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    NCERT Solutions for Class 8 Maths Chapter 8 Comparing Quantities

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    NCERT Solutions for Class 8 Maths Chapter 8 Comparing Quantities

    Edited By Ramraj Saini | Updated on Oct 09, 2023 04:55 PM IST

    NCERT Solutions for Class 8 Maths Chapter 8 Comparing Quantities

    Comparing Quantities Class 8 Questions And Answers provided here. These NCERT Solutions are created by expert team at craeers360 keeping the latest syllabus and pattern of CBSE 2023-23. This chapter includes several important topics, like ratios, percentages, discount, profit & loss, and simple and compound interest. The ratio of two quantities is known as comparing quantity. In this chapter, we are going to compare quantities like marks of two students, the height of two persons, a comparison of profit, sales value, etc.

    In the NCERT solutions for Class 8 Maths chapter 8 Comparing Quantities, there are 3 exercises with 26 questions. The first exercise of CBSE Class 8 chapter Comparing Quantities is on percentage and ratio. The second exercise is on finding the increase or decrease percent and finding discounts. Through these NCERT solutions for Class 8 Maths chapter 8 Comparing Quantities, students can cover all the problems related to ratios, percentages, discount, profit-loss, and simple-compound interest. Here you will get the detailed NCERT Solutions for Class 8 Maths by clicking on the link.

    Comparing Quantities Class 8 Questions And Answers PDF Free Download

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    Comparing Quantities Class 8 Solutions - Important Formulae

    • Profit: Profit = Selling price - Cost price

    • Loss: Loss = Cost price - Selling price

    • Profit or Loss Determination:

    • If SP > CP, then it is a profit.

    • If SP = CP, then it is neither profit nor loss.

    • If CP > SP, then it is a loss.

    • Discount: Discount = Marked Price - Sale Price

    • Discount Percentage: Discount % = (Discount × 100) / Marked Price

    • Profit Percentage: Profit Percentage = (Profit / Cost Price) × 100

    • Loss Percentage: Loss Percentage = (Loss / Cost Price) × 100

    • Percentage Increased: Percentage Increased = (Change in Value / Original Value) × 100

    • Simple Interest: Simple Interest = (Principal × Rate × Time) / 100

    • Compound Interest Formula: Compound Interest = Amount - Principal

    • Sales Tax or VAT: Sales tax or VAT = (Cost Price × Rate of Sales Tax) / 100

    • Billing Amount: Billing Amount = Selling price + VAT

    Free download NCERT Solutions for Class 8 Maths Chapter 8 Comparing Quantities for CBSE Exam.

    Comparing Quantities Class 8 NCERT Solutions (Intext Questions and Exercise)

    Comparing quantities class 8 NCERT solutions - Topic 8.1

    (i)

    In a primary school, the parents were asked the number of hours they spend per day in helping their children to do homework. There were 90 parents who helped \frac{1}{2} hour to 1\frac{1}{2} hours. The distribution of parents according to the time for which they said they helped is given in the adjoining figure; 20% helped for more than 1\frac{1}{2} hours; 30% helped for \frac{1}{2} hour to 1\frac{1}{2} hours; 50% did not help at all.

    Using this, answer the following :

    (i) How many parents were surveyed?

    1643102036873

    Answer:

    Let the number of parents surveyed be X.

    30% of them helped for \frac{1}{2} hour to 1\frac{1}{2} hours.

    In total, there were 90 such parents.

    \therefore 30% of X = 90

    \Rightarrow \frac{30}{100}\times X = 90 \\ \Rightarrow X = 90\times100 /30 = 300

    Therefore, there were a total of 300 parents who were surveyed.

    (iii)

    In a primary school, the parents were asked about the number of hours they spend per day in helping their children to do homework.There were 90 parents who helped for \frac{1}{2} hour

    to 1\frac{1}{2} hours. The distribution of parents according to the time for which they said they helped is given in the adjoining figure; 20% helped for more than 1\frac{1}{2} hours; 30% helped for \frac{1}{2} hour to 1\frac{1}{2} hours; 50 % did not help at all.

    Using this, answer the following :

    (iii) How many said that they helped for more than 1\frac{1}{2} hours?

    1643103226941

    Answer:

    from the first question number of parents surveyed X = 300

    Given, 20% helped for more than 1\frac{1}{2} hours.

    Therefore, number of such parents = 20% of 300 = 2 x 30 = 60.

    Class 8 comparing quantities NCERT solutions - Topic 8.3

    1(a) A shop gives 20% discount. What would the sale price of each of these be?

    (a) A dress marked at Rs 120.

    Answer:

    The marked price of dress = Rs120

    Discount rate = 20%

    \\\\ \\Total\ discount =Marked\ Price\times \frac{Discount\ rate}{100}\\ \\Total\ discount=120\times \frac{20}{100}\\ \\Total\ discount=Rs.24\\

    Selling price (SP) = Marked price - Total discount = Rs (120- 24) = Rs 96.

    1(b) A shop gives 20% discount. What would the sale price of each of these be?

    (b) A pair of shoes marked at Rs 750

    Answer:

    The marked price of shoes=Rs 750

    Discount rate = 20%

    \\Total\ discount =Marked\ Price\times \frac{Discount\ rate}{100}\\ \\Total\ discount=750\times \frac{20}{100}\\ \\Total\ discount=Rs.150\\

    Selling price= Marked price- Total discount =Rs (750- 150) = Rs 600.

    1(c) A shop gives 20% discount. What would the sale price of each of these be?

    (c) A bag marked at Rs 250

    Answer:

    The marked price of bag = Rs 250

    Discount rate=20%

    \\Total\ discount =Marked\ Price\times \frac{Discount\ rate}{100}\\ \\Total\ discount=250\times \frac{20}{100}\\ \\Total\ discount=Rs.50\\

    Selling price = Marked price - Total discount = Rs (250- 50) = Rs 200.

    2. A table market marked ar Rs 15,000 is available for Rs 14,400. Find the discount given and the discount per cent.

    Answer:

    Marked price = Rs 15000

    Selling Price = Rs 14400

    We know, Discount amount = Marked price - Selling price

    Discount amount = Rs 15000-Rs 14400 = Rs 600

    \\Discount\ percent=\frac{Discount}{Marked\ Price}\times 100\\ \therefore Discount\ percent=\frac{600}{15000}\times 100=4\%\\

    Therefore, Discount percentage = 4%

    3 An almirah is sold at Rs 5,225 after allowing a discount of 5%. Find its marked price.

    Answer:

    Selling price = Rs 5225

    Discount percent = 5%

    \\ Selling\: price = Marked \:price - Discount \:Amount\\ Selling\: price=Marked\ price-Marked\ price\times \frac{5}{100}\\ Selling\: price=Marked price\times \frac{95}{100}\\ \\Marked\ price= Selling\ price\times \frac{100}{95}\\ \\Marked\ price=\frac{100}{95} \times 5225\\

    Therefore, the marked price = Rs 5500

    NCERT Solutions for Class 8 Maths Chapter 8 Comparing Quantities Topic 8.4.1

    1(a) Find selling price (SP) if a profit of 5% is made on

    (a) A cycle of Rs 700 with Rs 50 as overhead charges.

