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JSTSE 2024-25 - The Directorate of Education, Delhi conducts the Junior Science Talent Search Examination. JSTSE 2024-25 is a single-level scholarship examination. A JSTSE application is available to students who are studying in class 9 and have attained 65% or more marks in class 8.
The JSTSE application form for 2024-25 can be submitted by eligible students through their respective schools. JSTSE 2024-25 exams will be held in December 2024, tentatively. For the JSTSE scholarship 2024-25, approximately 150 students will be selected. Check the complete article for comprehensive information about the Junior Science Talent Search Examination 2024-25.
Also read about other available Scholarships in India
The JSTSE Exam 2024-25 dates and other dates are listed in the following table:
Events | Tentative dates |
Notification release date | September 2024 |
Application start date | September 2024 |
Last date to submit an application | First week of October 2024 |
Admit card availability | December 2024 |
Exam date | December 2024 |
Answer key date | First week of January 2025 |
Result date | Second week of March 2025 |
Exam name | Junior Science Talent Search Examination |
Exam short name | JSTSE 2024-25 |
Conducting body | Science Branch of the Directorate of Education, Delhi |
Official website | |
Exam date | December 2024 (Tentative) |
Selection criteria | Merit-based |
Result date | Second week of March 2025 |
Students may apply for the Junior Science Talent Search Examination 2024–2025 if they meet the eligibility requirements listed below:
He/She should be enrolled in Class 9 during the academic year 2024-25, attending a government, government-aided, or recognized private school, whether aided or unaided.
The student should have successfully completed their Class 8 examinations during the academic year 2022-23 and obtained a minimum of 65% marks.
There is no minimum annual income limit applicable for JSTSE 2024-25.
There are no provisions for relaxation in minimum marks for SC/ST/PH/OBC/EWS category students.
Class 10 students can apply for the NTSE exam.
An application form for this exam can be found online in the form of a PDF file. Interested students can download the JSTSE 2024-25 registration forms from the official website. Through the respective schools, applications will be accepted in an offline mode.
Students must print out three copies of the application form.
Every student is required to complete three forms.
Next, they should provide the necessary documents in the attachment.
After that, submit the JSTSE 2024–25 application forms to the respective school authority.
Before the deadline, which is expected to fall in the last week of September 2024, school officials will attest the application form and submit the same DEO (Science Branch).
JSTSE exam 2024-25 does not have a prescribed syllabus. Nevertheless, the difficulty level of the exam is based on the level of class 9 students. The questions are based on the NCERT class 9 syllabus. The JSTSE 2024-25 will consist of two papers. The first paper will consist of general knowledge questions, while the second paper will include questions from science and mathematics. JSTSE examinations 2024-25 do not have negative marking and the exam will last 200 minutes from 10am to 1:20pm. The PH students will be given 30 extra minutes.
Particular | Paper-I | Paper-II |
Paper name | General Knowledge (GK) | Scholastic Aptitude Test (SAT) |
Number of questions | 50 | 150 |
Number of marks | 50 | 150 |
Duration | 50 minutes | 150 minutes |
Negative marking | 0 | 0 |
Qualifying marks | 40% | 40% |
In order to practise with various questions, students should download and solve previous year's question papers and sample papers.
Based on the JSTSE 2024-25 Syllabus, these sample papers will help students understand important topics, the types of questions asked in the examination, and various other aspects of the examination.
Following the completion of JSTSE sample papers, it's crucial to analyse one's performance. This helps in identifying any shortcomings and provides an opportunity to address and improve them, ultimately aiding in better preparation for the examination.
The Science Branch of the DoE is scheduled to release the JSTSE answer key 2024-25 during the first week of January 2025. This answer key will be made available on the official website in PDF format and will contain the correct answers for all the questions posed in the examination. Students can utilise the official JSTSE 2024-25 answer key to estimate their marks.
The results of the JSTSE exam 2024-25 will be announced in the second week of March 2025.
It will be announced through a merit list, which contains the names of the scholarship recipients.
JSTSE 2024-25 results will be made available in pdf format on the official website (edudel.nic.in).
A total of 150 students will be selected for the scholarship in JSTSE 2024-25.
For successful completion of this exam, each student must receive 40% in each subject. The authority withholds the cutoff marks. However, we have tabulated the minimum and maximum scores received by selected students in previous academic years. Cut off marks can also be used to describe minimum scores.
Particular | Details |
Maximum marks | 159 |
Minimum marks | 126 |
Scholarships will only be awarded to shortlisted students.
The marks scored in the JSTSE 2024-25 examination will determine the selection of around 150 students.
The amount of the JSTSE scholarship is not stated on the official website.
In any case, students should know that the Directorate of Education in Delhi will award a good amount of scholarship money and a certificate to qualifying candidates.
Yes, private school students can apply through their respective schools for the JSTSE exam 2024-25.
No, class 8 children are not qualified to take the JSTSE exam. The NMMS exam, however, is open to them.
To qualify, one must earn a minimum of 40% in both the GK and SAT paper.
Students selected for JSTSE 2024-25 will get a scholarship award and a certificate.
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