RD Sharma Solutions Class 12 Mathematics Chapter 30 MCQ

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RD Sharma Solutions Class 12 Mathematics Chapter 30 MCQ

Edited By Kuldeep Maurya | Updated on Jan 25, 2022 04:24 PM IST

RD Sharma class 12th exercise MCQ is not your standard NCERT solution. This book is one of the top-rated self-study guides that has already won the trust and respect of innumerable students and teachers. The RD Sharma class 12 chapter 29 exercise MCQ comes with a ton of answers that are simple to read and easy to understand. It can be a game-changer for many students who struggle to study on their own.

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RD Sharma Class 12 Solutions Chapter29 MCQ Linear Programming - Other Exercise
Linear Programming Excercise: MCQ
RD Sharma Chapter wise Solutions

Also Read - RD Sharma Solutions For Class 9 to 12 Maths

The RD Sharma class 12 chapter 29 exercise MCQ is a trusted NCERT solution that has already helped hundreds of students in their exams. The 29th chapter of the book is titled Linear Programming. Exercise MCQ has 28 questions that cover concepts: Objective function of LPP, Sets are convex, Maximum value and Minimum value subjected to constraints, Optimal Value, and Feasible region. The RD Sharma class 12th exercise MCQ will help you revise all concepts that you have learned in the chapter.

RD Sharma Class 12 Solutions Chapter29 MCQ Linear Programming - Other Exercise

Linear Programming Excercise: MCQ

Linear Programming Exercise Multiple Choice Question 1

Answer: (b)Open half plane not containing the origin.
Hint: Put $x=0$ and $y=0$ in given equation
Given: The solution set in equation $\text {2x+y}>5$
Solution: Let $\text {x,y}$ plane

By the given equation $\text {2x+y}>5$
$x=0$ and $y=0$
$y>5$ and $x>\frac{5}{2}$
In the above drawn plane, option a, c are not satisfied.
So, the correct option is (b) which is open half plane but not containing the origin.

Linnear Programing Exercise Multiple Choice Question 2

Answer: (b) A function to be optimized
Hint: We know the condition $\text {Z=CX}$
Given: Objective function of LPP______
Solution:
Let, $Z_{\max / \min }=C X$
The condition may be
$\begin{aligned} &a_{1} x \geq b_{1} \\ &a_{1} x \leq b_{2} \\ &x \geq 0 \end{aligned}$
So, the objective function of LP is a function to be optimized.

Linear Programming Exercise Multiple Choice Question 3

Answer: (d) $\{(x, y): y \geq 2, y \leq 4\}$
Hint:
For convex set, all points should be inside the set.
Given:
$\begin{aligned} &A=x^{2}+y^{2} \geq 1, B=y^{2} \geq x, C=3 x^{2}+4 y^{2} \geq 5 \\ &D=y \geq 2, y \leq 4 \end{aligned}$
Solution :
$\begin{aligned} &A=x^{2}+y^{2} \geq 1 \\ &x^{2}+y^{2}=1 \end{aligned}$
At $(0,0)$ we have $0\geq 1$ , which is wrong. So the region of set A will not contain the origin.

Here, its all points are outside the set. So option (a) is incorrect
$\begin{aligned} &B=y^{2} \geq x \\ &y^{2}=x \end{aligned}$

At $(0,0)$ we have $0\geq 0$ , which is wrong. So the region of set B will not contain the origin.
We observe that option (b) is also incorrect because, it’s all points are outside the set
$\begin{aligned} &C=3 x^{2}+4 y^{2} \geq 5 \\ &\Rightarrow \frac{x^{2}}{\frac{5}{3}}+\frac{y^{2}}{\frac{5}{4}} \geq 1 \end{aligned}$

At $(0,0)$ we have $0\geq 1$ , which is wrong. So, the region of set C will not contain the origin. We observe that option (c) also incorrect. Because it fails the condition of convex set
Now, $D=y \geq 2, y \leq 4$
It is only possible when $y=3$

So, the correct option is (d).