    Answer:

    We know, Cost price = Buying price + Overhead expenses

    \therefore Cost price = Rs 700 + Rs 50 = Rs 750

    Profit percent = 5%

    We know,

    \\Profit= Cost\ price\times \frac{Profit\ percent}{100} \\Profit=750\times \frac{5}{100}

    \therefore Profit = Rs 37.5

    Now, Selling price (SP) = Cost price + Profit =Rs 750 + Rs 37.5 = Rs 787.50

    Therefore, the selling price (SP) is Rs 787.50

    1(b) Find selling price (SP) if a profit of 5% is made on

    (b) a lawnmower bought at Rs 1150 with Rs 50 as transportation charges.

    Answer:

    If a profit of 5% is made on a lawnmower bought at Rs 1150 with Rs 50 as transportation charges then selling price is:

    \\Cost\ price=Rs\ 1150+Rs\ 50\\ \\Cost\ price=Rs\ 1200\\ \\Profit\ percent=5 \\Profit= Cost\ price\times \frac{Profit\ percent}{100} \\Profit=1200\times \frac{5}{100} \\Profit=Rs\ 60 \\Selling\ price= Cost\ price+Profit \\Selling\ price=Rs\ 1200+Rs\ 60 \\Selling\ price=Rs\ 1260

    1 (c) Find selling price (SP) if a profit of 5% is made on

    (c) a fan bought at Rs 560 and expenses of Rs 40 made on its repairs.

    Answer:

    We know, Cost price = Buying price + Overhead expenses

    \therefore Cost price = Rs 560 + Rs 40 = Rs 600

    Profit percent = 5%

    \\Profit= Cost\ price\times \frac{Profit\ percent}{100} \\Profit=600\times \frac{5}{100}

    \therefore Profit = Rs 30

    Now, Selling price (SP) = Cost price + Profit =Rs 600 + Rs 30 = Rs 630

    Therefore, the selling price (SP) is Rs 630

    1 A shopkeeper bought two TV sets at Rs 10,000 each He sold one at a profit of 10% and the other at a loss of 10%. Find whether he made an overall profit or loss.

    Answer:

    \\Profit\ on\ first\ TV=10000\times \frac{10}{100}=Rs\ 1000\\ \\Loss\ on\ second\ TV=10000\times \frac{10}{100}=Rs\ 1000\\

    Net profit = Rs 1000 - Rs 1000 = 0

    He neither made an overall profit or loss since the profit made on the first tv equals the loss suffered on the second one.

    Q 1 Two times a number is a 100% increase in the number. If we take half the number what would be the decrease in percent?

    Answer:

    Let the number be x.

    Half the number = \frac{x}{2}

    \\Decrease\ in\ percent=\frac{Number-Half\ the\ number}{Number}\times 100\\ =\frac{x-\frac{x}{2}}{x}\times 100\\ =\frac{1}{2}\times 100\\

    = 50 %

    Therefore, If we take half the number, the decrease in percent is 50%

    Q: 2 By what percent is Rs 2,000 less than Rs 2,400? Is it the same as the percent by which Rs 2,400 is more than Rs 2,000?

    Answer:

    Difference between Rs 2400 and Rs 2000 = Rs 2400- Rs 2000 = Rs 400

    \therefore The per cent by which Rs 2,000 is less than Rs 2,400 is

    \\ \frac{400}{2400}\times 100=16.66 \%\\ ( Less with respect to 2400. Hence, 2400 will be in the denominator! )

    Rs 2000 is less than Rs 2400 by 16.66%

    Now,

    \therefore The per cent by which Rs 2,400 is more than Rs 2,000 is

    \frac{400}{2000}\times 100=20 \% ( More with respect to 2000. Hence, 2000 will be in the denominator! )

    Rs 2400 is more than Rs 2000 by 20%


    Therefore, they are not the same.

    NCERT Solutions for Class 8 Maths Chapter 8 Comparing Quantities Topic 8.6

    Q Find interest and amount to be paid on Rs 15000 at 5% per annum after 2 years.

    Answer:

    \\Interest\ =Principal\ amount\times\frac{Interest\ rate}{100}\times time\\ \:\:=15000\times \frac{5}{100}\times 2\\

    =Rs1500

    Amount to be paid = Interest + Principal Amount

    =Rs 15000 + Rs 1500

    =Rs 16500

    Find the time period and rate for each.

    1. A sum taken for 1\frac{1}{2} years at 8% per annum is compounded half yearly.

    Answer:

    Since the sum taken is compounded half yearly:

    \\Since\ the\ sum\ taken\ is\ compounded\ half\ yearly:\\ Time\ period=2\times 1\frac{1}{2}\\ Time\ period=3\\ Rate=\frac{8}{2}=4\%

    Time period = 3 half years

    Rate = 4% per half year

    NCERT Solutions for Class 8 Maths Chapter 8 Comparing Quantities Topic 8.8

    Find the time period and rate for each.

    A sum taken for 2 years at 4% per annum compounded half yearly.

    Answer:

    Since the sum taken is compounded half yearly:

    \\Since\ the\ sum\ taken\ is\ compounded\ half\ yearly:\\ Time\ period=2\times 2\\ Time\ period=4\\ Rate=\frac{4}{2}=2\%

    Time period = 4 half years.

    Rate = 2% per half year

    Find the amount to be paid

    1. At the end of 2 years on Rs. 2,400 at 5% per annum compounded annually.

    Answer:

    \\A_{n}=P_{1}(1+\frac{R}{100})^{n}\\ P_{1}=Rs\ 2400\\ n=2\\ R=5\\ A_{2}=2400\times (1+\frac{5}{100})^2\\ A_{2}=Rs\ 2646\\

    The amount to be paid at the end of 2 years is Rs 2646

    Find the amount to be paid

    At the end of 1 year on Rs. 1800 at 8% per annum compounded quarterly.

    Answer:

    \\A_{n}=P_{1}(1+\frac{R}{100})^{n}\\ P_{1}=Rs\ 1800\\ n=4\\ R=\frac{8}{4}=2\ percent\ per\ quarter\ year\\ A_{4}=1800\times (1+\frac{2}{100})^4\\ A_{4}=Rs\ 1948.37\\

    The Amount to be paid at the end of 4 years is Rs 1948.37

    NCERT Solutions for Class 8 Maths Chapter 8 Comparing Quantities Topic 8.9

    1 A machinery worth Rs. 10,500 depreciated by 5%. Find its value after one year.

    Answer:

    Price of machinery = Rs. 10,500

    Depriciation=10500\times \frac{5}{100}=Rs.\ 525

    Value after one year = Rs 10,500- Rs 525 = Rs 9975

    2 Find the population of a city after 2 years, which is at present 12 lakh, if the rate of increase is 4%.

    Answer:

    The current population of city

    = 12 lakh

    1200000

    Population after two years =

    P\left ( 1+\frac{R}{100} \right )^{n}

    = 1200000\left ( 1+\frac{4}{100} \right )^{2}

    = 1200000\left ( 1+0.04 \right )^{2}

    = 1200000\left ( 1.04 \right )^{2}

    = 1200000\times 1.0816

    = 1297920

    Thus, the population after two years is 1297920.

    Class 8 maths chapter 8 question answer - Exercise 8.1

    1 (a) Find the ratio of the following.

    Speed of a cycle 15 km per hour to the speed of scooter 30 km per hour.

