NCERT Solutions for Class 10 Science Chapter 4 Carbon and Its Compounds

Edited By Irshad Anwar | Updated on Oct 08, 2023 10:38 AM IST | #CBSE Class 10th

NCERT Solutions for Class 10 Science Chapter 4 "Carbon and Its Compounds"

NCERT Solutions for Class 10 Science Chapter 4 Carbon and Its Compounds, is curated by the senior and experienced faculty and subject experts at Careers360. Solving the NCERT textbook while making the solutions easy to grasp and understand is one of the challenging tasks that we have perfectly done! NCERT Solutions for Carbon and Its Compounds covers all the questions given in Chapter 4 of NCERT Textbook Science. NCERT Class 10 Science Solutions Chapter 4 will help you to clarify your concepts related to this chapter. Carbon and Its Compounds, Class 10 Science, Chapter 4 NCERT Solutions will be beneficial for board exams as well as competitive exams. NCERT Solutions for Class 10 Science Chapter 4 Carbon and Its Compounds are provided in simple language and are easily understandable.

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NCERT Solutions for Class 10 Science Chapter 4 Carbon and Its Compounds

Class 10 Science Chapter 4 Question Answer: NCERT Solutions for Class 10 Science provides a solid foundation for each idea. It will be easy and clear to understand all the advanced concepts by working on NCERT Solutions PDF. Carbon and Its Compounds Class 10 Solutions will be heavily weighted in competitive exams like JEE and NEET, per the CBSE marking scheme. Class 10 Science Chapter 4 question answer are provided further in the article. Refer to NCERT Solutions for Class 10 for other subjects here.

NCERT Solutions for Class 10 Science Chapter 4 Carbon and Its Compounds:

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NCERT Solutions for Class 10 Science Chapter 4 - Carbon and Its Compounds (Intext Questions and Exercise)

NCERT solutions for class 10 science chapter 4 Carbon and its compounds

Topic:4.1 Bonding in carbon - The covalent bond

Q.1. What would be the electron dot structure of carbon dioxide which has the formula $CO_{2}$ ?

Answer:

The electron dot structure of carbon dioxide which has the formula $CO_{2}$ is:

1644211481948

Q.2. What would be the electron dot structure of a molecule of sulphur which is made up of eight atoms of sulphur? (Hint – The eight atoms of sulphur are joined together in the form of a ring)

Answer:

The electron dot structure of a molecule of $S_8$ is:

1644211503615

NCERT Textbook Solutions for Class 10 Science Chapter 4 Carbon and Its Compounds

Topic 4.2: Versatile nature of carbon

Q.1. How many structural isomers can you draw for pentane?

Answer:

There are three structural isomers of pentane:

n-pentane
iso-pentane
neo-pentane

Q. 2. What are the two properties of carbon which lead to the huge number of carbon compounds we see around us?

Answer:

The two properties of carbon which lead to the formation of a large number of carbon compounds are:

( 1) Catenation: Carbon has the unique ability to form bonds with other atoms of carbon which gives rise to large molecules. The carbon-carbon bond is very strong and hence stable.

(2) Tetravalency: Since carbon has a valency of four, it is capable of bonding with four other atoms. These bonds that carbon forms with other elements are very strong making these compounds exceptionally stable.

Q.3. What will be the formula and electron dot structure of cyclopentane?

Answer:

The formula of cyclopentane is $C_5H_{10}$ .

And, the electron dot structure of cyclopentane is :

1644211564354

Q. 4. Draw the structures for the following compounds.

(i) Ethanoic acid

Answer:

The structure of ethanoic acid is:

1644211590030

Q. 4. Draw the structures for the following compounds.

(ii) Bromopentane

Are structural isomers possible for bromopentane?

Answer:

The structure of bromopentane( $C_5H_{11}Br$ ) is:

1644211621219

Yes, structural isomers for bromopentane is possible.

For n-pentane: Br at $2^{nd}\ and\ 3^{rd}$ carbon

Also, Br at different carbons for iso-pentane and neo-pentane.

Q. 4. Draw the structures for the following compounds.

(iii) Butanone

Answer:

The structure of Butanone ( $C_2H_5COCH_3$ ) is:

1644211643456

Q. 4. Draw the structures for the following compounds.

(iv) Hexanal

Answer :

The structure of hexanal ( $C_5H_{11}CHO$ ) is:

1644211668979

Class 10 Science Chapter 4 Question Answer

Q. 5. (i) How would you name the following compound?

$CH_{3}-CH_{2}-Br$

Answer :

The compound ( $CH_{3}-CH_{2}-Br$ ) has 2 carbon atoms. Hence the parent hydrocarbon is ethane.