Linear Programming Exercise Multiple Choice Question 4

Answer: (b) $x=\lambda x_{1}+(1-\lambda) \times, 0 \leq \lambda \leq 1$ is an optimal solution.
Hint: As per known condition
Given: $\text {x}_{1}$ and $\text {x}_{2}$ are optimal solution.
Solution:
A set $A_{1}$ is convex if, for any two points $x_{1}, x_{2} \in A \text { and } \lambda \in[0,1]$ imply that $\lambda x_{1}+(1-\lambda) x_{2} \in A$
Since, here $\text {x}_{1}$ and $\text {x}_{2}$ are optimal solution.
Therefore, their convex combination will also be an optimal solution
Thus, option (b) $x=\lambda x_{1}+(1-\lambda) x, 0 \leq \lambda \leq 1$ gives an optimal solution.

Linear Programming Exercise Multiple Choice Question 5

Answer: (d) None of the options
Hint: Having drawn the graph find $\text {Z}_{\text {max}}$
Given: $\text {Z}_{\text {max}}=\text{4x}+\text{2y}$ subject to the constraints $2 x+3 y \leq 18, x+y \geq 10, x, y \geq 0$
Solution:
$2 x+3 y \leq 18$ and $x+y \geq 10$
$\frac{x}{9}+\frac{y}{6} \leq 1$

We observe having drawn the graph the inequalities of equation, $2 x+3 y \leq 18$ is inward and of $x+y \geq 10$ is outward
So, we are not getting feasible region and $\text {Z}_{\text {max}}$ cannot be determined
Thus, the correct option is (d).

Linear Programming Exercise Multiple Choice Question 6

Answer: (c) given by corner points of the feasible region.
Hint : Let $z=2x+3y$
Given :
The optimal value of objective function is attained at the point.
Solution:
Let we have a graph and plot some constraints

Now, we check the options

Given by intersection of inequalities with axes only which is incorrect.
Given by intersection of inequalities with x-axis only which is also incorrect
Given by corners points of feasible region which is correct. Because we get the optimal value in the feasible region.

So, the correct option is (c).

Linear Programming Exercise Multiple Choice Question 7

Answer: (d) None of these
Hint:
Put the extracted intercepts on the graph
Given: $\text{z}_{\text{max}}=4x+3y$ subject to the constraints $3 x+2 y \geq 160,5 x+2 y \geq 200, x+2 y \geq 80, x, y \geq 0$
Solution :
By the given constraints,
$\begin{aligned} &3 x+2 y \geq 160,5 x+2 y \geq 200, x+2 y \geq 80 \\ &\left(\frac{x}{\frac{160}{3}}\right)+\left(\frac{y}{80}\right) \geq 1, \frac{x}{40}+\frac{y}{100} \geq 1 \\ &\frac{x}{80}+\frac{y}{40} \geq 1, x, y \geq 0 \end{aligned}$
Now let’s plot the points in the graph

Graph moves outwards as per given situation. Therefore, we are getting unbounded region. So $Z_{max}$ cannot be determined. Thus, the correct option is (d).

Linear Programming Exercise Multiple Choice Question 8

Answer : (c) $2 x-y \geq 10$
Hint : Draw the graph and puts points on it
Given : $z_{\min }=6 x+10 y$ subject to the constraints $x \geq 6 ; y \geq 2 ; 2 x+y \geq 10 ; x, y \geq 10$
Solution :
$\begin{aligned} &x \geq 6 ; y \geq 2 ; 2 x+y \geq 10 ; x, y \geq 10 \\ &x=6, y=2,2 x+y=10 \end{aligned}$
By the given condition,

The shaded region represent the feasible of the given LPP
We observe that the feasible region is due to constraint $x \geq 6 ; y \geq 2$
Therefore, the redundant constraint is $2x+y\geq 10$ .

