JEE Main Important Physics formulas
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To quickly perform high-order multiplication, use Table 19. The pupils are urged to properly learn it so they can multiply numbers quickly in timed competitive exams like the CAT and GMAT. To help them remember outcomes for a very long time, it is advised that students routinely review all of the tables, especially tables with numbers 2 to 20.
The results of multiplying 19 by whole integers are included in the multiplication table for the number 19. The multiplication tables for children from 1 to 20 should be mastered by the time a student completes elementary school. You may learn the table of 19 quickly and easily by using the simple techniques, methods, and games we provide in this post.
The multiplication table of 19 is also referred to as the table of 19. The addition and multiplication arithmetic procedures can be used to produce this table. The table below displays the first 10 multiples of 19 using repeated addition and multiplication.
19 |
19 + 19 = 38 |
19 + 19 + 19 = 57 |
19 + 19 + 19 + 19 = 76 |
19 + 19 + 19 + 19 + 19 = 95 |
19 + 19 + 19 + 19 + 19 + 19 = 114 |
19 + 19 + 19 + 19 + 19 + 19 + 19 = 133 |
19 + 19 + 19 + 19 + 19 + 19 + 19 + 19 = 152 |
19 + 19 + 19 + 19 + 19 + 19 + 19 + 19 + 19 = 171 |
19 + 19 + 19 + 19 + 19 + 19 + 19 + 19 + 19 + 19 = 190 |
19 | x | 1 | = | 19 |
19 | x | 2 | = | 38 |
19 | x | 3 | = | 57 |
19 | x | 4 | = | 76 |
19 | x | 5 | = | 95 |
19 | x | 6 | = | 114 |
19 | x | 7 | = | 133 |
19 | x | 8 | = | 152 |
19 | x | 9 | = | 171 |
19 | x | 10 | = | 190 |
Q1. If a coconut candy costs 10 cents, how much would 19 coconut candies cost using the table of 19?
Ans: Since 1 candy costs 10 cents, the following is calculated using the 19-times table:
19 candies equal 19 times 10 cents and thus, cost 190 cents.
19 coconut candies cost 190 cents.
Q2. The first five multiples of 19 must be added up, and Mr. X is attempting to do so. Use table 19 to assist Mr. X in finding the correct answer.
Ans: The first five multiples of 19 are as follows:
\begin{equation}
\begin{aligned}
& 19 × 1 = 19 \\
& 19 × 2 = 38 \\
& 19 × 3 = 57 \\
& 19 × 4 = 76 \\
& 19 × 5 = 95 \\
\end{aligned}
\end{equation}
19 + 38 + 57 + 76 + 95 multiplied together yields 285 total.
Thus, the sum is 285
Q3. Evaluate 19 times 9 plus 80.
Ans: \begin{equation}
\begin{aligned}
19×6+80=114+80 \\
=194 \\
\end{aligned}
\end{equation}
Q4. 19 pals are being invited to Kate's birthday celebration. For them, she wants to bake cookies. Each of Kate's friends will receive 5 cookies from her.
Ans: There are 19 buddies.
Kate wants to give her pals eight cookies.
To find the number of cookies Kate has to bake, multiply 19 by 18.
So, \begin{equation}
19 \times 5 = 95
\end{equation}
Therefore, Kate has to bake 95 cookies.
Q5. What is 7 times 19?
Ans: 7 times 19 is \begin{equation}
7 \times 19 = 133
\end{equation}
The number 19 comes only in the table of 1 and 19.
The multiples of 19 are 19,38,57,76,95,114,133,152,171 and 190.
19 times 50 is 950
3
\begin{equation}
9 × 5 = 45
\end{equation}.
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