Bihar Board 10th Math Question Paper 2025 (18 Feb): Objective & Subjective Questions Analysis
  • Bihar Board 10th Exam
  • Bihar Board 10th Math Question Paper 2025 (18 Feb): Objective & Subjective Questions Analysis

Bihar Board 10th Math Question Paper 2025 (18 Feb): Objective & Subjective Questions Analysis

Vishal kumarUpdated on 17 Mar 2025, 11:29 AM IST

Bihar School Examination Board (BSEB) is responsible for conducting matrics and intermediate examinations across the state. The Bihar board class 10 examination started on 17 February with two shifts (morning and evening), which will conclude on 25 February 2025.

This Story also Contains

  1. Bihar Board Class 10 Mathematics Exam 2025 Overview
  2. BSEB Class 10 Math Exam 2025 Analysis
  3. Bihar Board Class 10 Mathematics Question Paper 2025
  4. Bihar Board Matric Mathematics Question Paper Previous Year
  5. Bihar Board Class 10 Mathematics Answer Key 2025
Bihar Board 10th Math Question Paper 2025 (18 Feb): Objective & Subjective Questions Analysis
Bihar Board 10th Math Question Paper 2025

The Bihar board class 10 mathematics (subject code- 110) examination is scheduled for 18 February (Tuesday), today in both the shifts from 9:30 am to 12:45 pm and 2:00 pm to 5:15 pm, respectively. The Bihar board matric mathematics examination 2025 both morning and evening shifts is over now. The level of difficulty of the Bihar board class 10 mathematics exam was moderate. Arithmetic Progression questions were dominating in the paper. Download the Bihar board class 10 maths question paper, answer key with details explanation and details analysis of BSEB matric maths exam 2025 scoring down to this page.

Bihar Board Class 10 Mathematics Exam 2025 Overview

Below is the Bihar Board matric examination overview, which contains exam information, the number of questions, and all the necessary details.

Exam Details

Information

Exam Name

BSEB Class 10th Mathematics Exam 2025

Conducting Body

Bihar School Examination Board (BSEB)

Exam Mode

Offline (Pen & Paper)

Total Marks

100

Section A (MCQ)

50

Section B

50

Exam Duration

3 Hours 15 Minutes

Total Questions

138 (100+30+8)

Question Booklet Sections

Section A & Section B

Passing Marks

30% (24/80 in Theory & 6/20 in Internal)

BSEB Class 10 Math Exam 2025 Analysis

The BSEB Class 10 Mathematics Exam 2025 was moderate-level, with almost 45% of the questions requiring two-step calculations and formula application.

Let's have a look at the level of difficulty of secondary school examination 2025 math from the table given below:

Difficulty LevelPercentageDescription
Easy40%

Formula-based, direct substitution, minimal calculation.

Moderate45%

Two-step calculations, direct application of formulas.

Challenging15%

Concept-heavy, multi-step problem-solving required.

The stacked bar chart below represents the number of questions asked in the BSEB Class 10 Mathematics Examination 2025, categorized by difficulty levels across different topics.output

Bihar Board Class 10 Mathematics Question Paper 2025

BSEB secondary school examination 2025 math is successfully over for shift 1 now. Click on the link below to download the BSEB class 10 maths question paper PDF 2025.

BSEB class 10 Mathematics Question paper

Download PDF

Bihar Board Class 10 Mathematics Question Paper

Click Here

1739881808312

Question 1. $\sin \left(90^{\circ}-A\right)=\cos A$
(A) $\sin A$
(B) $\cos A$
(C) $\tan A$
(D) $\sec A$

Question 2. If $\alpha=\beta=60^{\circ}$ then the value of $\cos (\alpha-\beta)$ is
(A) $\frac{1}{2}$
(B) 1
(C) 0
(D) 2

Question 3. If $\theta=45^{\circ}$ then the value of $\sin \theta+\cos \theta$ is
(A) $\frac{1}{\sqrt{2}}$
(B) $\sqrt{2}$
(C) $\frac{1}{2}$
(D) 1

Question 4. If $A=30^{\circ}$ then the value of $\frac{2 \tan A}{1-\tan ^2 A}$ is
(A) $2 \tan 30^{\circ}$
(B) $\quad \tan 60^{\circ}$
(C) $2 \tan 60^{\circ}$
(D) $\tan 30^{\circ}$

Question 5. If $\tan \theta=\frac{12}{5}$ then the value of $\sin \theta$ is
(A) $\frac{5}{12}$

