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NCERT Solutions for Class 11 Physics Chapter 11 Thermal Properties of Matter: If you're a Class 11 student seeking thermal properties of matter exercise solutions, you're in the right place for NCERT solutions. On this Careers360 page, you can access complete exercise solutions, covering questions from 11.1 to 11.20 in the main exercise, and questions 11.21 to 11.22 in the additional exercise. These accurate and precise class 11 physics chapter 11 exercise solutions are available for download in PDF format, providing convenient access for students. The answers have been crafted by the best subject matter experts, ensuring their reliability.
Temperature is a relative measure of indication of coldness (or hotness) while heat is the form of energy transferred between two or more systems or a system and its surroundings due to the temperature difference. Thermal Properties of Matter Class 11 solutions of NCERT Physics Chapter start with the questions related to temperature conversions from one scale to another. All the questions discussed in the CBSE NCERT solutions for Class 11 Physics chapter 11 Thermal Properties of Matter are important to understand the topics covered in the chapter. ch 11 class 11 physics ncert solutions are an important tool to perform well in exams.
** This chapter has been renumbered as Chapter 10 in accordance with the CBSE Syllabus 2023–24.
Free download thermal properties of matter class 11 exercise solution PDF for CBSE exam.
Access NCERT Solutions for Class 11 Physics Chapter 11 Thermal Properties of Matter - Exercise Solution
Answer:
The relation between Kelvin and Celcius scale is T K = T C + 273.15
Triple Point of Neon in Kelvin T K = 24.57 K
Triple Point of Neon in Celcius T C = T K -273.15 = 24.57 -273.15 =-248.58 o C
Triple Point of carbon dioxide in Kelvin T K = 216.55 K
Triple Point of carbon dioxide in Celcius T C = T K -273.15 = 216.55 - 273.15 = -56.60 o C
The relation between Celcius and Fahrenheit scale is
Triple Point of Neon in Fahrenheit is
T F = -415.44 o C
Triple Point of carbon dioxide in Fahrenheit is
T F = -69.88 o C
Answer:
200 A = 273 K
350 B = 273 K
Equating T K From the above two equations we have
The resistance is at the triple-point of water
and
at the normal melting point of lead
What is the temperature when the resistance is
?
Answer:
R 0 = T 0 =
R = R =
Putting the above values in the given equation we have
For R =
Answer:
Unlike the melting point of ice and boiling point of water, the triple point of water has a fixed value of 273.16 K. The melting point of ice and boiling point of water vary with pressure.
Q. 11.4 (b) Answer the following :
Answer:
The other fixed point on the Kelvin scale is 0 K. 0K is the absolute zero
Q. 11.4 (c) Answer the following :
(c) The absolute temperature (Kelvin scale) is related to the temperature
on the Celsius scale by
Why do we have in this relation, and not
Answer:
This is because 0 o C on the Celcius scale corresponding to the melting point at standard pressure is equal to 273.15 K whereas 273.16 K is the triple point of water. The triple point of water is 0.01 0 C , not 0 0 C
Q. 11.4 (d) Answer the following :
Answer:
Let at a certain temperature the reading on Fahrenheit and Kelvin Scale be T F and T K respectively
Let at another temperature the reading on Fahrenheit and Kelvin Scale be T' F and T' K respectively
Subtracting equation (ii) from (i)
For T K - T' K = 1 K, T F - T' F = 9/5
Therefore corresponding to 273.16 K the absolute scale whose unit interval size is equal to that of the Fahrenheit scale
Temperature | Pressure Thermometer A | Pressure Thermometer B |
Triple-point of water | ||
Normal melting point of sulphur |
(a) What is the absolute temperature of normal melting point of sulphur as read by thermometers A and B?
Answer:
As the moles of oxygen and hydrogen inside the thermometers and the volume occupied by the gases remain constant P/T would remain constant.
