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This article discuss about the class 10 maths ex 1.4 that deals with rational numbers i.e. real numbers that can be written in simple fractions p/q, where p and q are types of integers, q not equal to zero. These NCERT Solutions are created by expert team at careers360 considering the latest syllabus and pattern of the CBSE 2023-24, comprehensively covering step by step solutions of every problems.
In NCERT solutions for Class 10 Maths exercise 1.4 the focus is mainly on rational numbers and their decimal expansions. Most of the problems in Class 10th Maths chapter 1 exercise 1.4 are related to rational numbers that terminate or not. Along with Class 10 Maths chapter 1 exercise 1.4 the following exercises are also present.
Real Numbers Class 10 Chapter 1 - Exercise 1.4
Answer:
The denominator is of the form 2 a x 5 b where a = 0 and b = 5. Therefore the given rational number will have a terminating decimal expansion.
Answer:
The denominator is of the form 2 a x 5 b where a = 3 and b = 0. Therefore the given rational number will have a terminating decimal expansion.
Answer:
The denominator is not of the form 2 a x 5 b . Therefore the given rational number will have a non-terminating repeating decimal expansion.
Answer:
The denominator is of the form 2 a x 5 b where a = 6 and b = 1. Therefore the given rational number will have a terminating decimal expansion.
Answer:
The denominator is not of the form 2 a x 5 b . Therefore the given rational number will have a non-terminating repeating decimal expansion.
Answer:
The denominator is of the form 2 a x 5 b where a = 3 and b = 2. Therefore the given rational number will have a terminating decimal expansion.
Answer:
The denominator is not of the form 2 a x 5 b . Therefore the given rational number will have a non-terminating repeating decimal expansion.
Answer:
The denominator is of the form 2 a x 5 b where a = 0 and b = 1. Therefore the given rational number will have a terminating decimal expansion.
Answer:
The denominator is of the form 2 a x 5 b where a = 1 and b = 1. Therefore the given rational number will have a terminating decimal expansion.
Answer:
The denominator is not of the form 2 a x 5 b . Therefore the given rational number will have a non-terminating repeating decimal expansion.
Answer:
decimal expansions of rational numbers are
(i)
(ii)&nbsnbsp;
(iv)
(vI)
(viii)
(ix)
Answer:
The denominator is of the form 2 a x 5 b where a = 9 and b = 9. Therefore the given number is rational and has a terminating decimal expansion.
Answer:
Since the decimal part of the given number is non-terminating and non-repeating we can conclude that the given number is irrational and cannot be written in the form
Answer:
As the decimal part of the given number is non-terminating and repeating, the number is rational but its denominator will have factors other than 2 and 5.
Another important theorem which helps to solve problems of this class 10 ex 1.4, states that "Any rational number p/q. Be a rational number such that the prime factorisation of q is not of form 2n5m, where n, m are non-negative integers, where p and q are coprime. The rational number thus has a non-terminating repeated decimal expansion (recurring). NCERT book solutions for Class 10 Maths exercise 1.4 mainly focus on the decimal expansion of rational numbers. Questions given in the exercise 1.4 Class 10 Maths are very important for exam preparation. Students can practice 10th class maths exercise 1.4 answers to command the concepts.
Key Features of NCERT Solutions for Class 10 Maths Exercise 1.4
Also see-
As per latest 2024 syllabus. Maths formulas, equations, & theorems of class 11 & 12th chapters
17/16 has a terminating decimal expansion as 16 has factorisation 16=2*2*2*2, since the denominator has only 2 in the denominator.
Since the number has a terminating decimal expansion, it can be expressed in the form of p/q that is why this is a rational number.
Given rational number can also be written as:
12.1325=121325/10000
Since it is non-terminating and non-repeating decimal expansion, that is why it is an irrational number.
Major properties of rational numbers are Commutative, Associative, Distributive and Closure property.
Hello
Since you are a domicile of Karnataka and have studied under the Karnataka State Board for 11th and 12th , you are eligible for Karnataka State Quota for admission to various colleges in the state.
1. KCET (Karnataka Common Entrance Test): You must appear for the KCET exam, which is required for admission to undergraduate professional courses like engineering, medical, and other streams. Your exam score and rank will determine your eligibility for counseling.
2. Minority Income under 5 Lakh : If you are from a minority community and your family's income is below 5 lakh, you may be eligible for fee concessions or other benefits depending on the specific institution. Some colleges offer reservations or other advantages for students in this category.
3. Counseling and Seat Allocation:
After the KCET exam, you will need to participate in online counseling.
You need to select your preferred colleges and courses.
Seat allocation will be based on your rank , the availability of seats in your chosen colleges and your preferences.
4. Required Documents :
Domicile Certificate (proof that you are a resident of Karnataka).
Income Certificate (for minority category benefits).
Marksheets (11th and 12th from the Karnataka State Board).
KCET Admit Card and Scorecard.
This process will allow you to secure a seat based on your KCET performance and your category .
check link for more details
https://medicine.careers360.com/neet-college-predictor
Hope this helps you .
Hello Aspirant, Hope your doing great, your question was incomplete and regarding what exam your asking.
Yes, scoring above 80% in ICSE Class 10 exams typically meets the requirements to get into the Commerce stream in Class 11th under the CBSE board . Admission criteria can vary between schools, so it is advisable to check the specific requirements of the intended CBSE school. Generally, a good academic record with a score above 80% in ICSE 10th result is considered strong for such transitions.
hello Zaid,
Yes, you can apply for 12th grade as a private candidate .You will need to follow the registration process and fulfill the eligibility criteria set by CBSE for private candidates.If you haven't given the 11th grade exam ,you would be able to appear for the 12th exam directly without having passed 11th grade. you will need to give certain tests in the school you are getting addmission to prove your eligibilty.
best of luck!
According to cbse norms candidates who have completed class 10th, class 11th, have a gap year or have failed class 12th can appear for admission in 12th class.for admission in cbse board you need to clear your 11th class first and you must have studied from CBSE board or any other recognized and equivalent board/school.
You are not eligible for cbse board but you can still do 12th from nios which allow candidates to take admission in 12th class as a private student without completing 11th.
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