NCERT Solutions for Class 8 Maths Chapter 5 Data Handling

NCERT Solutions for Class 8 Maths Chapter 5 Data Handling

Edited By Ramraj Saini | Updated on Mar 01, 2024 06:21 PM IST

Data Handling Class 8 Questions And Answers provided here. These NCERT Solutions are created by expert team at craeers360 keeping the latest syllabus and pattern of CBSE 2023-23. In our daily life, we come across various types of data through the newspaper, television, social media which are related to many things like sports, economy, GDP, etc. Also, you must have seen these data are represented in the graphs, charts, and in the tabular form. Why we need data? What is the purpose of representing these data into a chart or in graph form?

In NCERT solutions for class 8 maths chapter 5 data handling, you will get answers to all these questions. Basically, the data is a collection of observations and information, while making important decisions, data is much helpful. Also, check NCERT class 8 solutions maths for maths and science subjects.

Data Handling Class 8 Questions And Answers PDF Free Download

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Data Handling Class 8 Solutions - Important Points

  • Data: A systematic record of facts or distinct values of a quantity.

  • Presentation of Data: Arranging data to study their salient features.

  • Frequency: The number of times a particular entity occurs in data.

  • Frequency Distribution Table: A table representing the frequency of different entities in the data.

  • Grouped Frequency Distribution Table: Data grouped into class intervals.

  • Class Size or Width: The number of values in each class interval.

  • Lower Class Limit: The lower value in a class interval.

  • Upper-class Limit: The upper value in a class interval.

  • Pictograph: Pictorial representation of data using symbols.

  • Bar Graph: A display of data using bars of uniform width, with heights proportional to values.

  • Double Bar Graph: A graph showing two sets of data simultaneously for comparison.

  • Histogram: A graphical representation of frequency distribution using rectangles with no gaps between them.

  • Circle Graph or Pie Chart: A representation of numerical data using proportional sectors in a circle.

  • Probability Formula: Probability = Number of outcomes making up an event / Total number of outcomes (assuming equally likely outcomes).

Free download NCERT Solutions for Class 8 Maths Chapter 5 Data Handling for CBSE Exam.

Data Handling Class 8 NCERT Solutions (Intext Questions and Exercise)

Q- Draw an appropriate graph to represent the given information.

Children Who prefer
School A
School B
School C
Walking
40
55
15
Cycling
45
25
35

Answer:

c1

Q- Draw an appropriate graph to represent the given information

Percentage wins in ODI by 8 top cricket teams

Team
From Champions
Trophy to World Cup-06
Last 10 ODI in 07
South Africa
75%
78%
Australia
61%
40%
Sri Lanka
54%
38%
New Zealand
47%
50%
England
46%
50%
Pakistan
45%
44%
West Indis
44%
30%
India
43%
56%

Answer:

c3

NCERT Class 8 Maths Solutions Chapter 5 - Organising Data

Q1 A group of students were asked to say which animal they would like most to have as a pet. The results are given below:
dog, cat, cat, fish, cat, rabbit, dog, cat, rabbit, dog, cat, dog, dog, dog, cat, cow, fish, rabbit, dog, cat, dog, cat, cat, dog, rabbit, cat, fish, dog. Make a frequency distribution table for the same.

Answer: The above data can be represented as shown below:

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NCERT Class 8 Maths Solutions Chapter 5 - Grouping Data

Q1 Study the following frequency distribution table and answer the questions given below.

Frequency Distribution of Daily Income of 550 workers of a factory (Table 5.3)

Class Interval
(Daily Income in Rs.)
Frequency
(Number of workers)
100-125
45
125-150
25
150-175
55
175-200
125
200-225
140
225-250
55
250-275
35
275-300
50
300-325
20
Total
550


(i) What is the size of the class intervals?

Answer: (i) The size of the class intervals = 125-100 = 25

(ii) Which class has the highest frequency?

