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**Polynomials Class 9 Questions And Answers **are provided here.** **A polynomial is an algebraic expression which consists of variables and coefficient with operations such as additions, subtraction, multiplication, and non-negative exponents. In this particular NCERT syllabus Class 9 chapter, you will learn the operations of two or more polynomials. NCERT solutions which are prepared by subjects expert at Careers360 keeping in mind of latest CBSE syllabus 2023, are there to help you while solving the problems related to this NCERT book Class 9 Maths chapter. Polynomials Class 9, introduces a lot of important concepts that will be helpful for those students who are targeting exams like JEE, CAT, SSC, etc.

This Story also Contains

- NCERT Solutions for Class 9 Maths Chapter 2 Polynomials
- Polynomials Class 9 Questions And Answers PDF Free Download
- Polynomials Class 9 Solutions - Important Formulae
- Polynomials Class 9 NCERT Solutions (Intext Questions and Exercise)
- More About NCERT Solutions For Class 9 Maths Chapter 2 Polynomials
- NCERT Solutions for Class 9 Maths Chapter Wise
- Key Features of NCERT Solutions For chapter 2 maths class 9
- NCERT Solutions for Class 9 Subject Wise
- NCERT Books and NCERT Syllabus

This chapter talk about Polynomials in One Variable, Zeroes of a Polynomial, Remainder Theorem, Factorisation of Polynomials, and Algebraic Identities. NCERT solutions for Class 9 Maths chapter 2 Polynomials can also be used while doing homework. It can be a good tool for the Class 9 students as it is designed in such a manner so that a student can fetch the maximum marks available for the particular question. Here students will get NCERT solutions for Class 9 also.

**Also Read|**

- NCERT Exemplar Solutions For Class 9 Maths Chapter 2 Polynomials
- Polynomial Class 9 Maths Chapter 2 Notes

The general form of a polynomial is: p(x) = a_{n}x^{n} + a_{n-1}x^{n-1} + … + a_{2}x^{2} + a_{1}x + a_{0}

where a_{0}, a_{1}, a_{2}, …. an are constants, and a_{n} ≠ 0.

Every one-variable linear polynomial will contain a unique zero, which is a real number that is a zero of the zero polynomial, and a non-zero constant polynomial that does not have any zeros.

>> Remainder Theorem: If p(x) has a degree greater than or equal to 1, and you divide p(x) by the linear polynomial (x - a), the remainder will be p(a).

>> Factor Theorem: The linear polynomial (x - a) will be a factor of the polynomial p(x) whenever p(a) = 0. Similarly, if (x - a) is a factor of p(x), then p(a) = 0.

Free download **NCERT Solutions for Class 9 Maths Chapter 2 Polynomials **for CBSE Exam.

** NCERT Polynomials class 9 solutions Exercise: 2.1 **

** Q1 (i) ** Is the following expression polynomial in one variable? State reasons for your answer.

** Answer: **

** YES **

Given polynomial has only one variable which is ** x **

** Q1 (ii) ** Is the following expression polynomial in one variable? State reasons for your answer.

** Answer: **

** YES **

Given polynomial has only one variable which is ** y **

** Q1 (iii) ** Is the following expression polynomial in one variable? State reasons for your answer.

** Answer: **

** NO **

Because we can observe that the exponent of variable t in term is which is not a whole number.

Therefore this expression is not a polynomial.

** Q1 (iv) ** Is the following expression polynomial in one variable? State reasons for your answer.

** Answer: **

** NO **

Because we can observe that the exponent of variable y in term is which is not a whole number. Therefore this expression is not a polynomial.

** Q1 (v) ** Is the following expression polynomial in one variable? State reasons for your answer.

** Answer: **

** NO **

Because in the given polynomial there are 3 variables which are ** x, y, t. ** That's why this is polynomial in three variable not in one variable.

** Q3 ** Give one example each of a binomial of degree 35, and of a monomial of degree 100.

** Answer: **

Degree of a polynomial is the highest power of the variable in the polynomial.

In binomial, there are two terms

Therefore, binomial of degree 35 is

Eg:-

In monomial, there is only one term in it.

Therefore, monomial of degree 100 can be written as

** Q4 (i) ** Write the degree the following polynomial:

** Answer: **

Degree of a polynomial is the highest power of the variable in the polynomial.

Therefore, the degree of polynomial is ** 3 ** .

** Q4 (ii) ** Write the degree the following polynomial:

** Answer: **

Degree of a polynomial is the highest power of the variable in the polynomial.

