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NCERT Solutions for Class 6 Science Chapter 10 - Motion and Measurement of Distances

NCERT Solutions for Class 6 Science Chapter 10 - Motion and Measurement of Distances

Edited By Irshad Anwar | Updated on Apr 09, 2025 01:46 PM IST

NCERT Solutions for Class 6 Science Chapter 10, Living Creatures: Exploring their Characteristics, are particularly made to provide the basic features of living beings to students. Such solutions include important topics such as growth, reproduction, movement, and breathing, introducing students to contrasts between the living and non-living objects. By exploring how living creatures interact with their environment, students gain an understanding of the adaptation and survival strategies of various species. The NCERT solutions provide clear explanations in simple language, making complex concepts available to young learners.

This Story also Contains
  1. NCERT Solutions for Class 6 Science Chapter 10 Living Creatures: Exploring their Characteristics
  2. Overview of NCERT Class 6 Science Chapter 10
  3. Key Topics of Chapter 10 NCERT Class 6 Science
  4. Essential Diagrams of Science NCERT Class 6 Chapter 10
  5. NCERT Solutions for Class 6 Science: Chapter-wise
NCERT Solutions for Class 6 Science Chapter 10 - Motion and Measurement of Distances
NCERT Solutions for Class 6 Science Chapter 10 - Motion and Measurement of Distances

The NCERT Solutions for the chapter are designed to give simple answers to each question of exercise in the textbook so that students can clear their doubts and solidify their grasp of important concepts. The solutions are perfect for exam preparation and form a strong foundation for classes above. They can be accessed in PDF form and can be utilized offline, hence ideal for revision and self-study. One can also view other NCERT Solutions for Class 6 to access different resources for different subjects, which can maximize one's academic exposure.

NCERT Solutions for Class 6 Science Chapter 10 Living Creatures: Exploring their Characteristics

Exercise: Questions and answers

Below are the detailed answers which can help you:

1. List the similarities and differences in the life cycles of plants and animals.

Answer:

The table below shows the similarities and differences in the life cycles of plants and animals:

FeaturePlantsAnimals
Similarities

Life CycleBirth/germination, growth, reproduction, deathBirth, growth, reproduction, death
RequirementsNutrients and energyNutrients and energy
ResponseRespond to stimuliRespond to stimuli
Differences

GrowthExtended growth periodRelatively shorter growth period
StagesMay lack a distinct juvenile stageDistinct juvenile stage
ReproductionSeeds or sporesSexual reproduction (mostly)
MobilityGenerally stationaryMobile

2. The table on the next page shows some data. Study the data and try to find out examples appropriate for the conditions given in the second and third columns. If you think that an example for any of the conditions given below is not possible, explain why

S. no.Does it grow?Does it respire?ExampleRemarks
1.NoNo

2.NoYes

3.YesNo

4.YesYes

Answer:

Here's the table with examples to match the given conditions:

S.No.Does it grow?Does it respire?ExampleRemarks
1.NoNoRockNon-living; doesn't grow or respire
2.NoYesBurning FireNon-living; it utilizes oxygen but does not grow.
3.YesNoVirusA virus can grow (reproduce) within a host cell but does not respire on its own.
4.YesYesHuman/AnimalLiving, growing and respiring

3. You have learnt that different conditions are required for seed germination. How can we use this knowledge for the proper storage of grains and pulses?

Answer:

Grains and pulses can be stored properly by ensuring they are kept in a cool, dry place with low humidity and limited air exposure. This prevents germination by depriving the seeds of the necessary moisture, oxygen, and temperature needed to sprout.


4. You have learnt that a tail is present in a tadpole, but it disappears as it grows into a frog. What is the advantage of having a tail in the tadpole stage?

Answer:

The tail in the tadpole stage is advantageous because it aids in swimming and movement in the aquatic environment. It allows the tadpole to propel itself through the water, find food, and evade predators.


5. Charan says that a wooden log is non-living as it cannot move. Charu counters it by saying that it is living because it is made of wood obtained from trees. Give your arguments in favour or against the two statements given by Charan and Charu.

Answer:

  • Charan's statement: It is correct to say that a wooden log is non-living because it does not exhibit the key characteristics of living organisms, such as growth, reproduction, respiration, or response to stimuli.