Linear Programming Exercise Multiple Choice Question 9

Answer: (c) Infinite number of points
Hint: Firstly convert the inequality into equations
Given: $z_{\max }=4 x+3 y$ subject to the constraints $3 x+4 y \leq 24,8 x+6 y \leq 48, x \leq 5, y \leq 6, x, y \geq 0$
Solution:
Let’s convert the given inequalities into equations, we obtain the following equations,
$3 x+4 y=24,8 x+6 y=48, x=5, y=6, x=0, y=0$
The line $3 x+4 y=24$ meets the coordinate axis at $A(8,0)$ and $B(0,6)$ join these points to obtain the line $3 x+4 y=24$
Clearly, $(0,0)$ satisfies the inequality $3x+4y\leq 24$ . So, the region in $xy$ plane that contains the origin represents the solution set of given equation.
The line $8x+6y=48$ meets the coordinate axis at $C(6,0)$ and $D(0,8)$ join these points to obtain the line $8x+6y=48$
Clearly, $(0,0)$ satisfies the inequality $8x+6y\leq 48$ . So, the region in $xy$ plane that contains the origin represents the solution set of given equation.
$x=5$ is the line passing through $x=5$ in y-axis region represented by $x\geq 0$ and $y\geq 0$ . Since every point in the first quadrant satisfies these in inequations.
So, the first quadrant is the region represented by the inequations.
The corner points of the feasible region are $O(0,0), G(5,0), F\left(5, \frac{4}{3}\right), E\left(\frac{24}{7}, \frac{24}{7}\right)$ and $B(0,6)$
The values of $z$ at these corners points are as follows,

$\text {corner point}$	$\text{z}=\text {4x+3y}$
$O(0,0)$	$4(0)+3(0)=0$
$G(5,0)$	$4(5)+3(0)=20$
$F\left ( 5,\frac{4}{3} \right )$	$4(5)+3\left ( \frac{4}{3} \right )=24$
$E\left ( \frac{24}{7},\frac{24}{7} \right )$	$4(\frac{24}{7})+3(\frac{24}{7})=\frac{196}{7}=24$
$B(0,6)$	$4(0)+3(6)=18$

We see that maximum value of the objective function $z$ is 24 which is at $F\left(5, \frac{4}{3}\right)$ and $E\left(\frac{24}{7}, \frac{24}{7}\right)$ . Thus, the optimal value of $z$ is 24.
Therefore, the given objective function can be subjected at an infinite number of points.
The correct option is (c).

Linear Programming Exercise Multiple Choice Question 10

Answer:
(a) The problem is to be re-evaluated.
Hint:
As per LPP condition
Given:
If the constraints in a linear programming are changed
Solution:
The optimization of the objective function of LPP is governed by the constraints
Therefore, if the constraints in a linear programming problem are changed, then the problem needs to be revaluated.
So, the correct option is (a).

Linear Programming Exercise Multiple Choice Question 11

Answer:
(c) If a LPP admits two optimal solution. It has an infinite number of optimal solution
Hint:
LPP condition
Given:
a) Every LPP admits an optional solution
b) A LPP admits unique optimal solution
c) If a LPP admits two optimal solution. It has an infinite number of optimal solution
d) The set of all feasible solutions of a LPP is not a converse set
Solution:
It is known that the optimal solution of an LPP either exists uniquely, does not exist or exist infinitely.
So, if an LPP admits two optimal solution, it has an infinite number of optimal solution.
Thus, the correct option is (c).

Linear Programming Exercise Multiple Choice Question 12

Answer : (c)
$\{x:|x|=5\}$
Hint:
Convex set is a set in which all points joining the line segment lies inside the set
Given:
a) $\begin{aligned} &\{(x, y): 2 x+5 y<7\} \\ \end{aligned}$
b) $\begin{aligned} &\left\{(x, y): x^{2}+y^{2} \leq 4\right\} \\ \end{aligned}$
c) $\begin{aligned} &\{x:|x|=5\} \\ \end{aligned}$
d) $\begin{aligned} &\left\{(x, y): 3 x^{2}+2 y^{2} \leq 6\right\} \end{aligned}$
Solution :
$\left | x \right |=5$ is not a convex set as any two points from negative and positive x-axis, if are joined will not lie in the set.
Since, option (a), (b) and (d) is a convex set and option (c) is not a convex set. So, the correct option is (c).