    Answer:

    The ratio of the speed of cycle to the speed of scooter =

    \frac{15\ km/ hour}{30\ km/ hour} = \frac{15}{30} = \frac{1}{2}

    = 1:2

    1(b) Find the ratio of the following.

    5m to 10km

    Answer:

    To find the ratio, we need to make both quantities of the same unit.

    We know, 1 km = 1000 m.

    \therefore 10 km = 10x1000 m = 10000 m

    Therefore the required ratio =

    \frac{5m}{10\times1000m} = \frac{5}{10000} = \frac{1}{2000}

    = 1 : 2000

    1(c) Find the ratio of the following.

    50 paise to Rs. 5

    Answer:

    To find the ratio, we first make the quantities of the same unit.

    We know, Rs. 1 = 100 paisa. \therefore Rs. 5 = 5x100 = 500 paisa

    Therefore, the required ratio =

    \frac{50 paisa}{Rs. 5}= \frac{50 paisa}{5\times100 paisa} = \frac{1}{10}

    = 1:10

    2 (a) Convert the following ratios into percentages.

    (a) 3:4

    Answer:

    To convert a ratio to a percentage, we multiply the ratio by 100%.

    \therefore The required percentage of the ratio 3:4 =

    \frac{3}{4}\times100\ \%= 75\%


    2 (b) Convert the following ratios to percentages.

    (b) 2:3

    Answer:

    To convert a ratio to a percentage, we multiply the ratio by 100%.

    \therefore The required percentage of ratio 2:3 =

    \frac{2}{3}\times100\ \%= 66.67 \%


    3 72% of 25 students are interested in mathematics. How many are not interested in mathematics?

    Answer:

    Given;

    72% of 25 students are interested in mathematics

    \therefore Percentage of students not interested in mathematics = (100 - 72)% = 28 %

    \therefore The number of students not interested in mathematics = 28% of 25

    =\frac{28}{100}\times25 = \frac{28}{4}

    = 7

    Therefore, 7 students (out of 25) are not interested in mathematics.

    4 A football team won 10 matches out of the total number of matches they played. If their win percentage was 40, then how many matches did they play in all?

    Answer:

    Given,

    Win percentage of the team = 40%

    This means that they won 40 matches out of 100 matches played.

    \therefore They won 10 matches out of \frac{100}{40}\times10 = 25 matches played.

    Therefore, they played a total of 25 matches in all.

    5 If Chameli had Rs 600 left after spending 75% of her money, how much did she have in the beginning?

    Answer:

    Let the amount of money Chameli had in the beginning = Rs. X

    She spends 75% of the money.

    \therefore Percentage of money left = (100 - 75)% = 25%

    Since she has Rs. 600 left.

    \therefore 25% of X = 600

    \Rightarrow \frac{25}{100}\times X = 600 \\

    \Rightarrow \frac{X}{4} = 600

    \\ \Rightarrow X = 600\times4

    X =2400

    Therefore, Chameli had Rs. 2400 with her in the beginning.

    6. If 60% of people in the city like cricket, 30% football and the remaining like other games, then what percent of the people like other games? If the total number of people is 50 lakh, find the exact number who like each type of game.

    Answer:

    Given,

    Total number of people = 50 lakhs

    Percentage of people who like cricket = 60%

    Percentage of people who like football = 30%

    Since remaining people like other games,

    \therefore Percentage of people who like other games = {100 - (60 + 30) } = (100 - 90) = 10%

    10% of the people like other games.

    Now,

    \therefore Number of people who like cricket = 60% of 50 lakhs

    =\frac{60}{100}\times50= 30 lakhs

    \therefore Number of people who like football = 30% of 50 lakhs

    =\frac{30}{100}\times50= 15 lakhs

    \therefore Number of people who like other games = 10% of 50 lakhs

    =\frac{10}{100}\times50 = 5 lakhs

    Class 8 maths chapter 8 NCERT solutions - Exercise 8.2

    1 A man got a 10% increase in his salary. If his new salary is Rs 1,54,000, find his original salary.

    Answer:

    Given,

    Percentage increase in the salary = 10%

    Therefore, if the original salary was Rs. 100, the new salary is Rs. 110

    If new salary is Rs 1,54,000, the original salary was

    =Rs. \frac{100}{110}\times154000= Rs. 140000

    Therefore, the original salary was Rs. 14,00,00.

    2 On Sunday 845 people went to the Zoo. On Monday only 169 people went. What is the percent decrease in the people visiting the Zoo on Monday?

    Answer:

    Given,

    Number of people who went to the zoo on Sunday = 845

    Number of people who went to the zoo on Monday = 169

    \therefore The decrease in the number of people visiting the zoo = (845 - 169) = 676

    \therefore Percentage decrease

    =\frac{676}{845}\times100 \%

    =80\% (Decrease from the original number)

    The percent decrease in the people visiting the Zoo is 80%

    3 A shopkeeper buys 80 articles for Rs 2,400 and sells them for a profit of 16%. Find the selling price of one article.

    Answer:

    Given,

    Cost price (CP) of the 80 articles = Rs. 2,400

    Profit percentage = 16%

    \therefore Profit amount on all 80 articles = 16% of 2400 = 16/100 x 2400 = Rs. 384

    \therefore The selling price of the 80 articles = Rs. (2400 + 384) = Rs. 2784

    \therefore Selling price (SP) of each item = Rs. 2784/80 = Rs. 34.8

    Therefore, the selling price of one article is Rs.34.8

    4 The cost of an article was Rs 15,500. Rs 450 was spent on its repairs. If it is sold on a profit of 15%, find the selling price of one article.

    Answer:

    Given,

    Cost of the article = Rs. 15500

    Cost of repair = Rs. 450

    \therefore Cost price(CP) of the article = Rs. (15500 + 450) = Rs. 15950

    Profit percentage = 15%

    \therefore Profit amount = 15% of Rs.15950 = Rs. 2392.50

    \therefore Selling Price = Rs.(15950 + 2392.50) = Rs. 18342.50

    OR

    \therefore Selling price (SP) of the article = CP + Profit = CP + (15% of CP)

    = 115% of CP

    =\frac{115}{100}\times15950= Rs. 18342.50

    5 A VCR and TV were bought for Rs 8,000 each. The shopkeeper made a loss of 4% on the VCR and a profit of 8% on the TV. Find the gain or loss percent on the whole transaction.

    Answer:

    Given,

    The cost price of the VCR = Rs. 8000

    The cost price of TV = Rs. 8000

    Now, He made a loss of 4% on VCR.

    \therefore Selling price (SP) of the VCR = (100-4)% of CP = 96% x Rs. 8000 = Rs. 7680

    Again, He made a profit of 8% on TV.

    \therefore Selling price (SP) of the TV = (100+8)% of CP = 108% x Rs. 8000 = Rs. 8640

    Net Selling price = Rs. (7680 + 8640) = Rs. 16320

    Net Cost price = Rs. (2x8000) = Rs. 16000

    Since, SP > CP, he made a net profit (gain)

    Now, Net Gain = CP - SP = Rs. (16320-16000) = Rs. 320

    \therefore Gain % = \frac{Profit}{CP}\times100\% = \frac{320}{16000}\times100\% = 2%

    \therefore The shopkeeper made a gain of 2% on the whole transaction.