The triple point of water(T 1 ) = 273.16 K
Pressure in thermometer A at a temperature equal to the triple point of water (P 1 ) =
Pressure in thermometer A at a temperature equal to Normal melting point of sulphur (P 2 ) =
The normal melting point of sulphur as read by thermometer A T 2 would be given as
Pressure in thermometer B at a temperature equal to the triple point of water (P' 1 ) =
Pressure in thermometer B at a temperature equal to Normal melting point of sulphur (P' 2 ) =
The normal melting point of sulphur as read by thermometer B T' 2 would be given as
Temperature | Pressure Thermometer A | Pressure Thermometer B |
Triple-point of water | ||
Normal melting point of sulphur |
(b) What do you think is the reason behind the slight difference in answers of thermometers A and B? (The thermometers are not faulty). What further procedure is needed in the experiment to reduce the discrepancy between the two readings?
Answer:
The slight difference in answers of thermometers A and B occur because the gases used in the thermometers are not ideal gases. To reduce this discrepancy the experiments should be carried out at low pressures where the behaviour of real gases tend close to that of ideal gases.
Answer:
At 27 o C the 63 cm (l 1 ) mark on the steel tape would be measuring exactly 63 cm as the tape is calibrated at 27 o C
Coefficient of linear expansion of steel
Actual length when the scale is giving a reading of 63 cm on at 45 o C is l 2
The actual length of the steel rod on a day when the temperature is 45 o C is 63.013608 cm.
Length of the same steel rod on a day when the temperature is 63 cm.
Answer:
Diameter of the steel shaft at 27 o C (T 1 ) d 1 = 8.70 cm
The diameter of the central hole in the wheel d 2 = 8.69 cm
Coefficient of linear expansion of the steel .
The wheel will slip on the shaft when the diameter of the steel shaft becomes equal to the diameter of the central hole in the wheel.
Let this happen at temperature T
Answer:
Coefficient of linear expansion of copper
Coefficient of superficial expansion of copper is
Diameter of the hole at 27 o C (d 1 ) = 4.24 cm
Area of the hole at 227 o C is
Let the diameter at 227 o C be d 2
Change in diameter is d 2 -d 1 = 4.24 -4.254 = 0.014 cm.
Answer:
Youngs Modulus of Brass,
Co-efficient of linear expansion of Brass,
The diameter of the given brass wire, d = 2.0 mm
Length of the given brass wire, l = 1.8 m
Initial Temperature T 1 = 27 o C
Final Temperature T 2 = -39 o C
The tension developed in the wire is 378 N. The negative sign signifies this tension is inward.
Answer:
Length of the rods l = 50 cm
Co-efficient of linear expansion of brass,
Co-efficient of linear expansion of steel,
Initial Temperature T 1 = 40.0 o C
Final Temperature T 2 = 250 o C
Change in length of brass rod is
Change in length of the steel rod is
Change in length of the combined rod is
Answer:
Coefficient of volume expansion of glycerine is
Let initial volume and mass of a certain amount of glycerine be V and m respectively.
Initial density is
Change in volume for a 30 o C rise in temperature will be
Final Density is
Fractional Change in density is
The negative sign signifies with an increase in temperature density will decrease.
Answer:
Power of the drilling machine, P = 10 kW
Time. t = 2.5 min
Total energy dissipated E is
Thermal energy absorbed by aluminium block is
Mass of the aluminium block, m = 8.0 kg
Specific heat of aluminium, c = 0.91 J g -1 K -1
Let rise in temperature be
Answer:
Mass of copper block m = 2.5 kg
Initial Temperature of the copper block, T 1 = 500 o C
Final Temperature of Copper block, T 2 = 0 o C
Specific heat of copper, c = 0.39 J g -1 K -1
Thermal Energy released by the copper block is
Latent heat of fusion of water, L = 335 j g -1
Amount of ice that can melt is
1.455 kg of ice can melt using the heat released by the copper block.
Answer:
Let the specific heat of the metal be C.
Mass of metal block m = 200 g
Initial Temperature of metal block = 150 o C
Final Temperature of metal block = 40 o C
The heat released by the block is
Initial Temperature of the calorimeter and water = 27 o C
Final Temperature of the calorimeter and water = 40 o C
Amount of water = 150 cm
Mass of water = 150 g
Water equivalent of calorimeter = 25 g
Specific heat of water = 4.186 J g -1 K -1
Heat absorbed by the Calorimeter and water is
The heat absorbed by the Calorimeter and water is equal to the heat released by the block
The above value would be lesser than the actual value since some heat must have been lost to the surroundings as well which we haven't accounted for.
