The term Arithmetic Progression (AP) refers to a set of numbers where any two successive integer differences are always the same. Popular names for AP include Arithmetic Sequence.
Arithmetic Progression, AP= 21, 18, 15, ……
First term, a = 21
Second term = 18
Required Sum = 0
Common difference, d = Second term - first term =18-21=-3 ![]()
The sum for n terms, S_{n} = \frac{n}{2}[2a+(n-1)d] ![]()
Where n = number of terms
a = first term
d = common difference
As the required sum is 0.
So, substituting the given values to find the value of n, i,e., number of terms.
S_{n} = \frac{n}{2}[2a+(n-1)d] ![]()
\Rightarrow
0 = \frac{n}{2}[2.21+(n-1)(-3)] ![]()
\Rightarrow
0 = n (42 - 3n +3)
\Rightarrow
0 = n (45 - 3n)
\Rightarrow
0 = 45n - 3n^{2} ![]()
\Rightarrow
0 = 3n (15 - n)
\Rightarrow
n = 0 or n = 15
For n = 0, this means 0 number term, which is impossible.
So, n = 15
Hence, 15 terms of the AP 21, 18, 15,.......... must be added to get the sum 0.
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For the given A.P. 21,18,15…; sum of 15 terms adds to get zero.
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