Probability Class 10 Chapter 15 Exercise: 15.2
Answer:
Total possible ways Shyam and Ekta can visit the shop =
(1) A case that both will visit the same day.
Shyam can go on any day between Tuesday to Saturday in 5 ways.
For any day that Shyam goes, Ekta will go on the same day in 1 way.
Total ways that they both go in the same day =
Answer:
Total possible ways Shyam and Ekta can visit the shop =
(2) The case that both will visit the shop on consecutive days.
Shyam can go on any day between Tuesday to Friday in 4 ways.
For any day that Shyam goes, Ekta will go on the next day in 1 way
Similarly, Ekta can go on any day between Tuesday to Friday in 4 ways.
And Shyam will go on the next day in 1 way.
(Note: None of the cases repeats since they are in a different order!)
Total ways that they both go in the same day =
Answer:
Total possible ways Shyam and Ekta can visit the shop =
(1) A case that both will visit the same day.
Shyam can go on any day between Tuesday to Saturday in 5 ways.
For any day that Shyam goes, Ekta will go on a different day in ways.
Total ways that they both go in the same day =
What is the probability that the total score is (i) even?
Answer:
+ | 1 | 2 | 2 | 3 | 3 | 6 |
1 | 2 | 3 | 3 | 4 | 4 | 7 |
2 | 3 | 4 | 4 | 5 | 5 | 8 |
2 | 3 | 4 | 4 | 5 | 5 | 8 |
3 | 4 | 5 | 5 | 6 | 6 | 9 |
3 | 4 | 5 | 5 | 6 | 6 | 9 |
6 | 7 | 8 | 8 | 9 | 9 | 12 |
Total possible outcomes when two dice are thrown =
(1) Number of times when the sum is even = 18
What is the probability that the total score is (ii) 6?
Answer:
+ | 1 | 2 | 2 | 3 | 3 | 6 |
1 | 2 | 3 | 3 | 4 | 4 | 7 |
2 | 3 | 4 | 4 | 5 | 5 | 8 |
2 | 3 | 4 | 4 | 5 | 5 | 8 |
3 | 4 | 5 | 5 | 6 | 6 | 9 |
3 | 4 | 5 | 5 | 6 | 6 | 9 |
6 | 7 | 8 | 8 | 9 | 9 | 12 |
Total possible outcomes when two dice are thrown =
Number of times when the sum is 6 = 4
What is the probability that the total score is (iii) at least 6?
Answer:
+ | 1 | 2 | 2 | 3 | 3 | 6 |
1 | 2 | 3 | 3 | 4 | 4 | 7 |
2 | 3 | 4 | 4 | 5 | 5 | 8 |
2 | 3 | 4 | 4 | 5 | 5 | 8 |
3 | 4 | 5 | 5 | 6 | 6 | 9 |
3 | 4 | 5 | 5 | 6 | 6 | 9 |
6 | 7 | 8 | 8 | 9 | 9 | 12 |
Total possible outcomes when two dice are thrown =
Number of times when the sum is at least 6, which means sum is greater than 5 = 15
Answer:
Let there be the number of blue balls in the bag.
Number of red balls = 5
Thus, the total number of balls = total possible outcomes =
And,
According to question,
Therefore, there are 10 blue balls in the bag.
Answer:
Total number of balls in the bag = 12
Number of black balls in the bag =
According to the question,
6 more black balls are added to the bag.
Total number of balls =
And, the new number of black balls =
Also,
The required value of is 3
Answer:
Let be the number of blue marbles in the jar.
Number of green marbles in the jar =
According to question,
Number of blue marbles in the jar is 8