Answer: (ii) The class which has the highest frequency = 200-225 and the highest frequency is 140

(iii) Which class has the lowest frequency?

Answer: (iii) The class which has the lowest frequency = 300-325 and the lowest frequency is 20.

(iv) What is the upper limit of the class interval 250-275?

Answer: (iv) The upper limit of the class interval 250-275 is 275 and frequency is 35.

(v) Which two classes have the same frequency?

Answer: (v) The two classes which have the same frequency are 150-175 and 225-250 also the frequency is 55.

Q2 Construct a frequency distribution table for the data on weights (in kg) of 20 students of a class using intervals 30-35, 35-40 and so on.

40, 38, 33, 48, 60, 53, 31, 46, 34, 36, 49, 41, 55, 49, 65, 42, 44, 47, 38, 39

Answer: The frequency distribution table for the data given is :

Intervals
students
30-35
3
35-40
5
40-45
3
45-50
5
50-55
2
55-60
1
60-65
1

total = 20

NCERT Class 8 Maths Solutions Chapter 5 - Bars With A Difference

Q1. Observe the histogram (Fig 5.3) and answer the questions given below.

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(i) What information is being given by the histogram?

Answer: The above histogram represents the number of girls as y-axis and heights in cm as x-axis.

(ii) Which group contains maximum girls?

Answer: The group which contains maximum girls is 140-145

(iiI) How many girls have a height of 145 cms and more?

Answer: The girls having a height of 145 cms and more are 4+2+1 = 7

(iv) If we divide the girls into the following three categories, how many would there be in each?
150 cms and more — Group A
140 cm to less than 150 cm — Group B
Less than 140 cm — Group C

Answer: 150 cms and more — Group A = 2+1 = 3
140 cm to less than 150 cm — Group B = 7+4 = 11
Less than 140 cm — Group C = 1+2+3 = 6

Class 8 maths chapter 5 NCERT solutions - Exercise: 5.1

Q1 For which of these would you use a histogram to show the data?

(a) The number of letters for different areas in a postman’s bag.

Answer: Histogram can be represented for the data which can be represented as a manner of intervals. The number of letters for different areas in a postman’s bag cannot be represented in form of interval so this cannot be represented using the histogram.

(b) The height of competitors in an athletics meet.

Answer: Histogram can be represented for the data which can be represented as a manner of intervals. The height of competitors in an athletics meet can be represented in form of interval so this can be represented using the histogram.

(c) The number of cassettes produced by 5 companies.

Histogram can be represented for the data which can be represented as a manner of intervals. The number of cassettes produced by 5 companies cannot be represented in form of interval so this cannot be represented using a histogram.

(d) The number of passengers boarding trains from 7 am to 7 pm at a station.

Answer: Histogram can be represented for the data which can be represented as a manner of intervals. The number of passengers boarding trains from 7 am to 7 pm at a station can be represented in form of interval so this can be represented using a histogram.

Q2 The shoppers who come to a departmental store are marked as: man (M), woman (W), boy (B) or girl (G). The following list gives the shoppers who came during the first hour in the morning: WWWGBWWMGGMMWWWWGBMWBGGMWWMMWWWMWBWGMWWWWGWMMWWMWGWMGWMMBGGW
Make a frequency distribution table using tally marks. Draw a bar graph to illustrate it.

Answer: The frequency distribution table using tally marks is as shown :

dthnd81

The graph is as shown below

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Q3 The weekly wages (in Rs) of 30 workers in a factory are.
830, 835, 890, 810, 835, 836, 869, 845, 898, 890, 820, 860, 832, 833, 855, 845, 804, 808, 812, 840, 885, 835, 836, 878, 840, 868, 890, 806, 840
Using tally marks make a frequency table with intervals as 800–810, 810–820 and so on.