    6 During a sale, a shop offered a discount of 10% on the market prices of all the items. What would a customer have to pay for a pair of jeans marked at Rs 1450 and two shirts marked at Rs 850 each?

    Answer:

    Since the 10% discount is on all the items, we can calculate the Selling price by totalling the Cost price of all item bought.

    Now,

    Total Cost price(CP) of the items he bought = CP of a pair of jeans + CP of two shirts = Rs.(1450 + 850 + 850) = Rs. 3150

    \therefore The selling price of these items = (100- 10)% of Rs. 3150 = 90% x Rs.3150 = Rs. 2835

    \therefore The customer has to pay Rs. 2835.

    7 A milkman sold two of his buffaloes for Rs 20,000 each. On one hand, he made a gain of 5% and on the other a loss of 10% Find his overall gain or loss. ( Hint: Find CP of each)

    Answer:

    Given,

    The milkman sold two of his buffaloes for Rs 20,000 each. This is the Selling price of the buffaloes.

    Let CP of one of the buffalo be Rs. X and the other be Rs. Y

    Since he made a profit of 5% on one of them.

    \therefore 105% of X = Rs. 20000

    \\ \implies \frac{105}{100}\times X = 20000 \\ \implies X = \frac{100}{105}\times20000

    \therefore X = Rs. 19047.6

    Similarly, since he made a loss of 10% on the other.

    \therefore 90% of Y = Rs. 20000

    \\ \implies \frac{90}{100}\times Y = 20000 \\ \implies Y = \frac{100}{90}\times20000

    \therefore Y = Rs. 22222.2

    \therefore Net CP = Rs.(19047.6 + 22222.2) = Rs. 41269.8

    And net SP = 2 x Rs.20000 = Rs. 40000

    Since SP < CP, he made a net loss.

    \therefore His overall loss = Rs. (41269.8 - 40000) = Rs. 1269.8 = Rs. 1270 (approx)

    8 The price of a TV is Rs 13,000. The sales tax charged on it is at the rate of 12%. Find the amount that Vinod will have to pay if he buys it.

    Answer:

    Given,

    Cost price of the TV = Rs. 13000

    Sales tax at the rate of 12%

    \therefore Selling price = CP + Sales Tax = CP + 12% of CP

    = 112% of CP =

    \frac{112}{100}\times 13000 = Rs. 14560

    \therefore Vinod will have to pay Rs. 14,560.

    9 Arun bought a pair of skates at a sale where the discount given was 20%. If the amount he pays is Rs 1,600, find the marked price.

    Answer:

    The discount given was 20% which means if CP is Rs. 100 then the SP is Rs. 80

    \therefore If SP is Rs. 80 then CP is Rs. 100

    For SP of Rs. 1600, CP

    =\frac{100}{80}\times1600 = Rs. 2000

    \therefore The marked price is Rs. 2000.

    10 I purchased a hair-dryer for Rs 5,400 including 8% VAT. Find the price before VAT was added.

    Answer:

    Given,

    VAT = 8%

    Let the original price be Rs. 100

    Original price + VAT = Rs. 100 + Rs. \left ( 8\%\, of\, 100 \right )

    Original price + VAT = Rs. 100 + Rs. 8 = Rs. 108

    \therefore If the price after VAT is Rs.5400, then the price before VAT is Rs. \frac{100}{108}\times5400 = Rs. 5000

    \therefore The price before VAT was added is Rs. 5000.

    11 An article was purchased for Rs 1,239 including GST of 18%. Find the price of the article before GST was added?

    Answer:

    Given,

    GST = 18%

    Cost with GST included = Rs. 1239

    Cost without GST = x Rs.


    x + ( \frac{18}{100} \times x ) = 1239

    cost before GST+ GST = cost with GST

    x + ( \frac{9x}{50} ) = 1239

    x = 1050

    Price before GST = 1050 rupees

    NCERT Solutions for Class 8 Maths Chapter 8 Comparing Quantities Exercise 8.3

    1 (a) Calculate the amount and compound interest on

    (a) Rs 10,800 for 3 years at 12\frac{1}{2} % per annum compounded annually .

    Answer:

    Given,

    Principal,P = Rs 10800

    Compound Interese Rate,R = 12\frac{1}{2} \% = \frac{25}{2}\% p.a.

    Time period,n = 3 years.

    We know,

    Amount when interest is compounded annually, A = P(1+\frac{R}{100})^n

    Therefore, the required amount = 10800(1+\frac{25}{2\times100})^{3} = Rs. 15377.34

    And Compound Interest, CI = Amount - Principal = Rs. (15377.34 - 10800) = Rs. 4577.34

    1 (b) Calculate the amount and compound interest on

    (b) Rs 18,000 for 2\frac{1}{2} years at 10% per annum compounded annually .

    Answer:

    Given,

    Principal,P =Rs.18000, Rate,R = 10% and time period,n = 2.5 years.

    We know, Amount when interest is compounded annually = P(1+\frac{R}{100})^n

    Amount after 2 years at 10% , A = 18000(1+\frac{10}{100})^2 = Rs.21780

    This acts as the principal amount for the next half year.

    SI on next 1/2 year at = \frac{21780\times\frac{1}{2}\times10}{100} = Rs. 1089

    Therefore, Total amount to be paid after 2.5 years = Rs. (21780+1089) = Rs.22869

    Now, Compound Interest after 2 years = A - P = Rs.(21780-18000) = Rs. 3780

    Therefore, Compound Interest after 2.5 years, CI = Rs. 3780 + SI = Rs.4869

    Q: 1 (c) Calculate the amount and compound interest on

    (c) Rs 62,500 for 1\frac{1}{2} years at 8% per annum compounded half yearly.

    Answer:

    Given,

    Principal,P =Rs 62500,

    Compound interest Rate,R = 8% compounded half yearly for 1.5 years.

    Since it is compounded half yearly, R becomes half = 4%, and time period doubles, n = 3 years.

    We know, Amount when interest is compounded annually, A = P(1+\frac{R}{100})^n

    Therefore, the required amount = 62500(1+\frac{4}{100})^3 = Rs.70304

    And Compound Interest, CI = Amount - Principal = Rs. (70304 - 62500) = Rs. 7804

    1 (d) Calculate the amount and compound interest on:

    (d) Rs 8000 for 1 year at 9% per annum compounded half yearly. (You could use the year by year calculation using SI formula to verify)

    Answer:

    Given,

    Principal,P =Rs.8000, Rate, R = 9% per annum compounded half yearly for 1 year.

    Now, there are two half years in a year. Therefore compounding has to be 2 times.

    And rate = half of 9% = 4.5% half yearly.

    Therefore, the required amount = 8000(1+\frac{9}{2\times100})^{2} = Rs. 8736.20

    And Compound Interest, CI = Amount - Principal = Rs. (8736.20 - 8000) = Rs. 736.20

    1 (e) Calculate the amount and compound interest on

    Rs 10,000 for 1 year at 8% per annum compounded half yearly.

    Answer:

    Given,

    Principal, P =Rs.10000, Rate, R = 8% per annum compounded half yearly for 1 year.

    Now, there are two half years in a year. Therefore compounding has to be 2 times.

    And rate = half of 10% = 5% half yearly.

