NCERT Solutions for Class 8 Maths Chapter 3 Understanding Quadrilaterals

From floor tiles to windows, quadrilaterals are everywhere. Let’s understand how they rule your world. Geometry becomes easier when quadrilaterals are understood. Let’s start. A geometrical closed shape made by using 4 straight lines and having four connecting points is called a Quadrilateral. Our phone screen, windows, doors, and even a kite flying in the sky are all examples of quadrilaterals. The sum of the interior angles in a quadrilateral is always 360 degrees. These NCERT Solutions for Class 8 Maths, Chapter 3, Understanding Quadrilaterals, cover important concepts in a student-friendly manner, providing students with answers that offer conceptual clarity. It carries around 35% of geometry weightage and includes questions based on concepts of rectangles, squares, rhombuses, parallelograms, trapeziums, and kites. The main goal of these solutions is to provide students with a clear approach to help them solve the NCERT “Understanding Quadrilaterals” questions without confusion.

Each type of quadrilateral is a unique character in the grand play of geometry. These NCERT Solutions are created by the expert team at Careers360, keeping in mind the latest syllabus and pattern of CBSE 2025-26. Practising questions is important to score good marks in Mathematics. NCERT solutions for Class 8 Maths discussed all questions and answers of all chapters in detail, including Chapter 3, Understanding Quadrilaterals. For syllabus, notes, and PDF, refer to this link: NCERT.

Understanding Quadrilaterals Class 8 Questions And Answers PDF Free Download

Students who wish to access the NCERT solutions for class 8, chapter 3, Understanding Quadrilaterals, can click on the link below to download the entire solution in PDF.

NCERT Solutions for Class 8 Maths Chapter 3: Exercise Questions

Question 1 (a): Given here are some figures.

Classify each of them based on the following.

(a) Simple curve

Answer:

(a) Simple curve: The curve that does not cross itself and has only one curve.

Some simple curves are $:1,2,5,6,7$

Question 1 (b): Given here are some figures.

Classify each of them based on the following.

(b) Simple closed curve

Answer:

Simple closed curve: A simple curve that is closed by a line segment or curved line.

Some simple closed curves are $:1,2,5,6,7$

Question 1 (c): Given here are some figures.

Classify each of them based on the following.

(c) Polygon

Answer:

A normally closed curve made up of more than 4 line segments is called a polygon.

Some polygons are shown in Figures $1,2.$

Question 1 (d): Given here are some figures.

Classify each of them based on the following.

(d) Convex polygon

Answer:

(d) Convex polygon: Convex polygons are polygons having all interior angles less than ${180}^{\circ }$.

Convex polygon = 2.

Q1 (e) Given here are some figures.

Classify each of them based on the following.

(e) Concave polygon

Answer:

(e) Concave polygon: A Concave polygon has one or more interior angles greater than ${180}^{\circ }$.

Concave polygon = 1.

Question 2 (i): What is a regular polygon?
State the name of a regular polygon of 3 sides

Answer:

A regular polygon is a polygon that has equal sides and equal angles.

The name of a regular polygon of 3 sides is an equilateral triangle.

All sides of the equilateral triangle are equal, and the angles are also equal.

Each angle = ${60}^{\circ }$

Question 2 (ii): What is a regular polygon?
State the name of a regular polygon of 4 sides

Answer:

A regular polygon is a polygon that has equal sides and equal angles.

The name of a regular polygon of 4 sides is a square.

Square has all angles of ${90}^{\circ }$ and all sides are equal.

Question 2 (iii): What is a regular polygon?
State the name of a regular polygon of 6 sides

Answer:

A regular polygon is a polygon which have equal sides and equal angles.

The name of a regular polygon of 6 sides is a hexagon.

All angles of the hexagon are ${120}^{\circ }$ each.

Question 1 (a): Find $x$ in the following figures.

Answer:

The sum of all exterior angles of a polygon is ${360}^{\circ }.$

$x+{125}^{\circ }+{125}^{\circ }={360}^{\circ }.$

$x={360}^{\circ }-{250}^{\circ }.$

$x={110}^{\circ }.$

Question 1 (b): Find $x$ in the following figures.

Answer:

The sum of all exterior angles of a polygon is ${360}^{\circ }$

$x+{90}^{\circ }+{60}^{\circ }+{90}^{\circ }+{70}^{\circ }={360}^{\circ }$

$x={360}^{\circ }-{310}^{\circ }$

$x={50}^{\circ }$

Question 2 (i): Find the measure of each exterior angle of a regular polygon of 9 sides.