Answer: Using tally marks a frequency table with intervals as 800–810, 810–820 and so on is as shown below:

dthnd82

Q4 (i) Draw a histogram for the frequency table made for the data in Question 3, and answer the following questions.
830, 835, 890, 810, 835, 836, 869, 845, 898, 890, 820, 860, 832, 833, 855, 845, 804, 808, 812, 840, 885, 835, 836, 878, 840, 868, 890, 806, 840
Which group has the maximum number of workers?

Answer: (i) The group which has the maximum number of workers is 830-840


Q4 (ii) Draw a histogram for the frequency table made for the data in Question 3, and answer the following questions.

830, 835, 890, 810, 835, 836, 869, 845, 898, 890, 820, 860, 832, 833, 855, 845, 804, 808, 812, 840, 885, 835, 836, 878, 840, 868, 890, 806, 840

How many workers earn Rs. 850 and more?

Answer:

(ii) The workers earning Rs 850 and more are 1 + 3 + 1 +1 + 4 = 10

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Q4 (iii) Draw a histogram for the frequency table made for the data in Question 3,and answer the following questions.

830, 835, 890, 810, 835, 836, 869, 845, 898, 890, 820, 860, 832, 833, 855, 845, 804, 808, 812, 840, 885, 835, 836, 878, 840, 868, 890, 806, 840

Q4 (iii) Draw a histogram for the frequency table made for the data in Question 3,and answer the following questions.

830, 835, 890, 810, 835, 836, 869, 845, 898, 890, 820, 860, 832, 833, 855, 845, 804, 808, 812, 840, 885, 835, 836, 878, 840, 868, 890, 806, 840

How many workers earn less than Rs 850

Answer: (iii) The workers earning less than RS 850 are 20 .

3 + 2 + 1 + 9 + 5 = 20

c7

Q5 (i) The number of hours for which students of a particular class watched television during holidays is shown through the given graph. Answer the following.

For how many hours did the maximum number of students watch TV?

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Answer: (i) From the graph we observed that the maximum number of students (32) watch TV for 4-5 hours.


Q5 (ii) The number of hours for which students of a particular class watched television during holidays is shown through the given graph. Answer the following.

How many students watched TV for less than 4 hours?

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Answer: (ii) 34 students watched TV for less than 4 hours.
The number of students who watched TV for less than 4 hours = sum of the students who watched TV for (3–4hours) + (2–3hours) + (1–2hours.)
So, the total number of students = 4 + 8 + 22 = 34

Q5 (iii) The number of hours for which students of a particular class watched television during holidays is shown through the given graph. Answer the following.

How many students spent more than 5 hours in watching TV?

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Answer: (iii) 14 students spent more than 5 hours in watching TV.
The number of students who watched TV for >5 hours = number of students who watched TV for (5 – 6 hours) + (6 – 7 hours).
So the no. of students = 8 + 6 = 14

NCERT Class 8 Maths Solutions Chapter 5 - Circle Graph or Pie Chart

Q1 (i) Each of the following pie charts (Fig 5.5) gives you a different piece of information about your class. Find the fraction of the circle representing each of this information.

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Answer: 50% of the fraction of the circle represent girls and other 50% represent boys of class.

Q1 (ii) Each of the following pie charts (Fig 5.5) gives you a different piece of information about your class. Find the fraction of the circle representing each of this information.

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Answer: The circle represents that 20% students use cycle for transportation, 40% walk and 40% use bus or car for transportation.

Q1 (iii) Each of the following pie charts (Fig 5.5) gives you a different piece of information about your class. Find the fraction of the circle representing each of this information.

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Answer:

(iii)

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The circle represents that 85% students love and 15% students hate Mathematics.

Q2 (i) Answer the following questions based on the pie chart given (Fig 5.6 ).

Which type of programmes are viewed the most?

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Answer:

(i) Entertainment programmes are viewed the most i.e. 50 \% .

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Q2 (ii) Answer the following questions based on the pie chart given (Fig 5.6 ). Which two types of programmes have number of viewers equal to those watching sports channels?

16288

Answer: Informative and News together have a number of viewers equal to those watching sports channels.

