JEE Main Important Physics formulas
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In the mathematics table, college students learn the way oftentimes a given variety may be written. We were taught multiplication statistics ever for the reason that number one school. These maths tables make it simpler for us to quickly clear up issues regarding multiplication.
The maths tables 1 thru 20 need to consequently be dedicated to reminiscence for college students to have the ability to finish difficult calculations with ease. Let's evaluate the mathematics tables from 1 to twenty right here and speak the way to memorise them. Mathematical skill ability with maths tables is an essential constructing block. The gate to multi-digit multiplication is opened with the aid of using it.
It establishes the basis for algebra, lengthy division, and fractional simplifying. The location version of multiplication turns into more and more crucial in better grades. The key to turning into a successful maths learner is for the scholars to memorise those tables and get beyond the limitations which have been proven to save you fulfilment in life, education, and employment.
41 is a prime number. The number 41 can only be divided by one and the number itself. For a number to be considered a prime number, there must be exactly two factors. Due to the fact that it only has the two elements 1 and 41, 41 is a prime number.
As you can see, we effectively multiply that particular natural number by the required number of times when multiplying the number 41 to obtain the necessary results. Like I intended to multiply 41 by four, like this: 41+41+41+41=164
The same natural number can therefore be multiplied by the appropriate number of times, which in this case equals 4, or it can be added to the needed number of times to get the answer of 164.
This can be multiplied by any quantity for which we need to know the answers by conducting calculations, either by adding or simply multiplying.
Q.1: Solve 41 + 41 + 41?
Ans: We can solve this by addition as it is given in addition so,
41 + 41 + 41 = 123
The easiest way to solve this is,
41 X 3 = 123
Q.2: What is the answer if we add 41 five times?
Ans: We can solve this by adding the number 41 five times or simply multiply 41 with five and we get the correct answer with the easiest method. So the answer is,
41 X 5 = 205
Q.3: Solve (41 x 2 ) + (41 x 9) = ?
Ans: To solve this we simply multiply 41 with two and nine rather than adding it two times then nine times. Solution is,
Simply add this both to get final answer,
Q.4: The cost of 1 kilo of sugar is Rs. 41 Find the cost of 7 kilos of sugar.
Ans: Here they gave the cost of 1 kilo sugar and we need to find out the cost of 7 kilos sugar, for this we simply multiply the cost of 1 kilo sugar with 7 kilos sugar.
Cost of 7 kilos sugar = (cost of 1 kilo sugar) X (7 kilo sugar)
= (41 Rs.) X (7 kilo)
= 287 Rs.
Q.5: Calculate six times 41.
Ans: We simply multiply 41 with 6 to get the answer,
41 X 6 = 246
Times table basically represents that when a number is added to itself the number of times equal to the number we intend to multiply it to, the repeated addition yields the same result as multiplication. It is shown below in the table.
41 × 1 = 41 | 41 |
41 × 2 = 82 | 41+41=82 |
41 × 3 = 123 | 41+41+41=123 |
41 × 4 = 164 | 41+41+41+41=164 |
41 × 5 = 205 | 41+41+41+41+41=205 |
41 × 6 = 246 | 41+41+41+41+41+41=246 |
41 × 7 = 287 | 41+41+41+41+41+41+41=287 |
41 × 8 = 328 | 41+41+41+41+41+41+41+41=328 |
41 × 9 = 369 | 41+41+41+41+41+41+41+41+41=369 |
41 × 10 = 410 | 41+41+41+41+41+41+41+41+41+41=410 |
Table of 41 is given below,
41 | x | 1 | 41 |
41 | x | 2 | 82 |
41 | x | 3 | 123 |
41 | x | 4 | 164 |
41 | x | 5 | 205 |
41 | x | 6 | 246 |
41 | x | 7 | 287 |
41 | x | 8 | 328 |
41 | x | 9 | 369 |
41 | x | 10 | 410 |
As per latest 2024 syllabus. Physics formulas, equations, & laws of class 11 & 12th chapters
As per latest 2024 syllabus. Chemistry formulas, equations, & laws of class 11 & 12th chapters
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As per latest 2024 syllabus. Maths formulas, equations, & theorems of class 11 & 12th chapters