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    How Many Molecules are Present in 9 g of Water
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    • How Many Molecules are Present in 9 g of Water

    How Many Molecules are Present in 9 g of Water

    Team Careers360Updated on 10 Apr 2023, 05:42 PM IST

    Introduction

    Let's define a "molecule" before determining how many molecules are contained in the 9 grams of water. A molecule is a collection of two or more atoms that are chemically bound together and constitutes the smallest building block of a compound that can take part in a chemical reaction. Any compound's molecular weight must be multiplied by Avogadro's constant to determine its molecular composition.

    Number of Molecules = number of moles X 6.023\times 10^{23} 1681128406242 …………(i)

    Where the number of moles:

    It is the proportion of a compound's actual mass to its molecular mass. The following is the expression to determine the number of moles:

    n = \frac{m}{M}, 1681128406624 …………..(ii)

    Here, "m" stands for the given mass of the compound, and "M" stands for the given compound's molar mass.

    Calculation

    To find out the number of molecules in 9 grams of water:

    Given the mass of water molecule = 9 g

    The molecular mass of water molecule = 18 g

    Using equation (ii), calculate the number of moles of water:

    Number of moles, n = \frac{9}{18} 1681128406499 = 0.5

    Using equation (i), calculate the number of molecules of water:

    Number of molecules = n\times 6.023 \10^{23}

    \Rightarrow 0.5 \times 6.023 \10^{23}

    \Rightarrow 3.01 \times 10^{23}

    1681128406754

    Conclusion

    Hence, the number of molecules in 9 grams of water is 3.01 \times 10^{23} 1681128406384molecules.

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