A bromo group is attached to one of the carbon atoms. Thus, the nomenclature of the compound is Bromoethane.

Q. 5. (ii) How would you name the following compounds?

1595094395582

Answer:

The compound ( $H_2 C = 0$ ) contains 1 carbon atom. Hence the parent hydrocarbon is methane. It contains the functional group aldehyde.

Thus, the nomenclature of the compound is: Methanal.

Q.5. (III) How would you name the following compound?

1595094408775

Answer:

The compound has 6 carbons in the chain. Hence the parent hydrocarbon is hexane. It contains a triple bond and hence the suffix -yne- is used. Thus, the nomenclature of the compound is: Hexyne

Topic 4.3 Chemical Properties of carbon compounds

Q. 1. Why is the conversion of ethanol to ethanoic acid an oxidation reaction?

Answer:

The conversion of ethanol to ethanoic acid is :

1644211690130

Since there is an addition of oxygen in the reaction, this is an oxidation reaction.

Q. 2. A mixture of oxygen and ethyne is burnt for welding. Can you tell why a mixture of ethyne and air is not used?

Answer:

A mixture of oxygen and ethyne is burnt for welding. But a mixture of ethyne and air is not used. This is because ethyne undergoes incomplete combustion in air giving a sooty flame.

In oxygen, ethyne gives a clean flame with temperature as high as 3300 K due to complete combustion.

Topic 4.4: Some Important Carbon Compounds - Ethanol and Ethanoic Acid

Q. 1. How would you distinguish experimentally between an alcohol and a carboxylic acid?

Answer:

We can distinguish between alcohol and carboxylic acid by reacting them with carbonates/hydrogen carbonates. The acid reacts with hydrogen carbonate to liberate carbon dioxide which turns lime water milky.

$CH_3COOH + NaHCO_3 \rightarrow CH_3COONa + CO_2 + H_2O$

Whereas alcohol shows no evolution of gas when reacted with carbonates.

$C_2H_5OH + NaHCO_3 \rightarrow no\ reaction$

Q.2. What are oxidizing agents?

Answer:

The oxidation reaction is the reaction in which oxygen is added or hydrogen is removed.

The substance which adds oxygen to others is known as oxidizing agents.

Example : AlkalinepPotassium permanganate

Topic 4.5: Soaps and Detergents

Q.1. Would you be able to check if the water is hard by using a detergent?

Answer:

No, we will not be able to check if the water is hard sing detergents. This is because detergents give rich lather with both hard and soft water without forming any scum.

Q. 2. People use a variety of methods to wash clothes. Usually after adding the soap, they ‘beat’ the clothes on a stone, or beat it with a paddle, scrub with a brush or the mixture is agitated in a washing machine. Why is agitation necessary to get clean clothes?

Answer:

Soap molecules form spherical structures known as micelles. The oily dirt is trapped inside these micelles which remain suspended as colloid. Hence, to remove these micelles containing the dirt, the clothes are agitated.

NCERT solutions for class 10 science chapter 4 Carbon and its Compounds - Exercise solutions

Q. 1. Ethane, with the molecular formula $C_{2}H_{6}$ has

(a) 6 covalent bonds.
(b) 7 covalent bonds.
(c) 8 covalent bonds.
(d) 9 covalent bonds.

Answer:

1644211711369

Ethane, with the molecular formula $C_{2}H_{6}$ has 7 covalent bonds.

(b) It has 1 ( $C-C$ ) and 6( $C-H$ ) bonds.

Q. 2. Butanone is a four-carbon compound with the functional group

(a) carboxylic acid.
(b) aldehyde.
(c) ketone.
(d) alcohol.

Answer:

Butanone is a four-carbon compound with the functional group ketone. (c)

Butan- one : one is the suffix used for the functional group ketone.

Q. 3. While cooking, if the bottom of the vessel is getting blackened on the outside, it means that

(a) the food is not cooked completely.

(b) the fuel is not burning completely.

(d) the fuel is burning completely.

Answer:

While cooking, if the bottom of the vessel is getting blackened on the outside, it means that the fuel is not burning completely.

(b) is the answer

Q. 4. Explain the nature of the covalent bond using the bond formation in.

Answer:

Carbon has four electrons in its outermost shell and needs to gain or lose four electrons to attain noble gas configuration. Carbon overcomes this problem by sharing its valence electrons with other atoms of carbon or with atoms of other elements.