Answer:

A regular polygon of 9 sides has all sides, interior angles, and exterior angles equal.

Sum of exterior angles of a polygon = ${360}^{\circ }$

Let the interior angle be A.

Sum of exterior angles of 9 sided polygon = $9\times A=$ ${360}^{\circ }$

Exterior angles of 9 sided polygon $=A={360}^{\circ }÷9$

$A={40}^{\circ }$

Hence, the measure of each exterior angle of a regular polygon of 9 sides is ${40}^{\circ }$

Question 2 (ii): Find the measure of each exterior angle of a regular polygon of 15 sides.

Answer:

A regular polygon of 15 sides has all sides, interior angles, and exterior angles equal.

Sum of exterior angles of a polygon = ${360}^{\circ }$

Let the interior angle be A.

Sum of exterior angles of 15 sided polygon = $15\times A=$ ${360}^{\circ }$

Exterior angles of 15 sided polygon $=A={360}^{\circ }÷15$

$A={24}^{\circ }$

Hence, the measure of each exterior angle of a regular polygon of 15 sides is ${24}^{\circ }$

Question 3: How many sides does a regular polygon have if the measure of an exterior angle is 24°?

Answer:

The measure of an exterior angle is 24°

A regular polygon has all exterior angles equal.

Sum of exterior angles of a polygon = ${360}^{\circ }$

Let the number of sides be X.

Sum of exterior angles of a polygon = $X\times {24}^{\circ }=$ ${360}^{\circ }$

Exterior angles of 15 sided polygon $=X={360}^{\circ }÷{24}^{\circ }$

$X=15$

Hence, a $15$ sided regular polygon has a measure of an exterior angle of 24°

Question 4: Hoof w many sides does a regular polygon have if each of its interior angles is 165°?

Answer:

The measure of each interior angle is 165°

So, measure of each exterior angle = 180°-165° = 15°

Regular polygons have regular exterior angles equal.

Let the number of sides the the s of the polygon = n

The sum of the Exterior angles of a polygon = ${360}^{\circ }$

$\left(n\right)\times {15}^{\circ }={360}^{\circ }$

$n=24$

Hence, a regular polygon having each of its interior angles is 165° has 24 sides.

Question 5 (a): Is it possible to have a regular polygon with a measure of each exterior angle of 22°?

Answer:

The measure of an exterior angle is 22°

A regular polygon has all exterior angles equal.

Sum of exterior angles of a polygon = ${360}^{\circ }$

Let the number of sides be X.

Sum of exterior angles of a polygon = $X\times {22}^{\circ }=$ ${360}^{\circ }$

Exterior angles of 15 sided polygon $=X={360}^{\circ }÷{22}^{\circ }$

$X=16.36$

Hence, the side of a polygon should be an integer but as shown ,above, the side is not an integer. So,it is not poss ible to have a regular polygon with the measure of each exterior angle as 22 o .

Question 5 (b): Can it be an interior angle of a regular polygon? Why?

Answer:

The measure of an interior angle is 22°

A regular polygon has all interior angles equal.

Let the number of sides and the number of interior angles be n.

Sum of interior angles of a polygon = $(n-2)\times {180}^{\circ }$

Sum of interior angles of a polygon = $(n-2)\times {180}^{\circ }$ = $\left(n\right)\times {22}^{\circ }$

$\left(n\right)\times {180}^{\circ }-\left(2\right)\times {180}^{\circ }=\left(n\right)\times {22}^{\circ }$

$\left(n\right)\times {180}^{\circ }-\left(n\right)\times {22}^{\circ }={360}^{\circ }$

$\left(n\right)\times {158}^{\circ }={360}^{\circ }$

$n=2.28$

The number of sides of a polygon should be an integer, but it is not an integer. So, it cannot be a regular polygon with an interior angle of 22 o

Question 6 (a): What is the minimum interior angle possible for a regular polygon? Why?

Answer:

Consider a polygon with the lowest number of sides, i.e., 3.

Sum of interior angles of 3 sided polygon = $(3-2)\times {180}^{\circ }={180}^{\circ }$

Interior angles of a regular polygon are equal = A.

$\therefore$ $A+A+A={180}^{\circ }$

$3\times A={180}^{\circ }$

$A={60}^{\circ }$

Hence, the minimum interior angle possible for a regular polygon is ${60}^{\circ }$.