16288

NCERT Class 8 Maths Solutions Chapter 5 - Drawing Pie Chart

Q1 Draw a pie chart of the data given below.

The time spent by a child during a day.

Sleep — 8 hours

School — 6 hours

Homework — 4 hours

Play — 4 hours

Others — 2 hours

Answer: Pie chart of the data is given below:

1643185648110

Q1 Which form of graph would be appropriate to display the following data.

Production of food grains of a state.

Year
2001
2002
2003
2004
2005
2006
Production
(in lakh tons)
60
50
70
55
80
85

Answer: Data can be represented as shown below as bar graph.

1643185672043

Q2 Which form of graph would be appropriate to display the following data.

Choice of food for a group of people.

Favourite food
Number of people
North Indian
30
South Indian
40
Chinese
25
Others
25
Total
120

Answer: The given data can be represented as shown below as pie chart.

1643185704975

Q3 Which form of graph would be appropriate to display the following data.

The daily income of a group of factory workers

Daily Income
(in Rupees)
Number of workers
(In a factory)
75-100
45
100-125
35
125-150
55
150-175
30
175-200
50
200-225
125
225-250
140
Total
480

Answer:

The data can be represented as shown below as bar graph.

1643185733792

Class 8 data handling NCERT solutions - Exercise: 5.2

Q1 A survey was made to find the type of music that a certain group of young people liked in a city. Adjoining pie chart shows the findings of this survey. From this pie chart answer the following:

(i) If 20 people liked classical music, how many young people were surveyed?

(ii) Which type of music is liked by the maximum number of people?

(iii) If a cassette company were to make 1000 CD’s, how many of each type would they make?

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Answer:

1643185776886

(i)If 20 people liked classical music

Total number of people = (100\times 20)\div 10 = 200 people.

(ii) Maximum number of people light music i.e. 40 \% .

(iii) If a cassette company were to make 1000 CD’s, then

Light music CD's = ( 40\times 1000) \div 100\:\:=400

Folk music CD's = \left ( 30\times 1000 \right )\div 100\:\:=300

Classical music CD's = \left ( 10\times 1000 \right )\div 100\:\:=100

Semi classical music CD's = \left ( 20\times 1000 \right )\div 100\:\:=200

Q2 A group of 360 people were asked to vote for their favourite season from the three seasons rainy, winter and summer.

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(i) Which season got the most votes?

(ii) Find the central angle of each sector.

(iii) Draw a pie chart to show this information.

Answer:

15961167462601596116744931

(i) Winter season got the most votes.

(ii) Total Votes = 90+120+150 = 360

central angle of summer = (90\degree\times 360\degree)\div 360\degree = 90\degree

central angle of rainy = (120\degree\times 360\degree)\div 360\degree = 120\degree

central angle of winter = (150\degree\times 360\degree)\div 360\degree = 150\degree

(iii)

1643185813246

Q3 Draw a pie chart showing the following information.

The table shows the colours preferred by a group of people.

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Answer:

15961170254461596117021652

colours
number of people
in fraction
central angles
Blue
18
\frac{18}{36}=\frac{1}{2}
\frac{1}{2}\times 360 \degree= 180\degree
Green
9
\frac{9}{36}=\frac{1}{4}
\frac{1}{4}\times 360 \degree= 90\degree
Red
6
\frac{6}{36}=\frac{1}{6}
\frac{1}{6}\times 360 \degree= 60\degree
Yellow
3
\frac{3}{36}=\frac{1}{12}
\frac{1}{12}\times 360 \degree= 30\degree


1643185856055

Q4 The adjoining pie chart gives the marks scored in an examination by a student in Hindi, English, Mathematics, Social Science and Science. If the total marks obtained by the students were 540 , answer the following questions.

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(i) In which subject did the student score 105 marks?

( Hint: for 540 marks, the central angle =360^{\circ} . So, for 105 marks, what is the central angle?)