Therefore, the degree of polynomial is ** 2. **

** Q4 (iii) ** Write the degree the following polynomial:

** Answer: **

Degree of a polynomial is the highest power of the variable in the polynomial.

Therefore, the degree of polynomial is ** 1 **

** Q4 (iv) ** Write the degree the following polynomial: 3

** Answer: **

Degree of a polynomial is the highest power of the variable in the polynomial.

In this case, only a constant value 3 is there and the degree of a constant polynomial is always ** 0. **

** Q5 (i) ** Classify the following as linear, quadratic and cubic polynomial:

** Answer: **

Linear polynomial, quadratic polynomial, and cubic polynomial has its degrees as 1, 2, and 3 respectively

Given polynomial is with degree 2

Therefore, it is a quadratic polynomial.

** Q5 (ii) ** Classify the following as linear, quadratic and cubic polynomial:

** Answer: **

Linear polynomial, quadratic polynomial, and cubic polynomial has its degrees as 1, 2, and 3 respectively

Given polynomial is with degree 3

Therefore, it is a cubic polynomial

** Q5 (iii) ** Classify the following as linear, quadratic and cubic polynomial:

** Answer: **

Linear polynomial, quadratic polynomial, and cubic polynomial has its degrees as 1, 2, and 3 respectively

Given polynomial is with degree 2

Therefore, it is quadratic polynomial.

** Q5 (iv) ** Classify the following as linear, quadratic and cubic polynomial:

** Answer: **

Linear polynomial, quadratic polynomial, and cubic polynomial has its degrees as 1, 2, and 3 respectively

Given polynomial is with degree 1

Therefore, it is linear polynomial

** Q5 (v) ** Classify the following as linear, quadratic and cubic polynomial:

** Answer: **

Linear polynomial, quadratic polynomial, and cubic polynomial has its degrees as 1, 2, and 3 respectively

Given polynomial is with degree 1

Therefore, it is linear polynomial

** Q5 (vi) ** Classify the following as linear, quadratic and cubic polynomial:

** Answer: **

Linear polynomial, quadratic polynomial, and cubic polynomial has its degrees as 1, 2, and 3 respectively

Given polynomial is with degree 2

Therefore, it is quadratic polynomial

** Q5 (vii) ** Classify the following as linear, quadratic and cubic polynomial:

** Answer: **

Linear polynomial, quadratic polynomial, and cubic polynomial has its degrees as 1, 2, and 3 respectively

Given polynomial is with degree 3

Therefore, it is a cubic polynomial

** Polynomials class 9 NCERT solutions Exercise: 2.2 **

** Q1 (i) ** Find the value of the polynomial at

** Answer: **

Given polynomial is

Now, at value is

Therefore, value of polynomial at x = 0 is ** 3 **

** Q1 (ii) ** Find the value of the polynomial at

** Answer: **

Given polynomial is

Now, at value is

Therefore, value of polynomial at x = -1 is ** -6 **

** Q1 (iii) ** Find the value of the polynomial at

** Answer: **

Given polynomial is

Now, at value is

Therefore, value of polynomial at x = 2 is ** -3 **

** Q2 (i) ** Find * p(0) * , * p(1) * and * p(2) * for each of the following polynomials:

** Answer: **

Given polynomial is

Now,

Therefore, values of * p(0) * , * p(1) * and * p(2) are 1 , 1 and 3 respectively * .

** Q2 (ii) ** Find * p(0) * , * p(1) * and * p(2) * for each of the following polynomials:

** Answer: **

Given polynomial is

Now,

Therefore, values of * p(0) * , * p(1) * and * p(2) are 2 , 4 and 4 respectively *

** Q2 (iii) ** Find p(0), p(1) and p(2) for each of the following polynomials:

** Answer: **

Given polynomial is

Now,

Therefore, values of * p(0) * , * p(1) * and * p(2) are 0 , 1 and 8 respectively *

** Q2 (iv) ** Find p(0), p(1) and p(2) for each of the following polynomials:

** Answer: **

Given polynomial is

Now,

Therefore, values of * p(0) * , * p(1) * and * p(2) are -1 , 0 and 3 respectively *

