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NCERT Solutions for Class 8 Science Chapter 12 Friction

NCERT Solutions for Class 8 Science Chapter 12 Friction

Edited By Vishal kumar | Updated on Apr 01, 2024 10:36 AM IST

NCERT Solutions Class 8 Science Chapter 12 – Access And Download Free PDF

NCERT solutions for class 8 science chapter 12 Friction: If you are a CBSE student in class 8, you may be one of those looking for solutions for NCERT class 8 chapter 12 friction. This is an important chapter for class 8 students. To score good marks, knowing the CBSE NCERT solutions for class 8 science chapter 12 friction would be an advantage. In this chapter, you will get to know the topics like forces of friction, factors affecting friction, why friction is necessary, what is increasing and decreasing friction, how wheels reduce friction, static friction, ball bearings, fluid friction, use of lubricants and more.

You can also check the detailed NCERT solutions for class 8 science chapter 12 friction on this page. Other NCERT solutions for class 8 are also available to understand how to derive the answers to the various questions asked in each chapter and each exercise. This, in turn, will help in performing better in the exams and scoring very good marks. Now just that, a good understanding of the NCERT solutions for subjects science or maths will further aid in higher classes and entrance exams like JEE Main and NEET which are for engineering and medical courses respectively.

**As per the CBSE Syllabus for the academic year 2023-24, this chapter has undergone a renumbering and is now designated as Chapter 8.

NCERT solutions for class 8 science chapter 12 friction: Solved Exercise Questions

Q1. Fill in the blanks.

(a) Friction opposes the _____________ between the surfaces in contact with each other.
(b) Friction depends on the _____________ of surfaces.
(c) Friction produces __________.
(d) Sprinkling of powder on the carrom board ________ friction.
(e) Sliding friction is ___________ than the static friction.

Answer:

(a) Friction opposes the motion between the surfaces in contact with each other.
(b) Friction depends on the nature of surfaces.
(c) Friction produces heat.
(d) Sprinkling of powder on the carrom board reduces friction.
(e) Sliding friction is less than the static friction.

Q2. Four children were asked to arrange forces due to rolling, static and sliding frictions in a decreasing order. Their arrangements are given below. Choose the correct arrangement.

(a) rolling, static, sliding
(b) rolling, sliding, static
(c) static, sliding, rolling
(d) sliding, static, rolling

Answer:

(c) is the correct arrangement.

Static friction > sliding friction > rolling friction.

Q3. Alida runs her toy car on dry marble floor, wet marble floor, newspaper and towel spread on the floor. The force of friction acting on the car on different surfaces in increasing order will be

(a) wet marble floor, dry marble floor, newspaper and towel.
(b) newspaper, towel, dry marble floor, wet marble floor.
(c) towel, newspaper, dry marble floor, wet marble floor.
(d) wet marble floor, dry marble floor, towel, newspaper

Answer:

The force of friction acting on the car on different surfaces in increasing order will be wet marble floor, dry marble floor, newspaper and towel. Therefore (a) is the correct answer.

Q5. You spill a bucket of soapy water on a marble floor accidentally. Would it make it easier or more difficult for you to walk on the floor? Why?

Answer:

It would make it more difficult for us to walk on the marble floor since the frictional force would further decrease and thus our grip on the floor while walking would become even lesser.

Q6. Explain why sportsmen use shoes with spikes.

Answer:

Sportsmen use shoes with spikes to increase the grip between their feet and the ground by increasing the friction with the help of spikes. This aids them while running on the ground.

Q7. Iqbal has to push a lighter box and Seema has to push a similar heavier box on the same floor. Who will have to apply a larger force and why?

Answer:

Seema would have to apply a larger force as she would have to overcome a greater frictional force. The frictional force between two surfaces exists due to the interlocking of the irregularities on the surface. The magnitude of this frictional force depends on how tight this interlocking is which in this case depends on the weight of the boxes which is more in the case of Seema.

Q8. Explain why sliding friction is less than static friction.

Answer:

Sliding friction is less than static friction as the frictional force between two surfaces depends on the interlocking between the irregularities on the surfaces. This interlocking in case of sliding decreases as the contact points does not get enough time to interlock properly thus reducing the frictional force.