    Therefore, the required amount = 10000(1+\frac{4}{100})^{2} = Rs. 10816

    And Compound Interest, C.I. = Amount - Principal = Rs. (10816 - 10000) = Rs. 816 .

    2 Kamala borrowed Rs 26,400 from a Bank to buy a scooter at a rate of 15% p.a. compounded yearly. What amount will she pay at the end of 2 years and 4 months to clear the loan? ( Hint: Find A for 2 years with interest is compounded yearly and then find SI on the 2nd year amount for \frac{4}{12} years )

    Answer:

    The amount borrowed from the bank = Principal amount, P = Rs 26400

    Compound interest rate, R = 15% p.a.

    Time period = 2 years 4 months = 2\frac{4}{12} = 2\frac{1}{3} years

    We know, Amount when interest is compounded annually, A = P(1+\frac{R}{100})^n

    Therefore, for the first 2 years, amount, A = 26400(1+\frac{15}{100})^2 = Rs 34914

    Now, this would act as principal for the next 1/3 year. We find the SI on Rs 34914 for 1/3 year.

    SI = \frac{34914\times\frac{1}{3}\times15}{100} = Rs 1745.70

    Therefore, Required amount at the end of 2 years and 4 months = A + SI = Rs (34914 + 1745.70) = Rs 36659.70

    3 Fabina borrows Rs 12,500 at 12% per annum for 3 years at simple interest and Radha borrows the same amount for the same time period at 10% per annum, compounded annually. Who pays more interest and by how much?

    Answer:

    For Fabina,

    Principal,P =Rs 12500

    Simple interest Rate,R = 12% p.a.

    Time period,n = 3 years.

    \therefore Simple Interest, SI at 12% for 3 years = 3\times\frac{12500\times12}{100} = Rs 4500

    For Radha,

    Principal,P =Rs 12500

    Compound interest Rate,R = 10% p.a.

    Time period,n = 3 years.

    We know, Amount when interest is compounded annually,

    A =P(1+\frac{R}{100})^n

    A=12500(1+\frac{10}{100})^3 = Rs 16637.50

    \therefore Compound \:\:Interest, CI = A - P = Rs\: (16637.50 - 12500) = Rs \:4137.50

    \therefore Fabina pays more interest and Rs (4500 - 4137.50) = Rs 362.50 more.

    4 . I borrowed Rs 12,000 from Jamshed at 6% per annum simple interest for 2 years. Had I borrowed this sum at 6% per annum compound interest, what extra amount would I have to pay?

    Answer:

    Given,

    Principal,P =Rs 12000

    Simple interest Rate,R = 6% p.a.

    Time period,n = 2 years.

    \therefore Simple Interest, SI at 6% for 2 years =

    =2\times\frac{12000\times6}{100} = Rs 1440

    If he would have borrowed it at a compound interest rate, R = 6% p.a.

    We know, Amount when interest is compounded annually, A =

    A = P(1+\frac{R}{100})^n

    \therefore A = 12000(1+\frac{6}{100})^2= Rs 13483.20

    \therefore Compound\:\: Interest, CI = A - P = Rs \:(13483.20 - 12000) = Rs\: 1483.20


    \therefore He would have to pay Rs (1483.20 - 1440) = Rs 43.20 extra.

    5 (i) Vasudevan invested Rs 60,000 at an interest rate of 12% per annum compounded half yearly. What amount would he get

    (i) after 6 months?

    Answer:

    Given,

    Principal, P = Rs 60,000

    Compound interest rate, R = 12% p.a

    = 6 % half yearly

    For a period of 6 months. \therefore Time period, n = 1 half year (As there is 1 half year in 6 months.)

    We know, Amount when interest is compounded annually, A =

    A = P(1+\frac{R}{100})^n

    A =60000(1+\frac{6}{100})^1= Rs 63600

    After 6 months, Vasudevan would get an amount Rs. 63600.

    5 (ii) Vasudevan invested Rs 60,000 at an interest rate of 12% per annum compounded half yearly. What amount would he get

    (ii) after 1 year?

    Answer:

    Given,

    Principal, P = Rs 60,000

    Compound interest rate, R = 12% p.a

    = 6 % half-yearly

    For a period of 1 year. \therefore Time period, n = 2 half years (As there are 2 half years in a year.)

    We know, Amount when interest is compounded annually, A =

    A = P(1+\frac{R}{100})^n

    A = 60000(1+\frac{6}{100})^2= Rs 67416

    After 1 year, Vasudevan would get an amount Rs. 67416.

    6 Arif took a loan of Rs 80,000 from a bank. If the rate of interest is 10% per annum, find the difference in amounts he would be paying after 1\frac{1}{2} years if the interest is-

    (i) compounded annually.

    (ii) compounded half yearly.

    Answer :

    (i) Given,

    Principal amount, P = Rs 80000

    Rate of interest, R = 10% p.a.

    Time period = 1\frac{1}{2} years.

    We know, Amount when interest is compounded annually, A =

    A =P(1+\frac{R}{100})^n

    Now, For the first year, A=

    A =80000(1+\frac{10}{100})^1= Rs. 88000

    For the next half-year, this will act as the principal amount.

    \therefore Interest for 1/2 year at 10% p.a =

    =\frac{88000\times\frac{1}{2}\times10}{100}= Rs 4400

    Required total amount = Rs (88000 + 4400) = Rs 92400

    (ii) If it is compounded half-yearly, then there are 3 half years in 1\frac{1}{2} years.

    \therefore n = 3 half years.

    And, Rate of interest = half of 10% p.a = 5% half yearly

    \therefore A =80000(1+\frac{5}{100})^3= Rs.\: 92610

    \therefore The difference in the two amounts = Rs (92610 - 92400) = Rs 210

    7 (i) Maria invested Rs 8,000 in a business. She would be paid interest at 5% per annum compounded annually. Find

    (i) The amount credited against her name at the end of the second year.

    Answer:

    Given,

    Principal amount, P = Rs 8,000

    Compound rate of interest, R = 5% p.a.

    Time period, n = 2 years

    We know, Amount when interest is compounded annually,

    A =P(1+\frac{R}{100})^n

    A =8000(1+\frac{5}{100})^2= Rs.\: 8,820

    Therefore, the amount credited against her name at the end of the second year is Rs 8,820

    7 (ii) Maria invested Rs 8,000 in a business. She would be paid interest at 5% per annum compounded annually. Find

    (ii) The interest for the 3rd year.

    Answer:

    Now, the amount after 2nd year will become the principal amount for the 3rd year

    \therefore Principal amount, P = Rs 8,820

    Compound rate of interest, R = 5% p.a.

    Time period, n' = 1 year

    \therefore Interest \:for\: the \:3rd \:year =\frac{8820\times1\times5}{100} = Rs.\ 441

    Therefore, the interest for the 3rd year is Rs 441.

    8. Find the amount and the compound interest on Rs 10,000 for 1\frac{1}{2} years at 10% per annum, compounded half yearly. Would this interest be more than the interest he would get if it was compounded annually?

    Answer:

    Principal = Rs.10,000

    Time = 1\frac{1}{2} years

    Rate = 10% per annum

    CASE 1 Interest on compounded half yearly.

