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RD Sharma Solutions Class 12 Mathematics Chapter 13 VSA

RD Sharma Solutions Class 12 Mathematics Chapter 13 VSA

Edited By Satyajeet Kumar | Updated on Jan 27, 2022 10:01 AM IST

Students in class 12 will have to face tough competition in their board exams. Due to the minimal time, it becomes almost impossible for them to complete the syllabus and understand all the concepts clearly. Hence, students are recommended to use the RD Sharma class 12th exercise VSA solutions for their home practice. RD Sharma Solutions It will help them to improve their performance and enhance their math skills. Everyone knows that RD Sharma class 12 chapter 13 exercise VSA is the top choice of students who have scored high in their board exams.
The 13th chapter of the NCERT recommended Mathematics Textbook has Differentials, Errors, and Approximations which is a complex topic. The concepts that are covered in this section are Absolute error, Relative error, Percentage error. It will also talk about the Geometrical meaning of differentials and many more. The exercise VSA in the book and the RD Sharma class 12 chapter 13 exercise VSA contain six questions based on the entire chapter.

This Story also Contains
  1. RD Sharma Class 12 Solutions Chapter 13 VSA Differentials, Errors and Approximations - Other Exercise
  2. Differentials, Errors and Approximations Excercise: VSA
  3. RD Sharma Chapter wise Solutions

RD Sharma Class 12 Solutions Chapter 13 VSA Differentials, Errors and Approximations - Other Exercise

Differentials, Errors and Approximations Excercise: VSA

Differentials Errors and Approximations exercise very short answer question 1

Answer: 2
Hint: Here we use this below formula,
Δy=F(x+Δx)F(x)
Given:
y=x2x=10 and Δx=0.1
Solution:
y=x2 and Δx=0.1
Let’s take Differentiate of y
y=x2dydx=2x
(dydx)=2×10(x=10)( given )Δy=dy=dydx×Δx=20×0.1=2( dx=Δx=0.1)( Given )

Differentials Errors and Approximations exercise very short answer question 2

Answer: 0.01
Hint: Here we use basic formula,
Δy=dy=dydx×dx
Given:
x=3,Δx=0.03y=logex
Solution:
For
x=3y=loge3
Also, dydx=1x
So, (dydx)x=3=13Δy=dy=dydx×ΔxΔy=13×0.03Δy=0.01
So, our answer is 0.01

Differentials Errors and Approximations exercise very short answer question 3

Answer:
2α ( 2 alpha) 
Hint:
Here, we use the concept of approximation.
Given:
Relative error in measuring the radius of circular plan is α.
Solution:
Let x be the radius and y be the area of the circular plan.
We have,
Δxx=α and y=x2dydx=2xΔyy=2xyΔx=2xx2Δx
Δyy=2α [d(xn)dx=nxn1]
Hence the relative error in the area of the circular plan is 2α.

Differentials Errors and Approximations exercise very short answer question 4

Answer: 3α
Hint:

Here we use the basic concept of approximation.

Given:
The percentage error in radius of sphere is α
Solution:
Let Vbe the volume of the sphere
V=43πr3
let radius r=x
We have,
Δxx×100=α
After differentiating,
dVdx=4πx2dVV=4πx2Vdx
ΔVV=4πx243πx3×xα100ΔVV×100=3α
Hence, the percentage error in volume of sphere is 3α.

Differentials Errors and Approximations exercise very short answer question 5
Answer: 3a

Hint:
Here we use basic formula of cube,
V=x3
Given:
The percentage error in the edge of cube is a
Solution:
Let x be the side and Vbe the volume of the cube
V=x3
We have,
Δxx×100=a
dVdx=3x2
ΔVV=3x2V×Δx
ΔVV=3x2x3×Δx100
ΔVV×100=3a [d(xn)dx=nxn1]
Hence, the percentage error in volume of cube is 3a

Differentials Errors and Approximations exercise very short answer question 6

Answer: F(2.1)=9.2
Hint: Here we use this below formula,
F(x+Δx)=F(x)+F(x)Δx
Given:
F(x)=x410
Solution:
We have,
F(x)=x410
So, F(x)=4x3
and x=2,Δx=0.1
The let’s put the value in formula
F(2+0.1)=F(2)+F(2)Δx
=2410+4(2)3(0.1)=1610+(32)(0.1)=1610+3.2=9.2
So,F(2.1) is 9.2

The students who are preparing for their public exams lookout for reliable resources to study. Many such students of class12 depend on the RD Sharma class 12th exercise VSA book during their preparation. Here are a few reasons on why there is a huge demand for the RD Sharma books:

  • The answers for the book back questions are framed by certain experts who have an in-depth knowledge in the field of mathematics. They have provided various tricks and techniques in the RD Sharma Class 12th Exercise VSA book that can be used to solve the sums easily.

  • Homework and assignments can also be completed by referring to the RD Sharma Class 12 Solutions Differentials, Errors, and Approximations ex VSA resource material.

  • The Class 12 RD Sharma Chapter 13 Exercise VSA solution material is available in the updated according to the current academic year’s textbook.

  • The Career 360 website gives the access for everyone to download the PDF format of the RD Sharma Class 12 Solutions Chapter 13 Ex VSA book.

RD Sharma Chapter wise Solutions

Frequently Asked Questions (FAQs)

1. How can the class 12 students prepare for their classes in advance?

As the class 12 students are capable of understanding certain concepts even without the guidance of teacher, they can refer to the RD Sharma solutions to learn in advance. 

2. What are the exams where the RD Sharma Class 12th exercise VSA books can be used for preparation?

The students can use the RD Sharma Class 12th exercise VSA reference book to prepare for the class tests, public exams, JEE Mains and other entrance and competitive exams.

3. What is the profitable way to attain the Class 12 RD Sharma Chapter 12 Exercise VSA Solution material?

It is better for the students to download the class 12 RD Sharma Chapter 13 Exercise VSA solution from the Career 360 website as it is available for free.

4. Why is it essential for the class 12 students to prepare using the RD Sharma Class 12th Exercise VSA book?

As the teachers use the RD Sharma Class 12th Exercise VSA reference material to set the question paper for tests and exams, it is vital for a student to refer to this set of solutions.

5. Are there any restrictions towards who can access the RD Sharma Class 12 Solutions Chapter 13 Ex VSA book?

There is no restrictions towards who can access the RD Sharma Class 12 Solutions Chapter 13 Ex VSA book at the Career 360 website. Anyone can utilize this resource material.

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