Q9. Give examples to show that friction is both a friend and a foe.

Answer:

Friction acting as a friend:

(a) It aids us to walk and cars to move on the roads.

(b)Fire can be ignited using friction.

Friction acting as a foe:

(a) It causes the efficiency of engines to decrease and also damages machinery.

(b) Friction causes the soles of shoes and tires to wear off.

Q10. Explain why objects moving in fluids must have special shapes.

Answer:

When an object is moving through a liquid there is an opposing force offered by the liquid against the motion of the object. To reduce this opposing force objects must have special shapes.

The subject matter experts at Careers360 have created a comprehensive class 8 science chapter 12 question answer that is designed to help students understand the concepts easily. The solutions are provided in a step-by-step format with diagrams, making it easier for students to follow along. The PDF version of the NCERT class 8 science chapter 12 solution can be downloaded by students for their convenience.

Additionally, the solutions for science class 8 chapter 12 cover a variety of question types, including fill-in-the-blanks, correct arrangement, and short answer type questions, giving students a well-rounded understanding of the chapter. Students can use these solutions to prepare for exams, revise the chapter, or simply deepen their understanding of the subject.

NCERT Solutions For Class 8 Science- Chapter-Wise

NCERT Solutions For Class 8: Subject-Wise

Class 8 Science Chapter 12 NCERT Solutions: Important Formulas and Diagrams

Friction

  • Friction is a force that opposes the relative motion or attempts to oppose the motion between two objects in contact.

  • It always acts in the direction opposite to the direction of motion or attempted motion.

Types of Friction

  • Static Friction: This is the friction that opposes the initial motion of an object at rest. It's the maximum force of friction that can be applied before motion starts.

  • Kinetic Friction: Once an object is in motion, this friction opposes its motion.

  • Rolling Friction: Occurs when one object rolls over another. It's generally less than kinetic friction.

Coefficient of Friction (μ)

  • It's a measure of the frictional properties between two materials.

  • The formula for frictional force: Frictional force (F) = Coefficient of friction (μ) × Normal force (N)

  • Coefficient of friction = force of friction / normal force

Methods to Reduce Friction

  • Lubrication: Adding a lubricant (like oil or grease) between surfaces reduces friction.

  • Smoothing: Making surfaces smoother can reduce friction.

  • Ball bearings: These reduce friction in rotating parts.

Reducing Friction in Daily Life

  • Lubricating moving parts of machines.

  • Using ball bearings in machinery.

  • Polishing or smoothing surfaces.

Friction Class 8 NCERT Science Chapter: Topics

  1. Force of friction
  2. Factors affecting friction
  3. Friction - a necessary evil
  4. Increasing and reducing friction
  5. Wheels reduce friction
  6. Fluid friction
  7. Ball Bearing
  8. Drag
  9. Fluid Friction
  10. Friction
  11. Interlocking
  12. Lubricants
  13. Rolling Friction
  14. Sliding Friction
  15. Static Friction

How to use chapter-wise NCERT solutions

Now that the NCERT solutions for class 8 science chapter 12 friction are done on this page, it's time to move to other chapters and topics as well. The list is given above. All you need to do is click on the given link and the NCERT chapter with solutions to all exercises will be displayed. Use them to understand and solve to score more marks in your exam.

Key Features of NCERT Solution for Class 8 Science

  1. Comprehensive Coverage: The friction class 8 solutions provide comprehensive coverage of the topic, addressing various aspects of friction, its causes, effects, and practical applications.

  2. Detailed Explanations: The friction class 8 NCERT Solutions offer detailed and easy-to-understand explanations for all the questions and concepts presented in the chapter. This helps students grasp the material effectively.

  3. Real-Life Examples: The class 8 science chapter 12 NCERT solutions include real-life examples and scenarios to illustrate the concepts of friction, making it easier for students to relate to and understand the subject matter.

  4. Variety of Question Types: The class 8 friction NCERT solutions cover various question types, including multiple-choice questions, short answer questions, long answer questions, and numerical problems. This diversity allows students to practice different problem-solving techniques.