Q. 11.15 Given below are observations on molar specific heats at room temperature of some common gases.
Gas Molar specific heat (Cv )
Hydrogen 4.87
Nitrogen 4.97
Oxygen 5.02
Nitric oxide 4.99
Carbon monoxide 5.01
Chlorine 6.17
The measured molar specific heats of these gases are markedly different from those for monatomic gases. Typically, molar specific heat of a monatomic gas is Explain this difference. What can you infer from the somewhat larger (than the rest) value for chlorine?
Answer:
Monoatomic gases have only translational degree of freedom but diatomic gases have rotational degrees of freedom as well. The temperature increases with increase in the spontaneity of motion in all degrees. Therefore to increase the temperature of diatomic gases more energy is required than that required to increase the temperature of monoatomic gases by the same value owing to higher degrees of freedom in diatomic gases.
If we only consider rotational modes of freedom the molar specific heat of the diatomic gases would be given as
The number of degrees of freedom = 5 (3 translational and 2 rotational)
The values given in the table are more or less in accordance with the above calculated one. The larger deviation from the calculated value in the case of chlorine is because of the presence of vibrational motion as well.
Answer:
Initial Temperature of the boy = 101 o F
Final Temperature of the boy = 98 o F
Change in Temperature is
Mass of the child is m = 30 kg
Specific heat of human body = 1000 cal kg -1 o C -1
Heat released is
Latent heat of evaporation of water = 580 cal g -1
The amount of heat lost by the body of the boy has been absorbed by water.
Let the mass of water which has evaporated be m'
Time in which the water has evaporated, t = 20 min.
Rate of evaporation is m'/t
Answer:
Side of the box s = 30 cm
Area available for conduction A
A = 6s 2
A=6(30) 2
A=5400 cm 2 = 0.54 m 2
Temperature difference = 45 o C
Co-efficient of thermal conductivity of thermacole is k = 0.01 J s -1 m -1 K -1
Width of the box is d = 5 cm
Heat absorbed by the box in 6 hours is
The heat of fusion of water is
Amount of ice which has melted is m'
Amount of ice left after 6 hours = 4 - 0.313 = 3.687 kg
Answer:
The rate at which water boils, R = 6.0 kg min -1
The heat of vaporisation of water,
The rate at which heat enters the boiler
The base area of the boiler, A = 0.15 m 2
Thickness, l = 1.0 cm
Thermal conductivity of brass
The temperature inside the boiler = Boiling point of water = 100 o C
Let the temperature of the flame in contact with the boiler be T
Amount of heat flowing into the boiler is
The temperature of the flame in contact with the boiler is 237.98 o C
Q. 11.19 (a) Explain why :
(a) a body with large reflectivity is a poor emitter
Answer:
A body with a large reflectivity is a poor absorber. As we know a body which is a poor absorber will as well be a poor emitter. Therefore a body with large reflectivity is a poor emitter.
Q .11.19 (b) Explain why :
(b) a brass tumbler feels much colder than a wooden tray on a chilly day
Answer:
Brass is a good conductor of heat. Therefore once someone touches brass heat from their body flows into it and it feels cold, in case of a wooden tray, no such conduction of heat from the body takes place as wood is a very poor conductor of heat.
Q. 11.19 (c) Explain why :
Answer:
An optical pyrometer relates the brightness of a glowing body with its temperature. In the open because of other sources of light the sensor in the optical pyrometer does not detect the true brightness of a red hot piece of iron and thus does not predict its temperature correctly whereas in the furnace the piece of iron is the only source of light and the sensor detects its brightness correctly thus giving the correct value of the temperature.
Q. 11.19 (d) Explain why :
(d) the earth without its atmosphere would be inhospitably cold
Answer:
The sun rays contain infrared radiations. These are reflected back by the lower part of the atmosphere after being reflected by the surface of the earth and are trapped inside the atmosphere thus maintaining the Earth's temperature at a hospitable level. Without these rays being trapped the temperature of the earth will go down severely and thus the Earth without its atmosphere would be inhospitably cold.
Q. 11.19 (e) Explain why :
Answer:
Heating systems based on the circulation of steam are more efficient in warming a building than those based on the circulation of hot water because the same amount of steam at 100 o C contains more energy available for heat dissipation than the same amount of water at 100 o C in the form of latent heat of vaporization.