Linear Programming Exercise Multiple Choice Question 13

Answer : (b) $x_{1}=2, x_{2}=6, z=36$
Hint :
Convert the inequalities into equation
Given: $z_{\max }=3 x_{1}+5 x_{2}$ Subject to the constraints are
$\begin{aligned} &3 x_{1}+2 x_{2} \leq 18 \\ &x_{1} \leq 4 \\ &x_{2} \leq 6 \\ &x_{1} \geq 0, x_{2} \geq 0 \end{aligned}$
Solution :
By the graphical method,
Now,
$\begin{aligned} &3 x_{1}+2 x_{2} \leq 18 \\ &\frac{x_{1}}{6}+\frac{x_{2}}{9} \leq 1 \end{aligned}$

Checking coordinates,
$\begin{aligned} &\mathrm{At}(0,0) \rightarrow z=0 \\ \end{aligned}$
$\begin{aligned} &\mathrm{At}(4,0) \rightarrow z=12 \\ \end{aligned}$
$\begin{aligned} &\mathrm{At}(4,3) \rightarrow z=27 \\ \end{aligned}$
$\begin{aligned} &\mathrm{At}(2,6) \rightarrow z=36 \end{aligned}$
$\begin{aligned} &\mathrm{At}(0,6) \rightarrow z=30 \\ \end{aligned}$
$\begin{aligned} &z_{\max }=36_{\mathrm{at}}(2,6) \end{aligned}$

So, the correct option is (b).

Linear Programming Exercise Multiple Choice Question 14

Answer: (c) bounded in first quadrant
Hint:
Convert the inequalities into equation
Given:
$x, y \geq 0, y \leq 6, x+y \leq 3$
Solution :
Let’s convert the given inequalities into equations, we obtain
$y=6, x+y=3, x=0, y=0$
$y=6$ is the line passing through $(0,6)$ and parallel to the x-axis. The region below the line $y=6$ will satisfy the given inequalities.
The line $x+y=3$ meets the coordinate axis at $A (3,0)$ and $B (0,3)$ . Join these point to obtain the line $x+y=3$ . Clearly $(0,0)$ satisfies the inequalities $x+y\leq 3$ . So, the region in $xy$ -plane that contains the origin represents the solution set of the given equation.
Region represented by $x\geq 0$ and $y\geq 0$
Since, every point in the first quadrant satisfies these inequalities. So, the first quadrant is the region represented by the inequalities.
So, the correct option is (c).

Linear Programming Exercise Multiple Choice Question 15

Answer : (d) $(40,15)$
Hint :
Convert the given inequalities into equation
Given:
$Z_{max}=x+y$ subject to the constraints $x+2 y \leq 70,2 x+y \leq 95, x, y \geq 0$
Solution:
Let us consider the mentioned constraints as equations for a while,
$x+2y=70$ ....(i)
$2x+y=95$ ....(ii)
Now, graph the equations by transforming the equations to intercept form of line.
Equation (i) dividing throughout by $70$
$\begin{aligned} &\frac{x}{70}+\frac{2 y}{70}=\frac{70}{70} \\ &\frac{x}{70}+\frac{y}{35}=1 \end{aligned}$
The line $x+2y=70$ can be plot in the graph as a line passing through the points, $(70,0)$ and $(0,35)$ as $70$ and $35$ are the intercepts of the line on the x-axis and y-axis respectively.
Similarly, Equation (ii) can be divided by $95$
$\begin{aligned} &\frac{2 x}{95}+\frac{y}{95}=\frac{95}{95} \\ &\frac{x}{\frac{95}{2}}+\frac{y}{95}=1 \end{aligned}$
The line $2x+y=95$ can be plot in the graph as a line passing through the points, $\left ( \frac{95}{2},0 \right )$ and $(0,95)$ as $\frac{95}{2}$ and $95$ are the intercepts of the line on the x-axis and y-axis respectively.
By considering the constraints $x\geq 0$ and $y\geq 0$ , thus clearly shows that the region can only be in the first quadrant. The graph of inequalities will look like,