Question 6 (b): What is the maximum exterior angle possible for a regular polygon?

Answer:

Let there be a polygon with the minimum number of sides, i.e., 3.

The exterior angles s an equilateral triangle have a maximum measure.

Sum of exterior angles of polygon = ${360}^{\circ }$

Let the exterior angle be A.

$\therefore$ $A+A+A={360}^{\circ }$

$3A={360}^{\circ }$

$A={120}^{\circ }$

Hence, the maximum exterior angle possible for a regular polygon is ${120}^{\circ }$.

Question 1 (i): Given a parallelogram ABCD. Complete each statement along with the definition or property used.

$AD=$ ......

Answer:

In a parallelogram, opposite sides are equal in length.

Hence,

$AD=BC$

Question 1 (ii): Given a parallelogram ABCD. Complete each statement along with the definition or property used.

$\mathrm{\angle }DCB=$ ......

Answer:

In a parallelogram, opposite angles are equal.

(ii) $\mathrm{\angle }DCB=$ $\mathrm{\angle }BAD.$

Question 1 (iii): Given a parallelogram ABCD. Complete each statement along with the definition or property used.

$OC=$ ......

Answer:

In a parallelogram, both diagonals bisect each other.

$OC=$ $OA$

Question 1 (iv): Given a parallelogram ABCD. Complete each statement along with the definition or property used.

$m\mathrm{\angle }DAB+m\mathrm{\angle }CDA=$ .....

Answer:

In a parallelogram, adjacent angles are supplementary to each other.

(iv) $m\mathrm{\angle }DAB+m\mathrm{\angle }CDA=$ ${180}^{\circ }$

Question 2 (i): Consider the following parallelograms. Find the values of the unknowns $x,y,z$.

Answer:

In a parallelogram, adjacent angles are supplementary to each other.

$\mathrm{\angle }B+\mathrm{\angle }C={180}^{\circ }$

${100}^{\circ }+x={180}^{\circ }$

$x={80}^{\circ }$

Opposite angles are equal.

Hence, z = $x={80}^{\circ }$

and y = 100

Question 2 (ii): Consider the following parallelograms. Find the values of the unknowns $x,y,z$.

Answer:

${50}^{\circ }+x={180}^{\circ }$ ( Two adjacent angles are supplementary to each other)

$x={130}^{\circ }$

x=y= ${130}^{\circ }$ (opposite angles are equal)

z=x= ${130}^{\circ }$ ( corresponding angles are equal)

Question 2 (iii): Consider the following parallelograms. Find the values of the unknowns $x, y, z.

Answer:

x= ${90}^{\circ }$ (vertically opposite angles)

$x+y+{30}^{\circ }={180}^{\circ }$ (sum of angles of a triangle is ${180}^{\circ }$ )

${90}^{\circ }+y+{30}^{\circ }={180}^{\circ }$

$y={60}^{\circ }$

y=z= ${60}^{\circ }$ (alternate interior angles)

Question 2 (iv): Consider the following parallelograms. Find the values of the unknowns $x,y,z$.

Answer:

$x+{80}^{\circ }={180}^{\circ }$ (adjacent angles are supplementary)

$x={100}^{\circ }$

y = ${80}^{\circ }$ ( opposite angles are equal)

z= ${80}^{\circ }$ (corresponding angles are equal)

Question 2 (v): Consider the following parallelograms. Find the values of the unknowns $x,y,z$.

Answer:

y = ${112}^{\circ }$ (opposite angles are equal)

$z+{40}^{\circ }+{112}^{\circ }={180}^{\circ }$ (adjacent angles are supplementary)

$z={180}^{\circ }-{152}^{\circ }$

$z={28}^{\circ }$

x = z = ${28}^{\circ }$ (alternate angles are equal)

Question 3 (i): Can a quadrilateral ABCD be a parallelogram if $\mathrm{\angle }D+\mathrm{\angle }B={180}^{\circ }$

Answer:

(i) $\mathrm{\angle }D+\mathrm{\angle }B={180}^{\circ }$

Opposite angles should be equal, and adjacent angles should be supplementary to each other.

$\mathrm{\angle }B,\mathrm{\angle }D$ are opposite angles.

Hence, a quadrilateral ABCD can be a parallelogram, but it is not confirmed.