    Rate = 10% per annum = 5 % per half yearly

    T= 1\frac{1}{2} years,n=3

    A= P\left ( 1+\frac{R}{100} \right )^{n}

    A= 10000\left ( 1+\frac{5}{100} \right )^{3}

    A= 10000\left ( 1+0.05 \right )^{3}

    A= 10000\left ( 1.05 \right )^{3}

    A= 11576.25 = Amount

    CI = Amount - principal

    CI = 11576.25-10000

    CI = 1576.25

    CASE 2 Interest on compounded anually

    Rate = 10% per annum

    T= 1\frac{1}{2} years ,n=1

    A= P\left ( 1+\frac{R}{100} \right )^{n}

    A= 10000\left ( 1+\frac{10}{100} \right )^{1}

    A= 10000\left ( 1+0.1\right )^{1}

    A= 10000\left ( 1.1\right )^{1}

    A= 11000 = Amount

    CI = Amount - principal

    CI = 11000-10000

    CI = 1000


    Interest for half years on 11000 =

    \frac{P\times R\times T}{100}

    =\frac{11000\times 10\times \frac{1}{2}}{100}

    = 55\times 10

    = 550

    Total interest = 1000+550

    = RS 1550

    Since 1576.25 > 1000

    Thus, interest would be more in CASE 1 i.e. compounded half yearly

    Answer:

    Given,

    Principal amount, P = Rs 4,096

    Rate of interest, R

    R =12\frac{1}{2} \% = \frac{25}{2} \% p.a. =\frac{25}{4} \% \ half\ yearly

    Time period, n = 18 months = (12 + 6) months = 1.5 years = 3 half years

    (There are 3 half years in 1.5 years)

    We know,

    Amount when interest is compounded annually, (A)

    A =P(1+\frac{R}{100})^n

    Therefore, the required amount

    =4096(1+\frac{25}{4\times100})^{3} = 4913

    \therefore Ram will get Rs 4,913 after 18 months.

    10 The population of a place increased to 54,000 in 2003 at a rate of 5% per annum

    (i) find the population in 2001.

    Answer:

    Let the population in 2001 be P

    Compound rate of increase = 5% p.a.

    The population in 2003 will be more than in 2001

    Time period, n = 2 years (2001 to 2003)

    \therefore \\ 54000 = P(1 + \frac{5}{100})^2 \\ \implies P = \frac{54000\times100\times100}{105\times105} \approx 48980

    Therefore, the population in 2001 was 48980 (approx)

    10 The population of a place increased to 54,000 in 2003 at a rate of 5% per annum.

    (ii) what would be its population in 2005?

    Answer:

    Let the population in 2001 be P'

    Compound rate of increase = 5% p.a.

    The population in 2005 will be more than in 2003

    Time period, n = 2 years (2003 to 2005)

    \therefore \\ P' = 54000(1 + \frac{5}{100})^2 \\ \implies P' = \frac{54000\times105\times105}{100\times100} \approx 59535

    Therefore, the population in 2005 will be 59535 (approx)

    11 In a Laboratory, the count of bacteria in a certain experiment was increasing at the rate of 2.5% per hour. Find the bacteria at the end of 2 hours if the count was initially 5, 06,000.

    Answer:

    Given,

    Initial count of bacteria, P = 5, 06,000 (Principal Amount)

    Rate of increase, R = 2.5% per hour.

    Time period, n = 2 hours

    (This question is done in a similar manner as compound interest)

    Number of bacteria after 2 hours = P(1+\frac{R}{100})^n

    = 506000(1+\frac{2.5}{100})^2 \approx 531616

    Therefore, the number of bacteria at the end of 2 hours will be 531616 (approx)

    12 A scooter was bought at Rs 42,000. Its value depreciated at the rate of 8% per annum. Find its value after one year.

    Answer:

    Given,

    Principal = Rs 42,000

    Rate of depreciation = 8% p.a

    \therefore Reduction = 8% of Rs 42000 per year

    =\frac{42000\times 8\times 1}{100} = Rs\ 3360

    \therefore Value at the end of 1 year = Rs (42000 – 3360) = Rs 38,640

    NCERT Solutions for Class 8 Maths Chapter 8 Comparing Quantities - Topics

    • Recalling Ratios and Percentages
    • Finding the Increase or Decrease Percent
    • Finding Discounts
    • Prices Related to Buying and Selling (Profit and Loss)
    • Sales Tax/Value Added Tax/Goods and Services Tax
    • Compound Interest
    • Deducing a Formula for Compound Interest
    • Rate Compounded Annually or Half Yearly (Semi-Annually)
    • Applications of Compound Interest Formula

    NCERT Solutions for Class 8 Maths - Chapter Wise

    Key Features Of class 8 comparing quantities NCERT solutions

    Complete Coverage: Solutions for maths chapter 8 class 8 cover all topics and concepts related to comparing quantities as per the Class 8 syllabus.

    Step-by-Step Solutions: Detailed, step-by-step explanations for each problem, making it easy for students to understand and apply mathematical concepts related to ratios, percentages, and discounts.

    Illustrations and Diagrams: The inclusion of diagrams, figures, and illustrations to visually explain concepts and methods for comparing quantities ch 8 maths class 8.

    NCERT Solutions for Class 8 - Subject Wise

    Also Check NCERT Books and NCERT Syllabus here:

    Frequently Asked Question (FAQs)

    1. What are the important topics of NCERT book chapter Comparing Quantities ?

    Increase or decrease percentage, discounts, profit and loss, simple and compound interest are the important topics of this chapter.

    2. Does CBSE NCERT syllabus class 8 maths is tough ?

    CBSE class 8 maths is damn simple and basic. Most of the chapters are related to the previous classes.

    3. How does the NCERT solutions are helpful ?

    NCERT solutions are helpful for the students if they are not able to NCERT problems on their own. These solutions are provided in a very detailed manner which will give them conceptual clarity.  

    4. How many chapters are there in the CBSE class 8 maths ?

    There are 16 chapters starting from rational number to playing with numbers in the CBSE class 8 maths.

    5. Where can I find the complete solutions of NCERT for class 8 ?

    Here you will get the detailed NCERT solutions for class 8 by clicking on the link.

    6. Where can I find the complete solutions of NCERT for class 8 maths ?

    Here you will get the detailed NCERT solutions for class 8 maths by clicking on the link.

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    A block of mass 0.50 kg is moving with a speed of 2.00 ms-1 on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is

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    0.34\; J

    Option 2)

    0.16\; J

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    0.67\; J

    A person trying to lose weight by burning fat lifts a mass of 10 kg upto a height of 1 m 1000 times.  Assume that the potential energy lost each time he lowers the mass is dissipated.  How much fat will he use up considering the work done only when the weight is lifted up ?  Fat supplies 3.8×107 J of energy per kg which is converted to mechanical energy with a 20% efficiency rate.  Take g = 9.8 ms−2 :

    Option 1)

    2.45×10−3 kg

    Option 2)

     6.45×10−3 kg

    Option 3)

     9.89×10−3 kg

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    12.89×10−3 kg

     

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    Option 1)

    2,000 \; J - 5,000\; J

    Option 2)

    200 \, \, J - 500 \, \, J

    Option 3)

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    Option 1)

    K/2\,

    Option 2)

    \; K\;

    Option 3)

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    Option 1)

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    Option 2)

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    Option 1)

    0.02

    Option 2)

    3.125 × 10-2

    Option 3)

    1.25 × 10-2

    Option 4)

    2.5 × 10-2

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    Option 1)

    decrease twice

    Option 2)

    increase two fold

    Option 3)

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    Option 1)

    twice that in 60 g carbon

    Option 2)

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    Option 3)

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    A career in pathology in India is filled with several responsibilities as it is a medical branch and affects human lives. The demand for pathologists has been increasing over the past few years as people are getting more aware of different diseases. Not only that, but an increase in population and lifestyle changes have also contributed to the increase in a pathologist’s demand. The pathology careers provide an extremely huge number of opportunities and if you want to be a part of the medical field you can consider being a pathologist. If you want to know more about a career in pathology in India then continue reading this article.