The points OABC is the feasible region of LPP
Now, form the points O,A,B and C the vertices of polygon formed by the constraints one of the points will provide the maximum solution $z=x+y$
Now, checking the points, O, A, B, and C by substituting in $z=x+y$
$\begin{aligned} &z_{\text {at }} O(0,0)=0+0=0 \\ \end{aligned}$
$z_{\text {at }} A(0,35)=0+35=35 \\$
$z_{\text {at }} B(40,15)=40+15=55 \\$
$z \text { at } C\left(\frac{95}{2}, 0\right)=\frac{95}{2}+0=\frac{95}{2}=47.5$
From the values, it is cler that $z$ maximized at $B(40,15)$ .

Linear Programming Exercise Multiple Choice Quetion 16

Answer:
(c) at any vertex of feasible region
Hint:
As per LPP conditions
Given:
The value of objective function is maximum under linear constraints_____
Solution:
In linear programming problem, we substitute the coordinates of vertices of feasible region in the objective function and then we obtain the maximum or minimum value.
Therefore, the value of objective function is maximum under linear constraints at any vertex of feasible region.
So, the correct option is (c).

Linear Programming Exercise Multiple Choice Question 17

Answer : (d) $q=3p$
Hint:
Find $z$ by the given corner points
Given:
Linear inequalities,
$\\2 x+y \leq 10, x+3 y \leq 15, x, y \geq 0$ are $(0,0),(5,0),(3,4)$ and $(0,5)$
Let $z=p x+q y$ where, $p, q>0$
Solution :
Let's find $z=p x+q y$ by the given corner points

Corner Points	Value of $z$
$(0,0)$	$0$
$(5,0)$	$5p$
$(3,4)$	$3p+4q$
$(0,5)$	$5q$

Now comparing corner points $(3,4)$ and $(0,5)$
$\text {Value on }(3,4)=\text {value on}(0,5)$
$3\text{p}+4\text{q}=5\text{q}$
$3\text{p}=\text{q}$
So, the correct option is (d).

Linear Programming Exercise Multiple Choice Question 18

Answer : (d) $\text{q = 3p}$
Hint : Put $(15,15)$ and $(0,20)$ in $\text {z = px + qy}$
Given : Linear constraints are $(0,10),(5,5),(15,15),(0,20)$
Let $\text {z = px + qy}$ where $\text {p,q}>0$ . $\text {z}_{\text {max}}$ occurs at both points $(15,15)$ and $(0,20)$ ________
Solution :
$\begin{aligned} &z_{\max (15,15)}=z_{\max (0,20)} \\ \end{aligned}$
$\begin{aligned} &p(15)+q(15)=p(0)+q(20) \\ \end{aligned}$
$\begin{aligned} &p(15)=q(20)-q(15) \\ \end{aligned}$
$\begin{aligned} &15 p=5 q \\ \end{aligned}$
$\begin{aligned} &3 p=q \end{aligned}$
So, the correct option is (d).

Linear Programming Exercise Multiple Choice Question 19

Answer : (b) $\text {q = 2p}$
Hint : Put the given corner points in $\text {z = px + qy}$
Given : Linear constraints $(0,3),(1,1),(3,0)$
Let $\text {z = px + qy}$ where $\text {p,q}>0$
Solution:
$\text {z}_{\text {min}}=\text {px + qy}$
By the given corners,
$\begin{aligned} &\mathrm{At}(1,1), z_{1}=p+q \\ \end{aligned}$
$\begin{aligned} &\mathrm{At}(3,0), z_{2}=3 p \end{aligned}$
Now,
$\begin{aligned} &z_{1}=z_{2} \\ \end{aligned}$
$\begin{aligned} &p+q=3 p \\ \end{aligned}$
$\begin{aligned} &q=2 p \end{aligned}$

