NEET/JEE Coaching Scholarship
Get up to 90% Scholarship on Offline NEET/JEE coaching from top Institutes
NCERT Solutions for Exercise 9.1 Class 10 Maths Chapter 9 Some Applications of Trigonometry are discussed here. These NCERT solutions are created by subject matter expert at Careers360 considering the latest syllabus and pattern of CBSE 2024-25. Class 10 maths ex 9.1 deal the application of trigonometry and to be specified, cover all the problems and questions related to height and distances in which we will use trigonometry to find the aspects asked.
New: Get up to 90% Scholarship on NEET/JEE Coaching from top Coaching Institutes
Latest: Download CBSE Syllabus 2025-26 for Class 9, 10, 11, 12th
CBSE 2025 Class 10th Paper with Solutions: Maths | Social Science | Science
Don't Miss: Best Courses after 10th
NCERT solutions for exercise 9.1 Class 10 Maths chapter 9 Some Applications of Trigonometry focuses on using trigonometry to find the angle of depression, angle of elevation and line of sight along with this finding the height or length of an object or the distance between two distant objects. 10th class Maths exercise 9.1 answers are designed as per the students demand covering comprehensive, step by step solutions of every problem. Practice these questions and answers to command the concepts, boost confidence and in depth understanding of concepts. Students can find all exercise together using the link provided below.
Some Applications of Trigonometry Class 10 Chapter 9 Excercise: 9.1
Answer:
Given that,
The length of the rope (AC) = 20 m. and
Let the height of the pole (AB) be
So, in the right triangle
By using the Sin rule
Hence the height of the pole is 10 m.
Answer:
Suppose DB is a tree and the AD is the broken height of the tree which touches the ground at C.
GIven that,
let AB =
So, AD+AB = DB =
In right angle triangle
So, the value of
Similarily,
the value of
So, the total height of the tree is-
= 8 (1.732) = 13.856 m (approx)
Answer:
Suppose
Given that,
AF = 1.5 m, BC = 3 m,
In triangle
The value of
Similarily in
the value of
Hence the length of the slide for children below 5 yrs. is 3 m and for the elder children is 3.468 m.
Answer:
Let the height of the tower AB is
According to question,
In the right triangle
the value of
Thus the height of the tower is 17.32 m
Answer:
A
Given that,
The length of AB = 60 m and the inclination of the string with the ground at point C is
Let the length of the string AC be
According to question,
In right triangle
The value of length of the string (
Hence the length of the string is 69.28 m.
Answer:
Given that,
The height of the tallboy (DC) is 1.5 m and the height of the building (AB) is 30 m.
According to question,
In right triangle AFD,
So, DF =
In right angle triangle
EF =
So, distance walked by the boy towards the building = DF - EF =
Answer:
Suppose BC =
We have,
AB = 20 m, BC =
According to question,
In triangle
So,
Again,
In triangle
Answer- the height of the tower is 14.64 m
Answer:
Let the height of the pedestal be
the angle of elevation of the top of the statue and top of the pedestal is(
Now,
In triangle
therefore, BC =
In triangle
the value of
Hence the height of the pedestal is
Answer:
It is given that, the height of the tower (AB) is 50 m.
Let the height of the building be
According to question,
In triangle PBQ,
In triangle ABQ,
On equating the eq(i) and (ii) we get,
therefore,
Answer:
Given that,
The height of both poles are equal DC = AB. The angle of elevation of of the top of the poles are
Let the height of the poles be
According to question,
In triangle DEC,
In triangle AEB,
On equating eq (i) and eq (ii), we get
So,
Hence the height of both poles is (
Answer:
Suppose the
It is given that, the width of CD is 20 m,
According to question,
In triangle
In triangle ACB,
On equating eq (i) and (ii) we get:
from here we can calculate the value of
Answer:
Let the height of the cable tower be (AB =
Given,
The height of the building is 7 m and angle of elevation of the top of the tower
According to question,
In triangle
since DB = CE = 7 m
In triangle
Thus, the total height of the tower equal to
Answer:
Given that,
The height of the lighthouse (AB) is 75 m from the sea level. And the angle of depression of two different ships are
Let the distance between both the ships be
According to question,
In triangle
In triangle
From equation (i) and (ii) we get;
Hence, the distance between the two ships is approx 55 m.
Answer:
Given that,
The height of the girl is 1.2 m. The height of the balloon from the ground is 88.2 m and the angle of elevation of the balloon from the eye of the girl at any instant is (
Let the
AB = ED = 88.2 - 1.2 =87 m
Now, In triangle
In triangle
Thus, distance traveled by the balloon from position A to D
Answer:
Let
According to question,
In triangle
In triangle
Put the value of
Hence, from point B car take 3 sec to reach the foot of the tower.
