Careers360 Logo
NCERT Solutions for Class 8 Science Chapter 13 Light

NCERT Solutions for Class 8 Science Chapter 13 Light

Edited By Vishal kumar | Updated on Apr 22, 2025 04:10 PM IST

Light is such a critical subject in Class 8 Science, and we use it every day without realizing it! Suppose you are looking at yourself in the mirror, and then, all of a sudden, the lights are switched off. Can you see your face? Of course not! Because in the absence of light, our eyes can't perceive anything. This straightforward example illustrates just how dependent we are on light to perceive the world around us. In Chapter 13 – Light of your NCERT Science textbook, students will understand how light benefits all of us.

This Story also Contains
  1. NCERT Solutions for Class 8 Science Chapter 13 Light
  2. NCERT Solutions for Class 8 Science Chapter 13 Light: Solved Exercise Questions
  3. Class 8 Science Chapter 13 NCERT Solutions: Important Formulas and Diagrams
  4. NCERT Solutions for Class 8 Science Chapter 13 Light: Points to Remember
  5. Light Class 8 Science Chapter 13- Topics
  6. Key Features of Light Class 8 Questions and Answers
  7. NCERT Chapter-Wise Solutions For Class 8th Science
NCERT Solutions for Class 8 Science Chapter 13 Light
NCERT Solutions for Class 8 Science Chapter 13 Light

The students benefit from NCERT Solutions to prepare for exams and more tasks. They explain everything step by step so students don't face any difficulties.

Download the Class 8 Science Chapter 13 – Light Question and Answer PDF for free to boost your CBSE exam preparation. Get all important NCERT solutions in one place, easy to understand and perfect for quick revision!

NCERT Solutions for Class 8 Science Chapter 13 Light

NCERT Solutions for Class 8 Science Chapter 13 Light: Solved Exercise Questions

Q1. Suppose you are in a dark room. Can you see objects in the room? Can you see objects outside the room? Explain.

Answer:

No, we cannot see the objects inside the room but we might see the objects outside the room. An object is visible to us when light reaches it, gets reflected and reaches our eyes. Inside the darkroom there is no light present to be reflected from the objects and reach our eyes and therefore we won't be able to see them but if there is light present outside the room and if it is reflected from objects outside the room and if this light reaches our eyes then we would be able to see the objects outside the room.

Q2. Differentiate between regular and diffused reflection. Does diffused reflection mean the failure of the laws of reflection?

Answer:

In regular reflection, the reflected rays are parallel to each other whereas in diffused reflection, the reflected rays are not parallel to each other. In diffused reflection, the laws of reflection are not violated. In the case of diffused reflection, the surface from which reflection takes place has microscopical irregularities which means the surfaces at the points where each ray gets reflected from are not parallel to each other.

Q3. Mention against each of the following whether regular or diffused reflection will take place when a beam of light strikes. Justify your answer in each case.

(a) Polished wooden table

Answer:

Regular reflection since the polished wooden table has a smooth surface.

Q3 (d). Mention against each of the following whether regular or diffused reflection will take place when a beam of light strikes. Justify your answer in each case.

Marble floor with water spread over it

Answer:

Regular reflection since marble with water spread over it is a smooth surface.

Q4. State the laws of reflection.

Answer:

The laws of reflection are:

(i) The angle of reflection is always equal to the angle of incidence.

(ii) The incident ray, the reflected ray and the normal at the point of incidence to the surface on which reflection takes place all lie in the same plane.

Q5. Describe an activity to show that the incident ray, the reflected ray and the normal at the point of incidence lie in the same plane.

Answer:

Place a plane mirror on the table. Take a piece of paper and make a small hole in it. Ensure that the light in the room is dim. Hold the sheet normal to the table. Take another piece of paper and place it on the table in contact with the mirror. Draw a normal from the mirror on the paper kept on the table Now, light a torch on the mirror through the small hole such that the ray of light falls on the normal at the bottom of the mirror. When the ray from this hole is incident on the mirror, it gets reflected in a certain direction. You can easily observe the incident ray, reflected ray and the normal to the mirror at the point of incidence on the sheet placed on the table. This shows that the incident ray, the reflected ray, and the normal to the surface at the point of incidence all lie in the same plane.

1659590496934

Q6. Fill in the blanks in the following.