    5 Jobs Available
    Gynaecologist

    Gynaecology can be defined as the study of the female body. The job outlook for gynaecology is excellent since there is evergreen demand for one because of their responsibility of dealing with not only women’s health but also fertility and pregnancy issues. Although most women prefer to have a women obstetrician gynaecologist as their doctor, men also explore a career as a gynaecologist and there are ample amounts of male doctors in the field who are gynaecologists and aid women during delivery and childbirth. 

    4 Jobs Available
    Surgical Technologist

    When it comes to an operation theatre, there are several tasks that are to be carried out before as well as after the operation or surgery has taken place. Such tasks are not possible without surgical tech and surgical tech tools. A single surgeon cannot do it all alone. It’s like for a footballer he needs his team’s support to score a goal the same goes for a surgeon. It is here, when a surgical technologist comes into the picture. It is the job of a surgical technologist to prepare the operation theatre with all the required equipment before the surgery. Not only that, once an operation is done it is the job of the surgical technologist to clean all the equipment. One has to fulfil the minimum requirements of surgical tech qualifications. 

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    3 Jobs Available
    Oncologist

    An oncologist is a specialised doctor responsible for providing medical care to patients diagnosed with cancer. He or she uses several therapies to control the cancer and its effect on the human body such as chemotherapy, immunotherapy, radiation therapy and biopsy. An oncologist designs a treatment plan based on a pathology report after diagnosing the type of cancer and where it is spreading inside the body.

    3 Jobs Available
    Dentist

    Those who wish to make a dentist career in India must know that dental training opens up a universe of expert chances. Notwithstanding private practice, the present dental school graduates can pick other dental profession alternatives, remembering working in medical clinic crisis rooms, leading propelled lab examinations, teaching future dental specialists, or in any event, venturing to the far corners of the planet with International health and relief organizations.

    2 Jobs Available
    Health Inspector

    Individuals following a career as health inspectors have to face resistance and lack of cooperation while working on the sites. The health inspector's job description includes taking precautionary measures while inspecting to save themself from any external injury and the need to cover their mouth to avoid toxic substances. A health inspector does the desk job as well as the fieldwork. Health inspector jobs require one to travel long hours to inspect a particular place.

    2 Jobs Available
    Actor

    For an individual who opts for a career as an actor, the primary responsibility is to completely speak to the character he or she is playing and to persuade the crowd that the character is genuine by connecting with them and bringing them into the story. This applies to significant roles and littler parts, as all roles join to make an effective creation. Here in this article, we will discuss how to become an actor in India, actor exams, actor salary in India, and actor jobs. 

    4 Jobs Available
    Acrobat

    Individuals who opt for a career as acrobats create and direct original routines for themselves, in addition to developing interpretations of existing routines. The work of circus acrobats can be seen in a variety of performance settings, including circus, reality shows, sports events like the Olympics, movies and commercials. Individuals who opt for a career as acrobats must be prepared to face rejections and intermittent periods of work. The creativity of acrobats may extend to other aspects of the performance. For example, acrobats in the circus may work with gym trainers, celebrities or collaborate with other professionals to enhance such performance elements as costume and or maybe at the teaching end of the career.

    3 Jobs Available
    Video Game Designer

    Career as a video game designer is filled with excitement as well as responsibilities. A video game designer is someone who is involved in the process of creating a game from day one. He or she is responsible for fulfilling duties like designing the character of the game, the several levels involved, plot, art and similar other elements. Individuals who opt for a career as a video game designer may also write the codes for the game using different programming languages. Depending on the video game designer job description and experience they may also have to lead a team and do the early testing of the game in order to suggest changes and find loopholes.

    3 Jobs Available
    Talent Agent

    The career as a Talent Agent is filled with responsibilities. A Talent Agent is someone who is involved in the pre-production process of the film. It is a very busy job for a Talent Agent but as and when an individual gains experience and progresses in the career he or she can have people assisting him or her in work. Depending on one’s responsibilities, number of clients and experience he or she may also have to lead a team and work with juniors under him or her in a talent agency. In order to know more about the job of a talent agent continue reading the article.

    If you want to know more about talent agent meaning, how to become a Talent Agent, or Talent Agent job description then continue reading this article.

    3 Jobs Available
    Radio Jockey

    Radio Jockey is an exciting, promising career and a great challenge for music lovers. If you are really interested in a career as radio jockey, then it is very important for an RJ to have an automatic, fun, and friendly personality. If you want to get a job done in this field, a strong command of the language and a good voice are always good things. Apart from this, in order to be a good radio jockey, you will also listen to good radio jockeys so that you can understand their style and later make your own by practicing.

    A career as radio jockey has a lot to offer to deserving candidates. If you want to know more about a career as radio jockey, and how to become a radio jockey then continue reading the article.

    3 Jobs Available
    Producer

    An individual who is pursuing a career as a producer is responsible for managing the business aspects of production. They are involved in each aspect of production from its inception to deception. Famous movie producers review the script, recommend changes and visualise the story. 

    They are responsible for overseeing the finance involved in the project and distributing the film for broadcasting on various platforms. A career as a producer is quite fulfilling as well as exhaustive in terms of playing different roles in order for a production to be successful. Famous movie producers are responsible for hiring creative and technical personnel on contract basis.

    2 Jobs Available
    Fashion Blogger

    Fashion bloggers use multiple social media platforms to recommend or share ideas related to fashion. A fashion blogger is a person who writes about fashion, publishes pictures of outfits, jewellery, accessories. Fashion blogger works as a model, journalist, and a stylist in the fashion industry. In current fashion times, these bloggers have crossed into becoming a star in fashion magazines, commercials, or campaigns. 

    2 Jobs Available
    Photographer

    Photography is considered both a science and an art, an artistic means of expression in which the camera replaces the pen. In a career as a photographer, an individual is hired to capture the moments of public and private events, such as press conferences or weddings, or may also work inside a studio, where people go to get their picture clicked. Photography is divided into many streams each generating numerous career opportunities in photography. With the boom in advertising, media, and the fashion industry, photography has emerged as a lucrative and thrilling career option for many Indian youths.

    2 Jobs Available
    Copy Writer

    In a career as a copywriter, one has to consult with the client and understand the brief well. A career as a copywriter has a lot to offer to deserving candidates. Several new mediums of advertising are opening therefore making it a lucrative career choice. Students can pursue various copywriter courses such as Journalism, Advertising, Marketing Management. Here, we have discussed how to become a freelance copywriter, copywriter career path, how to become a copywriter in India, and copywriting career outlook. 