Answer:
Let a body initially be at temperature T 1
Let its final Temperature be T 2
Let the surrounding temperature be T 0
Let the temperature change in time t.
According to Newton's Law of cooling
where K is a constant.
We have been given that the body cools from 80 o C to 50 o C in 5 minutes when the surrounding temperature is 20 o C.
T 2 = 50 o C
T 1 = 80 o C
T 0 = 20 o C
t = 5 min = 300 s.
For T 1 = 60 o C and T 2 = 30 o C we have
The body will take 10 minutes to cool from 60 o C to 30 o C at the surrounding temperature of 20 o C.
Q. 11.21(a) Answer the following questions based on the P-T phase diagram of carbon dioxide:
(a) At what temperature and pressure can the solid, liquid and vapour phases of co-exist in equilibrium?
Answer:
At the triple point temperature of -56.6 o C and pressure 5.11 atm the solid, liquid and vapour phases of co-exist in equilibrium.
Q. 11.21(b) Answer the following questions based on the P-T phase diagram of carbon dioxide:
(b) What is the effect of decrease of pressure on the fusion and boiling point of ?
Answer:
Both fusion and boiling point of CO 2 decrease with decrease in pressure. This we can see from the solid lines in the P-T phase diagram of CO 2 .
Q. 11.21 (c) Answer the following questions based on the P-T phase diagram of carbon dioxide:
(c) What are the critical temperature and pressure for ? What is their significance?
Answer:
The critical temperature and pressure for CO 2 are 31.1 o C and 73.0 atm respectively. If the temperature exceeds this critical value of temperature CO 2 would not liquefy no matter how high the pressure is.
Q .11.21 d(a) Answer the following questions based on the P-T phase diagram of carbon dioxide:
(d) Is solid, liquid or gas at
(a) under
Answer:
CO 2 is vapour at -70 o C under 1 atm pressure as the point corresponding to this condition lies in vapour region in the given P-T phase diagram of carbon dioxide.
Q .11.21 d (b) Answer the following questions based on the P-T phase diagram of carbon dioxide:
(d) Is solid, liquid or gas at
(b) under
Answer:
CO 2 is solid at -60 o C under 10 atm pressure as the point corresponding to this condition lies in the solid region in the given P-T phase diagram of carbon dioxide.
Q. 11.21 d(c) Answer the following questions based on the P-T phase diagram of carbon dioxide:
(d) Is solid, liquid or gas at
(c) under
Answer:
CO 2 is liquid at 15 o C under 56 atm pressure as the point corresponding to this condition lies in the liquid region in the given P-T phase diagram of carbon dioxide.
Q. 11.22 (a) Answer the following questions based on the P – T phase diagram of :
(a) at 1 atm pressure and temperature
is compressed isothermally. Does it go through a liquid phase?
Answer:
The temperature -60 o C lies to the left of the triple point of water i.e. in the region of solid and vapour phases. Once we start compressing CO 2 at this temperature starting from 1 atm pressure it will directly convert into solid without going through the liquid phase.
Q. 11.22 (b) Answer the following questions based on the P – T phase diagram of :
(b) What happens when at
atm pressure is cooled from room temperature at constant pressure?
Answer:
At room temperature (27 o C) and 4 atm pressure CO 2 exits in the vapour phase. The pressure 4 atm is less than the pressure at the triple point and therefore points corresponding to all temperatures and this pressure lie in the solid and vapour region. Once we start compressing CO 2 from room temperature at this constant pressure CO 2 turns from vapour to solid directly without going through the liquid phase.
Q. 11.22 (c) Answer the following questions based on the P – T phase diagram of :
(c) Describe qualitatively the changes in a given mass of solid at
pressure and temperature
as it is heated up to room temperature at constant pressure.
Answer:
At -65 o C under 10 atm pressure CO 2 is in the solid phase. At room temperature (27 o C) under 10 atm pressure CO 2 is in the vapour phase. At 10 atm pressure, CO 2 can exist in all three phases depending upon the temperature. Therefore as CO 2 is heated from -65 o C to room temperature at a constant pressure of 10 atm it goes from the solid phase to liquid phase and then ultimately it goes into the vapour phase.
