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Tables is an integral part of the arithmetic section of maths. They make life easier and it is given that for any student to really be at ease with maths, they must know the tables of at least the first 15 numbers. This article tells you about table 7 and how you can find more multiples if needed.
Table of 7 refers to the multiplication table of the whole number 7. A multiplication table is a table with a list of multiples of a number when it is multiplied by another number or itself.
For example, 7 \times 3 = 21 .
In order to understand how we got 21 by multiplying 7 by 3, go down below.
The table of 7 requires constant addition of the number 7 to itself equivalent to the number it is being multiplied by. For example, 7 \times 3 = 7 + 7 + 7 = 21 7 x 3 = 7 + 7 + 7 = 21.
These types of multiplications go on easily when dealing with single-digit numbers. But how do you multiply double digits numbers or more-digit numbers with 7? For example, 7 \times 20 7 x 20. Adding 7, 20 times to itself would not be a smart option here. So, what we do is, multiply the digit in the ones place first with the number and then multiply the tens digit with the number.
Thus, 7 \times 20 = 140 7 x 20 = 140.
A similar rule goes for numbers which are bigger than double digits numbers. You always start by multiplying the rightmost digit and then move to the right from there.
Times table basically represents that when a number is added to itself the number of times equal to the number we intend to multiply it to, the repeated addition yields the same result as multiplication. It is shown below in the table.
7 × 1 = 7 | 7 |
7 × 2 = 14 | 7+7=14 |
7 × 3 = 21 | 7+7+7=21 |
7 × 4 = 28 | 7+7+7+7=28 |
7 × 5 = 35 | 7+7+7+7+7=35 |
7 × 6 = 42 | 7+7+7+7+7+7=42 |
7 × 7 = 49 | 7+7+7+7+7+7+7=49 |
7 × 8 = 56 | 7+7+7+7+7+7+7+7=56 |
7 × 9 = 63 | 7+7+7+7+7+7+7+7+7=63 |
7 × 10 = 70 | 7+7+7+7+7+7+7+7+7+7=70 |
Table in Words | Table in Numbers | Result |
7 times 1 | \begin{equation} 7 \times 1 = \end{equation} 7 x 1 = | 7 |
7 times 2 | \begin{equation} 7 \times 2 = \end{equation} 7 x 2 = | 14 |
7 times 3 | \begin{equation} 7 \times 3 = \end{equation} 7 x 3 = | 21 |
7 times 4 | \begin{equation} 7 \times 4= \end{equation} 7 x 4 = | 28 |
7 times 5 | \begin{equation} 7 \times 5 = \end{equation} 7 x 5 = | 35 |
7 times 6 | \begin{equation} 7 \times 6 = \end{equation} 7 x 6 = | 42 |
7 times 7 | \begin{equation} 7 \times 7 = \end{equation} 7 x 7 = | 49 |
7 times 8 | \begin{equation} 7 \times 8 = \end{equation} 7 x 8 = | 56 |
7 times 9 | \begin{equation} 7 \times 9 = \end{equation} 7 x 9 = | 63 |
7 times 10 | \begin{equation} 7 \times 10 = \end{equation} 7 x 10 = | 70 |
7 times 11 | \begin{equation} 7 \times 11 = \end{equation} 7 x 11 = | 77 |
7 times 12 | \begin{equation} 7 \times 12 = \end{equation} 7 x 12 = | 84 |
7 times 13 | \begin{equation} 7 \times 13 = \end{equation} 7 x 13 = | 91 |
7 times 14 | \begin{equation} 7 \times 14 = \end{equation} 7 x 14 = | 98 |
7 times 15 | \begin{equation} 7 \times 15 = \end{equation} 7 x 15 = | 105 |
7 times 16 | \begin{equation} 7 \times 16 = \end{equation} 7 x 16 = | 112 |
7 times 17 | \begin{equation} 7 \times 17 = \end{equation} 7 x 17 = | 119 |
7 times 18 | \begin{equation} 7 \times 18 = \end{equation} 7 x 18 = | 126 |
7 times 19 | \begin{equation} 7 \times 19 = \end{equation} 7 x 19 = | 133 |
7 times 20 | \begin{equation} 7 \times 20 = \end{equation} 7 x 20 = | 140 |
Q1. Priya gets ₹ 50 for each day she works at a shop. She works for 7 days. How much should she get paid?
Ans. Days Priya works in the shop = 7
Pay per day = ₹ 50
To find out the total amount she should be paid, we have to multiply the pay per day by the number of days she worked.
\begin{equation}
50 \times 7 = 350
\end{equation}
Thus, Priya should be paid ₹ 350 for her 7 day work.
Q2. Multiply 135 by 7.
Ans. 135 = 100 + 30 + 5
To find their multiplication with 7, we need to multiply these along with their place values, starting with the leftmost digit and going to the right.
\begin{equation}
5 \times 7 = 35 \\
30 \times 7 = 210 \\
100 \times 7 = 700 \\
35 + 210 + 700 = 945
\end{equation}
Thus, 135 x 7 = 945. Notice how to reach the result, we added the results of the three multiplications.
Q3. There is a huge class of 70 students. How many groups of 7 can be formed from this class?
Ans. A total number of students in class = 70
Total number of students in a group = 7
Therefore, the total number of groups to be formed = 70 ÷ 7
\begin{equation}
70 \div 7 = 10
\end{equation}
Division is the opposite of multiplication. While multiplication adds, division subtracts. Division of a number requires a divisor to be subtracted from it for a couple of turns till it leaves behind a 0 or a number from which the divisor can no longer be subtracted. It goes from right to left.
Q4. A person daily fills 7 L of water in his storage. The storage can contain 280 L of water. How many days will the person require to fill the storage?
Ans. The total amount the storage can contain = 280 L
Amount of water filled daily = 7 L
Thus, the number of days required to fill the water = 280 ÷ 7
\begin{equation}
280 \div 7 = 40
\end{equation}
The storage will take 40 days to be filled completely.
Q5. 7 people work for 7 days to collect 7 coins per day. How many coins do you think they will collect in a month or 30 days?
Ans. To find the total number of coins collected in a month, we must multiply the number of people involved by the number of days they work, the number of coins collected on each day and the total number of days in a month.
A number of people = 7
Number of days they work = 7
Number of coins collected per day = 7
Total number of days in a month = 30
\begin{equation}
7 \times 7 \times 7 \times 30 = 10290
\end{equation}
Thus, the total number of coins collected in a month by the 7 people are 10290.
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