Of the four electrons, three are shared with hydrogen atoms and one with a chlorine atom. Thus it has three (C-H) and one (C-Cl) covalent bonds.

These bonds formed by the sharing of electrons are known as covalent bonds. Carbon, hydrogen, and chlorine attains the nearest noble gas configuration of Ne, He and Ar respectively.

Class 10 Carbon and Its Compounds Solutions:

Q.5. (a) Draw the electron dot structures for

ethanoic acid .

Answer:

The electron dot structure of ethanoic acid ( $CH_3COOH$ ) is:

1644211745945

Q.5. (b) Draw the electron dot structures for

$H_{2}S$ .

Answer:

The electron dot structure of hydrogen sulphide ( $H_{2}S$ ) is:

1644211765858

Q.5.(c) Draw the electron dot structures for

propanone .

Answer:

The electron dot structure of propanone ( $CH_3COCH_3$ ) is:

1644211803041

Q.5.(d) Draw the electron dot structures for

$F_{2}$

Answer:

The electron dot structure of $F_{2}$ is:

1644211828483

Q. 6. What is a homologous series? Explain with an example.

Answer:

A series of carbon compounds having different numbers of carbon atoms but have the same functional group substituting the hydrogen atom is known as a homologous series.

For example, methane, ethane, propane, butane, etc. constitute the alkane homologous series. The general formula for alkanes is $C_nH_{2n+2}$ . Methane $CH_4$ ; Ethane $C_2H_6$ ; Propane $C_3H_8$ and so on.

Q. 7. How can ethanol and ethanoic acid be differentiated on the basis of their physical and chemical properties?

Answer:

Physical Properties

Ethanol	Ethanoic acid
It has a pleasant smell.	It has a pungent smell of vinegar.
It has a low boiling point : 351 K.	It has a comparatively high boiling point: 391 K.

Chemical Properties:

Ethanol	Ethanoic acid
It has no action on litmus paper.	It turns blue litmus to red.
no reaction with $NaHCO_3$	Liberates $CO_2$ when reacted with $NaHCO_3$

Q. 8. Why does micelle formation take place when soap is added to water? Will a micelle be formed in other solvents such as ethanol also?

Answer:

A soap is a sodium or potassium salt of long-chain fatty acids. It has one polar hydrophilic end and one non-polar hydrophobic end. These molecules have a unique orientation inside water in form of clusters of molecule in which hydrophobic ends are in the interior of the cluster and ionic ends on the surface of cluster thus keeping the hydrocarbon portion out of water. This formation is known as Micelle. Soap in the form of a micelle is able to clean, as the oily dirt is collected in the centre of the micelle.

No, micelle formation does not take place in ethanol because the alkyl chain of soap becomes soluble in alcohol.

Q. 9. Why are carbon and its compounds used as fuels for most applications?

Answer:

Carbon compounds have high calorific values. Therefore, carbon and its compounds are used as fuels for most applications. They give a lot of heat and light when burnt in air. Saturated hydrocarbons like methane burn with a clean flame without any smoke and are thus environmentally friendly.

Class 10 Science Ch 4 NCERT Solutions

Q. 10. Explain the formation of scum when hard water is treated with soap.

Answer:

Hard water contains calcium and magnesium salts. When soap is added with hard water, it reacts with the calcium and magnesium ions of hard water to form an insoluble substance called scum. To overcome this problem, detergents are used.

Q. 11. What change will you observe if you test soap with litmus paper (red and blue)?

Answer:

Soap is basic in nature and hence will turn red litmus blue. However it will have no effect on blue litmus paper.

Q. 12. What is hydrogenation? What is its industrial application?

Answer:

The conversion of unsaturated hydrocarbon to saturated hydrocarbon by the addition of hydrogen in the presence of nickel catalyst is called hydrogenation. This reaction is commonly used in hydrogenation of vegetable oil into vegetable ghee.

Q. 13. Which of the following hydrocarbons undergo addition reactions:

$C_{2}H_{6}, C_{3}H_{8}, C_{3}H_{6}, C_{2}H_{2}\; and\: CH_{4}.$

Answer:

Unsaturated hydrocarbons like alkenes and alkynes will undergo addition reactions. Therefore, $C_3H_6$ (alkene having $-C=C-$ ) and $C_2H_2$ (alkyne having $-C\equiv C-$ ) will give addition reactions.