Question 3 (ii): Can a quadrilateral ABCD be a parallelogram if $AB=DC=8cm,AD=4cm$ and $BC=4.4cm$ ?

Answer:

Opposite sides of a parallelogram are equal in length.

Since $AD=4cm$ and $BC=4.4cm$ are opposite sides and have different lengths.

No, it is not a parallelogram.

Question 3 (iii): Can a quadrilateral ABCD be a parallelogram if $\mathrm{\angle }A={70}^{\circ }$ and $\mathrm{\angle }C={65}^{\circ }$ ?

Answer:

Opposite angles of a parallelogram are equal

Since here $\mathrm{\angle }A={70}^{\circ }$ and $\mathrm{\angle }C={65}^{\circ }$ are different.

So, it is not a parallelogram.

Question 4: Draw a rough figure of a quadrilateral that is not a parallelogram but has exactly two opposite angles.
of equal measure.

Answer:

The above-shown figure shows two opposite angles are equal. $\mathrm{\angle }B=\mathrm{\angle }D$ .

But, it's not a parallelogram because the other two angles are different, i.e., $\angle A\neq \angle C.

Question 5: The measures of two adjacent angles of a parallelogram are in the ratio 3 : 2. Find the measure of each of the angles of the parallelogram.

Answer:

The measures of two adjacent angles of a parallelogram are in the ratio 2.

The sum of the adjacent angles is ${180}^{\circ }$.

$\therefore$ $3\times x+2\times x={180}^{\circ }$

$5\times x={180}^{\circ }$

$x={36}^{\circ }$

Hence, angles are $2\times {36}^{\circ }={72}^{\circ }$ and $3\times {36}^{\circ }={108}^{\circ }$.

Let there be a parallelogram ABCD, then, $\mathrm{\angle }A=\mathrm{\angle }C={108}^{\circ }$ and $\mathrm{\angle }B=\mathrm{\angle }D={72}^{\circ }$. (Opposite angles are equal.)

Question 6: Two adjacent angles of a parallelogram have equal measure. Find the measure of each of the angles of the parallelogram.

Answer:

Given: Two adjacent angles of a parallelogram have equal measure = $\mathrm{\angle }A=\mathrm{\angle }B$.

$\mathrm{\angle }A+\mathrm{\angle }B={180}^{\circ }$ ( adjacent angles of a parallelogram are supplementary)

$2\times \mathrm{\angle }A={180}^{\circ }$

$\mathrm{\angle }A={90}^{\circ }$

$\therefore$ $\mathrm{\angle }A=\mathrm{\angle }B={90}^{\circ }$

$\mathrm{\angle }A=\mathrm{\angle }C={90}^{\circ }$ and $\mathrm{\angle }B=\mathrm{\angle }D={90}^{\circ }$ ( Opposite angles of a parallelogram are equal)

Hence, $\mathrm{\angle }A=\mathrm{\angle }B=\mathrm{\angle }C=\mathrm{\angle }D={90}^{\circ }$

Question 7: The adjacent figure HOPE is a parallelogram. Find the angle measures $x,y$, and $z$. State the properties you use to find them.

Answer:

The adjacent figure HOPE is a parallelogram.

$\mathrm{\angle }HOP+{70}^{\circ }={180}^{\circ }$ (linear pairs)

$\mathrm{\angle }HOP={110}^{\circ }$

$x=\mathrm{\angle }HOP={110}^{\circ }$ (opposite angles of a parallelogram are equal)

$\mathrm{\angle }HOP+\mathrm{\angle }EHO={180}^{\circ }$ ( adjacent angles are supplementary )

${110}^{\circ }+({40}^{\circ }+z)={180}^{\circ }$

$z={180}^{\circ }-{150}^{\circ }$

$z={30}^{\circ }$

y= ${40}^{\circ }$ (Alternate interior angles are equal)

Question 8 (i): The following figures, GUNS and RUNS, are parallelograms. Find $x$ and $y$ . (Lengths are in cm)

Answer:

GUNS is a parallelogram, so opposite sides are equal in length

$SG=UN$

$3\times x=18$

$x=18÷3$

$x=6$

$UG=NS$

$3\times Y-1=26$

$3\times Y=27$

$Y=9$

Hence, $x=6$ cm and $Y=9$ cm.

Question 8 (ii): The following figures, GUNS and RUNS, are parallelograms. Find $x$ and $y$ . (Lengths are in cm)

Answer:

Diagonals of a parallelogram intersect each other.