Q. 11.22 (d) Answer the following questions based on the P – T phase diagram of :
(d) is heated to a temperature
and compressed isothermally. What changes in its properties do you expect to observe?
Answer:
70 o C is above the critical temperature of CO 2 . Once CO 2 is isothermally compressed at this temperature it would not liquefy irrespective of how high the pressure is but at very high pressures CO 2 will not behave as an ideal gas.
The thermal properties of matter class 11 exercise solution are essential for board exams because questions from this chapter often appear. These solutions are also crucial for competitive exams like JEE and NEET, where a good understanding of thermal properties is frequently tested, impacting students' overall performance and future career opportunities. Also, mastering this chapter is important because it forms the basis for more advanced physics topics and is closely connected to other chapters, particularly those related to thermodynamics.
Chapter 1 | |
Chapter 2 | |
Chapter 3 | |
Chapter 4 | |
Chapter 5 | |
Chapter 6 | |
Chapter 7 | |
Chapter 8 | |
Chapter 9 | |
Chapter 10 | |
Chapter 11 | Thermal Properties of Matter |
Chapter 12 | |
Chapter 13 | |
Chapter 14 | |
Chapter 15 |
U = 1/2*strain*stress*volume
Where:
ΔQ is the amount of heat supplied to the substance and ΔT change in its temperature
These formulas and diagrams are valuable tools for students as they help in solving complex problems related to thermal properties of matter, aiding in a deeper comprehension of the subject and enhancing problem-solving skills
Highlights of thermal properties of matter class 11 ncert solutions are given below:
In ch 11 class 11 physics ncert solutions pdf, points are used to frame answers to help understand quickly.
Solution for thermal properties of matter class 11 are derived from the textbook by a highly qualified subject matter expert.
Questions and answers for ch 11 physics class 11 are given as per the latest CBSE Syllabus and guidelines.
thermal properties of matter class 11 ncert pdf links are readily available and easily accessible for free.
class 11 physics chapter 11 exercise solutions also boosts your knowledge and interest in physics. NCERT is the base of your learning and here it's easy to access.
11.2 Temperature and heat
11.3 Measurement of temperature
11.4 Ideal-gas equation and absolute temperature
11.5 Thermal expansion
11.6 Specific heat capacity
11.7 Calorimetry
11.8 Change of state
11.9 Heat transfer
11.10 Newton’s law of cooling
The difference between temperature and heat can be well understood from the following graph given in NCERT.
Even though heat is increased during the phase change, the temperature remains constant until the phase change has occurred. That is increasing heat always does not imply that there is an increase in temperature.
Dropped Topics –
The topics "Greenhouse Effect" and exercises 11.21 to 11.22 have been excluded from the ch 11 class 11 physics ncert solutions, "Thermal Properties of Matter," implying that they may not be part of the prescribed curriculum or are optional for students.
One question can be expected for NEET exam from the chapter Thermal Properties of Matter. Students can practice more questions from previous year NEET papers.
One question may be asked from Class 11 Physics chapter 11 Thermal Properties of Matter for JEE Main exam. This is one important chapter for KVPY and NSEP exms. Students can get more problems on the chapter from the NCERT Exemplar.
Topics covered in NCERT book Class 11 chapter Thermal Properties of Matter are-
One reliable online source to access thermal properties of matter ncert solutions is Careers360. These solutions have been created by subject experts to aid students in their exam preparation. The solutions provide clear and easy-to-understand explanations to help students gain a better conceptual understanding. The solutions are available in PDF format, making it convenient for students to access and save time while finding the correct answers.
There are a total of 10 topics in this chapter.
In the Class 11 Physics Chapter 11, "Thermal Properties of Matter," exercise, there are typically 22 questions are present, out of 22 questions from 1-20( exercise) and 21-22( additional exercise).
Application Date:20 November,2023 - 19 December,2023
Application Date:20 November,2023 - 19 December,2023
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Orthotists and Prosthetists are professionals who provide aid to patients with disabilities. They fix them to artificial limbs (prosthetics) and help them to regain stability. There are times when people lose their limbs in an accident. In some other occasions, they are born without a limb or orthopaedic impairment. Orthotists and prosthetists play a crucial role in their lives with fixing them to assistive devices and provide mobility.