Q. 14. Give a test that can be used to differentiate between saturated and unsaturated hydrocarbons.

Answer:

Butter is a saturated compound and oil is an unsaturated compound.

Test: When oil is added to a test tube containing alkaline potassium permanganate solution $KMnO_4$ , the pink colour of the solution disappear. Therefore, cooking oil causes decolourisation of the solution. This does not happen in case of butter.

Q. 15. Explain the mechanism of the cleaning action of soaps.

Answer:

A soap is a sodium or potassium salt of long-chain fatty acids. It has one polar hydrophilic end and one non-polar hydrophobic end. When soap is at the surface of the water, the hydrophobic tail of soap being nonsoluble in water protrudes out of the water with the ionic end in water.

When there is no more space for soap molecules on the surface, these molecules create a unique orientation inside water in form of clusters in which hydrophobic ends are in the interior of the cluster and ionic ends on the surface of cluster thus keeping the hydrocarbon portion out of water. This formation is known as Micelle.

Soap in the form of a micelle is able to clean, as the oily dirt is collected in the centre of the micelle.The ionic ends in the micelles remain attached to water. When the dirty clothes are agitated in a soap solution, the oily dirt particles entrapped by soap micelles get dispersed in water and the clothes get cleaned.

Ch 4 Science Class 10: Important Formulas and Diagrams + eBook link

This article also covers the Most important formulas from Chapter 4 of the Class 10 Science NCERT Textbook, apart from the Class 10th Science Chapter 4 question answer.

Chapter 4 Science Class 10 : Carbon and Its Compounds

Allotropes of Carbon

Diamond: In diamond every carbon atom is bonded to another four carbon atoms giving rise to a rigid three-dimensional structure.

Graphite: In graphite every carbon atom is bonded to three other carbon atoms in the same plane giving rise to a hexagonal array.

C-60 Buckminsterfullerene: In C-60 Buckminsterfullerene, carbon atoms are arranged in the shape of a football.

Saturated Carbon Compounds

Carbon compounds which involves single bonds are called saturated carbon compounds.

Unsaturated Carbon Compounds

Carbon compounds which involves double or triple bonds are called unsaturated carbon compounds

Functional group in Carbon Compounds

Hetero Atom	Class of Compounds	Formula
Cl/Br	Halo-(chloro, bromo)alkane	-Cl, -Br
Oxygen	Alcohol	-OH
	Aldehyde	-CHO
	Ketone	-CO
	Carboxylic acid	-COOH

Nomenclature of organic compounds

1690005684754

CHEMICAL PROPERTIES OF CARBON COMPOUNDS

Combustion

Carbon reacts with oxygen giving out carbon dioxide, heat and light.

1649411421728

Oxidation

When oxygen is added to the compound, the reaction is called oxidation reaction. It is done in the presence of an oxidizing agent.

Addition Reaction

When hydrogen is added to an unsaturated compound, in presence of a catalyst such as palladium or nickel giving rise to saturated hydrocarbons, the reaction is called addition reaction.

Substitution Reaction

When an atom or group of atoms are replaced by another atom, the reaction is called substitution reaction.

CH4 + Cl2 → CH3Cl + HCl (in the presence of sunlight)

Reactions of Ethanol

(i) Reaction with sodium –

2Na + 2CH3CH2OH → 2CH3CH2O–Na+ (Sodium ethoxide) + H2

(ii) Reaction to give unsaturated hydrocarbon:

CH3 - CH2OH —-- HOT CONC H2SO4—------> CH2 = CH2 +H20

Esterification reaction:

1690005683800

Reaction of ethanoic acid with a base:

NaOH + CH3COOH → CH3COONa + H2O

Reaction of ethanoic acid with carbonates and hydrogencarbonates:

2CH3COOH + Na2CO3 → 2CH3COONa + H2O + CO2

CH3COOH + NaHCO3 → CH3COONa + H2O + CO2

For more, Download Ebook - NCERT Class 10 Science: Chapterwise Important Formulas, Diagrams, And Points

Carbon and its Compounds Class 10 Solutions - Important Topics

Let us take a quick look at the list of units and subunits taken from NCERT Textbook Class 10 And included in NCERT Solutions for Class 10 Science Chapter 4, Carbon and Its Compounds before diving into the specifics.