$y+7=20$

$y=20-7$

$y=13$

$x+y=16$

$x=16-13$

$x=3$

Hence, $x=3$ cm and $y=13$ cm.

Question 9: In the above figure, both RISK and CLUE are parallelograms. Find the value of $x$.

Answer:

$\mathrm{\angle }SKR+\mathrm{\angle }KSI={180}^{\circ }$ ( adjacent angles are supplementary)

$\mathrm{\angle }KSI={180}^{\circ }-{120}^{\circ }$

$\mathrm{\angle }KSI={60}^{\circ }$

$\mathrm{\angle }CLU=\mathrm{\angle }UEC={70}^{\circ }$ (opposite angles are equal)

$x+\mathrm{\angle }UEC+\mathrm{\angle }KSI={180}^{\circ }$ (sum of angles of a triangle is ${180}^{\circ }$ )

$x+{70}^{\circ }+{60}^{\circ }={180}^{\circ }$

$x={180}^{\circ }-{130}^{\circ }$

$x={50}^{\circ }$

Question 10: Explain how this figure is a trapezium. Which of its two sides is parallel? (Fig. 3.26)

Answer:

Given, $\mathrm{\angle }M+\mathrm{\angle }L={100}^{\circ }+{80}^{\circ }$ = ${180}^{\circ }$ .

A transverse line is intersecting two lines such that the sum of angles on the same side of the transversal line is ${180}^{\circ }$ .

And hence, lines KL and MN are parallel to each other.

Quadrilateral KLMN has a pair of parallel lines, so it is a trapezium.

Question 11: Find $m\mathrm{\angle }C$ in Fig 3.33 if $\overline{AB}||\overline{DC}$ .

Answer:

Given , $\overline{AB}||\overline{DC}$

$\mathrm{\angle }B+\mathrm{\angle }C={180}^{\circ }$ (Angles on same side of transversal)

${120}^{\circ }+\mathrm{\angle }C={180}^{\circ }$

$\mathrm{\angle }C={180}^{\circ }-{120}^{\circ }$

$\mathrm{\angle }C={60}^{\circ }$

Hence, $m\mathrm{\angle }C={60}^{\circ }$.

Question 12: Find the measure of $\mathrm{\angle }P$ and $\mathrm{\angle }S$ if $\overline{SP}||\overline{RQ}$ in Fig 3.34.
(If you find $m\mathrm{\angle }R$, is there more than one method to find $m\mathrm{\angle }P$ ?)

Answer:

Given, $\overline{SP}||\overline{RQ}$

$\mathrm{\angle }P+\mathrm{\angle }Q={180}^{\circ }$ (angles on the same side of the transversal)

$\mathrm{\angle }P={180}^{\circ }-{130}^{\circ }$

$\mathrm{\angle }P={50}^{\circ }$

$\mathrm{\angle }R+\mathrm{\angle }S={180}^{\circ }$ (angles on the same side of the transversal)

$\mathrm{\angle }S={180}^{\circ }-{90}^{\circ }$

$\mathrm{\angle }S={90}^{\circ }$

Yes, to find $m\mathrm{\angle }P$, there is more than one method.

PQRS is a quadrilateral, so the sum of all angles is 360

$\mathrm{\angle }P+\mathrm{\angle }Q+\mathrm{\angle }R+\mathrm{\angle }S={360}^{\circ }$

and we know $\mathrm{\angle }Q,\mathrm{\angle }R,\mathrm{\angle }S$

so put values of $\mathrm{\angle }Q,\mathrm{\angle }R,\mathrm{\angle }S$ and we get a measurement of $\mathrm{\angle }P$

Question 1 (a): State whether True or False. All rectangles are squares

Answer:

(a) False, all squares are rectangles, but all rectangles can be squares.

Question 1 (b): State whether True or False. All rhombuses are parallelograms

Answer:

True. The opposite sides of the rhombus are parallel and equal.

Question 1 (c): State whether True or False. All squares are rhombuses and also rectangles.

Answer:

True. All squares are rhombuses because rhombuses have opposite sides parallel and equal, and same square has.

Also, all squares are rectangles because they have all interior angles of ${90}^{\circ }$.

Question 1 (d): State whether True or False. Not all squares are not parallelograms.

Answer:

False.

All squares have their opposite sides equal and parallel. Hence, they are parallelograms.