(a) A person 1 m in front of a plane mirror seems to be _______________ m away from his image.
(b) If you touch your ____________ ear with right hand in front of a plane mirror it will be seen in the mirror that your right ear is touched with ____________.
(c) The size of the pupil becomes ____________ when you see in dim light.
(d) Night birds have ____________ cones than rods in their eyes.

Answer:

(a) A person 1 m in front of a plane mirror seems to be 2 m away from his image.
(b) If you touch your left ear with the right hand in front of a plane mirror it will be seen in the mirror that your right ear is touched with the left hand .
(c) The size of the pupil becomes large when you see in dim light.
(d) Night birds have fewer cones than rods in their eyes.

Choose the correct option in Question 7

Q7. Angle of incidence is equal to the angle of reflection.

(a) Always (b) Sometimes (c) Under special conditions (d) Never

Answer:

The angle of incidence is always equal to the angle of reflection. This is the first law of reflection, therefore, option (a) is correct.

Choose the correct option in Question 8

Q8. Image formed by a plane mirror is

(a) virtual, behind the mirror and enlarged.
(b) virtual, behind the mirror and of the same size as the object.
(c) real at the surface of the mirror and enlarged.
(d) real, behind the mirror and of the same size as the object.

Answer:

The image formed by a plane mirror is virtual, behind the mirror and of the same size as the object . Therefore option (b) is correct.

Q9. Describe the construction of a kaleidoscope.

Answer:

To make a kaleidoscope, get three rectangular mirror strips each about 15 cm long and 4 cm wide. Join them together to form a prism as shown in Fig. (a). Fix this arrangement of mirrors in a circular cardboard tube or tube of a thick chart paper. Make sure that the tube is slightly longer than the mirror strips. Close one end of the tube by a cardboard disc having a hole in the centre, through which you can see [Fig (b)]. To make the disc durable, paste a piece of the transparent plastic sheet under the cardboard disc. At the other end, touching the mirrors, fix a circular plane glass plate [Fig (c)]. Place on this glass plate several small pieces of coloured glass (broken pieces of coloured bangles). Close this end of the tube by a ground glass plate. Allow enough space for the colour pieces to move around.

1659590615164

Q10. Draw a labelled sketch of the human eye.

Answer:

1659590635585

The human eye consists of the retina, lens, cornea, optic nerve, iris, ciliary muscle

Q11. Gurmit wanted to perform Activity 16.8 using a laser torch. Her teacher advised her not to do so. Can you explain the basis of the teacher’s advice?

Answer:

Laser light can harm the eye if looked at directly because of its high intensity and therefore Gurmit's teacher advised her to not use it.

Q12. Explain how you can take care of your eyes.

Answer:

We can take care of our eyes by following the following steps:

(i) Keeping a distance of at least 25 cm between our eyes and a book while reading it.

(ii) Not looking at a laptop or TV screen for a long time.

(iii) Regularly cleaning our eyes.

(iv) Visiting an ophthalmologist regularly.

Q13. What is the angle of incidence of a ray if the reflected ray is at an angle of 90° to the incident ray?

Answer:

The angle of incidence = angle of reflection. since the angle between the incident and reflected ray is 90 degrees. The angle of the incidents will be 90/2 =45 degrees

Angle of incidence = Angle of reflectionAngle of incidence + Angle of reflection = 902×Angle of incidence = 90Angle of incidence = 90÷\2Angle of incidence =\45

1659590663366

Q14. How many images of a candle will be formed if it is placed between two parallel plane mirrors separated by 40 cm?

Answer:

An infinite number of images of the candle will be formed because when an object is placed between to parallel plane mirrors, an infinite number of images are formed.

Q15. Two mirrors meet at right angles. A ray of light is incident on one at an angle of 30° as shown in Fig. 13.19. Draw the reflected ray from the second mirror.

Answer:

We use the first law of reflection to draw the path of the ray. It states the angle of incidence is equal to the angle of reflection.

1659590768280

Q16. Boojho stands at A just on the side of a plane mirror as shown in Fig. 13.20. Can he see himself in the mirror? Also, can he see the image of objects situated at P, Q and R?

Answer:

Boojho cannot see himself in the mirror because of the short length of the mirror. He would be able to see objects at position P and Q but not at R.

Q17. (a) Find out the position of the image of an object situated at A in the plane mirror (Fig. 13.21).

(b) Can Paheli at B see this image?
(c) Can Boojho at C see this image?
(d) When Paheli moves from B to C, where does the image of A move?