Answer:

subject
central angle
marks obtained
mathematics
90\degree
(90\degree\times 540)\div 360 = 135
science
80\degree
(80\degree\times 540)\div 360 = 120
social science
65\degree
(65\degree\times 540)\div 360 = 97.5
english
55\degree
(55\degree\times 540)\div 360 = 82.5
hindi
70\degree
(70\degree\times 540)\div 360 = 105

(i) In hindi subject the student score 105 marks.

Q4 (ii) The adjoining pie chart gives the marks scored in an examination by a student in Hindi, English, Mathematics, Social Science and Science. If the total marks obtained by the students were 540 , answer the following questions.

How many more marks were obtained by the student in Mathematics than in Hindi?

1643185910792

Answer:

subject
central angle
marks obtained
mathematics
90\degree
(90\degree\times 540)\div 360 = 135
science
80\degree
(80\degree\times 540)\div 360 = 120
social science
65\degree
(65\degree\times 540)\div 360 = 97.5
english
55\degree
(55\degree\times 540)\div 360 = 82.5
hindi
70\degree
(70\degree\times 540)\div 360 = 105

(ii) 135-105=30

Hence, 30 more marks were obtained by the student in Mathematics than in Hindi.

Q4 The adjoining pie chart gives the marks scored in an examination by a student in Hindi, English, Mathematics, Social Science and Science. If the total marks obtained by the students were 540, answer the following questions.

Examine whether the sum of the marks obtained in Social Science and Mathematics is more than that in Science and Hindi.

(Hint: Just study the central angles).

1643185937900

Answer:

subject
central angle
marks obtained
mathematics
90\degree
(90\degree\times 540)\div 360 = 135
science
80\degree
(80\degree\times 540)\div 360 = 120
social science
65\degree
(65\degree\times 540)\div 360 = 97.5
english
55\degree
(55\degree\times 540)\div 360 = 82.5
hindi
70\degree
(70\degree\times 540)\div 360 = 105

(iii) the sum of the marks obtained in Social Science and Mathematics = 97.5+135=232.5

the sum of the marks obtained in Science and Hindi = 120+105=225

Yes, the sum of the marks obtained in Social Science and Mathematics is more than that in Science and Hindi.

Q5 The number of students in a hostel, speaking different languages is given below. Display the data in a pie chart.

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Answer:

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The pie chart is as shown below:

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NCERT Class 8 Maths Solutions Chapter 5 Practise: Getting A Result

Q1 If you try to start a scooter, what are the possible outcomes?

Answer:

1.If you try to start a scooter,then there are two possibilities.

(i) . The scooter will start.

(ii) . The scooter will not start.

Q2 When a die is thrown, what are the six possible outcomes?

Answer:

2. When a die is thrown, the six possible outcomes are :

(i) 1

(ii) 2

(iii) 3

(iv) 4

(v) 5

(vi) 6

Q3 When you spin the wheel shown, what are the possible outcomes? (Fig 5.9) List them.

(Outcome here means the sector at which the pointer stops).

c3

Answer: 3. When we spin the wheel shown, the possible outcomes are:

(i) A

(ii) B

(iii) C

Q4 You have a bag with five identical balls of different colours and you are to pull out (draw) a ball without looking at it; list the outcomes you would get (Fig 5.10).

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Fig 5.10

Answer:

15961172311361596117227830

Fig 5.10

The possible outcomes are:

(i) W

(ii) R

(iii) B

(iv) G

(v) Y

Q5 In throwing a die:
Does the first player have a greater chance of getting a six?
Would the player who played after him have a lesser chance of getting a six?
Suppose the second player got a six. Does it mean that the third player would not have a chance of getting a six?

Answer: In throwing a die:
No, the first player also have same chance of getting a six.
No, the player who played after him have same chance of getting a six.
Suppose the second player got a six.It does not mean that the third player would not have a chance of getting a six. Third person also have same chance of getting six.