Question 1 (e): State whether True or False. All kites are rhombuses.

Answer:

False,

Kites do not have all sides equal, so they are not rhombuses.

Question 1 (f): State whether True or False. All rhombuses are kites.

Answer:

True, all rhombuses are kites because they have two adjacent sides that are equal.

Question 1 (g): State whether True or False. All parallelograms are trapeziums.

Answer:

True, all parallelograms are trapeziums because they have a pair of parallel sides.

Question 1 (h): State whether True or False. All squares are trapeziums.

Answer:

True, all squares are trapeziums because all squares have pairs of parallel sides.

Question 2 (a): Identify all the quadrilaterals that have four sides of equal length.

Answer:

The quadrilateral having four sides of equal length is are square and a rhombus.

Question 2 (b): Identify all the quadrilaterals that have four right angles

Answer:

All the quadrilaterals that have four right angles are rectangles and squares

Question 3 (i): Explain how a square is a quadrilateral

Answer:

A square is a quadrilateral because a square has four sides.

Question 3 (ii): Explain how a square is a parallelogram

Answer:

A square is a parallelogram because the square has opposite sides are parallel to each other.

Question 3 (iii): Explain how a square is a rhombus

Answer:

A square is a rhombus because a square has four sides equal.

Question 3 (iv): Explain how a square is a rectangle

Answer:

A square is a rectangle since it has all interior angles of ${90}^{\circ }$.

Question 4 (i): Name the quadrilaterals whose diagonals bisect each other

Answer:

The quadrilaterals whose diagonals bisect each other are a square, a rectangle, a parallelogram, and a rhombus.

Question 4 (ii): Name the quadrilaterals whose diagonals are perpendicular bisectors of each other.

Answer:

The quadrilaterals whose diagonals are perpendicular bisectors of each other are a rhombus and a square.

Question 4 (iii): Name the quadrilaterals whose diagonals are equal

Answer:

The quadrilaterals whose diagonals are equal are squares and rectangles.

Question 5: Explain why a rectangle is a convex quadrilateral.

Answer:

A rectangle is a convex quadrilateral because it has two diagonals and both lie in the interior of the rectangle.

Question 6: ABC is a right-angled triangle, and O is the midpoint of the side opposite to the right angle. Explain why O is equidistant from A, B, and C. (The dotted lines are drawn additionally to help you.)

Answer:

Draw line AD and DC such that $AB\parallel CD$ and $AD\parallel BC$.

$AD=BC$ and $AB=CD$

ABCD is a rectangle as it has opposite sides equal and parallel.

All angles of the rectangle are ${90}^{\circ }$, and a rectangle has two diagonals equal and bisect each other.

Hence, AO = BO = CO = DO

$\therefore$ O is equidistant from A, B, C, D.

Understanding Quadrilaterals Class 8 Solutions - Topics

The topics discussed in the NCERT Solutions for class 8, chapter 3, Understanding Quadrilaterals, are:

• Polygons
• Sum of the Measures of the Exterior Angles of a Polygon
• Kinds of Quadrilaterals
• Some Special Parallelograms

Understanding Quadrilaterals Class 8 Solutions - Important Formulae

Polygon

A closed two-dimensional figure composed of a finite number of straight line segments connected end to end is called a polygon. These line segments are called the sides of a polygon. The point where two line segments meet is called a corner or a vertex.

Polygons can be regular or irregular.

Triangles, squares, and rectangles are some of the examples of polygon .

• Angle Sum Property for Quadrilaterals: The sum of all angles of a quadrilateral is 360°.
• Sum of the Measures of Exterior Angles of a Polygon: Regardless of the number of sides in a polygon, the total measure of the exterior angles equals 360 degrees.

Categories of Quadrilaterals

Quadrilaterals are an important part of geometry, having four sides. There are some important quadrilaterals, i.e. squares, rectangles, trapezium, rhombus, and parallelograms. A quadrilateral also has four angles, four vertices, 12 edges, and two diagonals.

There are several formulas in geometry to calculate the area and parameters of the quadrilaterals.

NCERT Solutions for Class 8 Maths: Chapter Wise

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NCERT Solutions for Class 8 - Subject Wise

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• NCERT Solutions for Class 8 Maths
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NCERT Books and NCERT Syllabus

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• NCERT Books Class 8 Maths
• NCERT Syllabus Class 8 Maths
• NCERT Books Class 8
• NCERT Syllabus Class 8