** Q3 (i) ** Verify whether the following are zeroes of the polynomial, indicated against it.

** Answer: **

Given polynomial is

Now, at it's value is

Therefore, yes is a zero of polynomial

** Q3 (ii) ** Verify whether the following are zeroes of the polynomial, indicated against it.

** Answer: **

Given polynomial is

Now, at it's value is

Therefore, no is not a zero of polynomial

** Q3 (iii) ** Verify whether the following are zeroes of the polynomial, indicated against it.

** Answer: **

Given polynomial is

Now, at ** x = 1 ** it's value is

And at ** x = -1 **

Therefore, yes x = 1 , -1 are zeros of polynomial

** Q3 (iv) ** Verify whether the following are zeroes of the polynomial, indicated against it.

** Answer: **

Given polynomial is

Now, at ** x = 2 ** it's value is

And at ** x = -1 **

Therefore, yes x = 2 , -1 are zeros of polynomial

** Q3 (v) ** Verify whether the following are zeroes of the polynomial, indicated against it.

** Answer: **

Given polynomial is

Now, at ** x = 0 ** it's value is

Therefore, yes ** x = 0 ** is a zeros of polynomial

** Q3 (vi) ** Verify whether the following are zeroes of the polynomial, indicated against it.

** Answer: **

Given polynomial is

Now, at it's value is

Therefore, yes is a zeros of polynomial

** Q3 (vii) ** Verify whether the following are zeroes of the polynomial, indicated against it.

** Answer: **

Given polynomial is

Now, at it's value is

And at

Therefore, is a zeros of polynomial .

whereas is not a zeros of polynomial

** Q3 (viii) ** Verify whether the following are zeroes of the polynomial, indicated against it.

** Answer: **

Given polynomial is

Now, at it's value is

Therefore, is not a zeros of polynomial

** Q4 (i) ** Find the zero of the polynomial in each of the following cases:

** Answer: **

Given polynomial is

Zero of a polynomial is that value of the variable at which the value of the polynomial is obtained as 0.

Now,

Therefore, ** x = -5 ** is the zero of polynomial

** Q4 (ii) ** Find the zero of the polynomial in each of the following cases:

** Answer: **

Given polynomial is

Zero of a polynomial is that value of the variable at which the value of the polynomial is obtained as 0.

Now,

Therefore, ** x = 5 ** is a zero of polynomial

** Q4 (iii) ** Find the zero of the polynomial in each of the following cases:

** Answer: **

Given polynomial is

Zero of a polynomial is that value of the variable at which the value of the polynomial is obtained as 0.

Now,

Therefore, ** ** is a zero of polynomial

** Q4 (iv) ** Find the zero of the polynomial in each of the following cases:

** Answer: **

Given polynomial is

Zero of a polynomial is that value of the variable at which the value of the polynomial is obtained as 0.

Now,

Therefore, ** ** is a zero of polynomial

** Q4 (v) ** Find the zero of the polynomial in each of the following cases:

** Answer: **

Given polynomial is

Zero of a polynomial is that value of the variable at which the value of the polynomial is obtained as 0.

Now,

Therefore, ** ** is a zero of polynomial

** Q4 (vi) ** Find the zero of the polynomial in each of the following cases:

** Answer: **

Zero of a polynomial is that value of the variable at which the value of the polynomial is obtained as 0.

Now,

Therefore, ** ** is a zero of polynomial

** Q4 (vii) ** Find the zero of the polynomial in each of the following cases: are real numbers

** Answer: **

Zero of a polynomial is that value of the variable at which the value of the polynomial is obtained as 0.

Now,

Therefore, ** ** is a zero of polynomial

**Class 9 maths chapter 2 NCERT solutions Exercise: 2.3 **

** Q1 (i) ** Find the remainder when is divided by

** Answer: **

When we divide by .

By long division method, we will get

Therefore, remainder is .

** Q1 (ii) ** Find the remainder when is divided by

** Answer: **

When we divide by .

By long division method, we will get

Therefore, the remainder is

** Q1 (iii) ** Find the remainder when is divided by

** Answer: **

When we divide by .

By long division method, we will get

Therefore, remainder is .

** Q1 (iv) ** Find the remainder when is divided by

** Answer: **

When we divide by .

By long division method, we will get

Therefore, the remainder is

** Q1 (v) ** Find the remainder when is divided by

** Answer: **

When we divide by .

By long division method, we will get

Therefore, the remainder is

** Q2 ** Find the remainder when is divided by .

** Answer: **

When we divide by .

By long division method, we will get

Therefore, remainder is

** Q3 ** Check whether is a factor of

** Answer: **

When we divide by .