NCERT Class 8 Maths Solutions Chapter 5 - Excercise: Linking Chances of Probablity

Suppose you spin the wheel

Q1 (i) List the number of outcomes of getting a green sector and not getting a green sector on this wheel (Fig 5.11).

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Answer:

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(i) the number of outcomes of getting a green sector = 5

the number of outcomes of not getting a green sector = 3

Q1 (ii) Suppose you spin the wheel Find the probability of getting a green sector.

. 1643186116395

Answer:

1643186128981

(ii) the probability of getting a green sector = 5/8 = 0.625

Q1 (iii) Suppose you spin the wheel Find the probability of not getting a green sector.

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Answer: (iii) the probability of not getting a green sector = \frac{3}{8} = 0.375

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Class 8 maths chapter 5 question answer - Exercise: 5.3

Q1 (a) List the outcomes you can see in these experiments. Spinning a wheel

c6

Answer:

(a) the outcomes you can see in these experiments are:

c6

(i) A

(ii) B

(iii) C

(iv) D

Q1 (b) List the outcomes you can see in these experiments Tossing two coins together

Answer: (b)The outcomes you can see in the experiments Tossing two coins together are :

(i) Head

(ii) tail

Q2 When a die is thrown, list the outcomes of an event of getting

(i) (a) a prime number (b) not a prime number.

(ii) (a) a number greater than 5 (b) a number not greater than 5 .

Answer: When a die is thrown, the outcomes of an event of getting

(i) (a) a prime number are 2,3,5.

(b) not a prime number are 1,4,6.

(ii) (a) a number greater than 5 is 6.

(b) a number not greater than 5 are1,2,3,4,5.

Q3 (a) Find the Probability of the pointer stopping on D in (Question 1-(a))?

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Answer: (a) Probability of the pointer stopping on D =\frac{1}{5}=0.2

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Q3 (b) Find the Probability of getting an ace from a well-shuffled deck of 52 playing cards?

Answer: (b) Probability of getting an ace from a well-shuffled deck of 52 playing cards

=\frac{4}{52}=\frac{2}{26}=\frac{1}{13}=0.769

Q3 (c) Find the Probability of getting a red apple. (See figure below)

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Answer:

(c) Probability of getting a red apple

=\frac{4}{7}= 0.571

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Q4 Numbers 1 to 10 are written on ten separate slips (one number on one slip), kept in a box and mixed well. One slip is chosen from the box without looking into it. What is the probability of .

(i) getting a number 6?

(ii) getting a number less than 6?

(iii) getting a number greater than 6?

(iv) getting a 1-digit number?

Answer:

(i) the probability of getting a number

=\frac{1}{10}=0.1

(ii) the numbers less than 6 are: 1,2,3,4,5=5 numbers.

the probability of getting a number less than 6

=\frac{5}{10}=0.5

(iii) the numbers greater than 6 are: 7,8,9,10=4 numbers.

the probability of getting a number greater than 6

=\frac{4}{10}=0.4

(iv) 1 digit numbers = 1,2,3,4,5,6,7,8,9 = 9 numbers

the probability of getting a 1 digit number

=\frac{9}{10}=0.9

Q5 If you have a spinning wheel with 3 green sectors, 1 blue sector and 1 red sector, what is the probability of getting a green sector? What is the probability of getting a non blue sector?

Answer:

Total sectors = 5

  • the probability of getting a green sector

=\frac{3}{5}

  • Non blue sector = 5-1 = 4

probability of getting a non blue sector

=\frac{4}{5}

Q6 Find the probabilities of the events given in Question 2.

When a die is thrown, list the outcomes of an event of getting

(i) (a) a prime number

(b) not a prime number.

(ii) (a) a number greater than 5

(b) a number not greater than 5.

