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RD Sharma Solutions Class 12 Mathematics Chapter 10 FBQ

RD Sharma Solutions Class 12 Mathematics Chapter 10 FBQ

Edited By Satyajeet Kumar | Updated on Jan 20, 2022 06:34 PM IST

The RD Sharma Class 12 chapter 10 exercise FBQ arrangement – Our experts plan Differentiation to help ensure students in understanding the thoughts solicited in this chapter and procedures to deal with issues in a more restricted period.

In this RD Sharma class 12 solutions FBQ Chapter 10, Differentiation is a process in Maths, where we find the quick rate of function change based on one of its variables. Class 12 RD Sharma chapter 10 exercise FBQ solution consists of various topics that play a major role in finding the rate of displacement. At Careers360, RD Sharma class 12 chapter 10 exercise FBQ Solutions help students who seek to get a decent scholarly score in the exam.

This Story also Contains
  1. RD Sharma Class 12 Solutions Chapter 10 FBQ Differentiation - Other Exercise
  2. Differentiation Excercise: FBQ
  3. RD Sharma Chapter-wise Solutions

Also Read - RD Sharma Solution for Class 9 to 12 Maths

RD Sharma Class 12 Solutions Chapter 10 FBQ Differentiation - Other Exercise

Differentiation Excercise: FBQ

Differentiation exercise Fill in the blanks question 1

Answer: (dydu)u=1=2
Hint: y=(u2u0u2u<0)
Given: y=u|u|
Solution:
y=(u2u0u2u<0)dydu=(2u2u 02u2u<0)
(dydu)1=(2(1)
=2


Differentiation exercise Fill in the blanks question 2

Answer: (dydx)1=1 and (dydx)x=1=3
Hint: y=(3xx0xx<0)
Given: y=2x+|x|
Solution:
y=(2x+xx02xxx<0)y=(3xx0xx<0)dydx=(3x>01x<0)
(dydx)1=1 and (dydx)1=3


Differentiation exercise Fill in the blanks question 3

Answer: f1(2)=3
Hint: f(x)=(xx2x2x0x2xx2x0)
Given: f(x)=|x2x|
Solution: f(x)=|x2x|
f(x)=((x2x)x2x<0x2xx2x0)
f(x)=((xx2)x2x<0x2xx2x0)f(x)=((12x)x2x<02x1x2x0)
f(2)=2x1=2(2)1=3


Differentiation exercise Fill in the blanks question 4

Answer: k=1
Hint: dydx=cosx0
Given: y=sinx0 and dydx=kcosx0
Solution: y=sinx0 x0=π180x
Differentiating y.u.1 to x
dydx=π180cosx0(i) And dydx=kcosx0(ii)
By (i) and (ii)
k=π180


Differentiation exercise Fill in the blanks question 5

Answer: f1(0)=0
Hint: f1(x)=g1(x)>g1(x)
Solution: f(x)=exg(x)
Differentiating f(x) we get
f1(x)=exg1(x)+exg(x)f1(0)=e0g1(0)+e0g(0)
=1(1)+1(2)=1+2=3


Differentiation exercise Fill in the blanks question 6

Answer:f(3)=3
Hint:
|x+2|=((x+2)x2x>2x<2)=f(x)=3|x+2|
Solution: f(x)=3|x+2|
f(x)=(3(x+2)x23(x+2)x<2)f1(x)=(3x23x<2)f1(3)=3


Differentiation exercise Fill in the blanks question 7

Answer: 2
Hint: using chain rule
Given:f(1)=3
Solution: ddx=lnf(ex+2x)
=1f(ex+2x)f(ex+2x)×(ex+2)=(ex+2)f(e0+2x)f(e0+2x)
=3f(1)f(1)=3×23=2


Differentiation exercise Fill in the blanks question 8

Answer: f(x)=(2xx02xx20)
Hint:x|x|=(x2x0x2x<0)
Given:f|x|=x|x|
Solution:
f|x|=x|x|
f(x)=(x2x0x2x<0)f1(x)=(2xx02xx<0)


Differentiation exercise Fill in the blanks question 9

Answer: f1(2)=0
Hint: the mod function
Given: f(x)=|x1|+|x3|
Solution:
|x1|=(u1u>1(u1)u<1)|x3|=(x3x>3(x3)x3)
 Case- 1:x<1f(x)=|x1|+|x3|=x+1x>3=2x>4

 Case- 2:1x<3f(x)=|x1|(x3)=x1x+3=2

 Case. 3f(x)=x1>x+3=2x4f(x)=(2x+4x<121x<3(x3)x3)
f(x)=(2x<101x<32x3)f(x)=0


Differentiation exercise Fill in the blanks question 10

Answer: 1+32
Hint: cosx<sinx where 0xπ4
Given: f(x)=|cosxsinx|
Solution: f(x)=|cosxsinx|
f(x)=cosxsinx0xπ/4f(x)=(cosxsinx)π4xπ2
f(x)=cosxsinx0xπ/4f(x)=cosx+sinxπ4xπ2
=12+32=1+32


Differentiation exercise Fill in the blanks question 11

Answer: f(πx)=(12)
Hint: f(x)=(cosx0xπ2cosxπ2<x<π)
Given:f(x)=|cosx|
Solution:
f(x)=|cosx|
f(x)=(cosx0uπ2cosxπ2<u<π)
f(x)=(sinx0xπ2sinxπ2<x<π)f1(π2)=sinπ2=12


Differentiation exercise Fill in the blanks question 12

Answer: 23x
Hint:  take u=x2 and v=x3
Given:The derivative of x2 and x3
Solution:
 Let u=x2dudx=2x And let v=x3
dvdx=3x2dudv=du/dxdv/dx=2x3x2=23x