A veterinary doctor is a medical professional with a degree in veterinary science. The veterinary science qualification is the minimum requirement to become a veterinary doctor. There are numerous veterinary science courses offered by various institutes. He or she is employed at zoos to ensure they are provided with good health facilities and medical care to improve their life expectancy.
A career in pathology in India is filled with several responsibilities as it is a medical branch and affects human lives. The demand for pathologists has been increasing over the past few years as people are getting more aware of different diseases. Not only that, but an increase in population and lifestyle changes have also contributed to the increase in a pathologist’s demand. The pathology careers provide an extremely huge number of opportunities and if you want to be a part of the medical field you can consider being a pathologist. If you want to know more about a career in pathology in India then continue reading this article.
Gynaecology can be defined as the study of the female body. The job outlook for gynaecology is excellent since there is evergreen demand for one because of their responsibility of dealing with not only women’s health but also fertility and pregnancy issues. Although most women prefer to have a women obstetrician gynaecologist as their doctor, men also explore a career as a gynaecologist and there are ample amounts of male doctors in the field who are gynaecologists and aid women during delivery and childbirth.
An oncologist is a specialised doctor responsible for providing medical care to patients diagnosed with cancer. He or she uses several therapies to control the cancer and its effect on the human body such as chemotherapy, immunotherapy, radiation therapy and biopsy. An oncologist designs a treatment plan based on a pathology report after diagnosing the type of cancer and where it is spreading inside the body.
When it comes to an operation theatre, there are several tasks that are to be carried out before as well as after the operation or surgery has taken place. Such tasks are not possible without surgical tech and surgical tech tools. A single surgeon cannot do it all alone. It’s like for a footballer he needs his team’s support to score a goal the same goes for a surgeon. It is here, when a surgical technologist comes into the picture. It is the job of a surgical technologist to prepare the operation theatre with all the required equipment before the surgery. Not only that, once an operation is done it is the job of the surgical technologist to clean all the equipment. One has to fulfil the minimum requirements of surgical tech qualifications.
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A Maxillofacial Surgeon is a medical professional who performs facial surgeries that include tooth implant, neck, head or other surgeries such as removal of tumours, cosmetic surgeries and treatment of injuries on the face.
Surgical assistants are professionals in the service of saving others’ lives. They perform various medical procedures. In a career as a surgical assistant, one works in a team and contributes to the success of operations. Surgical assistants learn new procedures and update their knowledge of new medical technology and equipment. Surgical assistants clean and sterilize the tools used in surgery. In a career as a surgical assistant, individuals perform all the basic duties that allow surgeons to keep their focus on essential technical functions.
For an individual who opts for a career as an actor, the primary responsibility is to completely speak to the character he or she is playing and to persuade the crowd that the character is genuine by connecting with them and bringing them into the story. This applies to significant roles and littler parts, as all roles join to make an effective creation. Here in this article, we will discuss how to become an actor in India, actor exams, actor salary in India, and actor jobs.
Individuals who opt for a career as acrobats create and direct original routines for themselves, in addition to developing interpretations of existing routines. The work of circus acrobats can be seen in a variety of performance settings, including circus, reality shows, sports events like the Olympics, movies and commercials. Individuals who opt for a career as acrobats must be prepared to face rejections and intermittent periods of work. The creativity of acrobats may extend to other aspects of the performance. For example, acrobats in the circus may work with gym trainers, celebrities or collaborate with other professionals to enhance such performance elements as costume and or maybe at the teaching end of the career.
Career as a video game designer is filled with excitement as well as responsibilities. A video game designer is someone who is involved in the process of creating a game from day one. He or she is responsible for fulfilling duties like designing the character of the game, the several levels involved, plot, art and similar other elements. Individuals who opt for a career as a video game designer may also write the codes for the game using different programming languages. Depending on the video game designer job description and experience they may also have to lead a team and do the early testing of the game in order to suggest changes and find loopholes.
The career as a Talent Agent is filled with responsibilities. A Talent Agent is someone who is involved in the pre-production process of the film. It is a very busy job for a Talent Agent but as and when an individual gains experience and progresses in the career he or she can have people assisting him or her in work. Depending on one’s responsibilities, number of clients and experience he or she may also have to lead a team and work with juniors under him or her in a talent agency. In order to know more about the job of a talent agent continue reading the article.