Answer:

Total outcomes = 6

6.(i) (a) prime numbers = 2,3,5 = 3 numbers

probability of prime number

=\frac{3}{6}=\frac{1}{2}

(b) non prime numbers = 1,4,6 = 3 numbers

probability of non prime number

=\frac{3}{6}=\frac{1}{2}

(ii) (a) number greater than 5 = 6 = 1 number only

probability of getting number greater than 5

=\frac{1}{6}

(b) number not greater than 5 = 1,2,3,4,5 = 5 numbers.

probability of getting number not greater than 5

=\frac{5}{6}

NCERT Solutions for Class 8 Maths Chapter 5 Data Handling - Summary

In NCERT solutions class 8 maths chapter 5, you will learn the data representation in an organized form so that its interpretation and analysis can become easier. By referring to NCERT solutions for class 8 maths chapter 5, you will get to know about types of graphs and charts to represent data and some are listed below.

  • Tabular Chart - The most simple form of data presentation is Tabular chart where data is always represented in matrix form which is most easy to the readable form of data representation. Tabular Chart example is given below for students’ reference.

  • Pie Chart - NCERT class 8 maths solutions chapter 5 says that a pie chart is a chart where the data is represented either in the form of percentages or as angles made in the middle by that particular sector of the circle.

  • Bar Graph - As per NCERT solutions for class 8 maths chapter 5, the bar graph is the most preferred method of data representation where data is always represented in bars and multiple bars.

  • Line Graph - Line Graph is an integral part of NCERT 8th class maths solutions chapter 5 data handling. It is an extended and updated version of Bar Graph where the top of every bar is connected to the next bar’s top and the adjoining of these tops makes a line graph.

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There are many questions in the NCERT solutions for class 8 maths chapter 5 data handling, in which you will get to know about the use of different types of graphs for different types of data based on the need. There are 3 exercises with 16 questions in chapter 5 of NCERT class 8 maths solutions. You will get detailed explanations of these questions in the NCERT solutions for class 8 maths chapter 5 data handling.

NCERT solutions for class 8 maths chapter 5 Data Handling - Topics

  • Looking For Information
  • Organising Data
  • Grouping Data
  • Bars With A Difference
  • Excercise: 5.1
  • Circle Graph or Pie Chart
  • Drawing Pie Chart
  • Excercise: 5.2
  • Getting A Result
  • Excercise: Linking Chances of Probablity
  • Excercise: 5.3

NCERT Solutions for Class 8 Maths - Chapter Wise

NCERT Class 8 Maths Solutions - Subject Wise

NCERT Class 8 Maths Solutions Chapter 5 - Important Terms

There are some important terms and formulas used in the class 8 maths ch 5 question answer which are listed below.

  • Raw data:- Unorganised form of data is called raw data.
  • Frequency:- Number of times a particular entry occurs is the frequency of that entry.
  • Histogram:- It is a type of bar diagram, where the class intervals are shown on the horizontal axis and the heights of the bars show the frequency of that class interval.
  • Random experiment:- In simple word, an experiment is whose outcome cannot be predicted exactly in advance.
  • Event:- One or more outcomes of an experiment is called an event.
  • Probability:- Ratio of the number of outcomes of an event and the total number of outcomes of the experiment.

Probability = \frac{The \:number \:of \:outcomes\: that \:make \:an\: event }{Divided\: by\: total\: number\: of\: outcomes\: of\: the\: experiment}


There are many questions given after every topic. To make a grip on this topic, you should example, practice questions are given after every topic, and exercise questions by your self. If you finding difficulties you can take help from the NCERT solutions for class 8 maths chapter 5 data handling.

NCERT Books and NCERT Syllabus

Frequently Asked Questions (FAQs)

1. What are the important topics of chapter Data Handling ?

Organizing and grouping data, bar charts, pie charts, probability are the important topics of this chapter.

2. Does CBSE class maths is tough ?

CBSE class 8 maths is a basic and very simple maths where most of the topics related to the previous classes.

3. Where can I find the complete solutions of NCERT for class 8 ?

Here you will get the detailed NCERT solutions for class 8 by clicking on the link.