Linear Programming Exercise Multiple Choice Question 20

Answer: (d) any point on the line segment joining the points $(0,2)$ and $(3,0)$
Hint: Put the corners on $\text {z = 4x + 6y}$
Given: Corner points of the feasible region for an LPP are $(0,2),(3,0),(6,0),(6,8),(0,5)$
Let $\text {z = 4x + 6y}$
Solution:
Let’s put the corners on $\text {z = 4x + 6y}$

Corner points	Corresponding value of $\text {z = 4x + 6y}$
$(0,2)$	12 (minimum)
$(3,0)$	12 (minimum)
$(6,0)$	24
$(6,8)$	72 (maximum)
$(0,5)$	30

The maximum value of $z$ occurs at any point on the line segment joining the points $(0,2)$ and $(3,0)$
So, the correct option is (d).

Linear Programming Exercise Multiple Choice Question 21

Answer : (a) $60$
Hint : Put the given corners point on $\text {z = 4x+6y}$
Given : Corner points of the feasible region for an LPP are $(0,2),(3,0),(6,0),(6,8),(0,5)$
Let $\text {z = 4x+6y}$
Solution :
Let's put the corners on $\text {z = 4x+6y}$

Corner points	Corresponding value of $\text {z = 4x+6y}$
$(0,2)$	12 (minimum)
$(3,0)$	12 (minimum)
$(6,0)$	24
$(6,8)$	72 (maximum)
$(0,5)$	30

According to the question $Z_{\max }-z_{\min }$
$\begin{aligned} &z_{\max }=72 \text { and } z_{\min }=12 \\ \end{aligned}$
$\begin{aligned} &=z_{\max }-z_{\min } \\ \end{aligned}$
$\begin{aligned} &=72-12 \\ \end{aligned}$
$\begin{aligned} &=60 \end{aligned}$
So, the correct option is (a).

Linear Programming Exercise Multiple Choice Question 22

Answer : (b) 12
Hint : Putting the corner points in $z=3 x-4 y$
Given :
Let $z=3 x-4 y$

Solution :

Corner points	$z=3 x-4 y$
$(0,4)$	-16 (minimum)
$(0,0)$	0
$(12,6)$	$12(3)-4(6)=12\text {(maximum)}$

So, the correct option is (c) which is $z_{max}=12$

Linear Programming Exercise Multiple Choice Question 23

Answer : (b) quantity in column B is greater
Hint : Putting the corner point in $z=4 x+3 y$
Given :
Corner points of the feasible region determined by the system of linear constraints are
$(0,0),(0,40),(20,40),(60,20),(60,0)$
The objective finction is $z=4 x+3 y$
Solution :

Corner points	$z=4x+3y$
$(0,0)$	$0$
$(0,40)$	$120$
$(20,40)$	$200$
$(60,20)$	$300\; \text {(maximum)}$
$(60,0)$	$240$

$z_{max}=300<325$
So, the correct option is (b) which is quantity in column B is greater.

Linear Programming Exercise Multiple Choice Question 24

Answer : $(b)\; (0,8)$
Hint : Putting the corner points in $z=3 x-4 y$
Given :
Let $z=3 x-4 y$

Solution :

Corner points	$z=3 x-4 y$
$(5,0)$	$15$
$(6,5)$	$-2$
$(6,8)$	$-14$
$(4,10)$	$-28$
$(0,8)$	$-32 \; \text {(minimum)}$

Minimum of $z=-32$ at $(0,8)$
So, the correct option is (b).

Linear Programming Exercise Multiple Choice Question 25

Answer : (a) $(5,0)$
Hint: Putting the corner points in $z=3 x-4 y$
Given :
Let $z=3 x-4 y$

Solution :

Corner points	$z=3 x-4 y$
$(5,0)$	$15\; \text{(maximum)}$
$(6,5)$	$-2$
$(6,8)$	$-14$
$(4,10)$	$-28$
$(0,8)$	$-32$

Maximum of $z=15$ at $(5,0)$
So, the correct option is (a).