Answer:
Let the height of the tower be
we have PB = 4m and QB = 9 m
Suppose
According to question,
In triangle
In triangle
multiply the equation (i) and (ii), we get
Hence the height of the tower is 6 m.
NCERT syllabus Class 10 Maths chapter 9 exercise 1: The questions in exercise 9.1 Class 10 Maths, broadly consist of some basic questions in which we have to find height and distance with the help of the formula of tangent, cosine and sine. NCERT solutions for NCERT book Class 10 Maths exercise 9.1 also consist of questions that are a little bit harder as we have to apply the trigonometric formula twice and also use some basic phenomena of real life such as the shadow of objects. Exercise 9.1 Class 10 Maths covers all types of questions that can be formed height and distance. Students can find here Some applications of Trigonometry Class 10 Notes that are very helpful in quickly revising all important concepts discussed in this chapter.
Also see-
The values of all trigonometric functions dependent on the value of the ratio of sides in a right-angled triangle are known as trigonometric ratios.
angle of depression
angle of elevation
line of sight
finding the height or length of an object or the distance between two distant objects
The angle created by the line of sight with the horizontal when it is above the horizontal level is the angle of elevation of an item that we can see.
When we elevate our head to gaze at an object, for example.
The angle formed by the line of sight with the horizontal when it is below the horizontal level is the angle of depression of an item that we can see.
When we drop our head to gaze at an object, for example.
The line of sight is the line which is a line traced from an observer's eye to a point in the item being seen.
Trigonometric ratios can be used to calculate an object's height or length, as well as the distance between two distant objects.
Before the Class 10 Mathematics chapter 9 activity 9.1, there are seven key questions that must be answered.
In the NCERT solutions for the Class 10 Maths chapter 9 exercise, there are 16 problems.
Hello
Since you are a domicile of Karnataka and have studied under the Karnataka State Board for 11th and 12th , you are eligible for Karnataka State Quota for admission to various colleges in the state.
1. KCET (Karnataka Common Entrance Test): You must appear for the KCET exam, which is required for admission to undergraduate professional courses like engineering, medical, and other streams. Your exam score and rank will determine your eligibility for counseling.
2. Minority Income under 5 Lakh : If you are from a minority community and your family's income is below 5 lakh, you may be eligible for fee concessions or other benefits depending on the specific institution. Some colleges offer reservations or other advantages for students in this category.
3. Counseling and Seat Allocation:
After the KCET exam, you will need to participate in online counseling.
You need to select your preferred colleges and courses.
Seat allocation will be based on your rank , the availability of seats in your chosen colleges and your preferences.
4. Required Documents :
Domicile Certificate (proof that you are a resident of Karnataka).
Income Certificate (for minority category benefits).
Marksheets (11th and 12th from the Karnataka State Board).
KCET Admit Card and Scorecard.
This process will allow you to secure a seat based on your KCET performance and your category .
check link for more details
https://medicine.careers360.com/neet-college-predictor
Hope this helps you .
Hello Aspirant, Hope your doing great, your question was incomplete and regarding what exam your asking.
Yes, scoring above 80% in ICSE Class 10 exams typically meets the requirements to get into the Commerce stream in Class 11th under the CBSE board . Admission criteria can vary between schools, so it is advisable to check the specific requirements of the intended CBSE school. Generally, a good academic record with a score above 80% in ICSE 10th result is considered strong for such transitions.
hello Zaid,
Yes, you can apply for 12th grade as a private candidate .You will need to follow the registration process and fulfill the eligibility criteria set by CBSE for private candidates.If you haven't given the 11th grade exam ,you would be able to appear for the 12th exam directly without having passed 11th grade. you will need to give certain tests in the school you are getting addmission to prove your eligibilty.
best of luck!
According to cbse norms candidates who have completed class 10th, class 11th, have a gap year or have failed class 12th can appear for admission in 12th class.for admission in cbse board you need to clear your 11th class first and you must have studied from CBSE board or any other recognized and equivalent board/school.
You are not eligible for cbse board but you can still do 12th from nios which allow candidates to take admission in 12th class as a private student without completing 11th.
Get up to 90% Scholarship on Offline NEET/JEE coaching from top Institutes
This ebook serves as a valuable study guide for NEET 2025 exam.
This e-book offers NEET PYQ and serves as an indispensable NEET study material.
As per latest 2024 syllabus. Physics formulas, equations, & laws of class 11 & 12th chapters
As per latest 2024 syllabus. Chemistry formulas, equations, & laws of class 11 & 12th chapters
Accepted by more than 11,000 universities in over 150 countries worldwide