4. Where can I find the complete solutions of NCERT for class 8 maths ?

Here you will get the detailed NCERT solutions for class 8 maths by clicking on the link.

5. How many chapters are there in the CBSE class 8 maths ?

There are 16 chapters starting from rational number to playing with numbers in the CBSE class 8 maths.

6. Which is the official website of NCERT ?

NCERT official is the official website of the NCERT where you can get NCERT textbooks and syllabus from class 1 to 12.

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A block of mass 0.50 kg is moving with a speed of 2.00 ms-1 on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is

Option 1)

0.34\; J

Option 2)

0.16\; J

Option 3)

1.00\; J

Option 4)

0.67\; J

A person trying to lose weight by burning fat lifts a mass of 10 kg upto a height of 1 m 1000 times.  Assume that the potential energy lost each time he lowers the mass is dissipated.  How much fat will he use up considering the work done only when the weight is lifted up ?  Fat supplies 3.8×107 J of energy per kg which is converted to mechanical energy with a 20% efficiency rate.  Take g = 9.8 ms−2 :

Option 1)

2.45×10−3 kg

Option 2)

 6.45×10−3 kg

Option 3)

 9.89×10−3 kg

Option 4)

12.89×10−3 kg

 

An athlete in the olympic games covers a distance of 100 m in 10 s. His kinetic energy can be estimated to be in the range

Option 1)

2,000 \; J - 5,000\; J

Option 2)

200 \, \, J - 500 \, \, J

Option 3)

2\times 10^{5}J-3\times 10^{5}J

Option 4)

20,000 \, \, J - 50,000 \, \, J

A particle is projected at 600   to the horizontal with a kinetic energy K. The kinetic energy at the highest point

Option 1)

K/2\,

Option 2)

\; K\;

Option 3)

zero\;

Option 4)

K/4

In the reaction,

2Al_{(s)}+6HCL_{(aq)}\rightarrow 2Al^{3+}\, _{(aq)}+6Cl^{-}\, _{(aq)}+3H_{2(g)}

Option 1)

11.2\, L\, H_{2(g)}  at STP  is produced for every mole HCL_{(aq)}  consumed

Option 2)

6L\, HCl_{(aq)}  is consumed for ever 3L\, H_{2(g)}      produced

Option 3)

33.6 L\, H_{2(g)} is produced regardless of temperature and pressure for every mole Al that reacts

Option 4)

67.2\, L\, H_{2(g)} at STP is produced for every mole Al that reacts .

How many moles of magnesium phosphate, Mg_{3}(PO_{4})_{2} will contain 0.25 mole of oxygen atoms?

Option 1)

0.02

Option 2)

3.125 × 10-2

Option 3)

1.25 × 10-2

Option 4)

2.5 × 10-2

If we consider that 1/6, in place of 1/12, mass of carbon atom is taken to be the relative atomic mass unit, the mass of one mole of a substance will

Option 1)

decrease twice

Option 2)

increase two fold

Option 3)

remain unchanged

Option 4)

be a function of the molecular mass of the substance.

With increase of temperature, which of these changes?

Option 1)

Molality

Option 2)

Weight fraction of solute

Option 3)

Fraction of solute present in water

Option 4)

Mole fraction.

Number of atoms in 558.5 gram Fe (at. wt.of Fe = 55.85 g mol-1) is

Option 1)

twice that in 60 g carbon

Option 2)

6.023 × 1022

Option 3)

half that in 8 g He

Option 4)

558.5 × 6.023 × 1023

A pulley of radius 2 m is rotated about its axis by a force F = (20t - 5t2) newton (where t is measured in seconds) applied tangentially. If the moment of inertia of the pulley about its axis of rotation is 10 kg m2 , the number of rotations made by the pulley before its direction of motion if reversed, is

Option 1)

less than 3

Option 2)

more than 3 but less than 6

Option 3)

more than 6 but less than 9

Option 4)

more than 9

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