(B) $\frac{12}{13}$
(C) $\frac{5}{13}$
(D) $\frac{12}{5}$

Question 6. $
\frac{\cos 59^{\circ}}{\sin 31^{\circ}} \times \frac{\tan 80^{\circ}}{\cot 10^{\circ}}=
$

(A) $\frac{1}{\sqrt{2}}$

(B) 1
(C) $\frac{\sqrt{3}}{2}$
(D) $\frac{1}{2}$

Question 7. If $\tan 25^{\circ} \times \tan 65^{\circ}=\sin A$ then the value of $A$ is
(A) $25^{\circ}$
(B) $65^{\circ}$
(C) $90^{\circ}$
(D) $45^{\circ}$

Question 8. If $\cos \theta=x$ then $\tan \theta=$
(A) $\frac{\sqrt{1+x^2}}{x}$
(1) $\frac{\sqrt{1-x^2}}{x}$
(C) $\sqrt{1-x^2}$
(D) $\frac{x}{\sqrt{1-x^2}}$

Question 9. $\quad\left(1-\cos ^4 \theta\right)=$
(A) $\cos ^2 \theta\left(1-\cos ^2 \theta\right)$
(B4) $\sin ^2 \theta\left(1+\cos ^2 \theta\right)$
(C) $\sin ^2 \theta\left(1-\sin ^2 \theta\right)$.
(D) $\sin ^2 \theta\left(1+\sin ^2 0\right)$

Question 10. What is the form of a point lying on $y$-axis ?
(A) $(y, 0)$
(B) $(2, y)$
(C) $(0, x)$
(D) None of these

Bihar Board Matric Mathematics Question Paper Previous Year

Check the Bihar Board Matric previous year's question paper, which is one of the essential resources to score good marks in future Bihar Board matric exams.

BSEB Class 10 Maths Previous year Question PaperDownload PDF

BSEB Class 10 Maths Question Paper 2024

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BSEB Class 10 Maths Question Paper 2023

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BSEB Class 10 Maths Question Paper 2022

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BSEB Class 10 Maths Question Paper 2021

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BSEB Class 10 Maths Question Paper 2020

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Bihar Board Class 10 Mathematics Answer Key 2025

Bihar Board class 10 maths shift 1 paper was concluded and shift 2 is going according to the scheduled time. Bihar Board class 10 mathematics Answer key of question paper set F is given below.

Bihar Board Class 10 Maths Answer Key 2025 (SET- F): Section A
Question NumberCorrect OptionQuestion Number

Correct Option

1B11C
2B12A
3B13C
4B14B
5B15B
6B16A
7C17D
8B18B
9B19C
10C20C

BSEB Class 10 Maths Solution 2025: Section-A

(Q1)

We use the complementary angle identity of trigonometry:

$
\sin \left(90^{\circ}-A\right)=\cos A
$


Comparing with the given expression, we see that:

$
\sin \left(90^{\circ}-A\right)=\cos A
$

Hence, the answer is the option (2).

(Q2.)

Given:

$
\alpha=\beta=60^{\circ}
$


We use the trigonometric identity:

$
\cos (\alpha-\beta)=\cos 0^{\circ}
$


Since $\cos 0^{\circ}=1$, we get:

$
\cos \left(60^{\circ}-60^{\circ}\right)=\cos 0^{\circ}=1
$
Hence, the answer is the option (2).

(Q3.)

Given:

$
\theta=45^{\circ}
$


We calculate:

$
\sin 45^{\circ}+\cos 45^{\circ}
$


Since,

$
\sin 45^{\circ}=\frac{1}{\sqrt{2}}, \quad \cos 45^{\circ}=\frac{1}{\sqrt{2}}
$


Adding these values,

$
\sin 45^{\circ}+\cos 45^{\circ}=\frac{1}{\sqrt{2}}+\frac{1}{\sqrt{2}}=\frac{2}{\sqrt{2}}=\sqrt{2}
$
Hence, the answer is the option (2),

Ans.4)

We need to evaluate:

$
\frac{2 \tan A}{1-\tan ^2 A}
$


Given $A=30^{\circ}$, we substitute $\tan 30^{\circ}=\frac{1}{\sqrt{3}}$ :

$
\frac{2 \times \frac{1}{\sqrt{3}}}{1-\left(\frac{1}{\sqrt{3}}\right)^2}
$


Calculating the denominator:

$
1-\frac{1}{3}=\frac{3}{3}-\frac{1}{3}=\frac{2}{3}
$

Thus,

$
\frac{\frac{2}{\sqrt{3}}}{\frac{2}{3}}=\frac{2}{\sqrt{3}} \times \frac{3}{2}=\frac{6}{2 \sqrt{3}}=\frac{3}{\sqrt{3}}=\sqrt{3}
$


Since $\tan 60^{\circ}=\sqrt{3}$, we conclude:

$
\frac{2 \tan 30^{\circ}}{1-\tan ^2 30^{\circ}}=\tan 60^{\circ}
$
Hence, the answer is the option (2).