Carbon And Its Compounds

Bonding In Carbon – The Covalent Bond

Versatile Nature Of Carbon

Saturated and Unsaturated Carbon Compounds
Chains, Branches and Rings
Carbon - Will you be my Friend?
Homologous Series
Nomenclature of Carbon Compounds

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Chemical Properties Of Carbon Compounds

Combustion
Oxidation
Addition Reaction
Substitution Reaction

Some Important Carbon Compounds – Ethanol And Ethanoic Acid

Properties of Ethanol
Properties of Ethanoic Acid

Soaps And Detergents

Free download NCERT Solutions for Class 10 Science Chapter 4 Carbon And Its Compounds PDF for CBSE Exam.

NCERT Solutions for Class 10th for Other Subjects

Benefits of NCERT Solutions for Class 10 Science Chapter 4 Carbon and Its Compounds

NCERT Class 10 Science solutions chapter 4 will be of great help if you have an understanding of the chapter contents. Hence, read the entire chapter carefully before checking the solutions.
NCERT Solutions for Class 10 Science Chapter 4 will be useful for answer writing, as it will help you frame the answers correctly.
These Class 10 Science Chapter 4 NCERT solutions are prepared by subject matter experts, hence you can rely on it completely.

Chapter-wise NCERT Solutions for Class 10 Science

Chapter No.	Chapter Name
Chapter 1	Chemical Reactions and Equations
Chapter 2	Acids, Bases, and Salts
Chapter 3	Metals and Non-metals
Chapter 4	Carbon and Its Compounds
Chapter 5	Periodic Classification of Elements
Chapter 6	Life Processes
Chapter 7	Control and Coordination
Chapter 8	How do Organisms Reproduce?
Chapter 9	Heredity and Evolution
Chapter 10	Light Reflection and Refraction
Chapter 11	The Human Eye and The Colorful World
Chapter 12	Electricity
Chapter 13	Magnetic Effects of Electric Current
Chapter 14	Sources of Energy
Chapter 15	Our Environment
Chapter 16	Sustainable Management of Natural Resources

How to Use NCERT solutions for Class 10 Science Chapter 4 Carbon and its Compounds

The NCERT Class 10 Science Solutions Chapter 4 are easy to understand. It will help you clarify your concepts.
You can access the NCERT Solutions Class 10 Science Chapter 4 PDF download soon to practice offline.
The NCERT solutions for Class 10 Science Chapter 4 Carbon and Its Compounds are provided by the experts, so in case you have any doubt, you can ask the questions.

Highlights of NCERT Solutions for Class 10 Science Chapter 4 – Carbon And Its Compounds PDF

The highlights for the Class 10 Science Chapter 4 solution PDF are given below:

The NCERT (CBSE) Syllabus and Books are strictly followed in the Carbon and its Compounds Class 10 Solutions.
The NCERT Solutions for Class 10 Science Chapter 4 are easy-to-understand and comprehensive
On this page, you will find clear and concise concepts from Ch 4 Science Class 10.
The class 10 science chapter 4 question answer help clear doubt and give in-depth knowledge of concepts.
The NCERT Solutions Class 10 Chapter 4 Science are prepared by subject matter experts in the easiest possible way.
All the exercise questions and in-text solved questions are available for Science Chapter 4 Class 10.
Stepwise solutions are provided here for Carbon and its Compounds Class 10 questions with answers.
Diagrams for Class 10 Science Ch 4 are provided wherever required for a better understanding.

Also Check NCERT Books and NCERT Syllabus here:

Frequently Asked Questions (FAQs)

1. What is the weightage of chapter Carbon and Its Compounds in CBSE class 10 board final exam ?

Weightage of chapter Carbon and Its Compounds in CBSE class 10 board final exam is 5 marks. More questions on Carbon and its Compounds chapter can be practised using NCERT exemplar and CBSE previous year papers.

2. CBSE provides the solutions of NCERT class 10?

No, CBSE doesn’t provide NCERT solutions for any class or subject.

3. What are the important topics of Class 10 Science Chapter 4 Carbon and Its Compounds?

Covalent Bonding in Carbon Compounds, Homologous series, Saturated & Unsaturated hydrocarbons, Chemical Properties of Carbon Compounds, Nomenclature of Carbon Compounds Containing Functional Groups.

Also Read

The Human Eye and The Colorful world Class 10th Notes- Free NCERT Class 10 Science Chapter 11 Notes - Download PDF

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Magnetic Effects of Electric Current Class 10th Notes - Free NCERT Class 10 Science Chapter 13 Notes - Download PDF

Electricity Class 10th Notes - Free NCERT Class 10 Science Chapter 12 Notes - Download PDF

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Questions related to CBSE Class 10th

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sai raja 01 September,2024

show the previous year exams ?

