NCERT Syllabus for Class 6 English 2024

Q: Is it mandatory to read the complete book of NCERT score well in exams?

Yes, to score well you need to cover NCERT .

NCERT Syllabus for Class 6 English 2024 - Download PDF here

Edited By Dinesh Goyal | Updated on Oct 23, 2024 06:24 PM IST

NCERT Syllabus for Class 6 English 2024-25 - National Council of Educational Research and Training released the Class 6 English subject syllabus on the official website of NCERT. Students can download the NCERT Class 6 English syllabus 2024-25 from ncert.nic.in. It is a must for students to know the Class 6 English syllabus and prepare the study plan accordingly. The NCERT Syllabus for Class 6 English 2024-25 will comprise the topics and sub-topics.

NCERT Syllabus for Class 6 English 2024 - Download PDF here

The National Council of Educational and Research Training publishes the NCERT Syllabus as per the latest pattern. It is easily understandable and students can learn a lot from the NCERT Syllabus for Class 6 English 2024-25. The PDF link to download the English syllabus is given below. Read further to know more about the NCERT class 6 English syllabus.

Download links:

NCERT Syllabus for Class 6 English 2024-25

Refer to the table below to know the NCERT Class 6 English syllabus. There are two books prescribed in the syllabus, Honeysuckle and A Pact with the Sun. The syllabus for both books is given below.

NCERT Syllabus for Class 6 English

Textbook name	Chapter Names	Poetry
Honeysuckle	Who Did Patrick’s Homework?	A House, A Home
	How the Dog Found Himself a New Master!	The Kite
	Taro's Reward	The Quarrel
	An Indian-American Woman in Space: Kalpana Chawla	Beauty
	A Different Kind of School	Where Do All the Teachers Go
	Who I Am	The Wonderful Words
	Fair Play	Vocation
	The Banyan Tree
A Pact with the Sun	A Tale of Two Birds
	The Friendly Mongoose
	The Shepherd’s Treasure
	Tansen
	The Monkey and the Crocodile
	The Wonder Called Sleep
	A Pact with the Sun

Also, Check: CBSE Board Exam Date Sheet 2025

NCERT syllabus for class 6 English Grammar

Determiners
Linking words
Adjectives (comparative and superlative forms)
Adverbs (place and types)
Tense forms
Word order in sentence types
Clauses
Reported speech

Other Subject Syllabus

NCERT Syllabus for Class 6 Science	NCERT Syllabus for Class 6 Math
NCERT Syllabus for Class 6 Social Science	NCERT Syllabus for Class 6 Hindi

How to Download NCERT Syllabus for Class 6 English 2024-25 online?

Follow the below-mentioned steps to download the NCERT Syllabus for Class 6 English pdf.

Go to the official website of NCERT, ncert.nic.in.
On the home page, you will find the link for Syllabus classes 1 to 12. Click on the link.
Now click on the syllabus for elementary classes and then click on the syllabus for class 6 English.
The PDF of the NCERT Syllabus for Class 6 English 2024-25 online will be displayed on your screens.

Know about NCERT Books

Exam Preparation Tips for English Class 6

Check the complete NCERT Syllabus for Class 6 English 2024-25 and follow it religiously while preparing for the exams.
Follow the NCERT book for class 6 English to prepare for the exams.
Apart from the NCERT books, practice sample papers to improve your time and efficiency.
Check the NCERT Syllabus for Class 6 English grammar and prepare for it as well.
Make a habit of reading the newspaper regularly. This will be helpful for the reading section.

Also read - NCERT Solutions for Class 6 All Subjects

Frequently Asked Questions (FAQs)

1. Do all CBSE board schools follow NCERT syllabus?

Yes, almost every CBSE board school follows the syllabus of NCERT.

2. From where can I get the PDF of NCERT books for class 6?

The PDF is available at ncert.nic.in.

3. Is it mandatory to read the complete book of NCERT score well in exams?

Yes, to score well you need to cover NCERT.

Also Read

NCERT Solutions for Class 6 Science Chapter 3 Fibre to Fabric

NCERT Solutions for Class 6 Science Chapter 2 Components of Food

NCERT Solutions for Class 6 Science Chapter 1 Food Where Does It Come From

NCERT Solutions for Class 6 Maths Chapter 5 Understanding Elementary Shapes

NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry

NCERT Solutions for Class 6 Maths Chapter 13 Symmetry

Articles

Vidya Lakshmi Education Loan: Schemes, Eligibility & Repayment Details

Dec 09, 2024

Sainik School Entrance Exam 2025: Application, Exam Date, How to Apply, Syllabus

Dec 09, 2024

Canara Bank Education Loan : Check Education Loan Schemes Available, Eligibility, Repayment Period

