JEE Main Important Physics formulas
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The multiplication table for 11 is among the simplest to memorise. One of the simplest strategies to improve your mental calculation is to learn multiplication tables from 1 to 20. Thus it's important to memorise them. Learning multiplication tables can save a lot of time during exams because, most of the time, students are not permitted to bring calculators. The 11 multiplication table is among the simplest to learn of all the tables from 1 to 20.
Every youngster in lower elementary school needs to learn how to multiply. Complex computations are built on the basis of the four fundamental operations, which also include multiplication. Learning the tables promotes a child's calculation speed and sparks their interest in word problem-solving. Learning division is made simple once a solid multiplication foundation has been established.
One of the simplest math tables that we may memorise is the table of the number 11. After we have mastered the up-to-10 times tables completely, we should understand that multiplication is simply repeated addition. We will improve our mental maths speed as a result.
Multiple of 11 are created by multiplying n natural integers by 11. In other words, the numbers that can be divided by 11 without any remainder are the multiples of 11. We can multiply 11 by n natural numbers to get n different multiples of 11. Multiples of 11 are fairly simple to determine.
Addition of 11 | Subtraction of 11 | Multiplication of 11 | Division of 11 |
1 + 11 = 12 | 12 - 11 = 1 | 1 x 11 = 11 | 11 ÷ 11 = 1 |
2 + 11 = 13 | 13 - 11 = 2 | 2 x 11 = 22 | 22 ÷ 11 = 2 |
3 + 11 = 14 | 14 - 11 = 3 | 3 x 11 = 33 | 33 ÷ 11 = 3 |
4 + 11 = 15 | 15 - 11 = 4 | 4 x 11 = 44 | 44 ÷ 11 = 4 |
5 + 11 = 16 | 16 - 11 = 5 | 5 x 11 = 55 | 55 ÷ 11 = 5 |
6 + 11 = 17 | 17 - 11 = 6 | 6 x 11 = 66 | 66 ÷ 11 = 6 |
7 + 11 = 18 | 18 - 11 = 7 | 7 x 11 = 77 | 77 ÷ 11 = 7 |
8 + 11 = 19 | 19 - 11 = 8 | 8 x 11 = 88 | 88 ÷ 11 = 8 |
9 + 11 = 20 | 20 - 11 = 9 | 9 x 11 = 99 | 99 ÷ 11 = 9 |
10 + 11 = 21 | 21 - 11 = 10 | 10 x 11 = 110 | 110 ÷ 11 = 10 |
11 + 11 = 22 | 22 - 11 = 11 | 11 x 11 = 121 | 121 ÷ 11 = 11 |
12 + 11 = 23 | 23 - 11 = 12 | 12 x 11 = 132 | 132 ÷ 11 = 12 |
13 + 11 = 24 | 24 - 11 = 13 | 13 x 11 = 143 | 143 ÷ 11 = 13 |
14 + 11 = 25 | 25 - 11 = 14 | 14 x 11 = 154 | 154 ÷ 11 = 14 |
15 + 11 = 26 | 26 - 11 = 15 | 15 x 11 = 165 | 165 ÷ 11 = 15 |
16 + 11 = 27 | 27 - 11 = 16 | 16 x 11 = 176 | 176 ÷ 11 = 16 |
17 + 11 = 28 | 28 - 11 = 17 | 17 x 11 = 187 | 187 ÷ 11 = 17 |
18 + 11 = 29 | 29 - 11 = 18 | 18 x 11 = 198 | 198 ÷ 11 = 18 |
19 + 11 = 30 | 30 - 11 = 19 | 19 x 11 = 209 | 209 ÷ 11 = 19 |
20 + 11 = 31 | 31 - 11 = 20 | 20 x 11 = 220 | 220 ÷ 11 = 20 |
11 |
11 + 11 = 22 |
11 + 11 + 11 = 33 |
11 + 11 + 11 + 11 = 44 |
11 + 11 + 11 + 11 + 11 = 55 |
11 + 11 + 11 + 11 + 11 + 11 = 66 |
11 + 11 + 11 + 11 + 11 + 11 + 11 = 77 |
11 + 11 + 11 + 11 + 11 + 11 + 11 + 11 = 88 |
11 + 11 + 11 + 11 + 11 + 11 + 11 + 11 + 11 = 99 |
11 + 11 + 11 + 11 + 11 + 11 + 11 + 11 + 11 + 11 = 110 |
Any single-digit natural integer multiplied by 11 results in a product that is written twice.
The first 20 multiples of 11 are listed below.
11 | × | 1 | = | 11 |
11 | × | 2 | = | 22 |
11 | × | 3 | = | 33 |
11 | × | 4 | = | 44 |
11 | × | 5 | = | 55 |
11 | × | 6 | = | 66 |
11 | × | 7 | = | 77 |
11 | × | 8 | = | 88 |
11 | × | 9 | = | 99 |
11 | × | 10 | = | 110 |
11 | × | 11 | = | 121 |
11 | × | 12 | = | 132 |
11 | × | 13 | = | 143 |
11 | × | 14 | = | 154 |
11 | × | 15 | = | 165 |
11 | × | 16 | = | 176 |
11 | × | 17 | = | 187 |
11 | × | 18 | = | 198 |
11 | × | 19 | = | 209 |
11 | × | 20 | = | 220 |
Q1. John went to school and distributed 3 chocolates to his classmates. There are 11 students in his class. Using the table of 11 find how many chocolates he distributed in total.
Ans: John gave three chocolates to each of the 11 classmates. Therefore, 11 x 3 = 33 chocolates were delivered in total.
Q2. Rashmi makes five consecutive bows. Using the table of 11, determine how many times Rashmi must have bowed if she did so 11 times.
Ans: The young lady bowed five times in a row.
She bowed a total of 11 times, or 11 times 5 (using the table of 11), for a total of 55 times.
Thus, she has made a total of 55 bows.
Q3. Meera had an ice cream shop, and each customer bought 12 ice creams. The total number of customers who visited the shop is 11. How many ice creams did Meera sell that day?
Ans: Each of the 11 consumers purchased 12 ice creams. Therefore, 11 times 12 is 132, which is the total amount of ice cream sold.
Divisibility Rules for 11: A number is totally divisible by 11 if the difference between the sum of its alternate digits is divisible by 11.
11, 22, 33, 44, 55, 66, 77, 88, 99, 110, and so forth are the multiples of 11. We can get these multiples by multiplying 11 by the corresponding numbers 1, 2, 3,..., 10.
Read the number from left to right and add the digits in alternation. Check if the difference between the sum of its alternate digits is divisible by 11 If so, the original number is also divisible by 11. In 2728, for example, the sum of the digits is alternately 2 - 7 + 2 - 8, which is -11. -11 and 2728 are both divisible by 11, thus.
11 only has two factors because it is a prime number, which is one and the number itself. As a result, 11 factors are 1 and 11.
No, because 11 only has the factors 1 and 11. In other words, since 11 has no more than two factors, it is not a composite number.
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