We can also write as

By long division method, we will get

Since, remainder is not equal to 0

Therefore, is not a factor of

** Class 9 polynomials NCERT solutions Exercise: 2.4 **

** Q1 (i) ** Determine which of the following polynomials has a factor :

** Answer: **

Zero of polynomial is ** -1. **

If is a factor of polynomial

Then, must be equal to zero

Now,

Therefore, is a factor of polynomial

** Q1 (ii) ** Determine which of the following polynomials has a factor :

** Answer: **

Zero of polynomial is ** -1. **

If is a factor of polynomial

Then, must be equal to zero

Now,

Therefore, is not a factor of polynomial

** Q1 (iii) ** Determine which of the following polynomials has a factor :

** Answer: **

Zero of polynomial is ** -1. **

If is a factor of polynomial

Then, must be equal to zero

Now,

Therefore, is not a factor of polynomial

** Q1 (iv) ** Determine which of the following polynomials has a factor :

** Answer: **

Zero of polynomial is ** -1. **

If is a factor of polynomial

Then, must be equal to zero

Now,

Therefore, is not a factor of polynomial

** Q2 (i) ** Use the Factor Theorem to determine whether g(x) is a factor of p(x) in the following case:

** Answer: **

Zero of polynomial is

If is factor of polynomial

Then, must be equal to zero

Now,

Therefore, is factor of polynomial

** Q2 (ii) ** Use the Factor Theorem to determine whether g(x) is a factor of p(x) in the following case:

** Answer: **

Zero of polynomial is

If is factor of polynomial

Then, must be equal to zero

Now,

Therefore, is not a factor of polynomial

** Q2 (iii) ** Use the Factor Theorem to determine whether g(x) is a factor of p(x) in the following case:

** Answer: **

Zero of polynomial is

If is factor of polynomial

Then, must be equal to zero

Now,

Therefore, is a factor of polynomial

** Q3 (i) ** Find the value of * k * , if is a factor of p(x) in the following case:

** Answer: **

Zero of polynomial is

If is factor of polynomial

Then, must be equal to zero

Now,

Therefore, value of k is

** Q3 (ii) ** Find the value of * k * , if is a factor of p(x) in the following case:

** Answer: **

Zero of the polynomial is

If is factor of polynomial

Then, must be equal to zero

Now,

Therefore, value of k is

** Q3 (iii) ** Find the value of * k * , if is a factor of p(x) in the following case:

** Answer: **

Zero of polynomial is

If is factor of polynomial

Then, must be equal to zero

Now,

Therefore, value of k is

** Q3 (iv) ** the value of * k * , if is a factor of p(x) in the following case:

** Answer: **

Zero of polynomial is

If is factor of polynomial

Then, must be equal to zero

Now,

Therefore, value of k is

** Q4 (i) ** Factorise :

** Answer: **

Given polynomial is

We need to factorise the middle term into two terms such that their product is equal to and their sum is equal to

We can solve it as

** Q4 (ii) ** Factorise :

** Answer: **

Given polynomial is

We need to factorise the middle term into two terms such that their product is equal to and their sum is equal to

We can solve it as

** Q4 (iii) ** Factorise :

** Answer: **

Given polynomial is

We need to factorise the middle term into two terms such that their product is equal to and their sum is equal to

We can solve it as

** Q4 (iv) ** Factorise :

** Answer: **

We need to factorise the middle term into two terms such that their product is equal to and their sum is equal to

We can solve it as

** Q5 (i) ** Factorise :

** Answer: **

Given polynomial is

Now, by hit and trial method we observed that is one of the factors of the given polynomial.

By long division method, we will get

We know that Dividend = (Divisor × Quotient) + Remainder

Therefore, on factorization of we will get

** Q5 (ii) ** Factorise :

** Answer: **

Given polynomial is

Now, by hit and trial method we observed that is one of the factors of the given polynomial.

By long division method, we will get

We know that Dividend = (Divisor Quotient) + Remainder

Therefore, on factorization of we will get

** Q5 (iii) ** Factorise :

** Answer: **

Given polynomial is

Now, by hit and trial method we observed that is one of the factore of given polynomial.

By long division method, we will get

We know that Dividend = (Divisor Quotient) + Remainder

Therefore, on factorization of we will get

** Q5 (iv) ** Factorise :

** Answer: **

Given polynomial is

Now, by hit and trial method we observed that is one of the factors of the given polynomial.