    5 Jobs Available
    Journalist

    Careers in journalism are filled with excitement as well as responsibilities. One cannot afford to miss out on the details. As it is the small details that provide insights into a story. Depending on those insights a journalist goes about writing a news article. A journalism career can be stressful at times but if you are someone who is passionate about it then it is the right choice for you. If you want to know more about the media field and journalist career then continue reading this article.

    3 Jobs Available
    Publisher

    For publishing books, newspapers, magazines and digital material, editorial and commercial strategies are set by publishers. Individuals in publishing career paths make choices about the markets their businesses will reach and the type of content that their audience will be served. Individuals in book publisher careers collaborate with editorial staff, designers, authors, and freelance contributors who develop and manage the creation of content.

    3 Jobs Available
    Vlogger

    In a career as a vlogger, one generally works for himself or herself. However, once an individual has gained viewership there are several brands and companies that approach them for paid collaboration. It is one of those fields where an individual can earn well while following his or her passion. Ever since internet cost got reduced the viewership for these types of content has increased on a large scale. Therefore, the career as vlogger has a lot to offer. If you want to know more about the career as vlogger, how to become a vlogger, so on and so forth then continue reading the article. Students can visit Jamia Millia Islamia, Asian College of Journalism, Indian Institute of Mass Communication to pursue journalism degrees.

    3 Jobs Available
    Editor

    Individuals in the editor career path is an unsung hero of the news industry who polishes the language of the news stories provided by stringers, reporters, copywriters and content writers and also news agencies. Individuals who opt for a career as an editor make it more persuasive, concise and clear for readers. In this article, we will discuss the details of the editor's career path such as how to become an editor in India, editor salary in India and editor skills and qualities.

    3 Jobs Available
    Fashion Journalist

    Fashion journalism involves performing research and writing about the most recent fashion trends. Journalists obtain this knowledge by collaborating with stylists, conducting interviews with fashion designers, and attending fashion shows, photoshoots, and conferences. A fashion Journalist  job is to write copy for trade and advertisement journals, fashion magazines, newspapers, and online fashion forums about style and fashion.

    2 Jobs Available
    Multimedia Specialist

    A multimedia specialist is a media professional who creates, audio, videos, graphic image files, computer animations for multimedia applications. He or she is responsible for planning, producing, and maintaining websites and applications. 

    2 Jobs Available
    Corporate Executive

    Are you searching for a Corporate Executive job description? A Corporate Executive role comes with administrative duties. He or she provides support to the leadership of the organisation. A Corporate Executive fulfils the business purpose and ensures its financial stability. In this article, we are going to discuss how to become corporate executive.

    2 Jobs Available
    Product Manager

    A Product Manager is a professional responsible for product planning and marketing. He or she manages the product throughout the Product Life Cycle, gathering and prioritising the product. A product manager job description includes defining the product vision and working closely with team members of other departments to deliver winning products.  

    3 Jobs Available
    Quality Controller

    A quality controller plays a crucial role in an organisation. He or she is responsible for performing quality checks on manufactured products. He or she identifies the defects in a product and rejects the product. 

    A quality controller records detailed information about products with defects and sends it to the supervisor or plant manager to take necessary actions to improve the production process.

    3 Jobs Available
    Production Manager

    Production Manager Job Description: A Production Manager is responsible for ensuring smooth running of manufacturing processes in an efficient manner. He or she plans and organises production schedules. The role of Production Manager involves estimation, negotiation on budget and timescales with the clients and managers. 

    Resource Links for Online MBA 

    3 Jobs Available
    QA Manager

    Quality Assurance Manager Job Description: A QA Manager is an administrative professional responsible for overseeing the activity of the QA department and staff. It involves developing, implementing and maintaining a system that is qualified and reliable for testing to meet specifications of products of organisations as well as development processes. 

    2 Jobs Available
    QA Lead

    A QA Lead is in charge of the QA Team. The role of QA Lead comes with the responsibility of assessing services and products in order to determine that he or she meets the quality standards. He or she develops, implements and manages test plans. 

    2 Jobs Available
    Reliability Engineer

    Are you searching for a Reliability Engineer job description? A Reliability Engineer is responsible for ensuring long lasting and high quality products. He or she ensures that materials, manufacturing equipment, components and processes are error free. A Reliability Engineer role comes with the responsibility of minimising risks and effectiveness of processes and equipment. 

    2 Jobs Available
    Safety Manager

    A Safety Manager is a professional responsible for employee’s safety at work. He or she plans, implements and oversees the company’s employee safety. A Safety Manager ensures compliance and adherence to Occupational Health and Safety (OHS) guidelines.

    2 Jobs Available
    Corporate Executive

    Are you searching for a Corporate Executive job description? A Corporate Executive role comes with administrative duties. He or she provides support to the leadership of the organisation. A Corporate Executive fulfils the business purpose and ensures its financial stability. In this article, we are going to discuss how to become corporate executive.

    2 Jobs Available
    ITSM Manager

    ITSM Manager is a professional responsible for heading the ITSM (Information Technology Service Management) or (Information Technology Infrastructure Library) processes. He or she ensures that operation management provides appropriate resource levels for problem resolutions. The ITSM Manager oversees the level of prioritisation for the problems, critical incidents, planned as well as proactive tasks. 

    3 Jobs Available
    Information Security Manager

    Individuals in the information security manager career path involves in overseeing and controlling all aspects of computer security. The IT security manager job description includes planning and carrying out security measures to protect the business data and information from corruption, theft, unauthorised access, and deliberate attack 

    3 Jobs Available
    Computer Programmer

    Careers in computer programming primarily refer to the systematic act of writing code and moreover include wider computer science areas. The word 'programmer' or 'coder' has entered into practice with the growing number of newly self-taught tech enthusiasts. Computer programming careers involve the use of designs created by software developers and engineers and transforming them into commands that can be implemented by computers. These commands result in regular usage of social media sites, word-processing applications and browsers.

    3 Jobs Available
    Product Manager

    A Product Manager is a professional responsible for product planning and marketing. He or she manages the product throughout the Product Life Cycle, gathering and prioritising the product. A product manager job description includes defining the product vision and working closely with team members of other departments to deliver winning products.  

    3 Jobs Available
    IT Consultant

    An IT Consultant is a professional who is also known as a technology consultant. He or she is required to provide consultation to industrial and commercial clients to resolve business and IT problems and acquire optimum growth. An IT consultant can find work by signing up with an IT consultancy firm, or he or she can work on their own as independent contractors and select the projects he or she wants to work on.

    2 Jobs Available
    Data Architect

    A Data Architect role involves formulating the organisational data strategy. It involves data quality, flow of data within the organisation and security of data. The vision of Data Architect provides support to convert business requirements into technical requirements. 

    2 Jobs Available
    Security Engineer

    The Security Engineer is responsible for overseeing and controlling the various aspects of a company's computer security. Individuals in the security engineer jobs include developing and implementing policies and procedures to protect the data and information of the organisation. In this article, we will discuss the security engineer job description, security engineer skills, security engineer course, and security engineer career path.

    2 Jobs Available
    UX Architect

    A UX Architect is someone who influences the design processes and its outcomes. He or she possesses a solid understanding of user research, information architecture, interaction design and content strategy. 

     

    2 Jobs Available
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