Linear Programming Exercise Multiple Choice Question 26

Answer : (d)
Given let $z=3 x-4 y$
Hint :
Putting the corner points in $z=3 x-4 y$

Solution:

Corner points	$z=3 x-4 y$
$(5,0)$	$15\; \text{(maximum)}$
$(6,5)$	$-2$
$(6,8)$	$-14$
$(4,10)$	$-28$
$(0,8)$	$-32$

Maximum of $z=15$ aat $(5,0)$
Minimum of $z=-32(0,8)$
So maximum of z + minimum of $z=15-32=17$
Hence correct option is (d).

Linear Programming Exercise Multiple Choice Question 27

Answer : (b) half plane that neither contains the origin nor the points on the line $2x + 3y = 6$
Hint:
Convert the inequalities into equation
Given:
The graph of inequality,
$2x + 3y > 6$
Solution:
By the given inequality
$\begin{aligned} &3 y>6-2 x \\ &y>\frac{6-2 x}{3} \end{aligned}$
Now consider $y=\frac{6-2 x}{3}$ and the plot the graph

x	0	3
y	2	0

We used dashed as
$y>\frac{6-2 x}{3}$ as there is no equal to sign
Therefore, $y$ is greater than , $\frac{6-2 x}{3}$ we will shade the upper part because at (0,0) the inequality becomes 0 > 6, which is not correct.
Thus the graph of $2x+3y>6$ drawn among the option (b)
So, the correct option (b), half-plane that neither contains origin nor the points of the line $2x+3y=6$

Linear Programming Exercise Multiple Choice Question 28

Answer:
(b) A linear function to be optimized
Hint:
We know the LPP condition
Given:
The objective function of an LPP is ____
Solution:
The objective of linear programming problem (LPP) is to minimise or maximise the function
So, the correct option is (b) which is a function to be optimized

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Data Administrator

Database professionals use software to store and organise data such as financial information, and customer shipping records. Individuals who opt for a career as data administrators ensure that data is available for users and secured from unauthorised sales. DB administrators may work in various types of industries. It may involve computer systems design, service firms, insurance companies, banks and hospitals.

4 Jobs Available

Bio Medical Engineer

The field of biomedical engineering opens up a universe of expert chances. An Individual in the biomedical engineering career path work in the field of engineering as well as medicine, in order to find out solutions to common problems of the two fields. The biomedical engineering job opportunities are to collaborate with doctors and researchers to develop medical systems, equipment, or devices that can solve clinical problems. Here we will be discussing jobs after biomedical engineering, how to get a job in biomedical engineering, biomedical engineering scope, and salary.

4 Jobs Available

Ethical Hacker

A career as ethical hacker involves various challenges and provides lucrative opportunities in the digital era where every giant business and startup owns its cyberspace on the world wide web. Individuals in the ethical hacker career path try to find the vulnerabilities in the cyber system to get its authority. If he or she succeeds in it then he or she gets its illegal authority. Individuals in the ethical hacker career path then steal information or delete the file that could affect the business, functioning, or services of the organization.

3 Jobs Available

GIS Expert

GIS officer work on various GIS software to conduct a study and gather spatial and non-spatial information. GIS experts update the GIS data and maintain it. The databases include aerial or satellite imagery, latitudinal and longitudinal coordinates, and manually digitized images of maps. In a career as GIS expert, one is responsible for creating online and mobile maps.

3 Jobs Available

Data Analyst

The invention of the database has given fresh breath to the people involved in the data analytics career path. Analysis refers to splitting up a whole into its individual components for individual analysis. Data analysis is a method through which raw data are processed and transformed into information that would be beneficial for user strategic thinking.

Data are collected and examined to respond to questions, evaluate hypotheses or contradict theories. It is a tool for analyzing, transforming, modeling, and arranging data with useful knowledge, to assist in decision-making and methods, encompassing various strategies, and is used in different fields of business, research, and social science.