Ans.5)

We are given:

$
\tan \theta=\frac{12}{5}
$


Using the identity:

$
\tan \theta=\frac{\sin \theta}{\cos \theta}
$

we consider a right-angled triangle where the opposite side is 12 and the adjacent side is 5 . Using the Pythagorean theorem, the hypotenuse is:

$
r=\sqrt{12^2+5^2}=\sqrt{144+25}=\sqrt{169}=13
$

Hence, the answer is the option (2).

Ans 6)

We simplify the given expression:

$
\frac{\cos 59^{\circ}}{\sin 31^{\circ}} \times \frac{\tan 80^{\circ}}{\cot 10^{\circ}}
$


Using Complementary Angle Identities
We know that:

$
\cos 59^{\circ}=\sin \left(90^{\circ}-59^{\circ}\right)=\sin 31^{\circ}
$

Thus,

$
\frac{\tan 80^{\circ}}{\cot 10^{\circ}}=\tan 80^{\circ} \times \tan 10^{\circ}
$


Using the identity:

$
\tan \left(90^{\circ}-x\right)=\cot x
$

we get:

$
\tan 80^{\circ}=\cot 10^{\circ}
$

So,

$
\tan 80^{\circ} \times \tan 10^{\circ}=\cot 10^{\circ} \times \tan 10^{\circ}=1
$

Hence, the answer is the option (2).

Ans.7)

We are given:

$
\tan 25^{\circ} \times \tan 65^{\circ}=\sin A
$
We know that:

$
\tan \left(90^{\circ}-x\right)=\cot x
$


Thus,

$
\tan 65^{\circ}=\cot 25^{\circ}
$

$A=90^{\circ}$

Hence, the answer is the option (3).

Ans.8)

We are given:

$
\cos \theta=x
$
From the fundamental identity of trigonometry:

$
\sin ^2 \theta+\cos ^2 \theta=1
$


Substituting $\cos \theta=x$ :

$
\begin{aligned}
& \sin ^2 \theta+x^2=1 \\
& \sin ^2 \theta=1-x^2 \\
& \sin \theta=\sqrt{1-x^2}
\end{aligned}
$
We use the definition of tangent:

$
\tan \theta=\frac{\sin \theta}{\cos \theta}
$


Substituting values:

$
\tan \theta=\frac{\sqrt{1-x^2}}{x}
$
Hence, the answer is the option (2).

Ans.9)

We start with the given expression:

$
1-\cos ^4 \theta
$
We use the identity:

$
a^2-b^2=(a-b)(a+b)
$


Rewriting $\cos ^4 \theta$ as $\left(\cos ^2 \theta\right)^2$, we get:

$
1-\cos ^4 \theta=\left(1-\cos ^2 \theta\right)\left(1+\cos ^2 \theta\right)
$

Hence, the answer is the option (2).

Ans.10)

A point lying on the $y$-axis means that its $x$-coordinate is always 0 because any point on the $y$-axis has no horizontal displacement.

Thus, the general form of a point on the $y$-axis is:

$
(0, y)
$
Hence, the answer is the option (3).

To access the complete Bihar board class 10 mathematics answer key with a proper explanation, click on the link below, which is free of charge.

BSEB Class 10 Mathematics Paper Answer Key 2025Download PDF

BSEB Class 10 Mathematics Answer key with Solution

Click Here

Also Check:

Frequently Asked Questions (FAQs)

Q: How many MCQ questions are there in the Bihar board class 10?
A:

A total of 100 MCQs are present for Bihar board class 10.

Q: How many subjects are there in Bihar board class 10?
A:

A total of 6 subjects are present in the Bihar board class 10 examination.

Q: How many questions were present in the Bihar board math exam 2025?
A:

A total of 138 questions were present from both sections with 100 multiple-choice questions.

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