If you want to know more about talent agent meaning, how to become a Talent Agent, or Talent Agent job description then continue reading this article.
Radio Jockey is an exciting, promising career and a great challenge for music lovers. If you are really interested in a career as radio jockey, then it is very important for an RJ to have an automatic, fun, and friendly personality. If you want to get a job done in this field, a strong command of the language and a good voice are always good things. Apart from this, in order to be a good radio jockey, you will also listen to good radio jockeys so that you can understand their style and later make your own by practicing.
A career as radio jockey has a lot to offer to deserving candidates. If you want to know more about a career as radio jockey, and how to become a radio jockey then continue reading the article.
Individuals who opt for a career as a talent director are professionals who work in the entertainment industry. He or she is responsible for finding out the right talent through auditions for films, theatre productions, or shows. A talented director possesses strong knowledge of computer software used in filmmaking, CGI and animation. A talent acquisition director keeps himself or herself updated on various technical aspects such as lighting, camera angles and shots.
Careers in videography are art that can be defined as a creative and interpretive process that culminates in the authorship of an original work of art rather than a simple recording of a simple event. It would be wrong to portrait it as a subcategory of photography, rather photography is one of the crafts used in videographer jobs in addition to technical skills like organization, management, interpretation, and image-manipulation techniques. Students pursue Visual Media, Film, Television, Digital Video Production to opt for a videographer career path. The visual impacts of a film are driven by the creative decisions taken in videography jobs. Individuals who opt for a career as a videographer are involved in the entire lifecycle of a film and production.
A multimedia specialist is a media professional who creates, audio, videos, graphic image files, computer animations for multimedia applications. He or she is responsible for planning, producing, and maintaining websites and applications.
In a career as a copywriter, one has to consult with the client and understand the brief well. A career as a copywriter has a lot to offer to deserving candidates. Several new mediums of advertising are opening therefore making it a lucrative career choice. Students can pursue various copywriter courses such as Journalism, Advertising, Marketing Management. Here, we have discussed how to become a freelance copywriter, copywriter career path, how to become a copywriter in India, and copywriting career outlook.
Careers in journalism are filled with excitement as well as responsibilities. One cannot afford to miss out on the details. As it is the small details that provide insights into a story. Depending on those insights a journalist goes about writing a news article. A journalism career can be stressful at times but if you are someone who is passionate about it then it is the right choice for you. If you want to know more about the media field and journalist career then continue reading this article.
For publishing books, newspapers, magazines and digital material, editorial and commercial strategies are set by publishers. Individuals in publishing career paths make choices about the markets their businesses will reach and the type of content that their audience will be served. Individuals in book publisher careers collaborate with editorial staff, designers, authors, and freelance contributors who develop and manage the creation of content.
In a career as a vlogger, one generally works for himself or herself. However, once an individual has gained viewership there are several brands and companies that approach them for paid collaboration. It is one of those fields where an individual can earn well while following his or her passion. Ever since internet cost got reduced the viewership for these types of content has increased on a large scale. Therefore, the career as vlogger has a lot to offer. If you want to know more about the career as vlogger, how to become a vlogger, so on and so forth then continue reading the article. Students can visit Jamia Millia Islamia, Asian College of Journalism, Indian Institute of Mass Communication to pursue journalism degrees.
Individuals in the editor career path is an unsung hero of the news industry who polishes the language of the news stories provided by stringers, reporters, copywriters and content writers and also news agencies. Individuals who opt for a career as an editor make it more persuasive, concise and clear for readers. In this article, we will discuss the details of the editor's career path such as how to become an editor in India, editor salary in India and editor skills and qualities.
Fashion journalism involves performing research and writing about the most recent fashion trends. Journalists obtain this knowledge by collaborating with stylists, conducting interviews with fashion designers, and attending fashion shows, photoshoots, and conferences. A fashion Journalist job is to write copy for trade and advertisement journals, fashion magazines, newspapers, and online fashion forums about style and fashion.
A multimedia specialist is a media professional who creates, audio, videos, graphic image files, computer animations for multimedia applications. He or she is responsible for planning, producing, and maintaining websites and applications.