By long division method, we will get

We know that Dividend = (Divisor Quotient) + Remainder

Therefore, on factorization of we will get

** Class 9 maths chapter 2 question answer Exercise: 2.5 **

** Q1 (i) ** Use suitable identities to find the following product:

** Answer: **

We will use identity

Put

Therefore, is equal to

** Q1 (ii) ** Use suitable identities to find the following product:

** Answer: **

We will use identity

Put

Therefore, is equal to

** Q1 (iii) ** Use suitable identities to find the following product:

** Answer: **

We can write as

We will use identity

Put

Therefore, is equal to

** Q1 (iv) ** Use suitable identities to find the following product:

** Answer: **

We will use identity

Put

Therefore, is equal to

** Q1 (v) ** Use suitable identities to find the following product:

** Answer: **

We can write as

We will use identity

Put

Therefore, is equal to

** Q2 (i) ** Evaluate the following product without multiplying directly:

** Answer: **

We can rewrite as

We will use identity

Put

Therefore, value of is

** Q2 (ii) ** Evaluate the following product without multiplying directly:

** Answer: **

We can rewrite as

We will use identity

Put

Therefore, value of is

** Q2 (iii) ** Evaluate the following product without multiplying directly:

** Answer: **

We can rewrite as

We will use identity

Put

Therefore, value of is

** Q3 (i) ** Factorise the following using appropriate identities:

** Answer: **

We can rewrite as

Using identity

Here,

Therefore,

** Q3 (ii) ** Factorise the following using appropriate identities:

** Answer: **

We can rewrite as

Using identity

Here,

Therefore,

** Q3 (iii) ** Factorise the following using appropriate identities:

** Answer: **

We can rewrite as

Using identity

Here,

Therefore,

** Q4 (i) ** Expand each of the following, using suitable identities:

** Answer: **

Given is

We will Use identity

Here,

Therefore,

** Q4 (ii) ** Expand each of the following, using suitable identities:

** Answer: **

Given is

We will Use identity

Here,

Therefore,

** Q4 (iii) ** Expand each of the following, using suitable identities:

** Answer: **

Given is

We will Use identity

Here,

Therefore,

** Q4 (iv) ** Expand each of the following, using suitable identities:

** Answer: **

Given is

We will Use identity

Here,

Therefore,

** Q4 (v) ** Expand each of the following, using suitable identities:

** Answer: **

Given is

We will Use identity

Here,

Therefore,

** Q4 (vi) ** Expand each of the following, using suitable identities:

** Answer: **

Given is

We will Use identity

Here,

Therefore,

** Q6 (i) ** Write the following cubes in expanded form:

** Answer: **

Given is

We will use identity

Here,

Therefore,

** Q6 (ii) ** Write the following cube in expanded form:

** Answer: **

Given is

We will use identity

Here,

Therefore,

** Q6 (iii) ** Write the following cube in expanded form:

** Answer: **

Given is

We will use identity

Here,

Therefore,

** Q6 (iv) ** Write the following cube in expanded form:

** Answer: **

Given is

We will use identity

Here,

Therefore,

** Q7 (i) ** Evaluate the following using suitable identities:

** Answer: **

We can rewrite as

We will use identity

Here,

Therefore,

** Q7 (ii) ** Evaluate the following using suitable identities:

** Answer: **

We can rewrite as

We will use identity

Here,

Therefore,

** Q7 (iii) ** Evaluate the following using suitable identities:

** Answer: **

We can rewrite as

We will use identity

Here,

Therefore,

** Q14 (i) ** Without actually calculating the cubes, find the value of each of the following:

** Answer: **

Given is

We know that

If then ,

Here,

Therefore,

Therefore, value of is

** Q14 (ii) ** Without actually calculating the cubes, find the value of the following:

** Answer: **

Given is

We know that

If then ,

Here,

Therefore,

Therefore, value of is

** Answer: **

We know that

Area of rectangle is =

It is given that area =

Now, by splitting middle term method

Therefore, two answers are possible

** case (i) :- ** Length = and Breadth =

** case (ii) :- ** ** ** Length = and Breadth =

** Answer: **

We know that

Area of rectangle is =

It is given that area =

Now, by splitting the middle term method

Therefore, two answers are possible

** case (i) :- ** Length = and Breadth =

** case (ii) :- ** ** ** Length = and Breadth =

** Q16 (i) ** What are the possible expressions for the dimensions of the cuboid whose volumes is given below?

Volume : |

** Answer: **

We know that

Volume of cuboid is =

It is given that volume =

Now,

Therefore,one of the possible answer is possible

Length = and Breadth = and Height =

** Q16 (ii) ** What are the possible expressions for the dimensions of the cuboid whose volumes is given below?

Volume : |

** Answer: **

We know that

Volume of cuboid is =

It is given that volume =

