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The Central Board of Secondary Education (CBSE) is conducting the CBSE board exam from February 15 to March 18, 2025. According to the CBSE class 10 datasheet 2025, CBSE 10th basic math and slandered math were scheduled on March 10, 2025, from 10:30 am to 1:30 pm which is concluded.CBSE 10th mathematics paper was of moderate difficulty this year and slightly tougher than the last year. Students who have gone through the NCERT and practised the CBSE class 10 maths sample paper can solve the paper easily.
Students can download the CBSE 10th math question paper PDF 2025 from this page along with the solution and answer key of all the questions. CBSE class 10 math answer key will help students calculate the final marks and grades by calculating the total number.
Particulars | Details |
---|---|
Conducting Body |
CBSE |
Subject |
Mathematics (Basic and Standerd) |
Mode |
Offline |
Date |
March 10, 2025 |
Duration |
3 Hours |
Medium |
English / Hindi |
Question Types |
MCQs, Short & Long Answers |
Theory Marks |
80 |
Internal Assessment |
20 |
Total Marks |
100 |
Passing Marks |
33% (in aggregate) |
Difficulty Level |
Moderate |
Students can download the class 10th maths question paper PDF from here and practice to become familiar with the exam trends, types of questions, and marking schemes. The CBSE mathematics question paper PDF link will be activated soon here.
Question paper | Download PDF |
---|---|
CBSE Class 10 Mathematics Basic Question Paper 2025 |
Available Soon |
CBSE Class 10 Mathematics Standard Question Paper and Solution 2025 |
Some of the CBSE class 10 mathematics standard set 2 of QP code: 30/4/2 are given below:
1. Which of the following statements is true for a polynomial
(a)
(b)
(c)
(d)
2. A pair of dice is thrown once. The probability that the sum of numbers appearing on top faces is at least 4 is :
(a)
(b)
(c)
(d)
5. The value of '
(a) 2
(b) -2
(c)
(d)
6. The distance of which of the following points from the origin is less than 5 units?
(a)
(b)
(c)
(d)
7. The number of red balls in a bag is 10 more than the number of black balls. If the probability of drawing a red ball at random from this bag is
(a) 50
(b) 60
(c) 80
(d) 40
8. The value of '
(a) -6 only
(b) 6 only
(c)
(d) Any real number except
11. Which of the following statements is true?
(a)
(d)
(c)
12. A 30 m long rope is tightly stretched and tied firm the top of pole to the ground. If the rope makes an angle of
(b)
(a)
(c) 15 m are 10 and 13 respectively.
Students who have appeared in the CBSE 10th maths exam must match their answer with the CBSE class 10 maths answer key 2025 which is given below. Check all sets of answer keys and calculate the final score and grade based on the final marks.
Question number | Correct Option | Question number | Correct Option |
1 | D | 11 | C |
2 | D | 12 | D |
3 | C | 13 | C |
4 | C | 14 | C |
5 | D | 15 | B |
6 | D | 16 | A |
7 | A | 17 | A |
8 | C | 18 | B |
9 | C | 19 | B |
10 | C | 20 | D |
Check the detailed CBSE 10th mathematics standard set 2 solutions of QP code 30/4/2, starting from section B.
This section consists of 5 questions of 2 marks each.
21. A) Find the value of
Solution:
Expanding each term,
Since
Using the identity
Similarly,
Since
Using the identity
Adding both terms (1) and (2),
Using
Equating to the given expression.
Hence, the value of x is 7.
21. (B) Evaluate the following:
Solution:
Using
Hence,
22. Saima and Aryaa were born in the month of June in the year 2012. Find the probability that :
(i) they have different dates of birth.
(ii) they have the same date of birth.
Solution:
June has 30 days, so each child can be born on any of these 30 days.
The total number of ways to assign birthdates to both Saima and Aryaa is
The number of ways they can have the same birthdate is 30 (choosing one day for both).
The probability that they have the same birthdate is
The probability that they have different birthdates is
Thus,
(i) Probability that they have different birthdates
(ii) Probability that they have the same birthdate
23. Solve the following system of equations algebraically :
Solution:
Adding both equations:
Subtracting the second equation from the first:
Solving the two equations:
Adding both equations:
Substituting
Thus, the solution is
24. (A) A 1.5 m tall boy is walking away from the base of a lamp post which is 12 m high, at the speed of
Solution:
Let the height of the lamp post be
Let the distance of the boy from the base of the lamp post after 3 seconds be
Since the boy walks at
Using the property of similar triangles,
Substituting values:
Cross multiplying:
Thus, the length of the shadow after 3 seconds is 1.07 m.
24. (B) In parallelogram
Solution:
In parallelogram
Since
In
1. Angle
2. Angle
By AA similarity criterion,
Thus, it is proved that
25. Find the coordinates of the point
Solution:
Using the section formula, the coordinates of a point dividing a line segment
Here, point
Given:
Applying the external section formula:
Thus, the coordinates of
SECTION - C
This section consists of 6 questions of 3 marks each.
26.