Are you searching for a Corporate Executive job description? A Corporate Executive role comes with administrative duties. He or she provides support to the leadership of the organisation. A Corporate Executive fulfils the business purpose and ensures its financial stability. In this article, we are going to discuss how to become corporate executive.
A Product Manager is a professional responsible for product planning and marketing. He or she manages the product throughout the Product Life Cycle, gathering and prioritising the product. A product manager job description includes defining the product vision and working closely with team members of other departments to deliver winning products.
A quality controller plays a crucial role in an organisation. He or she is responsible for performing quality checks on manufactured products. He or she identifies the defects in a product and rejects the product.
A quality controller records detailed information about products with defects and sends it to the supervisor or plant manager to take necessary actions to improve the production process.
Production Manager Job Description: A Production Manager is responsible for ensuring smooth running of manufacturing processes in an efficient manner. He or she plans and organises production schedules. The role of Production Manager involves estimation, negotiation on budget and timescales with the clients and managers.
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Quality Assurance Manager Job Description: A QA Manager is an administrative professional responsible for overseeing the activity of the QA department and staff. It involves developing, implementing and maintaining a system that is qualified and reliable for testing to meet specifications of products of organisations as well as development processes.
A QA Lead is in charge of the QA Team. The role of QA Lead comes with the responsibility of assessing services and products in order to determine that he or she meets the quality standards. He or she develops, implements and manages test plans.
Are you searching for a Reliability Engineer job description? A Reliability Engineer is responsible for ensuring long lasting and high quality products. He or she ensures that materials, manufacturing equipment, components and processes are error free. A Reliability Engineer role comes with the responsibility of minimising risks and effectiveness of processes and equipment.
A Safety Manager is a professional responsible for employee’s safety at work. He or she plans, implements and oversees the company’s employee safety. A Safety Manager ensures compliance and adherence to Occupational Health and Safety (OHS) guidelines.
Are you searching for a Corporate Executive job description? A Corporate Executive role comes with administrative duties. He or she provides support to the leadership of the organisation. A Corporate Executive fulfils the business purpose and ensures its financial stability. In this article, we are going to discuss how to become corporate executive.
Careers in computer programming primarily refer to the systematic act of writing code and moreover include wider computer science areas. The word 'programmer' or 'coder' has entered into practice with the growing number of newly self-taught tech enthusiasts. Computer programming careers involve the use of designs created by software developers and engineers and transforming them into commands that can be implemented by computers. These commands result in regular usage of social media sites, word-processing applications and browsers.
A Product Manager is a professional responsible for product planning and marketing. He or she manages the product throughout the Product Life Cycle, gathering and prioritising the product. A product manager job description includes defining the product vision and working closely with team members of other departments to deliver winning products.
ITSM Manager is a professional responsible for heading the ITSM (Information Technology Service Management) or (Information Technology Infrastructure Library) processes. He or she ensures that operation management provides appropriate resource levels for problem resolutions. The ITSM Manager oversees the level of prioritisation for the problems, critical incidents, planned as well as proactive tasks.
Individuals in the information security manager career path involves in overseeing and controlling all aspects of computer security. The IT security manager job description includes planning and carrying out security measures to protect the business data and information from corruption, theft, unauthorised access, and deliberate attack
Big Data Analytics Engineer Job Description: A Big Data Analytics Engineer is responsible for collecting data from various sources. He or she has to sort the organised and chaotic data to find out patterns. The role of Big Data Engineer involves converting messy information into useful data that is clean, accurate and actionable.
A Cloud Solutions Developer is basically a Software Engineer with specialisation in cloud computing. He or she possesses a solid understanding of cloud systems including their operations, deployment with security and efficiency with no little downtime.
A Customer Relationship Management Technology Consultant or CRM Technology Consultant is responsible for monitoring and providing strategy for performance improvement with logged calls, performance metrics and revenue metrics. His or her role involves accessing data for team meetings, goal setting analytics as well as reporting to executives.
Career as IT Manager requires managing the various aspects of an organization's information technology systems. He or she is responsible for increasing productivity and solving problems related to software and hardware. While this role is typically one of the lower-level positions within an organisation, it comes with responsibilities related to people and ownership of systems.
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