Now,

Therefore,one of the possible answer is possible

Length = and Breadth = and Height =

It is an important topic in maths that comes under the algebra unit which holds 20 marks in the CBSE Class 9 Maths final exams. In this particular NCERT textbook chapter, you will study the definition of a polynomial, zeroes, coefficient, degrees, and terms of a polynomial, type of a polynomial. You will also study the remainder and factor theorems and the factorization of polynomials. In Polynomials, there are a total of 5 exercises that comprise of a total of 33 questions. NCERT solutions for Class 9 Maths chapter 2 Polynomials will cover the detailed solution to each and every question present in the practice exercises including optional exercises.

Interested students can practice class 9 maths ch 2 question answer using the following exercises.

- NCERT Solutions for Class 9 Maths Exercise 2.1
- NCERT Solutions for Class 9 Maths Exercise 2.2
- NCERT Solutions for Class 9 Maths Exercise 2.3
- NCERT Solutions for Class 9 Maths Exercise 2.4
- NCERT Solutions for Class 9 Maths Exercise 2.5

Chapter No. | Chapter Name |

Chapter 1 | |

Chapter 2 | Polynomials |

Chapter 3 | |

Chapter 4 | |

Chapter 5 | |

Chapter 6 | |

Chapter 7 | |

Chapter 8 | |

Chapter 9 | |

Chapter 10 | |

Chapter 11 | |

Chapter 12 | |

Chapter 13 | |

Chapter 14 | |

Chapter 15 |

- Comprehensive coverage of topics related to Polynomials in one variable, Zeros of a Polynomial, Real Numbers and their Decimal Expansions, and more.
- Maths chapter 2 class 9 solutions are designed in a clear and concise language to help students understand the concepts with ease.
- The step-by-step approach of the ch 2 maths class 9 solutions assists students in learning and solving mathematical problems in a structured manner.
- Inclusion of a wide range of solved examples and exercises to aid students in practicing and assessing their understanding of the concepts.

The class 9 chapter 2 maths solutions are prepared by experts at Careers360 who have extensive knowledge and experience in Mathematics.

- First of all, learn some basics and concepts regarding chapter Polynomials.
- While reading the basics, go through the examples so that you can understand the applications of the concepts.
- Once you have done the above two points, then you can directly move to the practice exercises.
- While practising the exercises, if you stuck anywhere then you can take the help of the NCERT solutions for Class 9 Maths chapter 2 Polynomials.
- After the completion of practice exercises, you can go through some previous year question papers.

*Keep Working Hard and Happy Learning! *

1. What are the important topics in NCERT Class 9 syllabus chapter Polynomials ?

The NCERT class 9 maths chapter 2 includes topics such as definition of a polynomial, zeroes, coefficient, degrees, and terms of a polynomial, different types of a polynomial, remainder and factor theorems, and the factorization of polynomials. students should practice these NCERT solutions to get indepth understanding of these concepts which ultimately lead to score well in the exam.

2. What is the number of exercises included in NCERT Solutions for class 9 maths polynomials?

Maths chapter 2 includes five exercises covering topics such as Polynomials in one variable, Zeros of a Polynomial, Real Numbers and their Decimal Expansions, Representing Real Numbers on the Number Line, Operations on Real Numbers, and Laws of Exponents for Real Numbers. Practicing these exercises of NCERT maths class 9 chapter 2 is crucial for achieving a better understanding of the concepts and scoring well in Mathematics. To help students gain confidence, Careers360 experts have designed these solutions to provide comprehensive explanations of the concepts covered in this chapter.

3. What are the advantages of choosing NCERT Solutions for Class 9 Maths Chapter 2?

NCERT Solutions for Class 9 Maths Chapter 2 use straightforward language to explain the concepts, making it accessible even for students who struggle with Mathematics. These solutions are meticulously crafted by a team of experts at Careers360 with the objective of helping students prepare for their CBSE exams effectively.

4. Is it challenging to grasp the concepts in NCERT Solutions for polynomials class 9 solutions?

Regular practice with NCERT Solutions for Class 9 Maths Chapter 2 can enable students to excel in their CBSE exams. These solutions are created by a team of skilled Maths experts at Careers360, and by solving all the questions and comparing their answers with the solutions, students can aim for high scores in their exams.

5. Where can I find the complete solutions of NCERT for Class 9 Maths ?

Here, students can get detailed NCERT solutions for Class 9 Maths which includes solutions to all the exercise of each chapters.

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