1596052057375

Answer:

(a) The image of object A forms behind the mirror at a distance equal from the mirror equal to the distance between the object and the mirror.

1659590846820

(b) Yes. Paheli at B can see this image.

(c) Yes. Boojho at C can see this image.

(d) Image of the object at A will not move. It will remain in the same position when Paheli moves from B to C.

Subject matter experts from Careers360 have created a comprehensive class 8 science chapter 13 question answe, presented in easy-to-understand language and step-by-step. The solution includes a total of seventeen questions, consisting of MCQs, fill-in-the-blanks, and short answer types. Students can also download the class 8 chapter 13 science solution and use it as a reference to reinforce their understanding of the chapter. In addition, the solutions have been curated keeping in mind the latest curriculum and are aimed at helping students score well in their exams.

Class 8 Science Chapter 13 NCERT Solutions: Important Formulas and Diagrams

Law of Reflection:
The law of reflection says that when light hits a shiny surface, it bounces off at the same angle it came in. This means the angle of incidence (incoming ray) is equal to the angle of reflection (outgoing ray). The incident ray, the reflected ray, and the normal (an imaginary line at 90° to the surface) all lie on the same flat surface or plane. This rule works for all reflective surfaces, like mirrors.

Image Formation in a Plane Mirror:
When you look into a plane mirror, the image you see is virtual (it can’t be caught on a screen), upright (erect), and laterally inverted (left appears right and vice versa). The image appears to be the same distance behind the mirror as the object is in front of it, and it’s formed by light following the law of reflection.

1694834996949

1694834997297

Number of Images(n)

n=(360/θ)1

Human Eye

1694835024723

NCERT Solutions for Class 8 Science Chapter 13 Light: Points to Remember

  • Light travels in a straight line.

  • A mirror reflects light, allowing us to see images.

  • The laws of reflection state that:

    • The angle of incidence is equal to the angle of reflection.

    • The incident ray, reflected ray, and the normal all lie in the same plane.

  • Regular reflection happens on smooth surfaces like mirrors and gives clear images.

  • Diffuse reflection occurs on rough surfaces and does not form clear images.

  • Periscope works on the principle of reflection using two plane mirrors.

  • The image formed by a plane mirror is always virtual, erect, and of the same size as the object.

  • A kaleidoscope uses multiple reflections to create beautiful patterns.

  • The human eye helps us see objects by detecting the light reflected from them.

  • The eye has parts like the cornea, iris, pupil, lens, retina, and optic nerve.

  • We should take care of our eyes by reading in proper light and not watching screens for too long.

  • Blindness can be caused by diseases or injuries, and tools like Braille help visually impaired people read.

NCERT chapter 13 Light also explains the structure of the eye and its functioning. It also deals with how we can take care of our eyes. Question 10 in the NCERT Solutions for Class 8 Science chapter 13 Light shows a labelled structure of the human eye.

Light Class 8 Science Chapter 13- Topics

Class 8 Science Chapter 13 – Light covers all the important topics you need to understand how light helps us see the world around us. From laws of reflection to real-life applications, this chapter makes learning about light both fun and informative.

  • What makes Things Visible
  • Laws of Reflection
  • Regular and Diffused Reflection
  • Reflected Light Can be Reflected Again
  • Multiple Images
  • Sunlight — White or Coloured
  • What is inside Our Eyes?
  • Care of the Eyes
  • Visually Challenged Persons Can Read and Write
  • What is the Braille System?

Key Features of Light Class 8 Questions and Answers

Here are the key features of Class 8 Science Chapter 13 – Light Questions and Answers that make learning easier and exam preparation more effective.
These points highlight why this resource is perfect for understanding concepts and scoring well in CBSE exams.

  • Covers Everything You Need: These Light chapter solutions include all the important topics from your Class 8 Science book, so you won’t miss a thing.

  • Easy to Understand: The answers are explained in a clear and simple way, making tough topics easier to understand.

  • Different Types of Questions: From laws of reflection to how light behaves in real life – there’s a mix of questions to help you learn better.

  • Lots of Practice: You’ll find many practice questions to test what you’ve learned and get better at solving problems.

  • Helpful Diagrams: Wherever needed, diagrams and pictures are added to make learning even easier.

  • Relatable Examples: Real-life situations are used to help you connect the concepts to things you see every day.

  • Totally Free: You can access all these questions and answers for free – no need to pay or sign up!

All of these features make Chapter 13 – Light a great study tool to help you learn better and do well in your exams.