Differentiation exercise Fill in the blanks question 14

Answer: f1(π4)=(12)
Hint:f1(x)=(sinx0xπ2sinxπ2<x<π)
Given: f(x)=|sinx|
Solution:
f(x)=(sinx0xπ2sinxπ2<x<π)f(x)=(cosx0xπ2cosxπ2<x<π)
fπ2=cosπ4=12


Differentiation exercise Fill in the blanks question 15

Answer: f1(π6)=1+32
Hint:
Given: f(x)=|sinxcosx|
Solution: f(x)=|sinxcosx|
f(x)=(sinxcosx0xπ4(sinxcosx)π4<xπ4)f(x)=(sinx+cosx0xπ4(sinx+cosx)π4<xπ4)
f(π6)=sinπ6+cosπ6=12+32
=3+12


Differentiation exercise Fill in the blanks question 16

Answer: 2
Hint: d(tanx)dx=sec2x
Given: y=tanx0
x0=π180xdydx=π180sec2π180x=π180sec2x0



Differentiation exercise Fill in the blanks question 17

Answer: dydx=0
Hint: ddx=(sin1x)=11x2
Given: y=sin1(ex)+cos1(ex)
Solution: y=sin1(ex)+cos1(ex)
Differentiating (i) we get;
dydx=11+e2xex11+e2xex=0


Differentiation exercise Fill in the blanks question 18

Answer: 31x2
Hint:  put x=sinθ
Given: y=sin1(3x4x3)
Solution: By putting x=sinθ in y
y=sin1(3sinθ4sinθ)y=sin1(sin3θ)
=3θ=3sin1x
dydx=31x2


Differentiation exercise Fill in the blanks question 19

Answer: 0
Hint: cos1x+sin1x=π2
Given: y=sec1(x+1x1)+sin1(x1x+1)
Solution:
y=cos1(x1x+1)+sin1(x1x+1)
=π2=0


Differentiation exercise Fill in the blanks question 20

Answer:  tan u
Hint:  put u=cosx and v=sinx
Given: The derivative of cosx w.r.t sinx
Solution:
 Let u=cosx and v=sinxdudv=sinxdvdu=cosx
Therefore:
dudv=dudvdvdu=sinxcosx=tanx


Differentiation exercise Fill in the blanks question 21

Answer: log10ex
Hint:  use: [ddxlogex=1x]
Given:  If y=log10x
Solution: log10x
y=log10elogexdydx=log10e×1x

So the answer is log10ex


Differentiation exercise Fill in the blanks question 22

Answer: the correct answer is 3x21+x6
Hint: integrate the function.
Given: ddxf(x)=11+x2
Solution: integrating we get
ddx(f(x))dx=[11+x2]dxf(x)=tan1x+e
f(x3)=tan1(x3)+cf1(x3)=3x21+x6
So the answer is 3x21+x6


Differentiation exercise Fill in the blanks question 23

Answer: the correct answer is ='0'
Hint: y=cos(sinx2)ddxsinx=cosx
dydx=sin(sinx2)cosx22x
Given: y=cos(sinx2)
Solution: using dydx to get the value at λ2
Now at x=π/2
ddx=sin(sinπ2)cosπ22π2=0
So the correct answer is ‘0'


Differentiation exercise Fill in the blanks question 24

Answer: The correct answer is 1x
Hint: Differentiate the function but u should not be equal to zero
Given: y=loge|x|
Solution:
y=log|x|=(log(x),x<0log(x),x>0)
dydx=(1x=1x,,x<01x,x>0)
Which means it is equal to 1x when x0
ddxlog|x|=1x,x0
So the answer is 1x


Differentiation exercise Fill in the blanks question 25

Answer: the correct answer is =0
Hint: put 1,4,5 in the equation to get the respective value the use f1(1)+f1(u)f1(5)
Given: y=ax2+bx+c
Solution:
y=ax2+bx+cf1(x)=dydx=2ax+bf1(1)=2a+b and 
f1(x)=3a+4bf1(5)=10a+5bf1(1)+f1(u)f1(5)
=2a+b+8a+4b10a5b
So the correct answer is 0


Differentiation exercise Fill in the blanks question 26

Answer: the correct answer is 12
Hint:
Given: f1(1)=2 and g1(2)=4
Solution:
y=f(tanx) and z=g(secx)dydx=f(tanx)sec2x and dzdx=g(secx)secx+tanx
dydz=f1(tanx)sec2xg1(secx)secxtanxdydz=f(1)(2)2g(2)(2)=12
So the answer is 12

This chapter of RD Sharma class 12 exercise FBQ evolves around the possibility of lucidness. Students can download the RD Sharma class 12 solutions FBQ Chapter 10 Differentiation to find out with regards to this topic.

The RD Sharma class 12 solution Differentiation exercise FBQ reference book is the most purchased book by the students. It is not a simple task to answer FBQs that too in a complex chapter like the Differentiation. The students must be clear about all the concepts to give the answers quickly by not wasting time.

Moreover, the Class 12 RD Sharma chapter 10 exercise FBQ solution book has many shortcuts and tricks that can be followed to arrive at the solution effortlessly. This Class 12 RD Sharma chapter 10 exercise FBQ material has around 26 solved questions.

Some important concepts used in chapter 10 FBQ:-

  • Questions related to Differentiation of a function.

  • Questions related to the Differentiation of inverse trigonometric functions by the chain rule.

  • Questions related to Differentiation by using trigonometric substitutions.

  • Solutions on Differentiation of implicit functions.

  • Questions related to Logarithmic differentiation.

  • Differentiation of infinite series.

  • Differentiation of parametric functions.

  • Differentiation of determinants.

RD Sharma Chapter-wise Solutions

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