions (FAQs)
This exercise has tough question which tests the capability of our understanding and problem solving.
Since each dice has 6 different outcomes, and we are rolling two dice at once.
So, the total number of outcomes = 6×6 = 36
total probability of all events is = 1
probability of first and the second event is 0.45 and 0.23
probability of the third event is = 1-(0.45+0.23)=0.32
The sample space of tossing three coins at once is:
{HHH, HHT, HTH, THH, HTT, THT, TTH, TTT}
Probability of a red ball to be drawn = 0.45
Total no of balls = 20
Total no of red balls = 20 × 0.45 = 9
On Question asked by student community
Hello
You asked about Class 10 sample paper board exam and most important questions. Practicing sample papers and previous year questions is one of the best ways to prepare for the board exam because it gives a clear idea of the exam pattern and types of questions asked. Schools and teachers usually recommend students to solve at least the last five years question papers along with model papers released by the board.
For Class 10 board exams, the most important areas are Mathematics, Science, Social Science, English, and Hindi or regional language. In Mathematics, questions from Algebra, Linear Equations, Geometry, Trigonometry, Statistics, and Probability are repeatedly seen. For Science, the key chapters are Chemical Reactions, Acids Bases and Salts, Metals and Non metals, Life Processes, Heredity, Light and Electricity. In Social Science, priority should be given to Nationalism, Resources and Development, Agriculture, Power Sharing, Democratic Politics, and Economics related topics. In English, focus on unseen passages, grammar exercises, and important writing tasks like letter writing and essays.
Follow these steps to access the SQPs and marking schemes:
Step 1: Visit https://cbseacademic.nic.in/
Step 2: Click on the link titled “CBSE Sample Papers 2026”
Step 3: A PDF will open with links to Class 10 and 12 sample papers
Step 4: Select your class (Class 10 or Class 12)
Step 5: Choose your subject
Step 6: Download both the sample paper and its marking scheme
Hello,
Yes, you can give the CBSE board exam in 2027.
If your date of birth is 25.05.2013, then in 2027 you will be around 14 years old, which is the right age for Class 10 as per CBSE rules. So, there is no problem.
Hope it helps !
Here are some strategies so u can do best in your board exams and get god score
1. Make a good and smart schedule
2. If u r from cbse board go through ncert books by heart
3. Solve pyqs of each subject
4. Do revision on daily basis
5. Practice on presentation and writing the answer .
6. Do your best and give exam with the best way possible all the best blud .
Hello! If you selected “None” while creating your APAAR ID and forgot to mention CBSE as your institution, it may cause issues later when linking your academic records or applying for exams and scholarships that require school details. It’s important that your APAAR ID correctly reflects your institution to avoid verification problems. You should log in to the portal and update your profile to select CBSE as your school. If the system doesn’t allow editing, contact your school’s administration or the APAAR support team immediately so they can correct it for you.
Hello Aspirant,
Here's how you can find it:
School ID Card: Your registration number is often printed on your school ID card.
Admit Card (Hall Ticket): If you've received your board exam admit card, the registration number will be prominently displayed on it. This is the most reliable place to find it for board exams.
School Records/Office: The easiest and most reliable way is to contact your school office or your class teacher. They have access to all your official records and can provide you with your registration number.
Previous Mark Sheets/Certificates: If you have any previous official documents from your school or board (like a Class 9 report card that might have a student ID or registration number that carries over), you can check those.
Your school is the best place to get this information.
Take Aakash iACST and get instant scholarship on coaching programs.
This ebook serves as a valuable study guide for NEET 2025 exam.
This e-book offers NEET PYQ and serves as an indispensable NEET study material.
As per latest syllabus. Physics formulas, equations, & laws of class 11 & 12th chapters
As per latest syllabus. Chemistry formulas, equations, & laws of class 11 & 12th chapters
As per latest 2024 syllabus. Study 40% syllabus and score upto 100% marks in JEE