NCERT Chapter-Wise Solutions For Class 8th Science

The chapter-wise NCERT solutions for all the science chapters are listed here along with their links:

NCERT Solutions For Class 8: Subject-Wise

Also Check NCERT Books and NCERT Syllabus here:

Frequently Asked Questions (FAQs)

1. What is light?

Light is the smallest quantity of energy that can be transported  a photon an elementary particle without a real size that can be split, only created or destroyed    

2. What is reflection?

Reflection is when a wave hits a boundary and bounces back in the opposite direction with the same frequency, wavelength, and speed. The angle of incidence equals the angle of reflection.

3. What are the benefits of using the NCERT Solutions for Class 8 Science Chapter 13?

The benefits of using NCERT Solutions for Class 8 Science Chapter 13 include accurate and easy-to-understand answers, step-by-step solutions, and improvement in problem-solving skills. These solutions are helpful for exam preparation and save students' time and effort.

Articles

A block of mass 0.50 kg is moving with a speed of 2.00 ms-1 on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is

Option 1)

0.34\; J

Option 2)

0.16\; J

Option 3)

1.00\; J

Option 4)

0.67\; J

A person trying to lose weight by burning fat lifts a mass of 10 kg upto a height of 1 m 1000 times.  Assume that the potential energy lost each time he lowers the mass is dissipated.  How much fat will he use up considering the work done only when the weight is lifted up ?  Fat supplies 3.8×107 J of energy per kg which is converted to mechanical energy with a 20% efficiency rate.  Take g = 9.8 ms−2 :

Option 1)

2.45×10−3 kg

Option 2)

 6.45×10−3 kg

Option 3)

 9.89×10−3 kg

Option 4)

12.89×10−3 kg

 

An athlete in the olympic games covers a distance of 100 m in 10 s. His kinetic energy can be estimated to be in the range

Option 1)

2,000 \; J - 5,000\; J

Option 2)

200 \, \, J - 500 \, \, J

Option 3)

2\times 10^{5}J-3\times 10^{5}J

Option 4)

20,000 \, \, J - 50,000 \, \, J

A particle is projected at 600   to the horizontal with a kinetic energy K. The kinetic energy at the highest point

Option 1)

K/2\,

Option 2)

\; K\;

Option 3)

zero\;

Option 4)

K/4

In the reaction,

2Al_{(s)}+6HCL_{(aq)}\rightarrow 2Al^{3+}\, _{(aq)}+6Cl^{-}\, _{(aq)}+3H_{2(g)}

Option 1)

11.2\, L\, H_{2(g)}  at STP  is produced for every mole HCL_{(aq)}  consumed

Option 2)

6L\, HCl_{(aq)}  is consumed for ever 3L\, H_{2(g)}      produced

Option 3)

33.6 L\, H_{2(g)} is produced regardless of temperature and pressure for every mole Al that reacts

Option 4)

67.2\, L\, H_{2(g)} at STP is produced for every mole Al that reacts .

How many moles of magnesium phosphate, Mg_{3}(PO_{4})_{2} will contain 0.25 mole of oxygen atoms?

Option 1)

0.02

Option 2)

3.125 × 10-2

Option 3)

1.25 × 10-2

Option 4)

2.5 × 10-2

If we consider that 1/6, in place of 1/12, mass of carbon atom is taken to be the relative atomic mass unit, the mass of one mole of a substance will

Option 1)

decrease twice

Option 2)

increase two fold

Option 3)

remain unchanged

Option 4)

be a function of the molecular mass of the substance.

With increase of temperature, which of these changes?

Option 1)

Molality

Option 2)

Weight fraction of solute

Option 3)

Fraction of solute present in water

Option 4)

Mole fraction.

Number of atoms in 558.5 gram Fe (at. wt.of Fe = 55.85 g mol-1) is

Option 1)

twice that in 60 g carbon

Option 2)

6.023 × 1022

Option 3)

half that in 8 g He

Option 4)

558.5 × 6.023 × 1023

A pulley of radius 2 m is rotated about its axis by a force F = (20t - 5t2) newton (where t is measured in seconds) applied tangentially. If the moment of inertia of the pulley about its axis of rotation is 10 kg m2 , the number of rotations made by the pulley before its direction of motion if reversed, is

Option 1)

less than 3

Option 2)

more than 3 but less than 6

Option 3)

more than 6 but less than 9

Option 4)

more than 9

Back to top