  • Charu's statement: Although wood comes from a living tree, the log itself is no longer living. The cells in the wood are dead, and the log cannot perform any life processes.


6. What are the similarities and distinguishing features in the life cycles of a mosquito and a frog?

Answer:

The table below shows the similarities and differences in the life cycles of a mosquito and a frog:

FeatureMosquitoFrog
Similarities

MetamorphosisUndergoes metamorphosisUndergoes metamorphosis
Water DependencyRequires water for larval stageRequires water for early development (tadpole stage)
ReproductionLays eggsLays eggs
Distinguishing Features

Life StagesEgg, larva, pupa, adultEgg, tadpole, adult
Larval StageAquatic larvae (wrigglers) feed on organic matterTadpoles are aquatic and have a more complex diet
Adult FormInsect with wingsAmphibian with legs

7. A plant is provided with all the conditions suitable for its growth (Fig. 10.9). Draw what you expect to see in the shoot and the root of the plant after one week. Write down the reasons.

Answer:

After one week, the shoot would have grown taller, with new leaves emerging. The existing leaves would have increased in size and turned a deeper green. The root system would have expanded, with new roots growing deeper and wider into the soil.

  • Reasons: The plant has favorable conditions (light, water, nutrients) for photosynthesis and growth. The shoot grows to capture more sunlight, and the roots grow to absorb more water and nutrients from the soil.


8. Tara and Vijay set up the experiment shown in the picture (Fig. 10.10). What do you think they want to find out? How will they know if they are correct?

Answer:

Tara and Vijay likely want to find out how light affects the direction of plant growth. They will know if they are correct if the plant stem bends towards the hole, demonstrating that plants grow towards a light source.


9. Design an experiment to check if temperature has an effect on seed germination.

Answer:

  1. Materials: Bean seeds, pots, soil, thermometer, refrigerator, and a warm location.

  2. Procedure:

    • Divide the seeds into three groups.

    • Plant each group of seeds in separate pots with similar soil.

    • Place one pot in a refrigerator (low temperature), one at room temperature, and one in a warm location.

    • Water all pots equally and regularly.

    • Monitor and record the number of seeds that germinate in each pot over a set period (e.g., 10 days).

  3. Observation: Count the number of seeds that germinate in each pot.

  4. Conclusion: Compare the germination rates in the different temperature conditions. The temperature at which most seeds germinate is the optimal temperature for seed germination.


Overview of NCERT Class 6 Science Chapter 10

Living Organisms: Characteristics and Habitats is a lesson on the unique characteristics of living organisms and their presence in the environment. The chapter speaks about the important features such as growth, reproduction, movement, respiration, and adaptation. The chapter also speaks about how living and non-living things differ from one another, why habitats are crucial, and how organisms adapt to survive under varied conditions.

Also Check the NCERT Books and the NCERT Syllabus here

Key Topics of Chapter 10 NCERT Class 6 Science

These form the basis of understanding how living things adapt to the environment and sustain life.

  1. Characteristics of living things
  2. Growth
  3. Reproduction
  4. Movement
  5. Respiration
  6. Living things and non-living things.
  7. Interdependence of living things and the environment.
  8. Indicators of survival and adaptation.
  9. Food, water, and air role in sustaining life.
  10. Habitats and their impacts on organisms.

Key Subtopics of Class 6 Science NCERT Chapter 10

The subtopics cover thoroughly different characteristics of living things, adaptations, and life cycles.

  1. Adaptations in plants and animals.
  2. Animals classification according to habitat and diet.
  3. Plant and animal life cycles.
  4. Response of living organisms to stimuli.
  5. Role of reproduction in the survival of a species.

NCERT Solutions for Class 6 Subject Wise:

Essential Diagrams of Science NCERT Class 6 Chapter 10

These diagrams visually represent important concepts such as habitats and adaptations, which are more visible.

Types of Habitats:

Types%20of%20Habitats


Food Chain:

food%20chain


Earth's Spheres:

earth%20sp

NCERT Solutions for Class 6 Science: Chapter-wise

Below mentioned are the Chapterwise solutions:


Frequently Asked Questions (FAQs)

1. What is Motion?

If we say that an object changes its position from one point to another point with respect to time we say that the object is in motion. 