  5. Practical Applications: Many questions are designed to highlight the practical applications of friction in everyday life, helping students see the relevance of the topic beyond the classroom.

  6. Step-by-Step Solutions: For friction class 8 questions and answers, step-by-step solutions are provided. These solutions guide students through the problem-solving process, enabling them to understand the methodology.

  7. Conceptual Clarity: The science chapter 12 class 8 aims to enhance students' conceptual clarity by breaking down complex ideas into simple, understandable explanations.

  8. Assessment and Practice: The questions and solutions serve as valuable tools for self-assessment and practice. Students can use them to test their understanding of the chapter and prepare for exams.

  9. Exam Orientation: Many questions are designed with a focus on exam preparation, aligning with the CBSE curriculum and exam pattern.

  10. Critical Thinking: Some questions encourage critical thinking, requiring students to analyze situations, make predictions, and draw conclusions based on their knowledge of friction.

  11. Comprehensive Answers: The class 8 science ch 12 question answer provided for each question are comprehensive and well-explained, ensuring that students not only know the correct answer but also understand the underlying concepts.

Also Check NCERT Books and NCERT Syllabus here:

Frequently Asked Questions (FAQs)

1. Is friction an important topic for higher studies?

Yes, friction, force, motion and pressure are important topics that will be studied in Class 9 NCERT Science Syllabus  and also in Class 11 NCERT Physics book

2. What is the role of friction?

Friction opposes the motion between the surfaces in contact with each other. If there is no frictional force we wont be able to walk. 

3. What are the topic covered in friction class 8

The following topics are covered in the chapter friction:

  •   Force of friction   

  •    Factors affecting friction   

  •    Friction - a necessary evil   

  •    Increasing and reducing friction   

  •    Wheels reduce friction   

  •    Fluid friction   

  •    Ball Bearing   

  •    Drag   

  •    Fluid Friction   

  •    Friction   

  •    Interlocking   

  •    Lubricants   

  •    Rolling Friction   

  •    Sliding Friction   

  •    Static Friction  

4. What is μ in friction?

 μ  represents the coefficient of friction between two surfaces.



5. What is the value of μ?

The value of the coefficient of friction (μ) varies depending on the materials of the surfaces in contact and other factors such as temperature and pressure. It can range from 0 to 1 or even higher.

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A block of mass 0.50 kg is moving with a speed of 2.00 ms-1 on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is

Option 1)

0.34\; J

Option 2)

0.16\; J

Option 3)

1.00\; J

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0.67\; J

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2.45×10−3 kg

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 6.45×10−3 kg

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 9.89×10−3 kg

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12.89×10−3 kg

 

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Option 1)

2,000 \; J - 5,000\; J

Option 2)

200 \, \, J - 500 \, \, J

Option 3)

2\times 10^{5}J-3\times 10^{5}J

Option 4)

20,000 \, \, J - 50,000 \, \, J

A particle is projected at 600   to the horizontal with a kinetic energy K. The kinetic energy at the highest point

Option 1)

K/2\,

Option 2)

\; K\;

Option 3)

zero\;

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2Al_{(s)}+6HCL_{(aq)}\rightarrow 2Al^{3+}\, _{(aq)}+6Cl^{-}\, _{(aq)}+3H_{2(g)}

Option 1)

11.2\, L\, H_{2(g)}  at STP  is produced for every mole HCL_{(aq)}  consumed

Option 2)

6L\, HCl_{(aq)}  is consumed for ever 3L\, H_{2(g)}      produced

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33.6 L\, H_{2(g)} is produced regardless of temperature and pressure for every mole Al that reacts

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67.2\, L\, H_{2(g)} at STP is produced for every mole Al that reacts .

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Option 1)

0.02

Option 2)

3.125 × 10-2

Option 3)

1.25 × 10-2

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2.5 × 10-2

If we consider that 1/6, in place of 1/12, mass of carbon atom is taken to be the relative atomic mass unit, the mass of one mole of a substance will

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decrease twice

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increase two fold

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remain unchanged

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be a function of the molecular mass of the substance.

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Weight fraction of solute

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less than 3

Option 2)

more than 3 but less than 6

Option 3)

more than 6 but less than 9

Option 4)

more than 9

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