Dec 09, 2024

TOSS SSC Result 2025 - Check Telangana Open School SSC Results @ telanganaopenschool.org

Dec 09, 2024

List of Rashtriya Military School in India 2024-25: Best RMS Schools

Dec 09, 2024

Union Bank of India Education Loan - Check Education Loan Schemes Available, Eligibility, Repayment Period

Dec 09, 2024

Bank of Baroda Education Loan - Details of Loan Scheme, Amount, Eligibility

Dec 09, 2024

Simultala Awasiya Vidyalaya Answer Key 2025 (Out), Download SAV Class 6 Answer Sheet Prelims Exam

Dec 09, 2024

Upcoming School Exams

Manipur Board 12th Examination

Application Date:11 November,2024 - 11 December,2024

Exam Pattern

Admit Card

Result

Bihar Open Board 10th Examination

Application Date:11 November,2024 - 10 December,2024

Admit Card

Result

Bihar Open Board 12th Examination

Application Date:11 November,2024 - 10 December,2024

Admit Card

Result

National Means Cum-Merit Scholarship

Application Date:20 November,2024 - 10 December,2024

Eligibility Criteria

Application Process

Exam Pattern

National Institute of Open Schooling 10th examination

Application Date:21 November,2024 - 20 December,2024

Application Process

Exam Pattern

Mock Test

View All School Exams

Get answers from students and experts

Popular Questions

A block of mass 0.50 kg is moving with a speed of 2.00 ms^-1 on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is

Option 1) $0.34\; J$	Option 2) $0.16\; J$
Option 3) $1.00\; J$	Option 4) $0.67\; J$

A person trying to lose weight by burning fat lifts a mass of 10 kg upto a height of 1 m 1000 times. Assume that the potential energy lost each time he lowers the mass is dissipated. How much fat will he use up considering the work done only when the weight is lifted up ? Fat supplies 3.8×10⁷J of energy per kg which is converted to mechanical energy with a 20% efficiency rate. Take g = 9.8 ms⁻² :

Option 1)

2.45×10⁻³ kg

Option 2)

6.45×10⁻³ kg

Option 3)

9.89×10⁻³ kg

Option 4)

12.89×10⁻³ kg

An athlete in the olympic games covers a distance of 100 m in 10 s. His kinetic energy can be estimated to be in the range

Option 1) $2,000 \; J - 5,000\; J$	Option 2) $200 \, \, J - 500 \, \, J$
Option 3) $2\times 10^{5}J-3\times 10^{5}J$	Option 4) $20,000 \, \, J - 50,000 \, \, J$

A particle is projected at 60⁰ to the horizontal with a kinetic energy $K$ . The kinetic energy at the highest point

Option 1) $K/2\,$	Option 2) $\; K\;$
Option 3) $zero\;$	Option 4) $K/4$

In the reaction,

$2Al_{(s)}+6HCL_{(aq)}\rightarrow 2Al^{3+}\, _{(aq)}+6Cl^{-}\, _{(aq)}+3H_{2(g)}$

Option 1) $11.2\, L\, H_{2(g)}$ at STP is produced for every mole $HCL_{(aq)}$ consumed	Option 2) $6L\, HCl_{(aq)}$ is consumed for ever $3L\, H_{2(g)}$ produced
Option 3) $33.6 L\, H_{2(g)}$ is produced regardless of temperature and pressure for every mole Al that reacts	Option 4) $67.2\, L\, H_{2(g)}$ at STP is produced for every mole Al that reacts .

How many moles of magnesium phosphate, $Mg_{3}(PO_{4})_{2}$ will contain 0.25 mole of oxygen atoms?

Option 1) 0.02	Option 2) 3.125 × 10^-2
Option 3) 1.25 × 10^-2	Option 4) 2.5 × 10^-2

If we consider that 1/6, in place of 1/12, mass of carbon atom is taken to be the relative atomic mass unit, the mass of one mole of a substance will

Option 1) decrease twice	Option 2) increase two fold
Option 3) remain unchanged	Option 4) be a function of the molecular mass of the substance.

With increase of temperature, which of these changes?

Option 1) Molality	Option 2) Weight fraction of solute
Option 3) Fraction of solute present in water	Option 4) Mole fraction.

Number of atoms in 558.5 gram Fe (at. wt.of Fe = 55.85 g mol^-1) is

Option 1) twice that in 60 g carbon	Option 2) 6.023 × 10²²
Option 3) half that in 8 g He	Option 4) 558.5 × 6.023 × 10²³

A pulley of radius 2 m is rotated about its axis by a force F = (20t - 5t²) newton (where t is measured in seconds) applied tangentially. If the moment of inertia of the pulley about its axis of rotation is 10 kg m² , the number of rotations made by the pulley before its direction of motion if reversed, is