Hello Aspirant, Hope your doing great, your question was incomplete and regarding what exam your asking.

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SWETCHCHA MISKA 10 July,2024

as an icse student in class 10 is above 80 percent good enough to get into commerce in 11th cbse

Yes, scoring above 80% in ICSE Class 10 exams typically meets the requirements to get into the Commerce stream in Class 11th under the CBSE board . Admission criteria can vary between schools, so it is advisable to check the specific requirements of the intended CBSE school. Generally, a good academic record with a score above 80% in ICSE 10th result is considered strong for such transitions.

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Manasvini Gupta 23 July,2024

i had cleared 10th from cbse in 2022 2 years ago now i wish to apply for 12th as private candidate in 2025. can i do so?

hello Zaid,

Yes, you can apply for 12th grade as a private candidate .You will need to follow the registration process and fulfill the eligibility criteria set by CBSE for private candidates.If you haven't given the 11th grade exam ,you would be able to appear for the 12th exam directly without having passed 11th grade. you will need to give certain tests in the school you are getting addmission to prove your eligibilty.

best of luck!

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Ashvadha 03 July,2024

i had cleared 10th in 2022 from cbse can i apply for 12th as private candidate this year?

According to cbse norms candidates who have completed class 10th, class 11th, have a gap year or have failed class 12th can appear for admission in 12th class.for admission in cbse board you need to clear your 11th class first and you must have studied from CBSE board or any other recognized and equivalent board/school.

You are not eligible for cbse board but you can still do 12th from nios which allow candidates to take admission in 12th class as a private student without completing 11th.

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sadafreen356 03 July,2024

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Central Board of Secondary Education Class 10th Examination

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Option 1) $0.34\; J$	Option 2) $0.16\; J$
Option 3) $1.00\; J$	Option 4) $0.67\; J$

Option 1) $2,000 \; J - 5,000\; J$	Option 2) $200 \, \, J - 500 \, \, J$
Option 3) $2\times 10^{5}J-3\times 10^{5}J$	Option 4) $20,000 \, \, J - 50,000 \, \, J$

Option 1) $K/2\,$	Option 2) $\; K\;$
Option 3) $zero\;$	Option 4) $K/4$

Option 1) $11.2\, L\, H_{2(g)}$ at STP is produced for every mole $HCL_{(aq)}$ consumed	Option 2) $6L\, HCl_{(aq)}$ is consumed for ever $3L\, H_{2(g)}$ produced
Option 3) $33.6 L\, H_{2(g)}$ is produced regardless of temperature and pressure for every mole Al that reacts	Option 4) $67.2\, L\, H_{2(g)}$ at STP is produced for every mole Al that reacts .

Option 1) 0.02	Option 2) 3.125 × 10^-2
Option 3) 1.25 × 10^-2	Option 4) 2.5 × 10^-2

Option 1) decrease twice	Option 2) increase two fold
Option 3) remain unchanged	Option 4) be a function of the molecular mass of the substance.

Option 1) Molality	Option 2) Weight fraction of solute
Option 3) Fraction of solute present in water	Option 4) Mole fraction.

Option 1) twice that in 60 g carbon	Option 2) 6.023 × 10²²
Option 3) half that in 8 g He	Option 4) 558.5 × 6.023 × 10²³

Option 1) less than 3	Option 2) more than 3 but less than 6
Option 3) more than 6 but less than 9	Option 4) more than 9

NCERT Solutions for Class 10 Science Chapter 4 Carbon and Its Compounds

NCERT Solutions for Class 10 Science Chapter 4 "Carbon and Its Compounds"

NCERT Solutions for Class 10 Science Chapter 4 Carbon and Its Compounds:

NCERT Solutions for Class 10 Science Chapter 4 - Carbon and Its Compounds (Intext Questions and Exercise)

NCERT solutions for class 10 science chapter 4 Carbon and its compounds

Topic:4.1 Bonding in carbon - The covalent bond

Topic 4.2: Versatile nature of carbon

Topic 4.3 Chemical Properties of carbon compounds

Topic 4.4: Some Important Carbon Compounds - Ethanol and Ethanoic Acid

Topic 4.5: Soaps and Detergents

NCERT solutions for class 10 science chapter 4 Carbon and its Compounds - Exercise solutions

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