Solution:
Given that
We need to find a quadratic polynomial whose zeroes are
Sum of new zeroes:
Product of new zeroes:
The required quadratic polynomial is:
27. Rectangle
Solution:
Since the rectangle
A necessary condition for a rectangle to have an inscribed circle is that the sum of its opposite sides must be equal, i.e.,
Since in a rectangle, opposite sides are equal, this simplifies to:
This means the length and breadth of the rectangle are equal, which implies that
Now, let the side length of the square be
Since the circle is inscribed, its diameter is equal to the side length of the square. The given radius of the circle is 10 cm, so the diameter is:
Thus, the side length of the square is:
The perimeter of square
Thus,
28. (A) Prove that
Solution:
Let us assume, for contradiction, that
where
Squaring both sides:
Multiplying both sides by
This shows that
Let
Dividing both sides by 2 :
This shows that
Since both
Thus, our initial assumption that
Therefore,
28. (B) Let
Solution:
The HCF is obtained by taking the lowest power of each prime factor in
-
-
-
The lowest powers of
The LCM is obtained by taking the highest power of each prime factor. The highest powers are
To verify the condition:
Since
29. The two angles of a given triangle are in the ratio
Solution:
Let the two angles of the triangle be
Since the sum of the angles in a triangle is always
Substituting
Thus, the three angles of the triangle are
30.
Solution:
Since
The slope of
The slope of
By the perpendicularity condition,
Using the identity
Multiplying both sides by
Rearranging,
This is the required relationship between
For
Thus, the possible values of
31. (A) Prove that
Solution:
We need to prove the identity:
Rewriting the right-hand side:
This means we need to prove:
Cross multiplying:
Expanding both sides:
Expanding
Since
Both sides simplify to:
Since both sides are equal, the given equation is proven:
Hence Proved
31. (B) If
Solution:
We are given the following equations:
We are tasked with proving that:
Subtract the second equation from the first:
Simplifying the left-hand side:
This gives:
Now, add the first and second equations:
Simplifying the left-hand side:
This gives:
Next, recall the identity
Simplifying:
Multiplying both sides by 2 :
Solving for
Now, using the identity
Substitute the expression for
Now, compute
Thus, the required identity is proven:
Hence Proved.
To calculate the total marks based on the answer key, follow the steps given below:
Suggested Articles:
The CBSE Class 10 Maths Exam was scheduled for March 10, 2025.
The exam duration was 3 hours long.
Students need to score at least 33% in aggregate to pass.
The paper includes MCQs, short answer, and long answer questions.
The exam is considered moderate and focuses on concept-based questions with application-based problem-solving.
The difficulty level of maths standard paper 2025 was moderate.
Set 3 was overall difficult as compared to other sets of CBSE 10th maths paper 2025.
Hello
Since you are a domicile of Karnataka and have studied under the Karnataka State Board for 11th and 12th , you are eligible for Karnataka State Quota for admission to various colleges in the state.
1. KCET (Karnataka Common Entrance Test): You must appear for the KCET exam, which is required for admission to undergraduate professional courses like engineering, medical, and other streams. Your exam score and rank will determine your eligibility for counseling.
2. Minority Income under 5 Lakh : If you are from a minority community and your family's income is below 5 lakh, you may be eligible for fee concessions or other benefits depending on the specific institution. Some colleges offer reservations or other advantages for students in this category.
3. Counseling and Seat Allocation:
After the KCET exam, you will need to participate in online counseling.
You need to select your preferred colleges and courses.
Seat allocation will be based on your rank , the availability of seats in your chosen colleges and your preferences.
4. Required Documents :
Domicile Certificate (proof that you are a resident of Karnataka).
Income Certificate (for minority category benefits).
Marksheets (11th and 12th from the Karnataka State Board).
KCET Admit Card and Scorecard.
This process will allow you to secure a seat based on your KCET performance and your category .
check link for more details
https://medicine.careers360.com/neet-college-predictor
Hope this helps you .
Hello Aspirant, Hope your doing great, your question was incomplete and regarding what exam your asking.
Yes, scoring above 80% in ICSE Class 10 exams typically meets the requirements to get into the Commerce stream in Class 11th under the CBSE board . Admission criteria can vary between schools, so it is advisable to check the specific requirements of the intended CBSE school. Generally, a good academic record with a score above 80% in ICSE 10th result is considered strong for such transitions.
hello Zaid,
Yes, you can apply for 12th grade as a private candidate .You will need to follow the registration process and fulfill the eligibility criteria set by CBSE for private candidates.If you haven't given the 11th grade exam ,you would be able to appear for the 12th exam directly without having passed 11th grade. you will need to give certain tests in the school you are getting addmission to prove your eligibilty.
best of luck!
According to cbse norms candidates who have completed class 10th, class 11th, have a gap year or have failed class 12th can appear for admission in 12th class.for admission in cbse board you need to clear your 11th class first and you must have studied from CBSE board or any other recognized and equivalent board/school.
You are not eligible for cbse board but you can still do 12th from nios which allow candidates to take admission in 12th class as a private student without completing 11th.
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