2. Give some examples of transport.

Here are examples of transport like; Bus, Car, Bike, Aeroplane, etc.

3. What are the topics covered in NCERT solution Class 6 Chapter 10?

The topics are covered in NCERT solution Class 6 Chapter 10 given below

  • Story of Transport 
  • How Far You Travelled (How Wide Is This Desk) 
  • Some Measurement  
  •  Standard Units Of Measurement 
  • Correct Measurement Of Lenght 
  • Measuring The Lenght Of A Curved Line 
  • Moving Things Around Us 
  • Types Of Motion  


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A block of mass 0.50 kg is moving with a speed of 2.00 ms-1 on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is

Option 1)

0.34\; J

Option 2)

0.16\; J

Option 3)

1.00\; J

Option 4)

0.67\; J

A person trying to lose weight by burning fat lifts a mass of 10 kg upto a height of 1 m 1000 times.  Assume that the potential energy lost each time he lowers the mass is dissipated.  How much fat will he use up considering the work done only when the weight is lifted up ?  Fat supplies 3.8×107 J of energy per kg which is converted to mechanical energy with a 20% efficiency rate.  Take g = 9.8 ms−2 :

Option 1)

2.45×10−3 kg

Option 2)

 6.45×10−3 kg

Option 3)

 9.89×10−3 kg

Option 4)

12.89×10−3 kg

 

An athlete in the olympic games covers a distance of 100 m in 10 s. His kinetic energy can be estimated to be in the range

Option 1)

2,000 \; J - 5,000\; J

Option 2)

200 \, \, J - 500 \, \, J

Option 3)

2\times 10^{5}J-3\times 10^{5}J

Option 4)

20,000 \, \, J - 50,000 \, \, J

A particle is projected at 600   to the horizontal with a kinetic energy K. The kinetic energy at the highest point

Option 1)

K/2\,

Option 2)

\; K\;

Option 3)

zero\;

Option 4)

K/4

In the reaction,

2Al_{(s)}+6HCL_{(aq)}\rightarrow 2Al^{3+}\, _{(aq)}+6Cl^{-}\, _{(aq)}+3H_{2(g)}

Option 1)

11.2\, L\, H_{2(g)}  at STP  is produced for every mole HCL_{(aq)}  consumed

Option 2)

6L\, HCl_{(aq)}  is consumed for ever 3L\, H_{2(g)}      produced

Option 3)

33.6 L\, H_{2(g)} is produced regardless of temperature and pressure for every mole Al that reacts

Option 4)

67.2\, L\, H_{2(g)} at STP is produced for every mole Al that reacts .

How many moles of magnesium phosphate, Mg_{3}(PO_{4})_{2} will contain 0.25 mole of oxygen atoms?

Option 1)

0.02

Option 2)

3.125 × 10-2

Option 3)

1.25 × 10-2

Option 4)

2.5 × 10-2

If we consider that 1/6, in place of 1/12, mass of carbon atom is taken to be the relative atomic mass unit, the mass of one mole of a substance will

Option 1)

decrease twice

Option 2)

increase two fold

Option 3)

remain unchanged

Option 4)

be a function of the molecular mass of the substance.

With increase of temperature, which of these changes?

Option 1)

Molality

Option 2)

Weight fraction of solute

Option 3)

Fraction of solute present in water

Option 4)

Mole fraction.

Number of atoms in 558.5 gram Fe (at. wt.of Fe = 55.85 g mol-1) is

Option 1)

twice that in 60 g carbon

Option 2)

6.023 × 1022

Option 3)

half that in 8 g He

Option 4)

558.5 × 6.023 × 1023

A pulley of radius 2 m is rotated about its axis by a force F = (20t - 5t2) newton (where t is measured in seconds) applied tangentially. If the moment of inertia of the pulley about its axis of rotation is 10 kg m2 , the number of rotations made by the pulley before its direction of motion if reversed, is

Option 1)

less than 3

Option 2)

more than 3 but less than 6

Option 3)

more than 6 but less than 9

Option 4)

more than 9

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