3 Jobs Available

Geothermal Engineer

Individuals who opt for a career as geothermal engineers are the professionals involved in the processing of geothermal energy. The responsibilities of geothermal engineers may vary depending on the workplace location. Those who work in fields design facilities to process and distribute geothermal energy. They oversee the functioning of machinery used in the field.

3 Jobs Available

Database Architect

If you are intrigued by the programming world and are interested in developing communications networks then a career as database architect may be a good option for you. Data architect roles and responsibilities include building design models for data communication networks. Wide Area Networks (WANs), local area networks (LANs), and intranets are included in the database networks. It is expected that database architects will have in-depth knowledge of a company's business to develop a network to fulfil the requirements of the organisation. Stay tuned as we look at the larger picture and give you more information on what is db architecture, why you should pursue database architecture, what to expect from such a degree and what your job opportunities will be after graduation. Here, we will be discussing how to become a data architect. Students can visit NIT Trichy, IIT Kharagpur, JMI New Delhi.

3 Jobs Available

Remote Sensing Technician

Individuals who opt for a career as a remote sensing technician possess unique personalities. Remote sensing analysts seem to be rational human beings, they are strong, independent, persistent, sincere, realistic and resourceful. Some of them are analytical as well, which means they are intelligent, introspective and inquisitive.

Remote sensing scientists use remote sensing technology to support scientists in fields such as community planning, flight planning or the management of natural resources. Analysing data collected from aircraft, satellites or ground-based platforms using statistical analysis software, image analysis software or Geographic Information Systems (GIS) is a significant part of their work. Do you want to learn how to become remote sensing technician? There's no need to be concerned; we've devised a simple remote sensing technician career path for you. Scroll through the pages and read.

3 Jobs Available

Budget Analyst

Budget analysis, in a nutshell, entails thoroughly analyzing the details of a financial budget. The budget analysis aims to better understand and manage revenue. Budget analysts assist in the achievement of financial targets, the preservation of profitability, and the pursuit of long-term growth for a business. Budget analysts generally have a bachelor's degree in accounting, finance, economics, or a closely related field. Knowledge of Financial Management is of prime importance in this career.

4 Jobs Available

Data Analyst

3 Jobs Available

Underwriter

An underwriter is a person who assesses and evaluates the risk of insurance in his or her field like mortgage, loan, health policy, investment, and so on and so forth. The underwriter career path does involve risks as analysing the risks means finding out if there is a way for the insurance underwriter jobs to recover the money from its clients. If the risk turns out to be too much for the company then in the future it is an underwriter who will be held accountable for it. Therefore, one must carry out his or her job with a lot of attention and diligence.

3 Jobs Available

5 Jobs Available

The word “choreography" actually comes from Greek words that mean “dance writing." Individuals who opt for a career as a choreographer create and direct original dances, in addition to developing interpretations of existing dances. A Choreographer dances and utilises his or her creativity in other aspects of dance performance. For example, he or she may work with the music director to select music or collaborate with other famous choreographers to enhance such performance elements as lighting, costume and set design.

2 Jobs Available

A multimedia specialist is a media professional who creates, audio, videos, graphic image files, computer animations for multimedia applications. He or she is responsible for planning, producing, and maintaining websites and applications.

2 Jobs Available

Welding Engineer

5 Jobs Available

QA Manager

4 Jobs Available

Quality Controller

A quality controller plays a crucial role in an organisation. He or she is responsible for performing quality checks on manufactured products. He or she identifies the defects in a product and rejects the product.

A quality controller records detailed information about products with defects and sends it to the supervisor or plant manager to take necessary actions to improve the production process.

3 Jobs Available

An AWS Solution Architect is someone who specializes in developing and implementing cloud computing systems. He or she has a good understanding of the various aspects of cloud computing and can confidently deploy and manage their systems. He or she troubleshoots the issues and evaluates the risk from the third party.

4 Jobs Available

Azure Administrator

An Azure Administrator is a professional responsible for implementing, monitoring, and maintaining Azure Solutions. He or she manages cloud infrastructure service instances and various cloud servers as well as sets up public and private cloud systems.